import os
def rename_files():
#(1) get file names from a folder
file_list = os.listdir("my_directory")
#print(file_list)
os.chdir("my_directory")
saved_path = os.getcwd()
print("Current work directory is " + saved_path)
os.getcwd()
#(2) for each file, rename filename
for file_name in file_list:
os.rename(file_name, file_name.translate(None, "0123456789"))
os.chdir("my_directory")
rename_files()
And after this I've got an error:
TypeError: translate() takes exactly one argument (2 given)
str.translate in python 3.x accepts just one argument i.e. translation table.
From docs:
str.translate(table)
Return a copy of the string in which each character has been mapped
through the given translation table
You can create required translation table using str.maketrans
table = str.maketrans(dict.fromkeys('0123456789'))
file_name.translate(table)
Related
I have a function that I want to open .dat files with, to extract data from them, but the problem is I don't know how to turn that data back into a dictionary to store in a variable. Currently, the data in the files are stored like this: "{"x":0,"y":1}" (it uses up only one line of the file, which is just the normal structure of a dictionary).
Below is just the function where I open the .dat file and try to extract stuff from it.
def openData():
file = fd.askopenfile(filetypes=[("Data",".dat"),("All Files",".*")])
filepath = file.name
if file is None:
return
with open(filepath,"r") as f:
contents = dict(f.read())
print(contents["x"]) #let's say there is a key called "x" in that dictionary
This is the error that I get from it: (not because the key "x" is not in dict, trust me)
Exception in Tkinter callback
Traceback (most recent call last):
File "...\AppData\Local\Programs\Python\Python39\lib\tkinter\__init__.py", line 1892, in __call__
return self.func(*args)
File "...\PycharmProjects\[this project]\main.py", line 204, in openData
contents = dict(f.read())
ValueError: dictionary update sequence element #0 has length 1; 2 is required
Process finished with exit code 0
Update: I tried using json and it worked, thanks to #match
def openData():
file = fd.askopenfile(filetypes=[("Data",".dat"),("All Files",".*")])
filepath = file.name
if file is None:
return
with open(filepath,"r") as f:
contents = dict(json.load(f))
print(contents["x"])
You need to parse the data to get a data structure from a string, fortunately, Python provides a function for safely parsing Python data structures: ast.literal_eval(). E.g:
import ast
...
with open("/path/to/file", "r") as data:
dictionary = ast.literal_eval(data.read())
Reference stackoverflow
I am using Octave 5.1.0 on Windows 10 (x64). I am parsing a series of directories looking for an Excel spreadsheet in each directory with "logbook" in its filename. The problem is these files are created by hand and the filenaming isn't consistent: sometimes it's "LogBook", other times it's "logbook", etc...
It looks like the string passed as input to the dir function is case-sensitive so if I don't have the correct case, dir returns an empty struct. Currently, I am using the following workaround, but I wondered if there was a better way of doing this (for a start I haven't captured all possible upper/lower case combinations):
logbook = dir('*LogBook.xls*');
if isempty(logbook)
logbook = dir('*logbook.xls*');
if isempty(logbook)
logbook = dir('*Logbook.xls*');
if isempty(logbook)
logbook = dir('*logBook.xls*');
if isempty(logbook)
error(['Could not find logbook spreadsheet in ' dir_name '.'])
end
end
end
end
You need to get the list of filenames (either via readdir, dir, ls), and then search for the string in that list. If you use readdir, it can be done like this:
[files, err, msg] = readdir ('.'); # read current directory
if (err != 0)
error ("failed to readdir (error code %d): %s", msg);
endif
logbook_indices = find (cellfun (#any, regexpi (files, 'logbook'));
logbook_filenames = files(logbook_indices);
A much less standard approach could be:
glob ('*[lL][oO][gG][bB][oO][kK]*')
How to append filenames in a folder
Filenames:
abc.wav
wjejrt.wav
13567tin.wav
Desired Output
abc_ENG.wav
wjejrt_ENG.wav
13567tin_ENG.wav
Tried this line code below but getting an error, maybe because I don't know the right use of file.rename function. Please help...
file.rename(list.files(pattern="*.wav"), paste0("_ENG"))
With base Ryou can do:
Filenames <- c("abc.wav", "wjejrt.wav", "13567tin.wav")
Fnames_new <- sub(".wav", "_ENG.wav", Filenames, fixed = TRUE)
file.rename(Filenames, Fnames_new)
Since you tagged Python, you could use os.rename() to rename your files:
from os import rename
from os import listdir
from os.path import splitext
# Current directory script is being run in
# You can change this to any path you want
path_to_folder = "."
for f in listdir(path_to_folder):
if f.endswith(".wav"):
name, ext = splitext(f)
rename(f, name + "_ENG" + ext)
You can try this one
^.*(?=\\.wav)
Explanation
^ - Anchor to start of string.
.* - Match anything except new line.
(?=\\.wav) - Positive look ahead matches .wav.
Change your code to this
file.rename(list.files(pattern=".*(?=\\.wav)"), paste0("_ENG"))
Demo
I'm trying to write a quick script to open a family document, change the parameter group of 2 specified parameters, and then close and save the document. I've done multiple tests and I am able to change the parameter groups of the specified parameters, but the changes of the groups don't save back to the family file. When I open the newly saved family, the parameter groups revert back to their original group.
This is with Revit 2017.2.
The same script, when run in RPS in Revit 2018 will do as desired.
import clr
import os
clr.AddReference('RevitAPI')
clr.AddReference('RevitAPIUI')
from Autodesk.Revit.DB import *
from Autodesk.Revit.UI import UIApplication
from System.IO import Directory, SearchOption
searchstring = "*.rfa"
dir = r"C:\Users\dboghean\Desktop\vanity\2017"
docs = []
if Directory.Exists(dir):
files = Directory.GetFiles(dir, searchstring, SearchOption.AllDirectories)
for f in files:
name, extension = os.path.splitext(f)
name2, extension2 = os.path.splitext(name)
if extension2:
os.remove(f)
else:
docs.append(f)
else:
print("Directory does not exist")
doc = __revit__.ActiveUIDocument.Document
app = __revit__.Application
uiapp = UIApplication(app)
currentPath = doc.PathName
pgGroup = BuiltInParameterGroup.PG_GRAPHICS
for i in docs:
doc = app.OpenDocumentFile(i)
paramList = [i for i in doc.FamilyManager.Parameters]
t = Transaction(doc, "test")
t.Start()
for i in paramList:
if i.Definition.Name in ["Right Sidesplash Edge line", "Left Sidesplash Edge line"]:
i.Definition.ParameterGroup = pgGroup
t.Commit()
doc.Close(True)
Any ideas?
Thanks!
I can confirm that this happens in Revit 2017. Strange!
A simple way around it is to arbitrarily rename the parameter using doc.FamilyManager.RenameParameter, then rename it back to the original name.
So in your case this would be three additional lines of code after changing the Parameter group:
originalName = i.Definition.Name
doc.FamilyManager.RenameParameter(i, "temp")
doc.FamilyManager.RenameParameter(i, originalName)
Doesnt get to the root problem, but works around it
I want to create an object in R, which will contain one string, with a few variables (in my case it is file path). When I try to use paste to concatenate the file paths I can see only one last variable instead of all variables in one string. I use next code:
for(i in seq_len(nrow(samples))) {
lib = samples$conditions[i]
txtFile = file.path(lib, "hits.txt")
testfiles = paste(txtFile, sep = ',')
}
print(testfiles)
and get something like
cond/hits.txt,
instead of
cond/hits.txt,cond1/hits.txt,cond2/hits.txt and so on
Thank you very much for help