Change from character to POSIXct [duplicate] - r

How do I use strptime or any other functions to parse time stamps with milliseconds in R?
time[1]
# [1] "2010-01-15 13:55:23.975"
strptime(time[1], format="%Y-%m-%d %H:%M:%S.%f")
# [1] NA
strptime(time[1], format="%Y-%m-%d %H:%M:%S")
# [1] "2010-01-15 13:55:23"`

Courtesy of the ?strptime help file (with the example changed to your value):
> z <- strptime("2010-01-15 13:55:23.975", "%Y-%m-%d %H:%M:%OS")
> z # prints without fractional seconds
[1] "2010-01-15 13:55:23 UTC"
> op <- options(digits.secs=3)
> z
[1] "2010-01-15 13:55:23.975 UTC"
> options(op) #reset options

You can also use strptime(time[1], "%OSn") where 0 <= n <= 6, without having to set digits.secs.
The documentation states "Which of these are supported is OS-dependent." so YMMV.

Related

Converting timestamp in microseconds to data and time in r

I'm trying to convert a timestamp in microseconds to the following format in R:
YYYY-MM-DD HH:MM:SS
I've tried different approaches, but couldn't succeed. Following my code:
options(digits=16)
value = 1521222492687300
as.POSIXct(value, tz = "UTC", origin="1970-01-01 00:00:00")
And I get this as return:
[1] "48207591-10-13 12:15:00 UTC"
Even divided by 1000, as some posts suggested, I'm still getting a non sense result:
as.POSIXct(value/1000, tz = "UTC", origin="1970-01-01 00:00:00")
[1] "50175-08-15 19:31:27.300048 UTC"
Any suggestion to solve this problem?
As Gabor hinted you need to divide by 1e6, not 1e3:
R> v <- 1521222492687300
R> v
[1] 1.52122e+15
R> anytime::anytime(v / 1e6)
[1] "2018-03-16 12:48:12.6872 CDT"
R>
Same of course with as.POSIXct etc but you nee to supply the redundant origin:
R> as.POSIXct(v / 1e6, origin="1970-01-01")
[1] "2018-03-16 12:48:12.6872 CDT"
R>
One way to see your scale is to convert current time:
R> w <- as.numeric(Sys.time())
R> c(v, w)
[1] 1.52122e+15 1.52346e+09
R>
which makes the scaling difference more obvious.

Convert Date with special format using R

I have several variables that exist in the following format:
/Date(1353020400000+0100)/
I want to convert this format to ddmmyyyy. I found this solution for the same problem using php, but I don't know anything about php, so I'm unable to convert that solution to what I need, which is a solution that I can use in R.
Any suggestions?
Thanks.
If the format is milliseconds since the epoch then anytime() or as.POSIXct() can help you:
R> anytime(1353020400000/1000)
[1] "2012-11-15 17:00:00 CST"
R> anytime(1353020400.000)
[1] "2012-11-15 17:00:00 CST"
R>
anytime() converts to local time, which is Chicago for me. You would have to deal with the UTC offset separately.
Base R can do it too, but you need the dreaded origin:
R> as.POSIXct(1353020400.000, origin="1970-01-01")
[1] "2012-11-15 17:00:00 CST"
R>
As far as I can tell from the linked question, this is milliseconds since the epoch:
x <- "/Date(1353020400000+0100)/"
spl <- strsplit(x, "[()+]")
as.POSIXct(as.numeric(sapply(spl,`[[`,2)) / 1000, origin="1970-01-01", tz="UTC")
#[1] "2012-11-15 23:00:00 UTC"
If you want to pick up the timezone difference as well, here's an attempt:
x <- "/Date(1353020400000+0100)/"
spl <- strsplit(x, "(?=[+-])|[()]", perl=TRUE)
tzo <- sapply(spl, function(x) paste(x[3:4],collapse="") )
dt <- as.POSIXct(as.numeric(sapply(spl,`[[`,2)) / 1000, origin="1970-01-01", tz="UTC")
as.POSIXct(paste(format(dt), tzo), tz="UTC", format = '%F %T %z')
#[1] "2012-11-15 22:00:00 UTC"
The package lubridate can come to the rescue as follows:
as.Date("1970-01-01") + lubridate::milliseconds(1353020400000)
Read: Number of milliseconds since epoch (= 1. January 1970, UTC + 0)
A parsing function can now be made using regular expressions:
parse.myDate <- function(text) {
num <- as.numeric(stringr::str_extract(text, "(?<=/Date\\()\\d+"))
as.Date("1970-01-01") + lubridate::milliseconds(num)
}
finally, format the Date with
format(theDate, "%d/%m/%Y %H:%M")
If you also need the time zone information, you can use this instead:
parse.myDate <- function(text) {
parts <- stringr::str_match(text, "^/Date\\((\\d+)([+-])(\\d{4})\\)/$")
as.POSIXct(as.numeric(parts[,2])/1000, origin = "1970-01-01", tz = paste0("Etc/GMT", parts[,3], as.integer(parts[,4])/100))
}

How to get milliseconds using as.POSIXct or as.POSIXlt in r?

I want to get subseconds so I use following:
> options(digits.secs=6)
> as.POSIXlt(df1$Global.Time[5]/1000, origin="1970-01-01", tz="America/Los_Angeles")
[1] "2005-06-15 07:53:42.7 PDT"
Why does the output not contain something like "07:53:42.700000"?
Same problem with POSIXct:
> as.POSIXct(df1$Global.Time[3]/1000, origin="1970-01-01", tz="America/Los_Angeles")
[1] "2005-06-15 07:53:42.5 PDT"
How about this (corrected per Frank's direction):
d <- as.POSIXct(Sys.time())
format(d,"%Y-%m-%d %H:%M:%OS6")
[1] "2015-05-30 18:06:08.693852"

how to read the date format in R language

I try to read the date like 03-Nov-11, and I use the code as followed:
s<-c("03-Nov-13")
s1<-as.Date(s,"%d-%b-%y")
but s1 is NA.
The %b seems to be problematic indeed. I've had luck with those though:
s1 <- "03-11-13"
as.POSIXct(s1, format = "%d-%m-%y")
# [1] "2013-11-03 EDT"
s2 <- "03-NOVEMBRE-13" # Note that I have Fr locale, hence the ending in "BRE"
as.POSIXct(s2, format = "%d-%B-%y")
# [1] "2013-11-03 EDT"
as.POSIXct(s2, format = "%d-%b-%y")
# [1] "2013-11-03 EDT"
However, the abbreviated version doesn't seem to work at all on Windows:
s3 <- "03-NOV-13"
as.POSIXct(s3, format = "%d-%B-%y")
# [1] NA
as.POSIXct(s3, format = "%d-%b-%y")
# [1] NA
EDIT
After trying on Linux, the %b does what is expected!
as.POSIXct(s3, format="%d-%b-%y")
# [1] "2013-11-03 PDT"
as.POSIXct(s3, format="%d-%B-%y")
# [1] "2013-11-03 PDT"
EDIT 2
Filed a bug report;
See https://bugs.r-project.org/bugzilla/show_bug.cgi?id=16301
EDIT 3
On my end I was mistaken -- my locale's months abbreviations are given by:
z <- seq.Date(as.Date('2015-01-01'), by='month', len = 12)
format(z, "%d-%b-%y")
# [1] "01-janv.-15" "01-févr.-15" "01-mars-15" "01-avr.-15" "01-mai-15"
# [6] "01-juin-15" "01-juil.-15" "01-août-15" "01-sept.-15" "01-oct.-15"
# [11] "01-nov.-15" "01-déc.-15"
So using "nov.", "NOV.", "NOVEMBRE" or "novembre" works fine.

R - Current timestamp with milliseconds precision [duplicate]

How do I use strptime or any other functions to parse time stamps with milliseconds in R?
time[1]
# [1] "2010-01-15 13:55:23.975"
strptime(time[1], format="%Y-%m-%d %H:%M:%S.%f")
# [1] NA
strptime(time[1], format="%Y-%m-%d %H:%M:%S")
# [1] "2010-01-15 13:55:23"`
Courtesy of the ?strptime help file (with the example changed to your value):
> z <- strptime("2010-01-15 13:55:23.975", "%Y-%m-%d %H:%M:%OS")
> z # prints without fractional seconds
[1] "2010-01-15 13:55:23 UTC"
> op <- options(digits.secs=3)
> z
[1] "2010-01-15 13:55:23.975 UTC"
> options(op) #reset options
You can also use strptime(time[1], "%OSn") where 0 <= n <= 6, without having to set digits.secs.
The documentation states "Which of these are supported is OS-dependent." so YMMV.

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