Getting a subset of variables in R summary - r

When using the summary function in R, is there an option I can pass in there to present only a subset of the variables?
In my example, I ran a panel regression I have several explanatory variables, and have many dummy variables whose coefficients I do not want to present. I suppose there is a simple way to do this, but couldn't find it in the function documentation. Thanks


It is in the documentation, but you have to look for the associacted print method for summary.plm. The argument is subset. Use it as in the following example:
library(plm)
data("Grunfeld", package = "plm")
mod <- plm(inv ~ value + capital, data = Grunfeld)
print(summary(mod), subset = c("capital"))


Assuming the regression you ran behaves similarly as the summary() of a basic lm() model:
# set up data
x <- 1:100 * runif(100, .01, .02)
y <- 1:100 * runif(100, .01, .03)
# run a very basic linear model
mylm <- lm(x ~ y)
summary(mylm)
# we can save summary of our linear model as a variable
mylm_summary <- summary(mylm)
# we can then isolate coefficients from this summary (summary is just a list)
mylm_summary$coefficients
#output:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 0.2007199 0.04352267 4.611846 1.206905e-05
y 0.5715838 0.03742379 15.273273 1.149594e-27
# note that the class of this "coefficients" object is a matrix
class(mylm_summ$coefficients)
# output
[1] "matrix"
# we can convert that matrix into a data frame so it is easier to work with and subset
mylm_df_coefficients <- data.frame(mylm_summary$coefficients)

Related

Create model.matrix() from LASSO output

I wish to create a model matrix of the independent variables/specific levels of categorical variables selected by LASSO so that I can plug said model matrix into a glm() function to run a logistic regression.
I have included an example of what I'm trying to do. Any help would be greatly appreciated
data("iris")
iris$Petal.Width <- factor(iris$Petal.Width)
iris$Sepal.Length2 <- ifelse(iris$Sepal.Length>=5.8,1,0)
f <- as.formula(Sepal.Length2~Sepal.Width+Petal.Length+Petal.Width+Species)
X <- model.matrix(f,iris)[,-1]
Y <- iris$Sepal.Length2
cvfit <- cv.glmnet(X,Y,alpha=1,family="binomial")
fit <- glmnet(X,Y,alpha=1,family = "binomial")
b <- coef(cvfit,s="lambda.1se")
print(b)
## This is the part I am unsure of: I want to create a model matrix of the non-zero coefficients contained within 'b'
## e.g.
lasso_x <- model.matrix(b,iris)
logistic_model <- glm.fit(lasso_x,Y,family = "binomial")
Edit:
I also tried the following:
model.matrix(~X)[which(b!=0)-1]
but it just gives me a single column of 1's, the length of the number of selections from LASSO (minus the intercept)

linear regression function creating a list instead of a model

I'm trying to fit an lm model using R. However, for some reason this code creates a list of the data instead of the usual regression model.
The code I use is this one
lm(Soc_vote ~ Inclusivity + Gini + Un_den, data = general_inclusivity_sweden )
But instead of the usual coefficients, the title of the variable appears mixed with the data in this way:
(Intercept) Inclusivity0.631 Inclusivity0.681 Inclusivity0.716 Inclusivity0.9
35.00 -4.00 -6.74 -4.30 4.90
Does anybody know why this happened and how it can be fixed?

What you are seeing is called a named num (a numeric vector with names). You can do the following:
Model <- lm(Soc_vote ~ Inclusivity + Gini + Un_den, data = general_inclusivity_sweden) # Assign the model to an object called Model
summary(Model) # Summary table
Model$coefficients # See only the coefficients as a named numeric vector
Model$coefficients[[1]] # See the first coefficient without name
If you want all the coefficients without names (so just a numeric vector), try:
unname(coef(Model))

It would be good if you could provide a sample of your data but I'm guessing that the key problem is that the numeric data in Inclusivity is stored as a factor. e.g.,
library(tidyverse)
x <- tibble(incl = as.factor(c(0.631, 0.681, 0.716)),
soc_vote=1:3)
lm(soc_vote ~ incl, x)
Call:
lm(formula = soc_vote ~ incl, data = x)
Coefficients:
(Intercept) incl0.681 incl0.716
1 1 2
Whereas, if you first convert the Inclusivity column to double, you get
y <- x %>% mutate(incl = as.double(as.character(incl)))
lm(soc_vote ~ incl, y)
Call:
lm(formula = soc_vote ~ incl, data = y)
Coefficients:
(Intercept) incl
-13.74 23.29
Note that I needed to convert to character first since otherwise I just get the ordinal equivalent of each factor.

Back-transform coefficients from glmer with scaled independent variables for prediction

I've fitted a mixed model using the lme4 package. I transformed my independent variables with the scale() function prior to fitting the model. I now want to display my results on a graph using predict(), so I need the predicted data to be back on the original scale. How do I do this?
Simplified example:
database <- mtcars
# Scale data
database$wt <- scale(mtcars$wt)
database$am <- scale(mtcars$am)
# Make model
model.1 <- glmer(vs ~ scale(wt) + scale(am) + (1|carb), database, family = binomial, na.action = "na.fail")
# make new data frame with all values set to their mean
xweight <- as.data.frame(lapply(lapply(database[, -1], mean), rep, 100))
# make new values for wt
xweight$wt <- (wt = seq(min(database$wt), max(database$wt), length = 100))
# predict from new values
a <- predict(model.1, newdata = xweight, type="response", re.form=NA)
# returns scaled prediction
I've tried using this example to back-transform the predictions:
# save scale and center values
scaleList <- list(scale = attr(database$wt, "scaled:scale"),
center = attr(database$wt, "scaled:center"))
# back-transform predictions
a.unscaled <- a * scaleList$scale + scaleList$center
# Make model with unscaled data to compare
un.model.1 <- glmer(vs ~ wt + am + (1|carb), mtcars, family = binomial, na.action = "na.fail")
# make new data frame with all values set to their mean
un.xweight <- as.data.frame(lapply(lapply(mtcars[, -1], mean), rep, 100))
# make new values for wt
un.xweight$wt <- (wt = seq(min(mtcars$wt), max(mtcars$wt), length = 100))
# predict from new values
b <- predict(un.model.1, newdata = xweight, type="response", re.form=NA)
all.equal(a.unscaled,b)
# [1] "Mean relative difference: 0.7223061"
This doesn't work - there shouldn't be any difference. What have I done wrong?
I've also looked at a number of similar questions but not managed to apply any to my case (How to unscale the coefficients from an lmer()-model fitted with a scaled response, unscale and uncenter glmer parameters, Scale back linear regression coefficients in R from scaled and centered data, https://stats.stackexchange.com/questions/302448/back-transform-mixed-effects-models-regression-coefficients-for-fixed-effects-f).

The problem with your approach is that it only "unscales" based on the wt variable, whereas you scaled all of the variables in your regression model. One approach that works is to adjust all of the variables in your new (prediction) data frame using the centering/scaling values that were used on the original data frame:
## scale variable x using center/scale attributes
## of variable y
scfun <- function(x,y) {
scale(x,
center=attr(y,"scaled:center"),
scale=attr(y,"scaled:scale"))
}
## scale prediction frame
xweight_sc <- transform(xweight,
wt = scfun(wt, database$wt),
am = scfun(am, database$am))
## predict
p_unsc <- predict(model.1,
newdata=xweight_sc,
type="response", re.form=NA)
Comparing this p_unsc to your predictions from the unscaled model (b in your code), i.e. all.equal(b,p_unsc), gives TRUE.
Another reasonable approach would be to
unscale/uncenter all of your parameters using the "unscaling" approaches presented in one of the linked question (such as this one), generating a coefficient vector beta_unsc
construct the appropriate model matrix from your prediction frame:
X <- model.matrix(formula(model,fixed.only=TRUE),
newdata=pred_frame)
compute the linear predictor and back-transform:
pred <- plogis(X %*% beta_unsc)

Extract p value from multiple linear regression f-test [duplicate]

How do you pull out the p-value (for the significance of the coefficient of the single explanatory variable being non-zero) and R-squared value from a simple linear regression model? For example...
x = cumsum(c(0, runif(100, -1, +1)))
y = cumsum(c(0, runif(100, -1, +1)))
fit = lm(y ~ x)
summary(fit)
I know that summary(fit) displays the p-value and R-squared value, but I want to be able to stick these into other variables.

r-squared: You can return the r-squared value directly from the summary object summary(fit)$r.squared. See names(summary(fit)) for a list of all the items you can extract directly.
Model p-value: If you want to obtain the p-value of the overall regression model,
this blog post outlines a function to return the p-value:
lmp <- function (modelobject) {
if (class(modelobject) != "lm") stop("Not an object of class 'lm' ")
f <- summary(modelobject)$fstatistic
p <- pf(f[1],f[2],f[3],lower.tail=F)
attributes(p) <- NULL
return(p)
}
> lmp(fit)
[1] 1.622665e-05
In the case of a simple regression with one predictor, the model p-value and the p-value for the coefficient will be the same.
Coefficient p-values: If you have more than one predictor, then the above will return the model p-value, and the p-value for coefficients can be extracted using:
summary(fit)$coefficients[,4]
Alternatively, you can grab the p-value of coefficients from the anova(fit) object in a similar fashion to the summary object above.

Notice that summary(fit) generates an object with all the information you need. The beta, se, t and p vectors are stored in it. Get the p-values by selecting the 4th column of the coefficients matrix (stored in the summary object):
summary(fit)$coefficients[,4]
summary(fit)$r.squared
Try str(summary(fit)) to see all the info that this object contains.
Edit: I had misread Chase's answer which basically tells you how to get to what I give here.

You can see the structure of the object returned by summary() by calling str(summary(fit)). Each piece can be accessed using $. The p-value for the F statistic is more easily had from the object returned by anova.
Concisely, you can do this:
rSquared <- summary(fit)$r.squared
pVal <- anova(fit)$'Pr(>F)'[1]

I came across this question while exploring suggested solutions for a similar problem; I presume that for future reference it may be worthwhile to update the available list of answer with a solution utilising the broom package.
Sample code
x = cumsum(c(0, runif(100, -1, +1)))
y = cumsum(c(0, runif(100, -1, +1)))
fit = lm(y ~ x)
require(broom)
glance(fit)
Results
>> glance(fit)
r.squared adj.r.squared sigma statistic p.value df logLik AIC BIC deviance df.residual
1 0.5442762 0.5396729 1.502943 118.2368 1.3719e-18 2 -183.4527 372.9055 380.7508 223.6251 99
Side notes
I find the glance function is useful as it neatly summarises the key values. The results are stored as a data.frame which makes further manipulation easy:
>> class(glance(fit))
[1] "data.frame"

While both of the answers above are good, the procedure for extracting parts of objects is more general.
In many cases, functions return lists, and the individual components can be accessed using str() which will print the components along with their names. You can then access them using the $ operator, i.e. myobject$componentname.
In the case of lm objects, there are a number of predefined methods one can use such as coef(), resid(), summary() etc, but you won't always be so lucky.

Extension of #Vincent 's answer:
For lm() generated models:
summary(fit)$coefficients[,4] ##P-values
summary(fit)$r.squared ##R squared values
For gls() generated models:
summary(fit)$tTable[,4] ##P-values
##R-squared values are not generated b/c gls uses max-likelihood not Sums of Squares
To isolate an individual p-value itself, you'd add a row number to the code:
For example to access the p-value of the intercept in both model summaries:
summary(fit)$coefficients[1,4]
summary(fit)$tTable[1,4]
Note, you can replace the column number with the column name in each of the above instances:
summary(fit)$coefficients[1,"Pr(>|t|)"] ##lm
summary(fit)$tTable[1,"p-value"] ##gls
If you're still unsure of how to access a value form the summary table use str() to figure out the structure of the summary table:
str(summary(fit))

This is the easiest way to pull the p-values:
coef(summary(modelname))[, "Pr(>|t|)"]

I used this lmp function quite a lot of times.
And at one point I decided to add new features to enhance data analysis. I am not in expert in R or statistics but people are usually looking at different information of a linear regression :
p-value
a and b
r²
and of course the aspect of the point distribution
Let's have an example. You have here
Here a reproducible example with different variables:
Ex<-structure(list(X1 = c(-36.8598, -37.1726, -36.4343, -36.8644,
-37.0599, -34.8818, -31.9907, -37.8304, -34.3367, -31.2984, -33.5731
), X2 = c(64.26, 63.085, 66.36, 61.08, 61.57, 65.04, 72.69, 63.83,
67.555, 76.06, 68.61), Y1 = c(493.81544, 493.81544, 494.54173,
494.61364, 494.61381, 494.38717, 494.64122, 493.73265, 494.04246,
494.92989, 494.98384), Y2 = c(489.704166, 489.704166, 490.710962,
490.653212, 490.710612, 489.822928, 488.160904, 489.747776, 490.600579,
488.946738, 490.398958), Y3 = c(-19L, -19L, -19L, -23L, -30L,
-43L, -43L, -2L, -58L, -47L, -61L)), .Names = c("X1", "X2", "Y1",
"Y2", "Y3"), row.names = c(NA, 11L), class = "data.frame")
library(reshape2)
library(ggplot2)
Ex2<-melt(Ex,id=c("X1","X2"))
colnames(Ex2)[3:4]<-c("Y","Yvalue")
Ex3<-melt(Ex2,id=c("Y","Yvalue"))
colnames(Ex3)[3:4]<-c("X","Xvalue")
ggplot(Ex3,aes(Xvalue,Yvalue))+
geom_smooth(method="lm",alpha=0.2,size=1,color="grey")+
geom_point(size=2)+
facet_grid(Y~X,scales='free')
#Use the lmp function
lmp <- function (modelobject) {
if (class(modelobject) != "lm") stop("Not an object of class 'lm' ")
f <- summary(modelobject)$fstatistic
p <- pf(f[1],f[2],f[3],lower.tail=F)
attributes(p) <- NULL
return(p)
}
# create function to extract different informations from lm
lmtable<-function (var1,var2,data,signi=NULL){
#var1= y data : colnames of data as.character, so "Y1" or c("Y1","Y2") for example
#var2= x data : colnames of data as.character, so "X1" or c("X1","X2") for example
#data= data in dataframe, variables in columns
# if signi TRUE, round p-value with 2 digits and add *** if <0.001, ** if < 0.01, * if < 0.05.
if (class(data) != "data.frame") stop("Not an object of class 'data.frame' ")
Tabtemp<-data.frame(matrix(NA,ncol=6,nrow=length(var1)*length(var2)))
for (i in 1:length(var2))
{
Tabtemp[((length(var1)*i)-(length(var1)-1)):(length(var1)*i),1]<-var1
Tabtemp[((length(var1)*i)-(length(var1)-1)):(length(var1)*i),2]<-var2[i]
colnames(Tabtemp)<-c("Var.y","Var.x","p-value","a","b","r^2")
for (n in 1:length(var1))
{
Tabtemp[(((length(var1)*i)-(length(var1)-1))+n-1),3]<-lmp(lm(data[,var1[n]]~data[,var2[i]],data))
Tabtemp[(((length(var1)*i)-(length(var1)-1))+n-1),4]<-coef(lm(data[,var1[n]]~data[,var2[i]],data))[1]
Tabtemp[(((length(var1)*i)-(length(var1)-1))+n-1),5]<-coef(lm(data[,var1[n]]~data[,var2[i]],data))[2]
Tabtemp[(((length(var1)*i)-(length(var1)-1))+n-1),6]<-summary(lm(data[,var1[n]]~data[,var2[i]],data))$r.squared
}
}
signi2<-data.frame(matrix(NA,ncol=3,nrow=nrow(Tabtemp)))
signi2[,1]<-ifelse(Tabtemp[,3]<0.001,paste0("***"),ifelse(Tabtemp[,3]<0.01,paste0("**"),ifelse(Tabtemp[,3]<0.05,paste0("*"),paste0(""))))
signi2[,2]<-round(Tabtemp[,3],2)
signi2[,3]<-paste0(format(signi2[,2],digits=2),signi2[,1])
for (l in 1:nrow(Tabtemp))
{
Tabtemp$"p-value"[l]<-ifelse(is.null(signi),
Tabtemp$"p-value"[l],
ifelse(isTRUE(signi),
paste0(signi2[,3][l]),
Tabtemp$"p-value"[l]))
}
Tabtemp
}
# ------- EXAMPLES ------
lmtable("Y1","X1",Ex)
lmtable(c("Y1","Y2","Y3"),c("X1","X2"),Ex)
lmtable(c("Y1","Y2","Y3"),c("X1","X2"),Ex,signi=TRUE)
There is certainly a faster solution than this function but it works.

For the final p-value displayed at the end of summary(), the function uses pf() to calculate from the summary(fit)$fstatistic values.
fstat <- summary(fit)$fstatistic
pf(fstat[1], fstat[2], fstat[3], lower.tail=FALSE)
Source: [1], [2]

Another option is to use the cor.test function, instead of lm:
> x <- c(44.4, 45.9, 41.9, 53.3, 44.7, 44.1, 50.7, 45.2, 60.1)
> y <- c( 2.6, 3.1, 2.5, 5.0, 3.6, 4.0, 5.2, 2.8, 3.8)
> mycor = cor.test(x,y)
> mylm = lm(x~y)
# r and rsquared:
> cor.test(x,y)$estimate ** 2
cor
0.3262484
> summary(lm(x~y))$r.squared
[1] 0.3262484
# P.value
> lmp(lm(x~y)) # Using the lmp function defined in Chase's answer
[1] 0.1081731
> cor.test(x,y)$p.value
[1] 0.1081731

x = cumsum(c(0, runif(100, -1, +1)))
y = cumsum(c(0, runif(100, -1, +1)))
fit = lm(y ~ x)
> names(summary(fit))
[1] "call" "terms"
[3] "residuals" "coefficients"
[5] "aliased" "sigma"
[7] "df" "r.squared"
[9] "adj.r.squared" "fstatistic"
[11] "cov.unscaled"
summary(fit)$r.squared

Use:
(summary(fit))$coefficients[***num***,4]
where num is a number which denotes the row of the coefficients matrix. It will depend on how many features you have in your model and which one you want to pull out the p-value for. For example, if you have only one variable there will be one p-value for the intercept which will be [1,4] and the next one for your actual variable which will be [2,4]. So your num will be 2.

change null hypothesis in lmtest in R

I have a linear model generated using lm. I use the coeftest function in the package lmtest go test a hypothesis with my desired vcov from the sandwich package. The default null hypothesis is beta = 0. What if I want to test beta = 1, for example. I know I can simply take the estimated coefficient, subtract 1 and divide by the provided standard error to get the t-stat for my hypothesis. However, there must be functionality for this already in R. What is the right way to do this?
MWE:
require(lmtest)
require(sandwich)
set.seed(123)
x = 1:10
y = x + rnorm(10)
mdl = lm(y ~ x)
z = coeftest(mdl, df=Inf, vcov=NeweyWest)
b = z[2,1]
se = z[2,2]
mytstat = (b-1)/se
print(mytstat)

the formally correct way to do this:
require(multcomp)
zed = glht(model=mdl, linfct=matrix(c(0,1), nrow=1, ncol=2), rhs=1, alternative="two.sided", vcov.=NeweyWest)
summary(zed)

Use an offset of -1*x
mdl<-lm(y~x)
mdl2 <- lm(y ~ x-offset(x) )
> mdl
Call:
lm(formula = y ~ x)
Coefficients:
(Intercept) x
0.5255 0.9180
> mdl2
Call:
lm(formula = y ~ x - offset(x))
Coefficients:
(Intercept) x
0.52547 -0.08197
You can look at summary(mdl2) to see the p-value (and it is the same as in mdl.

As far as I know, there is no default function to test the model coefficients against arbitrary value (1 in your case). There is the offset trick presented in the other answer, but it's not that straightforward (and always be careful with such model modifications). So, your expression (b-1)/se is actually a good way to do it.
I have two notes on your code:
You can use summary(mdl) to get the t-test for 0.
You are using lmtest with covariance structure (which will change the t-test values), but your original lm model doesn't have it. Perhaps this could be a problem? Perhaps you should use glm and specify the correlation structure from the start.

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