Removing the special symbols in data.frame column values - r

Question

I have two data frame each with a column Name
df1:
name
#one2
!iftwo
there_2_go
come&go
df1 = structure(list(name = c("#one2", "!iftwo", "there_2_go", "come&go")),.Names = c("name"), row.names = c(NA, -4L), class = "data.frame")
df2:
name
One2
IfTwo#
there-2-go
come.go
df2 = structure(list(name = c("One2", "IfTwo#", "there-2-go", "come.go")),.Names = c("name"), row.names = c(NA, -4L), class = "data.frame")
Now to compare the two data frames for inequality is cumbersome because of special symbols using %in%. To remove the special symbols using stringR can be useful. But how exactly we can use stringR functions with %in% and display the mismatch between them
have already done the mutate() to convert all in lowercasestoLower()as follows
df1<-mutate(df1,name=tolower(df1$name))
df2<-mutate(df2,name=tolower(df2$name))
Current output of comparison:
df2[!(df2 %in% df1),]
[1] "one2" "iftwo#" "there-2-go" "come.go"
Expected output as essentially the contents are same but with special symbols:
df2[!(df2 %in% df1),]
character(0)
Question : How do we ignore the symbols in the contents of the Frame

Answer 1

Here it is in a function,
f1 <- function(df1, df2){
i1 <- tolower(gsub('[[:punct:]]', '', df1$name))
i2 <- tolower(gsub('[[:punct:]]', '', df2$name))
d1 <- sapply(i1, function(i) grepl(paste(i2, collapse = '|'), i))
return(!d1)
}
f1(df, df2)
# one2 iftwo there2go comego
# FALSE FALSE FALSE FALSE
#or use it for indexing,
df2[f1(df, df2),]
#character(0)