Am running the project on the visual studio 2015, When I tried to read the PDF its giving me the following error;
Access to the path 'E:\FILE\FILEUPLOAD\InnerFile\File' is denied.
Function Defination
var cd = new System.Net.Mime.ContentDisposition { FileName = "PDF.pdf", Inline = true };
string contentType = MimeMapping.GetMimeMapping("PDF.pdf");
Response.AppendHeader("Content-Disposition", cd.ToString());
var innerPath = "InnerFile/File" ;
FileInfo fi = new FileInfo(PDFUploadRootPath + innerPath + "/PDF.pdf");
byte[] bytes = System.IO.File.ReadAllBytes(PDFUploadRootPath + innerPath);
return File(bytes, contentType);
NOTE:
Given Full permission to user
Physically File Exists
I dont understand what to do now please help!
Your FileInfo instance indeed references 'E:\FILE\FILEUPLOAD\InnerFile\File\PDF.pdf':
FileInfo fi = new FileInfo(PDFUploadRootPath + innerPath + "/PDF.pdf");
but when trying to read the file contents you forgot the file name and only use the path 'E:\FILE\FILEUPLOAD\InnerFile\File':
byte[] bytes = System.IO.File.ReadAllBytes(PDFUploadRootPath + innerPath);
Thus, also add the file name for reading all file bytes:
byte[] bytes = System.IO.File.ReadAllBytes(PDFUploadRootPath + innerPath + "/PDF.pdf");
Furthermore, as others have mentioned in comments, you should really use Path.Combine to glue path parts together, not simple string concatenation...
Try using FileStream instead of byte array for reading the pdf file.
FileStream templateFileStream = File.OpenRead(filePath);
return templateFileStream;
Also check (through code) if user has write permission to directory or path:
public static bool HasUserWritePermission(String path, String NtAccountName)
{
DirectoryInfo di = new DirectoryInfo(path);
DirectorySecurity acl = di.GetAccessControl(AccessControlSections.All);
AuthorizationRuleCollection rules = acl.GetAccessRules(true, true, typeof(NTAccount));
Boolean hasPermission = false;
//Go through the rules returned from the DirectorySecurity
foreach (AuthorizationRule rule in rules)
{
//If we find one that matches the identity we are looking for
if (rule.IdentityReference.Value.Equals(NtAccountName, StringComparison.CurrentCultureIgnoreCase))
{
//Cast to a FileSystemAccessRule to check for access rights
if ((((FileSystemAccessRule)rule).FileSystemRights & FileSystemRights.WriteData) > 0)
{
hasPermission = true;
}
else
{
hasPermission = false;
}
}
}
return hasPermission;
}
Related
I have following code for log file
which will create a log file and write log into that file.
But I want to write that log into file in DESC order
so that recent log text will come first.
string FilePath = Path(MYLOG.txt");
if (!File.Exists(FilePath))
{
byte[] fileBytes = null;
fileBytes = Encoding.GetEncoding(1252).GetBytes("My Log -\n");
using (Stream streamToWrite = File.Create(FilePath))
{
streamToWrite.Write(fileBytes, 0, fileBytes.Length);
streamToWrite.Flush();
}
I mean want to write new content from start not to end of the file
I think this will do
string currentContent = String.Empty;
if (File.Exists(filePath))
{
currentContent = File.ReadAllText(filePath);
}
File.WriteAllText(filePath, newContent + currentContent );
I had tried to develop a servlet that allow user to download file but it allow user to download the file but the file content contains binary garbage and not human readable. May I know what could be the reason ?
Code
int length = -1, index = 0;
byte[] buffer = null;
String attachmentPath = null, contentType = null, extension = null;
File attachmentFile = null;
BufferedInputStream input = null;
ServletOutputStream output = null;
ServletContext context = null;
attachmentPath = request.getParameter("attachmentPath");
if (attachmentPath != null && !attachmentPath.isEmpty()) {
attachmentFile = new File(attachmentPath);
if (attachmentFile.exists()) {
response.reset();
context = super.getContext();
contentType = context.getMimeType(attachmentFile.getName());
response.setContentType(contentType);
response.addHeader("content-length", String.valueOf(attachmentFile.length()));
response.addHeader("content-disposition", "attachment;filename=" + attachmentFile.getName());
try {
buffer = new byte[AttachmentTask.DEFAULT_BUFFER_SIZE];
input = new BufferedInputStream(new FileInputStream(attachmentFile));
output = response.getOutputStream();
while ((length = input.read(buffer)) != -1) {
output.write(buffer, 0, length);
index += length;
// output.write(length);
}
output.flush();
input.close();
output.close();
} catch (FileNotFoundException exp) {
logger.error(exp.getMessage());
} catch (IOException exp) {
logger.error(exp.getMessage());
}
} else {
try {
response.sendError(HttpServletResponse.SC_NOT_FOUND);
} catch (IOException exp) {
logger.error(exp.getMessage());
}
}
It is relate to writing file as binary or text mode or browser settings?
Please help.
Thanks.
The problem is not in the code given so far. You're properly using InputStream/OutputStream instead of a Reader/Writer to stream the file.
The cause of the problem is more likely in the way how you created/saved the file. This problem will manifest when you've used a Reader and/or Writer which is not been instructed to use the proper character encoding for the characters being read/written. Perhaps you're creating an upload/download service and the fault was in the upload process itself?
Assuming that the data is in UTF-8, you should have created the reader as follows:
Reader reader = new InputStreamReader(new FileInputStream(file), "UTF-8"));
and the writer as follows:
Writer writer = new OutputStreamWriter(new FileOutputStream(file), "UTF-8"));
But if you actually don't need to manipulate the stream on a per-character basis, but just wanted to transfer the data unmodified, then you should actually have used InputStream/OutputStream all the time.
See also:
Unicode - How to get the characters right?
I am using the below code to Upload an Image file to a SharePoint Document Library. The code works fine locally but once deployed to server, i get the Exception as file not found.
String fileToUpload = FlUpldImage.PostedFile.FileName; //#"C:\Users\admin.RSS\Desktop\Photos\me_skype.jpg";
String documentLibraryName = "SiteAssets";
if (!System.IO.File.Exists(fileToUpload))
throw new FileNotFoundException("File not found.", fileToUpload);
SPFolder myLibrary = web.Folders[documentLibraryName];
// Prepare to upload
Boolean replaceExistingFiles = true;
String fileName = CheckStringNull(txtFirstName.Text) + CheckStringNull(txtLastName.Text) + CheckDateNull(txtDOB) + System.IO.Path.GetFileName(fileToUpload); ;
if (fileName.Contains('/'))
{
fileName = fileName.Replace("/", "");
}
if (fileName.Contains(':'))
{
fileName = fileName.Replace(":", "");
}
FileStream fileStream = File.OpenRead(fileToUpload);
//Upload document
SPFile spfile = myLibrary.Files.Add(fileName, fileStream, replaceExistingFiles);
string url = site.ToString() + "/" + spfile.ToString();
if (url.Contains("="))
{
url = url.Split('=')[1];
}
//Commit
myLibrary.Update();
The string fileupload contains URL as C:\Users\admin.RSS\Desktop\Photos\me.jpg This URL is actually the client system and the server side code throws exception as file not found. How to handle this issue?
UPDATE:
I removed the lines of code that checks if the file exists and now i get the exeption on FileStream fileStream = File.OpenRead(fileToUpload); as c:\windows\system32\inetsrv\20120605_133145.jpg cold not be found
Kindly help. Thank You
if (this.fuAvatarUpload.HasFile && this.fuAvatarUpload.PostedFile.FileName.Length > 0)
{
string extension = Path.GetExtension(file.FileName).ToLower();
string mimetype;
switch (extension)
{
case ".png":
case ".jpg":
case ".gif":
mimetype = file.ContentType;
break;
default:
_model.ShowMessage("We only accept .png, .jpg, and .gif!");
return;
}
if (file.ContentLength / 1000 < 1000)
{
Image image = Image.FromStream(file.InputStream);
Bitmap resized = new Bitmap(image, 150, 150);
byte[] byteArr = new byte[file.InputStream.Length];
using (MemoryStream stream = new MemoryStream())
{
resized.Save(stream, System.Drawing.Imaging.ImageFormat.Png);
byteArr = stream.ToArray();
}
file.InputStream.Read(byteArr, 0, byteArr.Length);
profile.ImageUrl = byteArr;
profile.UseGravatar = false;
profileService.UpdateProfile(profile);
this._model.ShowApprovePanel();
}
else
{
_model.ShowMessage("The file you uploaded is larger than the 1mb limit. Please reduce the size of your file and try again.");
}
}
Saving the file physically onto server and than working on the same helped me resolve my issue.
I m using Opendialogbox to read the file. Then stored the file in byte[] array.
file --> byte []
byte[] --> stored on SQL AZure in varbinary(max) field.
Here is my code:
OpenFileDialog ofd = new OpenFileDialog();
if ((bool)ofd.ShowDialog())
{
FileStream fileStream = ofd.File.OpenRead());
byte[] buffer = new byte[fileStream.Length];
int read = 0;
using (BinaryReader binaryReader = new BinaryReader(fileStream))
{
do
{
read = binaryReader.Read(buffer, 0, Convert.ToInt32(fileStream.Length));
// Stored the File in byte[] Array buffer
} while (read > 0);
}
}
Now I want to convert this byte array to the original file (like .doc,.txt,jpeg). i know the extension in which file is to be convert.
SQL AZure ---> byte[] // done
byte[] ---> to original file. // Problem
Please give solution to download the file.
One way - not necessarily the best - is as follows:
using (MemoryStream ms = new MemoryStream(theBytes))
{
using (FileStream fs = new FileStream(string.Format("C:\\tempfile.{0}", theExtension)))
{
ms.WriteTo(fs);
}
}
namespace FileSaveDialogDemo
{
public partial class MainPage : UserControl
{
#region Fields
SaveFileDialog dialog= new SaveFileDialog();
#endregion
#region Constructors
public MainPage()
{
InitializeComponent();
this.dialog = new SaveFileDialog();
try
{
this.dialog.DefaultExt = ".txt";
this.dialog.Filter = "Text Files|*.txt|Log Files|*.log|All Files|*.*";
this.dialog.FilterIndex = 2;
}
catch ( Exception ex )
{
this.tblError.Text = "Error configuring SaveFileDialog: " + ex.Message;
}
}
#endregion
private void btnSaveFile_Click( object sender, RoutedEventArgs e )
{
bool? dialogResult = this.dialog.ShowDialog();
if ( dialogResult == true )
{
try
{
byte[] fileBytes; // your varbinary file from database
using (Stream fs = (Stream)dialog.OpenFile())
{
fs.Write(fileBytes, 0, fileBytes.Length);
fs.Close();
lblMsg.Content = "File successfully saved!";
}
}
catch ( Exception ex )
{
this.tblError.Text = "Error calling service: " + ex.Message;
}
}
} // End of Function
}// End of MainPage class
}
It seems the issue you have has probably nothing to do with saving a binary file; it is more likely a basic security issue. Try saving to a path on which you have programmatic write access. For example, try saving to your My Documents directory instead of C:. Try using the Environment.SpecialFolder enumeration like this, and append the file name + extension.
Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments)
You have a number of other ways to work around this issue, including starting Visual Studio in Elevated Mode (run as Administrator), and/or allow "Everyone" write access to your C:\ drive. But I wouldn't recommend these techniques necessarily; consider saving to a folder where the security settings are lower than c:\, such as My Documents.
I am trying to programatically build a list of files in a folder, with certain attributes like file size and modified date.
I can return the file name, but any other attribute throws an error: System.IO.IOException: The filename, directory name, or volume label syntax is incorrect.
What am I missing here?
private void BuildDocList()
{
var files = Directory.GetFiles(Server.MapPath(FilePath));
foreach (var f in files)
{
var file = new FileInfo(FilePath + f);
var fileItem = new ListItem();
// this line works fine
fileItem.Text = file.Name.Split('.')[0] + ", ";
// this line causes the runtime error
fileItem.Text = file.CreationTime.ToShortDateString();
FileList.Items.Add(fileItem);
}
}
You're trying to use the wrong filename for the FileInfo - you're using the unmapped path. You should use something like this:
string directory = Server.MapPath(FilePath);
string[] files = Directory.GetFiles(directory);
foreach (string f in files)
{
FileInfo file = new FileInfo(Path.Combine(directory, f));
// Now the properties should work.