I have an app where you can choose (or add if they don't exist!) a superhero/villain character from a certain universe on the first page; then outfit him with weapons, clothes, and gadgets on the second page (build).
I have this route defined:
Router.route('/build/:character', {
name: 'build'
waitOn: Meteor.subscribe('characters', {name: this.params.character})
//and a few other subscriptions and sessions as well for the items
//and stuff, but those don't matter here.
}
The link from the specific character, though, passes along a query as well:
<a href="{{pathFor 'build' query=this.universe}}">
So the final link could look something like this:
/build/Aquaman?DCComics
Now the page you are on will display a list of weapons and gadgets where you could also add other stuff if you so wish. Then you are supposed to drag the items you want to include onto your version of this hero.
Problem is, at this point the app doesn't know you even want to create your own hero. Maybe the user is just looking through them for fun. There's a button that the user has to click first to initialize the creating process, and that's when the actual _id is created, something like this:
Meteor.methods({
buildHero: function(heroCharacterName, heroUniverse) {
var heroToAdd = {}
heroToAdd['characterName'] = heroCharacterName
heroToAdd['universe'] = heroUniverse
heroToAdd['_createdAt'] = new Date()
CreatedHeroes.insert(heroToAdd, function() {
if (! error)
//Update the subscription somehow...
})
}
})
So, the _id that is created here in the new Collection must be passed along to a subscription somehow, because I don't want the user to see other personal heroes that have been created, only his own newly created one.
The solution I have in mind is adding the _id onto the URL in form of a hastag, and use this.params.hash in the subscription like so:
Router.route('/build/:character', {
name: 'build'
waitOn: [Meteor.subscribe('characters', {name: this.params.character}),
Meteor.subscribe('createdheroes', this.params.hash)]
}
First of all, is this a valid approach? If so, how do I accomplish it; how do I actually update the URL to include this hash?
If not, what would be a better approach?
I think you have to handle this logic in the data context or in a template helper and not in the way of subscribing/publishing.
If I was you I would besure that the newly created item is being published and subscribed by the client and modify your search query just that it only adds the newly created item.
I am not sure if I understand your question well but what I got, you will know the last _id which was used on your insert.
Instead of letting done this automatically by meteor, just use the meteor method to create / get that _id value >> see Meteor Documentation
var new_id = new Mongo.ObjectID()
col1.insert({ _id: new_id, ... });
col2.insert({ ..., ref_col1_id: new_id, ... });
I have an app where users can take notes.
In the html page I iterate over each note like so:
<div id="notes-container" class="notes">
{{each notes}}
{{> note}}
{{/each}}
</div>
and in my router file I return the data like so:
#route: 'notes'.
path: '/notes/:_id',
data: ->
notes = Notes.find
threadId: #params._id
trash:
$exists: false
,
sort:
date: -1
All is typical meteor stuff so far. But I am confused now about how to adjust the data that is iterated on in the html page.
Each notes has a array field for tags like tags: ['apple' ,'red', 'green']
What if the user wants to return all notes with the tag 'red'. So there is a input box on the site the user enters a tag and presses enter.
How can I adjust the data that is sent to the page so queries mongodb to return all notes with tag red? I know how to write the query I am not sure how to set this up though in meteor.
One way I tried to do it is called the same route with query paramters like: '/notes/326363235474?tags=apple'
And in iron router I can look for query parameters and return the right set of documents but then when I call the original route again to clear the search, it does not load all of the original documents again.
Any suggestion on how I can set this up? Thanks
the data function simply needs to return the data you want available within the template context, if I'll define this function to a certain route:
data: ->
return Drawing.findOne
_id: window._drawing_id
I will have that data in my "this" object when proccessing that template.
I'm trying to test out Firebase to allow users to post comments using push. I want to display the data I retrieve with the following;
fbl.child('sell').limit(20).on("value", function(fbdata) {
// handle data display here
}
The problem is the data is returned in order of oldest to newest - I want it in reversed order. Can Firebase do this?
Since this answer was written, Firebase has added a feature that allows ordering by any child or by value. So there are now four ways to order data: by key, by value, by priority, or by the value of any named child. See this blog post that introduces the new ordering capabilities.
The basic approaches remain the same though:
1. Add a child property with the inverted timestamp and then order on that.
2. Read the children in ascending order and then invert them on the client.
Firebase supports retrieving child nodes of a collection in two ways:
by name
by priority
What you're getting now is by name, which happens to be chronological. That's no coincidence btw: when you push an item into a collection, the name is generated to ensure the children are ordered in this way. To quote the Firebase documentation for push:
The unique name generated by push() is prefixed with a client-generated timestamp so that the resulting list will be chronologically-sorted.
The Firebase guide on ordered data has this to say on the topic:
How Data is Ordered
By default, children at a Firebase node are sorted lexicographically by name. Using push() can generate child names that naturally sort chronologically, but many applications require their data to be sorted in other ways. Firebase lets developers specify the ordering of items in a list by specifying a custom priority for each item.
The simplest way to get the behavior you want is to also specify an always-decreasing priority when you add the item:
var ref = new Firebase('https://your.firebaseio.com/sell');
var item = ref.push();
item.setWithPriority(yourObject, 0 - Date.now());
Update
You'll also have to retrieve the children differently:
fbl.child('sell').startAt().limitToLast(20).on('child_added', function(fbdata) {
console.log(fbdata.exportVal());
})
In my test using on('child_added' ensures that the last few children added are returned in reverse chronological order. Using on('value' on the other hand, returns them in the order of their name.
Be sure to read the section "Reading ordered data", which explains the usage of the child_* events to retrieve (ordered) children.
A bin to demonstrate this: http://jsbin.com/nonawe/3/watch?js,console
Since firebase 2.0.x you can use limitLast() to achieve that:
fbl.child('sell').orderByValue().limitLast(20).on("value", function(fbdataSnapshot) {
// fbdataSnapshot is returned in the ascending order
// you will still need to order these 20 items in
// in a descending order
}
Here's a link to the announcement: More querying capabilities in Firebase
To augment Frank's answer, it's also possible to grab the most recent records--even if you haven't bothered to order them using priorities--by simply using endAt().limit(x) like this demo:
var fb = new Firebase(URL);
// listen for all changes and update
fb.endAt().limit(100).on('value', update);
// print the output of our array
function update(snap) {
var list = [];
snap.forEach(function(ss) {
var data = ss.val();
data['.priority'] = ss.getPriority();
data['.name'] = ss.name();
list.unshift(data);
});
// print/process the results...
}
Note that this is quite performant even up to perhaps a thousand records (assuming the payloads are small). For more robust usages, Frank's answer is authoritative and much more scalable.
This brute force can also be optimized to work with bigger data or more records by doing things like monitoring child_added/child_removed/child_moved events in lieu of value, and using a debounce to apply DOM updates in bulk instead of individually.
DOM updates, naturally, are a stinker regardless of the approach, once you get into the hundreds of elements, so the debounce approach (or a React.js solution, which is essentially an uber debounce) is a great tool to have.
There is really no way but seems we have the recyclerview we can have this
query=mCommentsReference.orderByChild("date_added");
query.keepSynced(true);
// Initialize Views
mRecyclerView = (RecyclerView) view.findViewById(R.id.recyclerView);
mManager = new LinearLayoutManager(getContext());
// mManager.setReverseLayout(false);
mManager.setReverseLayout(true);
mManager.setStackFromEnd(true);
mRecyclerView.setHasFixedSize(true);
mRecyclerView.setLayoutManager(mManager);
I have a date variable (long) and wanted to keep the newest items on top of the list. So what I did was:
Add a new long field 'dateInverse'
Add a new method called 'getDateInverse', which just returns: Long.MAX_VALUE - date;
Create my query with: .orderByChild("dateInverse")
Presto! :p
You are searching limitTolast(Int x) .This will give you the last "x" higher elements of your database (they are in ascending order) but they are the "x" higher elements
if you got in your database {10,300,150,240,2,24,220}
this method:
myFirebaseRef.orderByChild("highScore").limitToLast(4)
will retrive you : {150,220,240,300}
In Android there is a way to actually reverse the data in an Arraylist of objects through the Adapter. In my case I could not use the LayoutManager to reverse the results in descending order since I was using a horizontal Recyclerview to display the data. Setting the following parameters to the recyclerview messed up my UI experience:
llManager.setReverseLayout(true);
llManager.setStackFromEnd(true);
The only working way I found around this was through the BindViewHolder method of the RecyclerView adapter:
#Override
public void onBindViewHolder(final RecyclerView.ViewHolder holder, int position) {
final SuperPost superPost = superList.get(getItemCount() - position - 1);
}
Hope this answer will help all the devs out there who are struggling with this issue in Firebase.
Firebase: How to display a thread of items in reverse order with a limit for each request and an indicator for a "load more" button.
This will get the last 10 items of the list
FBRef.child("childName")
.limitToLast(loadMoreLimit) // loadMoreLimit = 10 for example
This will get the last 10 items. Grab the id of the last record in the list and save for the load more functionality. Next, convert the collection of objects into and an array and do a list.reverse().
LOAD MORE Functionality: The next call will do two things, it will get the next sequence of list items based on the reference id from the first request and give you an indicator if you need to display the "load more" button.
this.FBRef
.child("childName")
.endAt(null, lastThreadId) // Get this from the previous step
.limitToLast(loadMoreLimit+2)
You will need to strip the first and last item of this object collection. The first item is the reference to get this list. The last item is an indicator for the show more button.
I have a bunch of other logic that will keep everything clean. You will need to add this code only for the load more functionality.
list = snapObjectAsArray; // The list is an array from snapObject
lastItemId = key; // get the first key of the list
if (list.length < loadMoreLimit+1) {
lastItemId = false;
}
if (list.length > loadMoreLimit+1) {
list.pop();
}
if (list.length > loadMoreLimit) {
list.shift();
}
// Return the list.reverse() and lastItemId
// If lastItemId is an ID, it will be used for the next reference and a flag to show the "load more" button.
}
I'm using ReactFire for easy Firebase integration.
Basically, it helps me storing the datas into the component state, as an array. Then, all I have to use is the reverse() function (read more)
Here is how I achieve this :
import React, { Component, PropTypes } from 'react';
import ReactMixin from 'react-mixin';
import ReactFireMixin from 'reactfire';
import Firebase from '../../../utils/firebaseUtils'; // Firebase.initializeApp(config);
#ReactMixin.decorate(ReactFireMixin)
export default class Add extends Component {
constructor(args) {
super(args);
this.state = {
articles: []
};
}
componentWillMount() {
let ref = Firebase.database().ref('articles').orderByChild('insertDate').limitToLast(10);
this.bindAsArray(ref, 'articles'); // bind retrieved data to this.state.articles
}
render() {
return (
<div>
{
this.state.articles.reverse().map(function(article) {
return <div>{article.title}</div>
})
}
</div>
);
}
}
There is a better way. You should order by negative server timestamp. How to get negative server timestamp even offline? There is an hidden field which helps. Related snippet from documentation:
var offsetRef = new Firebase("https://<YOUR-FIREBASE-APP>.firebaseio.com/.info/serverTimeOffset");
offsetRef.on("value", function(snap) {
var offset = snap.val();
var estimatedServerTimeMs = new Date().getTime() + offset;
});
To add to Dave Vávra's answer, I use a negative timestamp as my sort_key like so
Setting
const timestamp = new Date().getTime();
const data = {
name: 'John Doe',
city: 'New York',
sort_key: timestamp * -1 // Gets the negative value of the timestamp
}
Getting
const ref = firebase.database().ref('business-images').child(id);
const query = ref.orderByChild('sort_key');
return $firebaseArray(query); // AngularFire function
This fetches all objects from newest to oldest. You can also $indexOn the sortKey to make it run even faster
I had this problem too, I found a very simple solution to this that doesn't involved manipulating the data in anyway. If you are rending the result to the DOM, in a list of some sort. You can use flexbox and setup a class to reverse the elements in their container.
.reverse {
display: flex;
flex-direction: column-reverse;
}
myarray.reverse(); or this.myitems = items.map(item => item).reverse();
I did this by prepend.
query.orderByChild('sell').limitToLast(4).on("value", function(snapshot){
snapshot.forEach(function (childSnapshot) {
// PREPEND
});
});
Someone has pointed out that there are 2 ways to do this:
Manipulate the data client-side
Make a query that will order the data
The easiest way that I have found to do this is to use option 1, but through a LinkedList. I just append each of the objects to the front of the stack. It is flexible enough to still allow the list to be used in a ListView or RecyclerView. This way even though they come in order oldest to newest, you can still view, or retrieve, newest to oldest.
You can add a column named orderColumn where you save time as
Long refrenceTime = "large future time";
Long currentTime = "currentTime";
Long order = refrenceTime - currentTime;
now save Long order in column named orderColumn and when you retrieve data
as orderBy(orderColumn) you will get what you need.
just use reverse() on the array , suppose if you are storing the values to an array items[] then do a this.items.reverse()
ref.subscribe(snapshots => {
this.loading.dismiss();
this.items = [];
snapshots.forEach(snapshot => {
this.items.push(snapshot);
});
**this.items.reverse();**
},
For me it was limitToLast that worked. I also found out that limitLast is NOT a function:)
const query = messagesRef.orderBy('createdAt', 'asc').limitToLast(25);
The above is what worked for me.
PRINT in reverse order
Let's think outside the box... If your information will be printed directly into user's screen (without any content that needs to be modified in a consecutive order, like a sum or something), simply print from bottom to top.
So, instead of inserting each new block of content to the end of the print space (A += B), add that block to the beginning (A = B+A).
If you'll include the elements as a consecutive ordered list, the DOM can put the numbers for you if you insert each element as a List Item (<li>) inside an Ordered Lists (<ol>).
This way you save space from your database, avoiding unnecesary reversed data.
Meteor Parties Example: http://www.meteor.com/examples/parties
What's the most efficient way of limiting 1 RSVP per user? I'd like to just modify the RSVP method somehow but unsure of how to go about it.
My general thought would be something like this:
if(Parties.find({rsvps:{user}}) > 1 )
Any help would be greatly appreciated!
You've basically got the right idea: add a check to the rsvp function in model.js. Here's the schema for the parties collection:
/* Each party is represented by a document in the Parties collection:
owner: user id
x, y: Number (screen coordinates in the interval [0, 1])
title, description: String
public: Boolean
invited: Array of user id's that are invited (only if !public)
rsvps: Array of objects like {user: userId, rsvp: "yes"} (or "no"/"maybe")
*/
To check if a user already has an rsvp, you'd want to add a line to that function like this:
if (Parties.find({'rsvps.user': this.userId}).count()) return;
This'll basically work. There's a minor race condition, though, where one user can call rsvp twice in quick succession, this check can pass for both updates, and then he'll be rsvp-ed twice. There are ways around that (ex: some form of two-phase commit...) but they're more involved.
I have the following in Drupal 6:
A Master CCK type which contains a User reference field and other fields. There will only be one record per user here.
A View of this CCK, shown as a table, with one of the fields being the user ref from the CCK type. This field is initially shown as a user name, linking to the user profile.
A Second CCK type which can have several pieces of data about a particular user.
A View for this CCK type, displaying information as a table. It takes a user id as an argument (an integer)
I want to click on the user name in the master view, and be directed to the detail view for this user. To do this, I tried selecting 'Output this field as a link' on the user field. The thing available for me to replace are:
Fields
* [field_my_user_ref_uid_1] == Content: User (field_my_user_ref)
Arguments
* %1 == User: Uid
However, the [field_my_user_ref_uid_1] element is replaced by the user name, and %1 seems to get replaced with an empty string. How can I put the user id in here?
Well, I'm not sure what the right way to do this is, but I'm solving it the hacky way I seem to be solving all my Views problems: by throwing jquery at it.
Currently, the User Ref field already has a link with the user id, so I've added this to the footer:
<script type="text/javascript">
$(function() {
var $rows = $("table.views-table tbody tr");
$rows.children("td:nth-child(1)").each(function() {
var $anchor = $(this).children("a");
var linkElements = $anchor.attr("href").split("/");
var userId = linkElements[linkElements.length - 1];
$anchor.attr("href","/my_detail_view/" + userId);
});
});
</script>
I hate that I have to do it like this, but I sure do love jquery.