Using Serial.print and digitalWrite in Same Arduino Script - arduino

Question

I am using an Arduino Uno and Windows 7. My goal is to have an LED light that blinks, and when it blinks, it prints out "Blink" to the serial monitor.
When I run the code below, I am able to print out "Blink" to the serial monitor every 2 seconds, however, the light remains constantly on. When I remove the line
Serial.begin(9600);
the lights will blink, but nothing will print. The code I am running is as follows:
int LED3 = 0;
void setup() {
// When I comment out the line below, the lights flash as intended, but
// nothing prints. When I have the line below not commented out,
// printing works, but the lights are always on (ie do not blink).
Serial.begin(9600); // This is the line in question.
pinMode (LED3, OUTPUT);
}
void loop() {
Serial.println("Blink");
digitalWrite (LED3, HIGH);
delay(1000);
digitalWrite (LED3, LOW);
delay(1000);
}
I am unclear on what causes this behavior and would appreciate an explanation of why this occurs and how to avoid this problem. Thank you!

Answer 1

what causes this behavior ?
Pins 0 and 1 are used for serial communications. It's really not possible to use pins 0 and 1 for external circuitry and still be able to utilize serial communications or to upload new sketches to the board.
From the Arduino Serial reference documentation:
Serial is used for communication between the Arduino board and a computer or other devices. All Arduino boards have at least one serial port (also known as a UART or USART): Serial. It communicates on digital pins 0 (RX) and 1 (TX) as well as with the computer via USB. Thus, if you use them in functions in your sketch, you cannot also use pins 0 and 1 for digital input or output.
Just think it this way how can a pin act serial and digital simultaneously ? Yeah that's what you are trying to do !! . You set pin to serial at a baud rate and then you used it for making LED blink.
So, when you do serial.begin(9600); it Sets the data rate in bits per second (baud) for serial data transmission to 9600.Thus you used serial pins in this function, after that you cannot use pins 0 and 1 for digital input or output ( like an LED ). when you comment serial.begin(9600); your pins are free to use and thus you obtain the output.
how to avoid this problem ?
Change the LED from pin 0 to digital pins.
The following code will obtain the result that you expect (I used pin 7 in it) :
int LED3 = 7; //I have changed pin to 7 ( you can use any except 0 and 1 )
void setup() {
// When I comment out the line below, the lights flash as intended, but
// nothing prints. When I have the line below not commented out,
// printing works, but the lights are always on (ie do not blink).
Serial.begin(9600); // This is the line in question.
pinMode (LED3, OUTPUT);
}
void loop() {
Serial.println("Blink");
digitalWrite (LED3, HIGH);
delay(1000);
digitalWrite (LED3, LOW);
delay(1000);
}

Answer 2

The Arduino is using pins 0 and 1 for serial communications.
Pin 0 is RX and 1 is TX, so when you are trying to flash the LED also connected to pin 0, the two start stomping all over each other.
Try to move the LED to a different pin and update your sketch to match, and it should start working.
This page contains information on the Arduino serial connection: https://www.arduino.cc/en/Reference/Serial
Happy hacking