scrape the next pages in python using Beautifulsoup - web-scraping

Question

I want to scrape the links from each page and move on to the next pages and do the same. here is my code to scrape links from the first page:
import requests
from bs4 import BeautifulSoup
page='https://www.booli.se/slutpriser/goteborg/22/?objectType=L%C3%A4genhet'
request = requests.get(page)
soup = BeautifulSoup(request.text,'lxml')
links= soup.findAll('a',class_='search-list__item')
url=[]
prefix = "https://www.booli.se"
for link in links:
url.append(prefix+link["href"])
I tried the following for the first three pages, but it didn't work.
import re
import requests
from bs4 import BeautifulSoup
url=[]
prefix = "https://www.booli.se"
with requests.Session() as session:
for page in range(4):
response = session.get("https://www.booli.se/slutpriser/goteborg/22/?
objectType=L%C3%A4genhet&page=%f" % page)
soup = BeautifulSoup(response.content, "html.parser")
links= soup.findAll('a',class_='search-list__item')
for link in links:
url.append(prefix+link["href"])

Answer 1

First you have to create code that is working fine with one page.
Then you have to put your scraping code in loop
url = "https://www.booli.se/slutpriser/goteborg/22/?objectType=L%C3%A4genhet&page=1"
while True:
code goes here
You will notice there is a page=number at the end of the link.
You have to figure to run loop on these url with changing the page=number
i=1
url = "https://www.booli.se/slutpriser/goteborg/22/?objectType=L%C3%A4genhet&page=" + str(i)
while True:
i = i+1
page = requests.get(url)
if page.status_code != 200:
break
url = "https://www.booli.se/slutpriser/goteborg/22/?objectType=L%C3%A4genhet&page=" + str(i)
#Your scraping code goes here
#
#
I have used if statement so that the loop does not goes forever. It will go upto the last page.

Answer 2

Yes, I did it. Thank you. Here is the code for the first two pages:
urls=[]
for page in range(3):
urls.append("https://www.booli.se/slutpriser/goteborg/22/?
objectType=L%C3%A4genhet&page={}".format(page))
page=urls[1:]
#page
import requests
from bs4 import BeautifulSoup
inturl=[]
for page in page:
request = requests.get(page)
soup = BeautifulSoup(request.text,'lxml')
links= soup.findAll('a',class_='search-list__item')
prefix = "https://www.booli.se"
for link in links:
inturl.append(prefix+link["href"])