R - Weeks of supply - r

I am trying to calculate the number of weeks the inventory on hand will last given the sales projections for a dataset with 10s of million of rows. I have listed the expected output in the last column of the data structure given below. I also attached the implementation of this in Excel.
Logic
Weeksofsupply = Number of weeks the current inventory on hand will last.
example - in the attached image (SKU_CD 222, STORE_CD 33), the inventory on hand is 19, the sales values are
WK1 + WK2 = 15, Wk1 + Wk2 + Wk3 = 24, Which is greater than 19,
So we are picking 2, which the count of Weeks the current inventory will last.
Expected output in the last column
Data = structure(list(
SKU_CD = c(111, 111, 111, 111, 111, 111, 111,111, 111, 111, 111, 111, 222, 222, 222, 222, 222, 222, 222, 222, 222, 222, 222, 222),
STORE_CD = c(22, 22, 22, 22, 22, 22, 22,22, 22, 22, 22, 22, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33),
FWK_CD = c(201627, 201628, 201629, 201630, 201631, 201632,201633, 201634, 201635, 201636, 201637, 201638, 201627, 201628, 201629, 201630, 201631, 201632, 201633, 201634, 201635, 201636, 201637, 201638),
SALES = c(5, 2, 2, 2, 1, 3, 2, 2, 3, 2, 3, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 7, 5),
INVENTORY = c(29, 27, 25, 23, 22, 19, 17, 15, 12, 10, 25, 1, 19, 17, 15, 13, 12,9, 7, 5, 2, 0, 25, 18),
WeeksofSupply = c("11", "10", "9", "8", "8", "6", "5", "4", "3", "2", "Inventory More", "Inventory Less", "2", "2", "1", "1", "1", "Inventory Less", "Inventory Less", "Inventory Less", "Inventory Less", "Inventory Less", "Inventory More", "Inventory More")),
class = c("tbl_df", "tbl", "data.frame"), row.names = c(NA, -24L),
.Names = c("SKU_CD", "STORE_CD", "FWK_CD", "SALES", "INVENTORY", "WeeksofSupply"))
Current Excel Code: (Here the weeks are shown in columns, but it should be rows like shown in the expected output.)
=IF(A2<SUM(B2:K2),SUMPRODUCT(--(SUBTOTAL(9,OFFSET(B2:K2,,,,COLUMN(B2:K2)-
COLUMN(B2)+1))<=A2))+LOOKUP(0,SUBTOTAL(9,OFFSET(B2:K2,,,,COLUMN(B2:K2)-
COLUMN(B2)+1))-B2:K2-A2,(A2-(SUBTOTAL(9,OFFSET(B2:K2,,,,COLUMN(B2:K2)-
COLUMN(B2)+1))-B2:K2))/B2:K2),IF(A2=SUM(B2:K2),COUNT(B2:K2),"Inventory
exceeds forecast"))
I would appreciate any input to implement this efficiently in R. Many Thanks for your time!

For your revised data in long format, you can do the following...
library(dplyr) #for the grouping functionality
#define a function to calculate weeks Supply from Sales and Inventory
weekSup <- function(sales,inv){
sales <- unlist(sales)
inv <- unlist(inv)
n <- length(sales)
weeksup <- rep(NA,n)
for(i in 1:n){
if(i==n | inv[i]<sales[i]){
weeksup[i] <- ifelse(inv[i]>sales[i],NA,inv[i]/sales[i])
} else {
weeksup[i] <- approxfun(cumsum(sales[i:n]),1:(n-i+1))(inv[i])
}
}
#Your 'inventory more' is coded as -1 (a number) to avoid whole column being forced to a character vector
weeksup <- replace(weeksup,is.na(weeksup),-1)
return(weeksup) #for whole weeks, change this to `return(floor(weeksup))`
}
Data2 <- Data %>% group_by(SKU_CD,STORE_CD) %>% mutate(weekSup=weekSup(SALES,INVENTORY))
head(Data2,20)
SKU_CD STORE_CD FWK_CD SALES INVENTORY WeeksofSupply weekSup
<dbl> <dbl> <dbl> <dbl> <dbl> <chr> <dbl>
1 111 22 201627 5 29 11 11.3333333
2 111 22 201628 2 27 10 10.8333333
3 111 22 201629 2 25 9 9.8333333
4 111 22 201630 2 23 8 8.8333333
5 111 22 201631 1 22 8 8.0000000
6 111 22 201632 3 19 6 6.6666667
7 111 22 201633 2 17 5 5.8333333
8 111 22 201634 2 15 4 4.8333333
9 111 22 201635 3 12 3 3.6666667
10 111 22 201636 2 10 2 2.8333333
11 111 22 201637 3 25 Inventory More -1.0000000
12 111 22 201638 6 1 Inventory Less 0.1666667
13 222 33 201627 7 19 2 2.4444444
14 222 33 201628 8 17 2 2.0000000
15 222 33 201629 9 15 1 1.6000000
16 222 33 201630 10 13 1 1.2727273
17 222 33 201631 11 12 1 1.0833333
18 222 33 201632 12 9 Inventory Less 0.7500000
19 222 33 201633 13 7 Inventory Less 0.5384615
20 222 33 201634 14 5 Inventory Less 0.3571429

Here is one way to do it, using the linear interpolation method approxfun...
data$WeeksSupply <- sapply(1:nrow(data),function(i)
approxfun(cumsum(as.vector(c(data[i,2:11]))),1:10)(data$Inventory[i]))
data$WeeksSupply <- replace(data$WeeksSupply,is.na(data$WeeksSupply),
"Inventory Exceeds Forecast")
data
# A tibble: 2 x 12
Inventory Wk1 Wk2 Wk3 Wk4 Wk5 Wk6 Wk7 Wk8 Wk9 Wk10 WeeksSupply
<dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <chr>
1 200 20 15 25 40 35 45 30 50 45 55 6.66666666666667
2 2000 20 15 25 40 35 45 30 50 45 55 Inventory Exceeds Forecast

Related

Find the Maximum Value with respect to another within two data frames (VLOOKUP which returns Max Value) in R

I am trying to find the do a function which is similar to a vlookup in excel but which returns the maximum value and the other values in the same row.
The data frame looks like this:
The data frame which I am dealing with are given below:
dput(Book3)
structure(list(Item = c("ABA", "ABB", "ABC", "ABD", "ABE", "ABF"
)), class = c("tbl_df", "tbl", "data.frame"), row.names = c(NA,
-6L))
dput(Book4)
structure(list(Item = c("ABA", "ABB", "ABC", "ABD", "ABE", "ABF",
"ABA", "ABB", "ABC", "ABD", "ABE", "ABF", "ABA", "ABB", "ABC",
"ABD", "ABE", "ABF"), Max1 = c(12, 68, 27, 17, 74, 76, 78, 93,
94, 98, 46, 90, 5, 58, 67, 64, 34, 97), Additional1 = c(40, 66,
100, 33, 66, 19, 8, 70, 21, 93, 48, 34, 44, 89, 74, 20, 0, 47
), Additional2 = c(39, 31, 85, 58, 0, 2, 57, 28, 31, 32, 15,
22, 93, 41, 57, 81, 95, 46)), class = c("tbl_df", "tbl", "data.frame"
), row.names = c(NA, -18L))
The Expected output for this is given below:
You are looking for slice_max:
library(dplyr)
Book4 %>%
group_by(Item) %>%
slice_max(Max1)
# Item Max1 Additional1 Additional2
# 1 ABA 78 8 57
# 2 ABB 93 70 28
# 3 ABC 94 21 31
# 4 ABD 98 93 32
# 5 ABE 74 66 0
# 6 ABF 97 47 46
Using base R
subset(Book4, Max1 == ave(Max1, Item, FUN = max))
-output
# A tibble: 6 × 4
Item Max1 Additional1 Additional2
<chr> <dbl> <dbl> <dbl>
1 ABE 74 66 0
2 ABA 78 8 57
3 ABB 93 70 28
4 ABC 94 21 31
5 ABD 98 93 32
6 ABF 97 47 46
An alternative base solution that is more resilient to floating-point precision problems (c.f., Why are these numbers not equal?, https://cran.r-project.org/doc/FAQ/R-FAQ.html#Why-doesn_0027t-R-think-these-numbers-are-equal_003f). It also allows two behavior options if there are duplicate max-values:
if you want all of them, use ties.method = "min";
if you want the first (or just one) of them, then ties.method = "first".
Book4[ave(Book4$Max1, Book4$Item, FUN = function(z) rank(-z, ties.method = "first")) == 1,]
# # A tibble: 6 x 4
# Item Max1 Additional1 Additional2
# <chr> <dbl> <dbl> <dbl>
# 1 ABE 74 66 0
# 2 ABA 78 8 57
# 3 ABB 93 70 28
# 4 ABC 94 21 31
# 5 ABD 98 93 32
# 6 ABF 97 47 46
Using R base aggregate + max + merge
> merge(Book4, aggregate(Max1~Item, data = Book4, max), by = c("Item", "Max1"))
Item Max1 Additional1 Additional2
1 ABA 78 8 57
2 ABB 93 70 28
3 ABC 94 21 31
4 ABD 98 93 32
5 ABE 74 66 0
6 ABF 97 47 46

How to remove some variables in R with names that are dates

I have a dataset in R where some of the variable names are dates, see a simplified example of the input data below (in Excel):
What I want to do with this data is to remove some of the columns with names that are dates that are older than or equal to a certain date, e.g. 2019-01-31. See a simplified example of the desired output data below (in Excel):
Now, I am able to achieve this by transposing the data, filtering out rows with a date lower than or equal to 31 January 2019 and finally transposing the data back. However I am wondering whether there is a different way to do this using just the column names without pivoting back and forth?
# Example data to copy and paste into R for easy reproduction of problem:
df <- data.frame (id = c("apples", "pears", "grapes", "tomatoes", "carrots", "cucumber", "rabbit", "cat", "dog"),
type = c("fruit", "fruit", "fruit", "veggies", "veggies", "veggies", "pets", "pets", "pets"),
color = c("red", "green", "purple", "red", "orange", "green", "grey", "black", "brown"),
'2019-04-30' = c(353, 91, 270, 2029, 107, 62, 30, 61, 137),
'2019-03-31' = c(349, 90, 267, 2028, 104, 60, 29, 59, 133),
'2019-02-28' = c(345, 89, 264, 2027, 101, 58, 28, 57, 129),
'2019-01-31' = c(341, 88, 261, 2026, 98, 56, 27, 55, 125),
'2018-12-31' = c(337, 87, 258, 2025, 95, 54, 26, 53, 121),
'2018-11-30' = c(333, 86, 255, 2024, 92, 52, 25, 51, 117),
check.names = FALSE)
We can do this in base R. Your dates are conveniently in YYYY-MM-DD format, which means they will be ordered correctly by the >= and <= operators. We can also use a simple regex to preserve any columns that are not in date format:
df[!grepl('\\d{4}-\\d{2}-\\d{2}', colnames(df)) | colnames(df) >= '2019-02-28']
id type color 2019-04-30 2019-03-31 2019-02-28
1 apples fruit red 353 349 345
2 pears fruit green 91 90 89
3 grapes fruit purple 270 267 264
4 tomatoes veggies red 2029 2028 2027
5 carrots veggies orange 107 104 101
6 cucumber veggies green 62 60 58
7 rabbit pets grey 30 29 28
8 cat pets black 61 59 57
9 dog pets brown 137 133 129
The approach is as follows:
extract the column names
transform to Date if possible and NA if not date like
create boolean vector to filter too old dates and non dates (i.e. NAs in the step before) columns
Sample Data
## sample data frame
m <- matrix(1, 3, 10)
colnames(m) <- c("a", "b", as.character(seq.Date(as.Date("2021-1-1"), length.out = 8, by = "days")))
(d <- as.data.frame(m))
# a b 2021-01-01 2021-01-02 2021-01-03 2021-01-04 2021-01-05 2021-01-06 2021-01-07 2021-01-08
# 1 1 1 1 1 1 1 1 1 1 1
# 2 1 1 1 1 1 1 1 1 1 1
# 3 1 1 1 1 1 1 1 1 1 1
Filter
r <- vapply(names(d), as.Date, numeric(1), optional = TRUE)
d[, is.na(r) | r <= as.Date("2021-1-3")]
# a b 2021-01-01 2021-01-02 2021-01-03
# 1 1 1 1 1 1
# 2 1 1 1 1 1
# 3 1 1 1 1 1
r <- vapply(names(df), as.Date, numeric(1), optional = TRUE)
df[, is.na(r) | r >= as.Date("2019-1-31")]
# id type color 2019-04-30 2019-03-31 2019-02-28 2019-01-31
# 1 apples fruit red 353 349 345 341
# 2 pears fruit green 91 90 89 88
# 3 grapes fruit purple 270 267 264 261
# 4 tomatoes veggies red 2029 2028 2027 2026
# 5 carrots veggies orange 107 104 101 98
# 6 cucumber veggies green 62 60 58 56
# 7 rabbit pets grey 30 29 28 27
# 8 cat pets black 61 59 57 55
# 9 dog pets brown 137 133 129 125
Description
One can re-shape the data to the long format and filter based on the date column.
Data
Same data as provided in the example
df <- data.frame (id = c("apples", "pears", "grapes", "tomatoes", "carrots", "cucumber", "rabbit", "cat", "dog"),
type = c("fruit", "fruit", "fruit", "veggies", "veggies", "veggies", "pets", "pets", "pets"),
color = c("red", "green", "purple", "red", "orange", "green", "grey", "black", "brown"),
'2019-04-30' = c(353, 91, 270, 2029, 107, 62, 30, 61, 137),
'2019-03-31' = c(349, 90, 267, 2028, 104, 60, 29, 59, 133),
'2019-02-28' = c(345, 89, 264, 2027, 101, 58, 28, 57, 129),
'2019-01-31' = c(341, 88, 261, 2026, 98, 56, 27, 55, 125),
'2018-12-31' = c(337, 87, 258, 2025, 95, 54, 26, 53, 121),
'2018-11-30' = c(333, 86, 255, 2024, 92, 52, 25, 51, 117),
check.names = FALSE)
Solution
library(dplyr)
library(tidyr)
df %>%
tidyr::pivot_longer(cols = !c(id, type, color), names_to = 'date', values_to = 'value') %>%
dplyr::mutate(date = as.Date(date, format = '%Y-%m-%d')) %>%
dplyr::filter( date >= as.Date('2019-01-31')) %>%
tidyr::pivot_wider(names_from = 'date', values_from = 'value')
Desired output
id type color `2019-04-30` `2019-03-31` `2019-02-28` `2019-01-31`
<chr> <chr> <chr> <dbl> <dbl> <dbl> <dbl>
1 apples fruit red 353 349 345 341
2 pears fruit green 91 90 89 88
3 grapes fruit purple 270 267 264 261
4 tomatoes veggies red 2029 2028 2027 2026
5 carrots veggies orange 107 104 101 98
6 cucumber veggies green 62 60 58 56
7 rabbit pets grey 30 29 28 27
8 cat pets black 61 59 57 55
9 dog pets brown 137 133 129 125

Splitting one column into two columns using data wrangling with R

I would really appreciate your help in using R for data wrangling. I have a data where I want to split one column (variable) into two whenever applicable as conditioned by other variables. For example, as per the sample below, the data represents reactions time measures (RT1 and RT2) of some words (item) that appear in different times of reading (block). I want to see if RT1 and RT2 values in block 3, 4, and 5 are correlated with RT1 and RT2 values of the same item at block 1. The target items that appeared in block 1 and re-appeared in subsequent blocks are coded as 'EI' in the column 'condition', whereas items coded as 'E' or 'I' appeared only once.
dput(d1)
structure(list(RECORDING_SESSION_LABEL = c(26, 26, 26, 26, 26,
26, 26, 26), RT1 = c(5171, 3857, 3447, 314, 460, 731, 957, 1253
), RT2 = c(357, 328, 122, 39, 86, 132, 173, 215), item = c("foreign",
"detailed", "large", "foreign", "foreign", "large", "large",
"disputable"), block = c(1, 1, 1, 3, 4, 3, 4, 3), condition = c("EI",
"E", "EI", "EI", "EI", "EI", "EI", "I")), row.names = c(NA, -8L
), class = c("tbl_df", "tbl", "data.frame"))
Where a sample of the data would look like this:
> d1
# A tibble: 8 x 6
RECORDING_SESSION_LABEL RT1 RT2 item block condition
<dbl> <dbl> <dbl> <chr> <dbl> <chr>
1 26 5171 357 foreign 1 EI
2 26 3857 328 detailed 1 E
3 26 3447 122 large 1 EI
4 26 314 39 foreign 3 EI
5 26 460 86 foreign 4 EI
6 26 731 132 large 3 EI
7 26 957 173 large 4 EI
8 26 1253 215 disputable 3 I
In order to present in a format that R would understand, the target data frame I want to achieve would be similar to the one below (where the highlighted columns should be added). Rows in blanks at these columns represent items which do not appear repetitively (condition is not coded as 'EI') ; therefore, they are irrelevant and should be coded as 'NA'.
dput(d2)
structure(list(RECORDING_SESSION_LABEL = c(26, 26, 26, 26, 26,
26, 26, 26), `RT 1` = c(5171, 3857, 3447, 314, 460, 731, 957,
1253), RT2 = c(357, 328, 122, 39, 86, 132, 173, 215), item = c("foreign",
"detailed", "large", "foreign", "foreign", "large", "large",
"disputable"), block = c(1, 1, 1, 3, 4, 3, 4, 3), condition = c("EI",
"E", "EI", "EI", "EI", "EI", "EI", "I"), `RT 1_at_block1` = c(NA,
NA, NA, 5171, 5171, 3447, 3447, NA), RT2_at_block1 = c(NA, NA,
NA, 357, 357, 122, 122, NA)), row.names = c(NA, -8L), class = c("tbl_df",
"tbl", "data.frame"))
And a sample of the data format targeted would look like this:
> d2
# A tibble: 8 x 8
RECORDING_SESSI~ `RT 1` RT2 item block condition `RT 1_at_block1`
<dbl> <dbl> <dbl> <chr> <dbl> <chr> <dbl>
1 26 5171 357 fore~ 1 EI NA
2 26 3857 328 deta~ 1 E NA
3 26 3447 122 large 1 EI NA
4 26 314 39 fore~ 3 EI 5171
5 26 460 86 fore~ 4 EI 5171
6 26 731 132 large 3 EI 3447
7 26 957 173 large 4 EI 3447
8 26 1253 215 disp~ 3 I NA
# ... with 1 more variable: RT2_at_block1 <dbl>
> head(d2)
# A tibble: 6 x 8
RECORDING_SESSION_LABEL `RT 1` RT2 item block condition `RT 1_at_block1` RT2_at_block1
<dbl> <dbl> <dbl> <chr> <dbl> <chr> <dbl> <dbl>
1 26 5171 357 foreign 1 EI NA NA
2 26 3857 328 detailed 1 E NA NA
3 26 3447 122 large 1 EI NA NA
4 26 314 39 foreign 3 EI 5171 357
5 26 460 86 foreign 4 EI 5171 357
6 26 731 132 large 3 EI 3447 122
Thanks in advance for any help.
A possible solution using dplyr:
d1 <- structure(list(RECORDING_SESSION_LABEL = c(26, 26, 26, 26, 26, 26, 26, 26),
RT1 = c(5171, 3857, 3447, 314, 460, 731, 957, 1253),
RT2 = c(357, 328, 122, 39, 86, 132, 173, 215),
item = c("foreign", "detailed", "large", "foreign", "foreign", "large", "large", "disputable"),
block = c(1, 1, 1, 3, 4, 3, 4, 3), condition = c("EI", "E", "EI", "EI", "EI", "EI", "EI", "I")),
row.names = c(NA, -8L), class = c("tbl_df", "tbl", "data.frame"))
library(dplyr)
d2 <- d1 %>%
left_join(d1 %>% filter(block == 1) %>% select(RECORDING_SESSION_LABEL, item, RT1_at_block1 = RT1)) %>%
left_join(d1 %>% filter(block == 1) %>% select(RECORDING_SESSION_LABEL, item, RT2_at_block1 = RT2))
After that, d2 looks like this:
RECORDING_SESSION_LABEL RT1 RT2 item block condition RT1_at_block1 RT2_at_block1
<dbl> <dbl> <dbl> <chr> <dbl> <chr> <dbl> <dbl>
1 26 5171 357 foreign 1 EI 5171 357
2 26 3857 328 detailed 1 E 3857 328
3 26 3447 122 large 1 EI 3447 122
4 26 314 39 foreign 3 EI 5171 357
5 26 460 86 foreign 4 EI 5171 357
6 26 731 132 large 3 EI 3447 122
Edit: Adding a mutate if you want to set the values for block 1 to NA:
d2 <- d1 %>%
left_join(d1 %>% filter(block == 1) %>% select(RECORDING_SESSION_LABEL, item, RT1_at_block1 = RT1)) %>%
left_join(d1 %>% filter(block == 1) %>% select(RECORDING_SESSION_LABEL, item, RT2_at_block1 = RT2)) %>%
mutate(RT1_at_block1 = ifelse(block == 1, NA, RT1_at_block1),
RT2_at_block1 = ifelse(block == 1, NA, RT2_at_block1))

Need to create a variable based on the equality of other variables

I have a dataset called CSES (Comparative Study of Electoral Systems) where each row corresponds to an individual (one interview in a public opinion survey), from many countries, in many different years .
I need to create a variable which identifies the ideology of the party each person voted, as perceived by this same person.
However, the dataset identifies this perceived ideology of each party (as many other variables) by letters A, B, C, etc. Then, when it comes to identify WHICH PARTY each person voted for, it has a UNIQUE CODE NUMBER, that does not correspond to these letters across different years (i.e., the same party can have a different letter in different years – and, of course, it is never the same party across different countries, since each country has its own political parties).
Fictitious data to help clarify, reproduce and create a code:
Let’s say:
country = c(1,1,1,1,2,2,2,2,3,3,3,3)
year = c (2000,2000,2004,2004, 2002,2002,2004,2008,2000,2000,2000,2000)
party_A_number = c(11,11,12,12,21,21,22,23,31,31,31,31)
party_B_number = c(12, 12, 11, 11, 22,22,21,22,32,32,32,32)
party_C_number = c(13,13,13,13,23,23,23,21,33,33,33,33)
party_voted = c(12,13,12,11,21,24,23,22,31,32,33,31)
ideology_party_A <- floor(runif (12, min=1, max=10))
ideology_party_B <- floor(runif (12, min=1, max=10))
ideology_party_C <- floor(runif (12, min=1, max=10))
Let’s call the variable I want to create “ideology_voted”:
I need something like:
IF party_A_number == party_voted THEN ideology_voted = ideology_party_A
IF party_B_number == party_voted, THEN ideology_voted == ideology_party_B
IF party_C_number == party_voted, THEN ideology_voted == ideology_party_C
The real dataset has 9 letters for (up to) 9 main parties in each country , dozens of countries and election-years. Therefore, it would be great to have a code where I could iterate through letters A-I instead of “if voted party A, then …; if voted party B then….”
Nevertheless, I am having trouble even when I try longer, repetitive codes (one transformation for each party letter - which would give me 8 lines of code)
library(tidyverse)
df <- tibble(
country = c(1, 1, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3),
year = c(2000, 2000, 2004, 2004, 2002, 2002, 2004, 2008, 2000, 2000, 2000, 2000),
party_A_number = c(11, 11, 12, 12, 21, 21, 22, 23, 31, 31, 31, 31),
party_B_number = c(12, 12, 11, 11, 22, 22, 21, 22, 32, 32, 32, 32),
party_C_number = c(13, 13, 13, 13, 23, 23, 23, 21, 33, 33, 33, 33),
party_voted = c(12, 13, 12, 11, 21, 24, 23, 22, 31, 32, 33, 31),
ideology_party_A = floor(runif (12, min = 1, max = 10)),
ideology_party_B = floor(runif (12, min = 1, max = 10)),
ideology_party_C = floor(runif (12, min = 1, max = 10))
)
> df
# A tibble: 12 x 9
country year party_A_number party_B_number party_C_number party_voted ideology_party_A ideology_party_B
<dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl>
1 1 2000 11 12 13 12 9 3
2 1 2000 11 12 13 13 2 6
3 1 2004 12 11 13 12 3 8
4 1 2004 12 11 13 11 7 8
5 2 2002 21 22 23 21 2 7
6 2 2002 21 22 23 24 8 2
7 2 2004 22 21 23 23 1 7
8 2 2008 23 22 21 22 7 7
9 3 2000 31 32 33 31 4 3
10 3 2000 31 32 33 32 7 5
11 3 2000 31 32 33 33 1 6
12 3 2000 31 32 33 31 2 1
# ... with 1 more variable: ideology_party_C <dbl>
It seems you're after conditioning using case_when:
ideology_voted <- df %>% transmute(
ideology_voted = case_when(
party_A_number == party_voted ~ ideology_party_A,
party_B_number == party_voted ~ ideology_party_B,
party_C_number == party_voted ~ ideology_party_C,
TRUE ~ party_voted
)
)
> ideology_voted
# A tibble: 12 x 1
ideology_voted
<dbl>
1 3
2 7
3 3
4 8
5 2
6 24
7 8
8 7
9 4
10 5
11 6
12 2
Note that the evaluation of case_when is lazy, so the first true condition is used (if it happens that more than one is actually true, say).

transform matrix such that a factor becomes rowname

I have the following data - it is a dump from a normalized database, but I can not access the database, and the database maintainer insists that this is not necessary.
The obs variable is the unique observation id, a.k.a. the one to "pivot" around
Specifically, I want to go from this olddata to the newdata data frame below:
> olddata
species obs variable value
3 ADFA 1 mean 4
4 ADFA 1 lat 118
5 ADFA 1 lon 49
6 ADFA 1 masl 74
96 HODO 8 mean 18
97 HODO 8 lat 120
98 HODO 8 lon 45
99 HODO 8 masl 36
189 HODO 9 mean 34
190 HODO 9 lat 126
191 HODO 9 lon 12
192 HODO 9 masl 35
I would like to reshape this data frame to look like:
> newdata
species obs mean lat lon masl
1 ADFA 1 4 118 49 74
2 HODO 8 18 120 45 36
3 HODO 9 34 126 12 35
Disclaimer: this has likely been asked before but I am unable to find the question among the many questions related to transforming data frames / matrices
Here are the dataframes for use when reproducing this issue:
olddata <- structure(list(species = c("ADFA", "ADFA", "ADFA", "ADFA", "HODO",
"HODO", "HODO", "HODO", "HODO", "HODO", "HODO", "HODO"), obs = c(1,
1, 1, 1, 8, 8, 8, 8, 9, 9, 9, 9), variable = c("mean", "lat",
"lon", "masl", "mean", "lat", "lon", "masl", "mean", "lat", "lon",
"masl"), value = c(4, 118, 49, 74, 18, 120, 45, 36, 34, 126,
12, 35)), .Names = c("species", "obs", "variable", "value"),
row.names = c("1", "2", "3", "4", "5", "6", "7", "8", "9", "10",
"11", "12"), class = "data.frame")
newdata <- structure(list(species = c("ADFA", "HODO", "HODO"), obs = c(1,
8, 9), mean = c(4, 18, 34), lat = c(118, 120, 126), lon = c(49,
45, 12), masl = c(74, 36, 35)), .Names = c("species", "obs",
"mean", "lat", "lon", "masl"), row.names = c(NA, -3L),
class = "data.frame")
Here is an example:
> library(reshape2)
> dcast(olddata, species+obs~variable)
species obs lat lon masl mean
1 ADFA 1 118 49 74 4
2 HODO 8 120 45 36 18
3 HODO 9 126 12 35 34
library(reshape2)
dcast(olddata,species+obs~variable)

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