Sed - remove last two character quotes and comma - unix

Question

i wanted to keep only the 10.100.52.11 and delete everything else, 10.100.52.11 keeps changing so i don't want to hard code it
The original output was as below
"PrivateIpAddress": "10.100.52.111",
I tried the below command and removed "PrivateIpAddress": "
sudo aws ec2 describe-instances --filter Name=tag:Name,Values=bip-spark-es-worker1 |grep PrivateIpAddress |head -1|sed 's/^[ ^t]*\"PrivateIpAddress\"[:]* \"//g'
so the output for the above command now is
10.100.52.111",
I want to delete even the ending quotes and comma.
I tried with ["].$ and also \{2\}.$ did not work.
Please help.

Answer 1

Let sed do all the work. You don't need grep or head:
sed -n '/"PrivateIpAddress": /{s///; s/[",]//g; p; q}'

Answer 2

If content within " do not have " themselves,
grep PrivateIpAddress |head -1|sed 's/^[ ^t]*\"PrivateIpAddress\"[:]* \"//g'
can be replaced with
awk -F\" '/PrivateIpAddress/{print $4; exit}'
-F\" use " as field separator
/PrivateIpAddress/ if line matches this string
print $4 print 4th field which is 10.100.52.111 for given sample
exit will quit as only first match is required

Answer 3

some awk proposals
echo '"PrivateIpAddress": "10.100.52.111",'| awk -F: '{print substr($2,3,13)}'
10.100.52.111
echo '"PrivateIpAddress": "10.100.52.111",'| awk -F\" '{print $4}'
10.100.52.111

Answer 4

Alternative :
$ echo "\"PrivateIpAddress\": \"10.100.52.111\", "
"PrivateIpAddress": "10.100.52.111",
$ echo "\"PrivateIpAddress\": \"10.100.52.111\", " |grep -Po '(\d+[.]){3}\d+'
10.100.52.111
$ echo "\"PrivateIpAddress\": \"10.100.52.111\", " |grep -Eo '([[:digit:]]+[.]){3}[[:digit:]]+'
10.100.52.111