CSS Star outline - css

Is there any way to make a css star shape outline?
I know you can make a filled in one, with the following css
.star-five {
margin: 50px 0;
position: relative;
display: block;
color: red;
width: 0px;
height: 0px;
border-right: 100px solid transparent;
border-bottom: 70px solid red;
border-left: 100px solid transparent;
-moz-transform: rotate(35deg);
-webkit-transform: rotate(35deg);
-ms-transform: rotate(35deg);
-o-transform: rotate(35deg);
}
.star-five:before{
...
}
.star-five:after {
...
}
Working example here: jsfiddle
But what about a transparent fill with a red outline?

I know this isn't quite the answer you were looking for, but I'm gonna post it anyway. For my knowledge there's no way of doing this with pure CSS. However, in my website I took a more easy approach. I had to style a rating bar with stars. Instead of creating the star with CSS, I simply did this:
<span>☆</span>
You can style this star however you like (and even fill it with the CSS content property).
Hope this help, and looking forward to see the other answers here.

You could use an SVG:
<svg width="320" height="320"><path d="
M 160.000 180.000
L 183.511 192.361
L 179.021 166.180
L 198.042 147.639
L 171.756 143.820
L 160.000 120.000
L 148.244 143.820
L 121.958 147.639
L 140.979 166.180
L 136.489 192.361
L 160.000 180.000
" stroke="#f00" stroke-width="1" fill="none"/></svg>
I used this site to generate it if it helps: http://www.smiffysplace.com/stars.html

Here is a pure CSS solution using the same Fiddle you provided. I just scaled a star in and made it white.
body {
margin: 0px;
}
.star-five {
margin: 50px 0;
position: relative;
display: block;
color: red;
width: 0px;
height: 0px;
border-right: 100px solid transparent;
border-bottom: 70px solid red;
border-left: 100px solid transparent;
-moz-transform: rotate(35deg);
-webkit-transform: rotate(35deg);
-ms-transform: rotate(35deg);
-o-transform: rotate(35deg);
}
.star-five:before {
border-bottom: 80px solid red;
border-left: 30px solid transparent;
border-right: 30px solid transparent;
position: absolute;
height: 10px;
width: 0;
top: -45px;
left: -65px;
display: block;
content: '';
-webkit-transform: rotate(-35deg);
-moz-transform: rotate(-35deg);
-ms-transform: rotate(-35deg);
-o-transform: rotate(-35deg);
}
.star-five:after {
position: absolute;
display: block;
color: red;
top: 3px;
left: -105px;
width: 0px;
height: 0px;
border-right: 100px solid transparent;
border-bottom: 70px solid red;
border-left: 100px solid transparent;
-webkit-transform: rotate(-70deg);
-moz-transform: rotate(-70deg);
-ms-transform: rotate(-70deg);
-o-transform: rotate(-70deg);
content: '';
}
.star-outline>.star-five,
.star-outline>.star-five:before,
.star-outline>.star-five:after {
border-bottom-color: white;
}
.star-outline {
position: absolute;
top: 0px;
left: 0px;
transform: scale(0.9);
}
<div class="star">
<span class="star-five" width="10" height="10">
</span>
<div class="star-outline">
<span class="star-five">
</span>
</div>
</div>

Use below CSS properties:
-webkit-text-stroke-width: 2px;
-webkit-text-stroke-color: red;
Visualization:
Hope this could help ~ RDaksh

Related

How can I create this particular shape?

Is there an easier or better way to create this particular shape/combination of shapes in CSS3 than what am I currently doing? I have tried a few different things already.
The downward facing triangle should be sitting just below the three lines, but I can't seem to get it there.
I want it to look like this:
https://jsfiddle.net/s6bcjzjr/
.triangle-container {
top: 0;
width: 30px;
height: 40px;
position: relative;
border-bottom: 2px solid #e74c3c;
}
.triangle {
position: relative;
margin: auto;
top: 30px;
left: 0;
right: 0;
width: 21px;
height: 21px;
transform: rotate(45deg);
-webkit-transform: rotate(45deg);
-moz-transform: rotate(45deg);
-o-transform: rotate(45deg);
-ms-transform: rotate(45deg);
border-right: 2px solid #e74c3c;
border-bottom: 2px solid #e74c3c;
}
.line {
width: 30px;
position: relative;
border-bottom: 2px solid #e74c3c;
margin-top: 3px;
}
<a href="#" class="open">
<div class="line"></div>
<div class="line"></div>
<div class="line"></div>
<div class="triangle-container">
<div class="triangle"></div>
</div>
</a>
I switch the triangle container's border to top and adjusted the margins
* {
-webkit-box-sizing: border-box;
-moz-box-sizing: border-box;
box-sizing: border-box;
}
.triangle-container {
top: 0;
width: 30px;
height: 40px;
position: relative;
border-top: 2px solid #e74c3c;
margin-top: 3px;
}
.triangle {
position: relative;
margin: auto;
top: -10.5px;
left: 0;
right: 0;
width: 21px;
height: 21px;
transform: rotate(45deg);
-webkit-transform: rotate(45deg);
-moz-transform: rotate(45deg);
-o-transform: rotate(45deg);
-ms-transform: rotate(45deg);
border-right: 2px solid #e74c3c;
border-bottom: 2px solid #e74c3c;
}
.line {
width: 30px;
position: relative;
border-bottom: 2px solid #e74c3c;
margin: 3px 0 0 0;
}
<a href="#" class="open">
<div class="line"></div>
<div class="line"></div>
<div class="line"></div>
<div class="triangle-container">
<div class="triangle"></div>
</div>
</a>
Using SVG:
You can create this easily using SVG. There is nothing complex and all that you would need is three line elements and one path element.
All three line elements have two co-ordinates where (x1,y1) represent the starting point of the line and (x2,y2) represent the ending point of the line.
The path element takes a path (d) and it value can be interpreted as follows:
M5,20 - Move to the point which is 5px to the right of the container and 20px down.
L95,20 - Draw a line from the previous point (5,20) to (95,20).
L50,45 - Draw a line from the previous point (95,20) to (50,45).
z - Close the path. That is, draw a line connecting the point (50,45) and the starting point.
svg {
height: 100px;
width: 50px;
}
line,
path {
stroke: #e74c3c;
stroke-width: 2;
}
path {
fill: none;
stroke-linejoin: bevel;
}
<svg viewBox='0 0 100 100' preserveAspectRatio='none'>
<g id='graphic'>
<line x1='5' y1='5' x2='95' y2='5' />
<line x1='5' y1='10' x2='95' y2='10' />
<line x1='5' y1='15' x2='95' y2='15' />
<path d='M5,20 L95,20 L50,45z' />
</g>
</svg>
Using CSS with single element:
You can achieve the same shape using a single element also with CSS. Below is a sample snippet for the same. Below is an explanation of how the shape is achieved.
The parent anchor tag which has the height and width of the container.
The :before pseudo-element which is positioned absolutely with respect to the container and is 20px tall. The background of this element is a linear-gradient which has the required color for 2px and is transparent for the remaining part. Gradients by default repeat to fill its container and so this single background pattern produces the three lines.
The :after element is again positioned absolutely with respect to the container. This pseudo-element is then rotated such that its left and bottom borders produce angled parts of the triangle. Another linear-gradient background produces the top line of the triangle.
I have calculated height and width of the :after pseudo using Pythagoras theorem. If container is not a square then you have to manually calculate the values.
a {
position: relative;
display: inline-block;
height: 50px;
width: 50px;
}
a:before {
position: absolute;
content: '';
top: 3px;
left: 0px;
height: 20px;
width: 100%;
background: linear-gradient(to bottom, #e74c3c 2px, transparent 2px);
background-size: 100% 5px;
}
a:after {
position: absolute;
content: '';
top: 50%;
left: 50%;
height: calc(50px / 1.414);
width: calc(50px / 1.414);
border-bottom: 2px solid #e74c3c;
border-left: 2px solid #e74c3c;
transform: translateX(-50%) translateY(-50%) rotate(-45deg);
background: linear-gradient(to top right, transparent 46%, #e74c3c 46%, #e74c3c 50%, transparent 50%);
}
<a href='#'></a>
.triangle-container {
top: -35px;
width: 30px;
height: 40px;
position: relative;
border-bottom: 2px solid #e74c3c;
}
https://jsfiddle.net/s6bcjzjr/6/
i've updated your fiddle and now your shape looks perfect. What I did is changed the border-bottom to border-top of the triangle-container, and adjusted height and margin to align the triangle perfectly
here is the fiddle - https://jsfiddle.net/s6bcjzjr/5/
The answer is:
.triangle-container {
top: -36px;
}
See it here:
.triangle-container {
top: -36px;
width: 30px;
height: 40px;
position: relative;
border-bottom: 2px solid #e74c3c;
}
.triangle {
position: relative;
margin: auto;
top: 30px;
left: 0;
right: 0;
width: 21px;
height: 21px;
transform: rotate(45deg);
-webkit-transform: rotate(45deg);
-moz-transform: rotate(45deg);
-o-transform: rotate(45deg);
-ms-transform: rotate(45deg);
border-right: 2px solid #e74c3c;
border-bottom: 2px solid #e74c3c;
}
.line {
width: 30px;
position: relative;
border-bottom: 2px solid #e74c3c;
margin-top: 3px;
}
<a href="#" class="open">
<div class="line"></div>
<div class="line"></div>
<div class="line"></div>
<div class="triangle-container">
<div class="triangle"></div>
</div>
</a>
A one element method using before and after (fiddle):
.down-arrow {
display: inline-block;
position: relative;
width: 30px;
height: 14px;
border-top: 2px solid #e74c3c;
border-bottom: 2px solid #e74c3c;
}
.down-arrow::before {
display: block;
position: absolute;
top: 3px;
right: 0;
left: 0;
height: 3px;
border-top: 2px solid #e74c3c;
border-bottom: 2px solid #e74c3c;
content: '';
}
.down-arrow::after {
display: block;
position: relative;
top: 4px;
left: 0;
right: 0;
width: 21px;
height: 21px;
margin: 0 auto;
transform: rotate(45deg);
-webkit-transform: rotate(45deg);
-moz-transform: rotate(45deg);
-o-transform: rotate(45deg);
-ms-transform: rotate(45deg);
border-right: 2px solid #e74c3c;
border-bottom: 2px solid #e74c3c;
content: '';
}
.triangle-container {
top: 0px;
width: 30px;
height: 1px;
position: relative;
border-top: 2px solid #e74c3c;
margin-top: 3px;
}
.triangle {
position: absolute;
margin: auto;
top: -12px;
left: 0;
right: 0;
width: 21px;
height: 21px;
transform: rotate(45deg);
-webkit-transform: rotate(45deg);
-moz-transform: rotate(45deg);
-o-transform: rotate(45deg);
-ms-transform: rotate(45deg);
border-right: 2px solid #e74c3c;
border-bottom: 2px solid #e74c3c;
}
.line {
width: 30px;
position: relative;
border-bottom: 2px solid #e74c3c;
margin-top: 3px;
}

Drawing angled lines in CSS

What I'm trying to do LOOKS simple, but I can't seem to figure out how to do it.
As you can see in my image there are a couple of red lines that go across the bottom, then bend upwards close to the right side.
Is there a way in CSS to draw a line like this?
You can create angled lines in CSS by using skew transforms (transform: skew(Xdeg)). Below is a sample snippet:
.shape {
height: 50px;
width: 200px;
border-bottom: 2px solid red;
border-right: 2px solid red;
-moz-transform: skew(-45deg);
-webkit-transform: skew(-45deg);
transform: skew(-45deg);
}
<div class="shape"></div>
Double line with one above the content area and one behind it can also be done using a single element (and a couple of pseudos) like in the below snippet:
.shape:before {
position: absolute;
bottom: -5px;
left: -5px;
content: '';
height: 50px;
width: 100%;
border-bottom: 3px solid red;
border-right: 4px solid red;
-webkit-transform: skew(-45deg);
-moz-transform: skew(-45deg);
transform: skew(-45deg);
}
.shape:after {
position: absolute;
content: '';
bottom: -10px;
left: 0px;
height: 55px;
width: 100%;
border-bottom: 3px solid red;
border-right: 4px solid red;
-webkit-transform: skew(-45deg);
-moz-transform: skew(-45deg);
transform: skew(-45deg);
z-index: -1;
}
.shape {
position: relative;
height: 80px;
width: 400px;
background: whitesmoke;
}
<div class="shape">
Some text that goes within the element...
</div>

CSS - style horizontal line

I need to style a horizontal line <hr> like the picture attached. Is there any way to do this with pure css that would also work in IE8?
EDIT: Sorry, I missed your IE8 requirement...this probably won't work there. I apologize. I don't have access to it to check.
You can use the :before and create a box, rotate it, apply some border, absolutely position it and voila, there you have it:
http://jsfiddle.net/v7y1bp9s/1/
HTML:
<div class="container">
<hr class="line"></hr>
</div>
CSS:
.container {
float: left;
width: 100%;
height: 50px;
background-color: #1978a4;
line-height: 50px;
}
hr.line {
border-color: #fff;
position: relative;
}
hr.line:before {
content: '';
height: 10px;
width: 10px;
-webkit-transform: rotate(45deg);
-moz-transform: rotate(45deg);
-o-transform: rotate(45deg);
-ms-transform: rotate(45deg);
transform: rotate(45deg);
position: absolute;
left: 50px;
border-bottom: 1px solid #fff;
border-right: 1px solid #fff;
background-color: #1978a4;
top: -5px;
}

Half hexagon shape with one element

I'm trying to replicate the following shape with no success:
I'm guessing I'll need some :before and :after pseudo elements along with the following css:
#pentagon {
position: relative;
width: 78px;
height:50px;
background:#3a93d0;
}
Using Border Method:
You can do it using the below CSS. The shape is obtained by placing a triangle shape at the bottom of the rectangle using :after pseudo element. The triangular part is achieved using border method.
.pentagon {
height: 50px;
width: 78px;
background: #3a93d0;
position: relative;
}
.pentagon:after {
border: 39px solid #3a93d0;
border-top-width: 15px;
border-color: #3a93d0 transparent transparent transparent;
position: absolute;
top: 50px;
content: '';
}
<div class="pentagon"></div>
Using CSS Transforms:
This approach uses rotate, skewX and hence would need a fully CSS3 compliant browser to work properly. The advantage of this approach is that it allows borders to be added around the shape unlike when using border method. The drawback is that it needs additional calculations for the angles.
It is a modified version of the short triangle method mentioned in this CodePen demo by web-tiki.
.pentagon {
position: relative;
height: 50px;
width: 78px;
background: #3a93d0;
}
.pentagon:before {
position: absolute;
content: '';
top: 12px;
left: 0;
width: 46px;
height: 38px;
background: #3a93d0;
transform-origin: 0 100%;
transform: rotate(29deg) skewX(-30deg);
}
.pentagon.bordered {
background: white;
border: 1px solid #3a93d0;
}
.pentagon.bordered:before {
width: 44px;
height: 37px;
background: white;
border: 1px solid #3a93d0;
border-color: transparent #3a93d0 #3a93d0 transparent;
transform: rotate(29deg) skewX(-30deg);
}
/* Just for demo */
.pentagon {
display: inline-block;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/prefixfree/1.0.7/prefixfree.min.js"></script>
<div class="pentagon"></div>
<div class="pentagon bordered"></div>
Using CSS Skew Transforms:
This approach uses just skew() (along both X and Y axes) and does not need any complex angle calculations. It just needs the dimensions and position of the pseudo-element to be adjusted as the dimension of the parent changes.
.pentagon {
position: relative;
height: 50px;
width: 78px;
border: 1px solid #3a93d0;
border-bottom: none;
background: aliceblue;
}
.pentagon:before {
position: absolute;
content: '';
top: 10px; /* parent height - child height -1px */
left: -1px;
width: 39px;
height: 39px; /* width of parent/2 */
border-right: 1px solid #3a93d0;
border-bottom: 1px solid #3a93d0;
background: aliceblue;
transform-origin: 0 100%;
transform: matrix(1, 0.414213562373095, -1, 0.41421356237309515, 0, 0);
}
<div class="pentagon">
</div>
The above snippet uses matrix transform because as per MDN, the skew(x, y) is removed and should not be used anymore. The Matrix Resolutions site can be used to obtain the equivalent matrix function. The matrix function for rotate(45deg) skew(-22.5deg, -22.5deg) is
matrix(1, 0.414213562373095, -1, 0.41421356237309515, 0, 0).
Using Clip Path:
Here is another approach to creating the pentagon shape with clip-path. Either a pure CSS clip-path or one with inline SVG can be used depending on required browser support. CSS clip-path is supported only by Webkit browsers at present.
IE (all versions) do not support either the CSS or the SVG clip-path.
.pentagon {
position: relative;
width: 75px;
height: calc(75px / 1.414);
background: #3a93d0;
}
.pentagon.css {
-webkit-clip-path: polygon(0% 0%, 0% 66%, 50% 100%, 100% 66%, 100% 0%);
clip-path: polygon(0% 0%, 0% 66%, 50% 100%, 100% 66%, 100% 0%);
}
.pentagon.svg {
-webkit-clip-path: url(#clipper);
clip-path: url(#clipper);
}
.pentagon.bordered:after {
position: absolute;
content: '';
height: calc(100% - 2px);
width: calc(100% - 2px);
left: 1px;
top: 1px;
background: white;
}
.pentagon.css.bordered:after {
-webkit-clip-path: polygon(0% 0%, 0% 66%, 50% 100%, 100% 66%, 100% 0%);
clip-path: polygon(0% 0%, 0% 66%, 50% 100%, 100% 66%, 100% 0%);
}
.pentagon.svg.bordered:after {
-webkit-clip-path: url(#clipper);
clip-path: url(#clipper);
}
/* Just for demo */
.pentagon {
margin: 10px;
}
<svg width="0" height="0">
<defs>
<clipPath id="clipper" clipPathUnits="objectBoundingBox">
<path d="M0,0 0,0.66 0.5,1 1,0.66 1,0z" />
</clipPath>
</defs>
</svg>
<h3>CSS Clip Path</h3>
<div class="pentagon css"></div>
<div class="pentagon bordered css"></div>
<h3>SVG Clip Path</h3>
<div class="pentagon svg"></div>
<div class="pentagon bordered svg"></div>
You can try an alternate approach using transform scaleX and rotate: 45deg;. This makes it very easy to create the bottom part of the shape.
transform: scaleX() rotate(45deg);
Working
*sorry for bad quality gif! :(
Sans border:
Fiddle
#pent{
height: 50px;
width: 100px;
position: relative;
background-color: deepskyblue;
}
#pent:before{
content: '';
position: absolute;
bottom: 0;
left: 0;
width:45px;
height:45px;
-webkit-transform-origin: 0 100%;
-moz-transform-origin: 0 100%;
-ms-transform-origin: 0 100%;
transform-origin: 0 100%;
-webkit-transform: scaleX(1.57) rotate(45deg);
-moz-transform: scaleX(1.57) rotate(45deg);
-ms-transform: scaleX(1.57) rotate(45deg);
transform: scaleX(1.57) rotate(45deg);
background-color: deepskyblue;
}
<div id="pent"></div>
With border :
Fiddle
#pent{
height: 50px;
width: 100px;
position: relative;
border: 1px solid black;
border-bottom: 0;
}
#pent:before{
content: '';
position: absolute;
bottom: 0;
left: -1px;
width:45px;
height:45px;
-webkit-transform-origin: 0 100%;
-moz-transform-origin: 0 100%;
-ms-transform-origin: 0 100%;
transform-origin: 0 100%;
-webkit-transform: scaleX(1.57) rotate(45deg);
-moz-transform: scaleX(1.57) rotate(45deg);
-ms-transform: scaleX(1.57) rotate(45deg);
transform: scaleX(1.57) rotate(45deg);
border: 1px solid black;
border-top: 0;
border-left: 0;
}
<div id="pent"></div>
See a demo - basically it uses css triangles and a pseudo element to give a place for the triangle.
.shape {
position: relative;
width: 78px;
height:30px;
background:#3a93d0;
}
.shape:after {
content: '';
display: block;
position: absolute;
top: 100%;
width: 0;
height: 0;
border-style: solid;
border-width: 25px 39px 0 39px;
border-color: #3a93d0 transparent transparent transparent;
}
<style>
#pentagon
{
position: relative;
width: 54px;
border-width: 40px 18px 0;
border-style: solid;
border-color: #3a93d0;
}
#pentagon:after {
border-color: #3a93d0 transparent transparent;
border-style: solid;
border-width: 21px 45px 0;
content: "";
height: 0;
left: -17px;
position: absolute;
top: 0;
width: 0;
}
</style>
if you dont want to use css3 you can do it with css
only problem is this implementation is not responsive. :(
<pre>
<div class="moregrey"></div>
<div class="arrowdown"></div>
.moregrey
{
width: 1000px;
height: 30px;
background: #3f3f40;
}
.arrowdown
{
border-top:50px solid #3f3f40;
border-left:500px solid transparent;
border-bottom:500px solid transparent;
border-right:500px solid transparent;
display:block;
width:0px;
height:10px;
}
</pre>
<pre>
http://jsfiddle.net/jmqoj5nh/1/
</pre>

Single div horizontal CSS hexagon button

I'd like to create a CSS button in the shape of a hexagon using a single div to keep the markup clean. I've been experimenting with before and after pseudo elements and can do it with the hexagon 'points' at top and bottom but would like to do it with them pointing left and right to fit the rest of my theme. I've got close but I can't get the after pseudo element where I want it. Can anyone fix this?
Here's where I'm up to:
#hex {
background-color:green;
width:100px;
height:100px;
float:left;
display:block;
}
#hex::before {
content:"";
border-top:50px solid red;
border-bottom:50px solid red;
border-right:30px solid blue;
float:left;
}
#hex::after {
content:"";
border-top:50px solid red;
border-bottom:50px solid red;
border-left:30px solid blue;
float:left;
}
and there's a JS Fiddle at http://jsfiddle.net/higginbottom/YKx2M/
try this example: http://jsbin.com/ipaked/6
(tested on Fx and Chrome)
relevant CSS
.hexagon {
position: relative;
width: 124px;
height: 100px;
background: #d8d8d8;
}
.hexagon:after,
.hexagon:before {
position: absolute;
content: "";
z-index: 1;
top: 0;
width: 0px;
background: #fff;
border-top: 50px transparent solid;
border-bottom: 50px transparent solid;
}
.hexagon:before {
left: 0;
border-right: 30px #d8d8d8 solid;
}
.hexagon:after {
right: 0;
border-left: 30px #d8d8d8 solid;
}
(Adjust border-width and size of the hexagon so it can look as you prefer.)
As alternative you can also use a single pseudoelement in which you could show the black hexagon unicode character U+2B21, like in this example: http://jsbin.com/ipaked/7
CSS
.hexagon {
position: relative;
width: 120px;
height: 100px;
line-height: 100px;
text-align: center;
}
.hexagon:before {
position: absolute;
content: "\2B21";
font-size: 160px;
z-index: 1;
width: 100%;
height: 100%;
left: 0;
top: 0;
}
This is probably a better choice (if using a relative font size) so the hexagon can adjust itself when the user increase or decrease the base font-size on his browser.
I'm using clip-path:
.btn {
display: inline-block;
text-align: center;
text-decoration: none;
vertical-align: middle;
user-select: none;
padding: 0.375rem 2rem;
--btn-raise: 1rem;
clip-path: polygon(var(--btn-raise) 0%, calc(100% - var(--btn-raise)) 0%, 100% 50%, calc(100% - var(--btn-raise)) 100%, var(--btn-raise) 100%, 0 50%);
background-color: #fefd64;
text-transform: uppercase;
}
<a class="btn" href="/call">Call call</a>
Try This codepen link http://codepen.io/bherumehta/pen/egdXLv or http://codepen.io/bherumehta/pen/VPKRBG
.hexa{
width:300px;
background:red;
height:70px;
color:#fff;
postion:relative;
border-top:1px solid red;
border-bottom:1px solid red;
}
.hexa-inner{
height:70px;
position:relative;
}
.hexa-inner{
height:70px;
position:relative;
}
.hexa-inner:before{
content: '';
position: absolute;
top: 0;
left: 0;
height: 50%;
width: 50px;
background: red;
-webkit-transform: skew(-45deg, 0deg);
-moz-transform: skew(-45deg, 0deg);
-ms-transform: skew(-45deg, 0deg);
-o-transform: skew(-45deg, 0deg);
transform: skew(-45deg,0deg);
}
.hexa-inner:after {
content: '';
position: absolute;
top: 50%;
left: 0;
height: 50%;
width: 50px;
background: red;
-webkit-transform: skew(-135deg, 0deg);
-moz-transform: skew(-135deg, 0deg);
-ms-transform: skew(-135deg, 0deg);
-o-transform: skew(-135deg, 0deg);
transform: skew(-135deg, 0deg);
}
.left-arrow{
margin-left:-18px;
float:left;
}
.right-arrow{
transform:rotate(180deg);
float:right;
margin-right:-18px
}
.hexa p{
white-space:nowrap;
max-width:100%;
overflow:hidden;
text-overflow:ellipsis;
}
HTML
<div class="hexa">
<div class="hexa-inner left-arrow"> </div>
<div class="hexa-inner right-arrow"> </div>
<p>hexagonhexagonhexagonhexagonhexagonhexagonhexagonhexagonhexago
xagonhexagonhexagonhexagonhexagonhexagonhexagon</p>
</div>

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