I am trying to create an index for a data frame. Each team playing has its own row, but I would like to add a column to use as an index so that the first two teams have the index 'Game 0', the next two teams have the index 'Game 1' until the length of half the list. In python the code would look as follows:
for i in range(0,int(len(teams)/2)):
gamenumber.append('Game '+str(i))
gamenumber.append('Game '+str(i))
I am unfamiliar with R so any help would be appreciated!
This will give you a list of paired index numbers:
> teams=1:100
> data.frame("Games"=sort(c(1:(length(teams)/2), 1:(length(teams)/2))))
Games
1 1
2 1
3 2
4 2
5 3
6 3
7 4
8 4
9 5
10 5
11 6
12 6
13 7
14 7
15 8
16 8
17 9
18 9
19 10
20 10 #etc.
Assuming teams is a data.frame with an even number of rows:
rep(1:(nrow(teams)/2), each=2)
Related
guys:
I have two matrix as following:
d <- cbind(c(1,2,3,4),c(1,1,1,1),c(1,2,4,8))
v <- cbind(c(2,2,2,2),c(3,3,3,3))
But I want to get a matrix consisted of divj as following:
d1v1 d1v2 d2v1 d2v2 d3v1 d3v2
2 3 2 3 2 3
4 6 2 3 4 6
6 9 2 3 8 12
8 12 2 3 16 24
This is an example of my question,I wonder if you can tell me how to write codes to solve this question.Many thanks.
matrix(apply(v,2,function(x){x*d}),4,6)
I have a data frame of GPS locations with a column of seconds. How can I split create a new column based on time-gaps? i.e. for this data.frame:
df <- data.frame(secs=c(1,2,3,4,5,6,7,10,11,12,13,14,20,21,22,23,24,28,29,31))
I would like to cut the data frame when there is a time gap between locations of 3 or more seconds seconds and create a new column entitled 'bouts' which gives a running tally of the number of sections to give a data frame looking like this:
id secs bouts
1 1 1
2 2 1
3 3 1
4 4 1
5 5 1
6 6 1
7 7 1
8 10 2
9 11 2
10 12 2
11 13 2
12 14 2
13 20 3
14 21 3
15 22 3
16 23 3
17 24 3
18 28 4
19 29 4
20 31 4
Use cumsum and diff:
df$bouts <- cumsum(c(1, diff(df$secs) >= 3))
Remember that logical values get coerced to numeric values 0/1 automatically and that diff output is always one element shorter than its input.
This question already has answers here:
Filtering a data frame by values in a column [duplicate]
(3 answers)
Closed 3 years ago.
I have the following data with the ID of subjects.
V1
1 2
2 2
3 2
4 2
5 2
6 2
7 2
8 2
9 2
10 2
11 2
12 2
13 2
14 2
15 2
16 4
17 4
18 4
19 4
20 4
21 4
22 4
23 4
24 4
I want to subset all the rows of the data where V1 == 4. This way I can see which observations relate to subject 4.
For example, the correct output would be
16 4
17 4
18 4
19 4
20 4
21 4
22 4
23 4
24 4
However, the output I'm given after subsetting does not give me the correct rows . It simply gives me.
V1
1 4
2 4
3 4
4 4
5 4
6 4
7 4
8 4
I'm unable to tell which observations relate to subject 4, as observations 1:8 are for subject 2.
I've tried the usual methods, such as
condition<- df == 4
df[condition]
How can I subset the data so I'm given back a dataset that shows the correct row numbers for subject 4.
You can also use the subset function:
subset(df,df$V1==4)
I've managed to find a solution since posting.
newdf <- subset(df, V1 == 4).
However i'm still very interested in other solutions to this problems, so please post if you're aware of another method.
Simple question, I think. Basically, I want to use the concept "less than or equal to a number" as the condition to select the row of one column, and then find the value on the same row in another column. But what happens if the number stated in the condition isn't found in the first column?
Let's assume this is my data frame:
df<-as.data.frame((matrix(c(1:10,11:20), nrow = 10, ncol = 2)))
df
V1 V2
1 1 11
2 2 12
3 3 13
4 4 14
5 5 15
6 6 16
7 7 17
8 8 18
9 9 19
10 10 20
Let's assume I want to use the condition <=5 in df$V1 to obtain the row that is used to find the value of the same row in df$V2.
df[which(df$V1 <= 5),2]
15
But what happens if the number used in the condition isn't found? Let's assume this is my new data.frame
V1 V2
1 1 11
2 2 12
3 3 13
4 4 14
5 6 15
6 7 16
7 8 17
8 9 18
9 10 19
10 11 20
Using the same above command df[which(df$V1 <= 5),2], I obtain a different answer. For some reason I obtain the entire column instead of one number.
11 12 13 14 15 16 17 18 19 20
Any suggestions?
Use the subset operator:
df[df[,2]<= 5,1]
I printed out the summary of a column variables as such:
Please see below the summary table printed out from R:
I would like to generate it into a data.frame. However, there are too many subject names that it's very difficult to list out all, also, the term "OTHER" with number 31 means that there are 319 subjects which appear only 1 time in the original data.frame.
So, the new data.frame I hope to produce would look like below:
Here is one possible solution.
Table<-table(rpois(100,5))
as.data.frame(Table)
Var1 Freq
1 1 2
2 2 11
3 3 9
4 4 18
5 5 13
6 6 20
7 7 14
8 8 8
9 9 3
10 10 1
11 11 1