I am trying to use printf to align some columns up I am not very familiar with the syntax of the printf command so I will give an explanation of what I want it to do
printf("%-15s %-15s %25s\n", Fname, Lname, Num)
I want to create 3 columns one called "Fname" one called "Lname" and one called "Num"
I want the Fname column to be left aligned and 15 spaces long, same with the Lname column I don't care about alignment in the Num column, but I want it to be slightly longer at 25 characters
This is my error
Syntax error near unexpected token `"%-15s %-15s %25s\n",'
You dont need the brackets to enclose the statement.
Also, i guess that you may need to be handling Lname, Fname,Num as variables too, so you would need to correct this also.
Correct syntax:
printf "%-15s %-15s %25s\n" $Fname, $Lname, $Num
Related
I am trying to extract the following from the text field using Regrex in Oracle.
For example
"This is example,
and this really a example :h,j,j,j,j,
l //Updated question , as this letter is on the next line
now this is a disease:yes"
I am expecting a result as h,j,j,j,j,l, but if I use
REGEXP_SUBSTR(text_field,'example :[^:]+,') AS Result
I am getting example:h,j,j,j,j
But I am not getting the last letter 'l' like above and I am guessing that's because it's on the next line.Also, if I want the string "disease:yes" only, that will be so helpful as well. Thank you much!
The result you are getting is because your pattern includes the word 'example' and ends with a comma, leaving out the ending 'l'. Try this form instead. Note the example is shown using a Common table Expression (CTE). The WITH statement creates the table called tbl which just sets up test data, kind of like a temp table. This is also a great way to set up data when asking a question. This form of the REGEXP_SUBSTR() function uses a captured group, which is the set of characters after the string 'example:' until the end of that line in the multi-line field. From this you should be able to get the other string you are after. Give it a go.
WITH tbl(text_field) AS (
SELECT 'This is example,
and this really a example :h,j,j,j,j,l
now this is a disease:yes' FROM dual
)
SELECT REGEXP_SUBSTR(text_field,'example :(.*)', 1, 1, NULL, 1) AS Result
FROM tbl;
RESULT
-----------
h,j,j,j,j,l
1 row selected.
Edit based on new info. Since that last letter could be on it's own line, you'll need to allow for the newline. Use the 'n' flag to REGEXP_REPLACE() which allows the newline to match in the usage of the dot (match any character) symbol in regex. We switch to REGEXP_REPLACE as we'll need to return multiple capture groups. Here the WITH sets up 2 rows, one with an embedded newline in the data and one without. The capture groups are (going left to right) 1-the data after "example :" and ending in a comma, 2-the optional newline and 3-the next single character. Then replace the entire data with captured groups 1 and 3 (leaving out the newline).
NOTE this is very specific to the case of only 1 character on the following line.
WITH tbl(ID, text_field) AS (
SELECT 1, 'This is example,
and this really a example :h,j,j,j,j,
l
now this is a disease:yes' FROM dual UNION ALL
SELECT 2, 'This is example,
and this really a example :h,j,j,j,j,l
now this is a disease:yes' FROM dual
)
SELECT ID,
REGEXP_REPLACE(text_field, '.*example :(.*,)('||CHR(10)||')?(.).*', '\1\3', 1, 1, 'n') AS Result
FROM tbl;
ID RESULT
---------- ------------
1 h,j,j,j,j,l
2 h,j,j,j,j,l
2 rows selected.
My data is string like:
'湯姆 is a boy.'
or '梅isagirl.'
or '約翰,is,a,boy.'.
And I want to split the string and only choose the Chinese name.
In R, I can use the command
tmp=strsplit(string,[A-z% ])
unlist(lapply(tmp,function(x)x[1]))
And then getting the Chinese name I want.
But in PostgreSQL
select regexp_split_to_array(string,'[A-z% ]') from db.table
I get a array like {'湯姆','','',''},{'梅','','',''},...
And I don't know how to choose the item in the array.
I try to use the command
select regexp_split_to_array(string,'[A-z% ]')[1] from db.table
and I get an error.
I don't think that regexp_split_to_array is the appropriate function for what you are trying to do here. Instead, use regexp_replace to selectively remove all ASCII characters:
SELECT string, regexp_replace(string, '[[:ascii:]~:;,"]+', '', 'g') AS name
FROM yourTable;
Demo
Note that you might have to adjust the set of characters to be removed, depending on what other non Chinese characters you expect to have in the string column. This answer gives you a general suggestion for how you might proceed here.
I need to replace single quotes in a string of numbers and use in a WHERE IN clause. for example, I have
WHERE Group_ID IN (''4532','3422','1289'')
The criteria within parenthesis is being passed as a parameter, so I have no control over that. I tried using :
WHERE Group_ID IN (REGEXP_REPLACE(''4532','3422','1289'', '[']', ' ',1,0,i))
also tried using OReplace
WHERE Group_ID IN (OReplace(''4532','3422','1289'', '[']', ' '))
but get the same error:
[Teradata Database] [3707] Syntax error, expected something like ','
between a string or a Unicode character literal and the integer '4532'.
Please suggest how to remove the single enclosing quotes or even removing all single quotes should work as well.
The string ''4532','3422','1289'' you are using is incorrect because it contains non-escaped single quotes. This is a syntax error in SQL. In this particular form, no matter what function you use to fix it or which RDBMS you use, it will result in error with standard SQL.
Functions in the SQL cannot fix syntax errors. REGEXP_REPLACE and OReplace never get executed because the query never enters the execution state. It never goes past the SQL syntax parser.
To see the error from perspective of the SQL parser, you may break the string in to multiple parts
'' -- SQL Parser sees this as a starting and ending quote and hence an empty string
4532 -- Now comes what appears to SQL parser as an integer value
',' -- Now this is a pair of quotes containing a single comma
3422 -- Again an integer
',' -- Again a comma
1289 -- Again integer
'' -- Again emtpy string
This amalgam of strings and numbers will not mean anything to the SQL parser and will result in an error.
Fix
The fix is to properly escape the data. Single quotes must be escaped using another preceding single quote. So correct string in this scenario becomes '''4532'',''3422'',''1289'''
Another thing is that the OReplace usage (once syntax is fixed) is like OReplace(yourStringValueHere, '''', ' ')) Observe the usage of escaped single quote here. Two outer quotes are for the string start and end. First inner quote is the escape character and second inner quote is the actual data passed to the function.
I have a mySQL column called description and I have several sentences in this column. For example: "John ran down a hill. He was tired. John went to get water." I would like a line break after each sentence so that it outputs like:
John went to get water.
He was tired.
John went to get water.
I'm using a SQLite DB Browser (http://sqlitebrowser.org/). I thought I could do line breaks with: "John ran down a hill. \n" but unfortunately it outputs the \n as well as the "". Can anyone help me with these line breaks? Thanks!
SQLite doesn't have string escaping logics. You have to concatenate the newline char using another way, like the char(10) function or typing it in exadecimal: x'0a'. Remember that the character 10 is the newLine for windows architectures.
Just use a query like this (to update all the rows):
update tabel_name set "description" =
replace("description", '.', '.' || x'0a')
If you want to edit a specific row add a WHERE clause:
update tabel_name set "description" =
replace("description", '.', '.' || x'0a')
WHERE "rowid" = 1
The || is the concatenation operator in SQLite.
There is table column containing file names: image1.jpg, image12.png, script.php, .htaccess,...
I need to select the file extentions only. I would prefer to do that way:
SELECT DISTINCT SUBSTR(column,INSTR('.',column)+1) FROM table
but INSTR isn't supported in my version of SQLite.
Is there way to realize it without using INSTR function?
below is the query (Tested and verified)
for selecting the file extentions only. Your filename can contain any number of . charenters - still it will work
select distinct replace(column_name, rtrim(column_name,
replace(column_name, '.', '' ) ), '') from table_name;
column_name is the name of column where you have the file names(filenames can have multiple .'s
table_name is the name of your table
Try the ltrim(X, Y) function, thats what the doc says:
The ltrim(X,Y) function returns a string formed by removing any and all characters that appear in Y from the left side of X.
List all the alphabet as the second argument, something like
SELECT ltrim(column, "abcd...xyz1234567890") From T
that should remove all the characters from left up until .. If you need the extension without the dot then use SUBSTR on it. Of course this means that filenames may not contain more that one dot.
But I think it is way easier and safer to extract the extension in the code which executes the query.