perspective() problems fixed with perspective? - css

I have a flip animation were I use perspective, I have a simple card that flips when hovered. From my understanding the perspective property and the transform property perspective() are the same except perspective is applied to the parent and is rendered on its children and the perspective() is applied directly to an element you want to have perspective, is this correct? I used the perspective property at first then realized I could simplify my code slightly by using perspective() so I changed it. With perspective() if you hover over the card the animation works but if you move the mouse off and back on before the animation finishes at the very beginning of the animation you get some weird results, the back of the card will show through the front and the card will stretch across the screen, all this weird behavior stops when I give the card a parent with a perspective property and delete the perspective(), so is this a browser error or am I not understanding the differences correctly or is there some other property I need to use with perspective() that I'm not aware off?
two versions of css with results
perspective: 1000px;
https://fiddle.jshell.net/rqzwoguw/28/
transform: perspective(1000px);
https://fiddle.jshell.net/rqzwoguw/29/ // move mouse on and off at the beginning or the middle point of the transition.

Keep the pespective constant, don't change it on hover.
Just add to .card: (no rotation, but the same pespective that you are setting on hover)
transform: perspective(1000px) rotateY(0deg);
.front,
.back,
.card {
width: 100px;
height: 170px;
border-radius: 10px;
text-align: center;
}
.card {
position: relative;
transition: transform 1s ease-in-out 0s;
transform-style: preserve-3d;
transform-origin: right;
transform: perspective(1000px) rotateY(0deg);
}
.card:hover {
transform: perspective(1000px) rotateY(180deg);
}
.front {
background-color: red;
}
.back {
background-color: blue;
transform: rotateY(180deg);
position: absolute;
top: 0px;
z-index: -1;
}
<div class="card">
<div class="front">
FRONT
</div>
<div class="back">
BACK
</div>
</div>

Related

Why is CSS position attribute affecting a rotation animation?

I'm working on a website (that I didn't design, someone else gave me the HTML/CSS) as a developer and We've got a nice spinner animation for async loading components. It's forever-spinning animation is defined by this CSS rule:
animation: spinning 1s infinite linear; (it has also vendor prefix versions but it's irrelevant).
The spinning animation is defined as:
#keyframes spinning {
0% { transform: rotate(0); }
100% { transform: rotate(360deg); }
}
Our designer has put a position: absolute !important attribute to the spinning element. I was trying to position it inside some other element and I've thought that attribute was irrelevant. As soon as I removed position: absolute, the spinner stopped spinning. When I added it again, spinner started spinning again.
I've tried other position values too, it seems that absolute and fixed are working okay (in regards to spinning animation) while relative and static cause the animation to stop.
Why would CSS position attribute affect a spinner animation?
Here is a snippet reproducing the problem:
#keyframes spinning {
0% { transform: rotate(0); }
100% { transform: rotate(360deg); }
}
#first{
position: absolute;
}
#second{
position: relative; /* or don't specify it at all */
}
<div style='background:yellow;width:400px;height:100px;'>
<span id='first' style='animation:spinning 1s infinite linear'>hello</span>
</div>
<div style='background:lime;width:400px;height:100px;'>
<span id='second' style='animation:spinning 1s infinite linear'>hello</span>
</div>
It's because a span is an inline-element by default and so is not affected by transforms.
Setting the position to absolute imparts a block formatting to the span.
Just add display:inline-block:
#keyframes spinning {
0% {
transform: rotate(0);
}
100% {
transform: rotate(360deg);
}
}
div.one {
background: yellow;
width: 400px;
height: 100px;
}
div.two {
background: lime;
width: 400px;
height: 100px;
}
#first {
position: absolute;
animation: spinning 1s infinite linear
}
#second {
position: relative;
/* or don't specify it at all */
animation: spinning 1s infinite linear;
display: inline-block;
}
<div class="one">
<span id='first'>hello</span>
</div>
<div class="two">
<span id='second'>hello</span>
</div>

Transform and Stacking Order

I am trying to understand what is really happening “3d” world of CSS.
I made a simple example
Particularly the code which bugs me the most is:
.back {
background-color: tomato;
transform: rotateY(180deg);
z-index: 1;
}
The thing which is not clear to me is why when you hover over .inner, its background color (gold) is not visible?? If you remove the transform property from .back or if you set the rotateY to 0deg then the gold background color of the .inner is clearly visible.
Why is the transform property of .back changing the stacking order?
Logically it makes sense that children(.front and .back) should appear in front of their parent(.inner).
Also, I would like to know what really happens when you set transform-style to flat? Does that make parent and all of its children collapse into single “unit” where element with highest stacking order takes priority/visibility?
in your code :
.outer {
display: block;
width: 200px;
height: 200px;
border: 2px solid gold;
perspective: 1000px;
padding: 10px;
margin: 0 auto;
}
.inner {
position: relative;
height: 100%;
width: 100%;
transition: transform 2s linear;
transform-style: preserve-3d;
background-color: gold;
backface-visibility: visible;
transform: rotateY(50deg);
}
.sides {
position: absolute;
width: 100%;
height: 100%;
left: 0;
top: 0;
color: white;
backface-visibility: hidden;
}
.front {
background-color: blue;
transform: translateZ(20px)
}
.back {
background-color: tomato;
transform: rotateY(180deg) translateZ(10px);
}
.inner:hover {
transform: rotateY(180deg)
}
<div class="outer">
<div class="inner">
<div class="sides front">Front Side</div>
<div class="sides back">Back Side</div>
</div>
</div>
you are using
transform: rotateY(180deg) translateZ(10px);
The transforms are applied right to left, so first it goes to the front 10px. But after that, it rotates 180deg. (around the transform-origin that is constant). That makes the previous 10px go towards the back instead of to the front.
if the order is the inverse
transform: translateZ(10px) rotateY(180deg);
now the rotation is done first, and so the translation is unafected by it and goes to the front.
and No, sorry, z-index is not a substitute for 3-d transforms, if you want to use 3d transforms, translation is the only way to go ....
In your first example, z-index is useless, as can be seen easily
codepen with z-index removed
This works because you are setting
backface-visibility: hidden;
So only the face that is facing front will be visible

Transform scale working on Chrome but not on Firefox

Once I start animating, on Chrome I get a ripple effect. My circle transform scales up. On Firefox, that exact same animation is ignored for some reason.
$("#animate").click(function() {
$("#square").toggleClass("animate");
$("#fab").toggleClass("ripple");
});
#keyframes ripple {
from {
transform: scale(0)
}
to {
transform: scale(20)
}
}
#square {
position: relative;
width: 300px;
height: 300px;
overflow: hidden;
border: 1px solid red;
transition: background 0.1s linear 0.6s, transform 1s;
transform: rotate(0deg);
}
#fab {
position: absolute;
width: 56px;
height: 56px;
border-radius: 50%;
background: #4FB5AB;
top: 122px;
right: 0;
transform: scale(1);
transition: transform 1s;
}
.ripple {
animation: ripple 1s 0.5s;
transform: scale(20) !important;
/*Duration - delay */
transition: transform 0s 1s !important;
}
.animate {
transform: rotate(90deg) !important;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="square">
<div id="fab"></div>
</div>
<br />
<button id="animate">animate</button>
CodePen Demo
Before I start explaining the problem with your code, here is a word of caution - Do not use transitions and animations together. They generally end up causing problems like the one faced here.
When an animation is specified on an element, it will take complete control over the properties that are being animated unless there is a rule with !important setting. If !important setting is used then that rule takes precedence over the animation. (but unfortunately Chrome and Firefox seem to be handling this case differently).
As per W3C Spec:
CSS Animations affect computed property values. During the execution of an animation, the computed value for a property is controlled by the animation. This overrides the value specified in the normal styling system. Animations override all normal rules, but are overriden by !important rules.
emphasis is mine
In your code, there were two problems and they are as follows:
Within .ripple selector, you were specifying the transition-duration as 0s, which means, there is no transition at all and that the change of transform is an instant one. As explained in the W3C Spec, Firefox seems to be (correctly) giving the control to the rule with !important setting (that is, the transform and transition within .ripple selector) and so it transitions the state change immediately after the specified 1s delay+. Chrome lets animation take control and thus produces the effect you are looking for.
Firefox seems to animate the element quicker than Chrome does and so while a duration of 1s is enough for the animation in Chrome, FF needs it to be 2s to be slower and show the effect.
+ - You can further verify this by removing the !important settings on the rules. Once !important is removed, the animation would take control.
$("#animate").click(function() {
$("#square").toggleClass("animate");
$("#fab").toggleClass("ripple");
});
#keyframes ripple {
from {
transform: scale(0)
}
to {
transform: scale(20)
}
}
#square {
position: relative;
width: 300px;
height: 300px;
overflow: hidden;
border: 1px solid red;
transition: background 0.1s linear 0.6s, transform 1s;
transform: rotate(0deg);
}
#fab {
position: absolute;
width: 56px;
height: 56px;
border-radius: 50%;
background: #4FB5AB;
top: 122px;
right: 0;
transform: scale(1);
transition: transform 1s;
}
#fab.ripple {
animation: ripple 2s 1s;
transform: scale(20);
/*Duration - delay */
transition: transform 1s 1s;
}
#square.animate {
transform: rotate(90deg);
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="square">
<div id="fab"></div>
</div>
<br />
<button id="animate">animate</button>
Finally, please do not use !important unless it is mandatory. Instead just make the selector more specific. In the snippet, I have made it more specific by using the #id.class format.

Flip image and stop at a certain angle

I have this CSS:
-moz-transform: scaleY(-1);
-o-transform: scaleY(-1);
-webkit-transform: scaleY(-1);
transform: scaleY(-1);
filter: FlipV;
-ms-filter: "FlipV";
that flips and image upside down.
All I want is the image to stop when has flipped 90° and so it's invisible.
Is that possible in any way?
If your need is to flip and image by 90 degrees such that it becomes invisible then you should look at using rotate(90deg) transforms (rotateX(90deg) in this case) like in the below snippet.
I am not sure on when you would be making the element become invisible (like :hover, click etc) but if you make it invisible on :hover then put the :hover selector on a container element instead of the image itself. This is because once the image is hovered and becomes invisible due to rotation then the mouse pointer is technically no longer over the image (in other words, hover is no longer applicable). This would mean that the image immediately reverts back to original state automatically.
div {
border: 1px solid #777;
height: 100px;
width: 200px;
}
img {
transition: all 1s;
}
div:hover img {
transform: rotateX(90deg);
}
<div>
<img src="http://lorempixel.com/200/100/nature/1" />
</div>
On the other hand if you are insistent on using scaleY() transform to achieve this effect, then you would have to use scaleY(0) in-order to make the element invisible. scaleY(-1) will always end up at -180deg and there is no way to stop this in the middle.
div {
border: 1px solid #777;
height: 100px;
width: 200px;
}
img {
transition: all 1s;
}
div:hover img {
transform: scaleY(0);
}
<div>
<img src="http://lorempixel.com/200/100/nature/1" />
</div>
http://davidwalsh.name/demo/css-flip.php
Take a look at this demo from great David Walsh :)
I think for you the vertical flip is more interesting
Just change the .front and .back # :hover to 90deg and you get the result you want!

Image shifting/jumping after CSS transition effect with scale transform in Firefox

I have a problem in latest Firefox browser version 34 (system: Windows 7, screen width: 1600px). I made effect with zooming images (in some container) after hover on it. I am using transform: scale(1.1) with transition: transform 0.3s ease-in-out. But when I hover on image, and after image zoom in.. it make some strange 1px-shifting. Some rendering browser bug, but I hope that existing some fix for it.
Most important CSS definition and part of HTML code:
figure {
display: block;
overflow: hidden;
position: relative;
backface-visibility: hidden;
}
figure img {
width: 100%;
transform: scale(1);
transition: transform 0.3s ease-in-out;
}
figure:hover img {
transform: scale(1.1);
}
<figure>
<img class="img-responsive" src="http://lorempixel.com/600/400/fashion/7">
</figure>
Sample with bug is online here: http://templates.silversite.pl/test/jumpingimg/
I saw also that somebody can fix it, but I do not know how, e.g. box "Our recent work" on http://demo.qodeinteractive.com/bridge/
I had a similar problem on my project. All images were position: absolute; and the transform look like that:
figure img{
transform: translate( -50%, 50%) scale(1);
position: absolute;
top: 50%;
left: 50%;
}
figure img:hover{
transform: translate( -50%, 50%) scale(1.1);
}
I replace every scale with scale3d and that solved my problem.
The final styles look like that:
figure img{
transform: translate( -50%, 50%) scale3d(1, 1, 1);
position: absolute;
top: 50%;
left: 50%;
}
figure img:hover{
transform: translate( -50%, 50%) scale3d(1.1, 1.1, 1);
}
Hope that's will fix your problem
On the link that you provided, http://demo.qodeinteractive.com/bridge/ , if you actually go here: http://demo.qodeinteractive.com/bridge/portfolio/gallery-style-condensed/two-columns-grid/ , you can see that, once looking at dev tools, that they apply a margin of "1px" on left/right side
.projects_holder.hover_text.no_space article .image img {
margin: 0 1px;
}
If you disable that style, you'll see the image move as you're describing when hovering on the image.
Therefore, your CSS for the image should be:
figure img {
width: 100%;
transform: scale(1);
transition: transform 0.3s ease-in-out;
display: block; /* (or inline-block) */
margin: 0 1px;
}
I have just run into this same problem now. The solutions here didn't fix the issue, so I'm posting what I did to get this to work.
Like OP I had a container with oveflow hidden and was the same size as the image inside it. The image would scale on hover to create a 'zoom' effect - but when initially starting and ending the transition, the image was "jumping"/growing a tiny bit on the bottom and right-hand side. This made it jumpy and not smooth.
I had calculated the dimensions of my components based off of percentages, which caused them to be non-integers (Chrome). I have a feeling Scale & Scale3d round the pixel values when scaling, which caused this jump. I gave a parent container display:table, which caused all children to have their width/heights be rounded to be an integer value. This fixed the issue for me, and the images now scale smoothly!
7,5 years later it's still an issue and the now solution is will-change css property. Only IE won't get this, but others seems to be doing fine - no more px jumping (edit: on non retina screens).
figure {
display: block;
overflow: hidden;
position: relative;
backface-visibility: hidden;
}
figure img {
width: 100%;
transform: scale(1);
transition: transform 0.3s ease-in-out;
}
figure:hover img {
transform: scale(1.1);
will-change: transform;
}
I just run over the same issue and for me it looks like that the browser corrects the decimal pixel after the scaling is done. Or some how the height and the width doesn't get scaled equals and that gets corrected in the end.
So I think the solution is to use an image with a 1 x 1 ration factor.
So for me the code of the question works fine when I use a the lorempixel with a width and height of 400px.
Let me know if that solves the issue?!
figure {
display: block;
overflow: hidden;
position: relative;
backface-visibility: hidden;
}
figure img {
width: 100%;
transform: scale(1);
transition: transform 0.3s ease-in-out;
}
figure:hover img {
transform: scale(1.1);
}
<figure>
<img class="img-responsive" src="http://lorempixel.com/400/400/fashion/7">
</figure>

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