Hide key from Qt Virtual keyboard - qt

Question

Is there a way to hide the language selection key from the virtual keyboard without use a custom layout?

Answer 1

I was able to hide the language key with a workaround:
property var keyboardLayout: inputPanel.keyboard.layout
function findChildByProperty(parent, propertyName, propertyValue, compareCb) {
var obj = null
if (parent === null)
return null
var children = parent.children
for (var i = 0; i < children.length; i++) {
obj = children[i]
if (obj.hasOwnProperty(propertyName)) {
if (compareCb !== null) {
if (compareCb(obj[propertyName], propertyValue))
break
} else if (obj[propertyName] === propertyValue) {
break
}
}
obj = findChildByProperty(obj, propertyName, propertyValue, compareCb)
if (obj)
break
}
return obj
}
onKeyboardLayoutChanged: {
if(keyboardLayout!=""){
var ChangeLanguageKey= findChildByProperty(inputPanel.keyboard, "objectName", "changeLanguageKey", null)
if(ChangeLanguageKey){
ChangeLanguageKey.visible=false
}
}
}
InputPanel {
id: inputPanel
z: 99
y: parent.height
anchors.left: parent.left
anchors.right: parent.right
states: State {
name: "visible"
when: inputPanel.active
PropertyChanges {
target: inputPanel
y: parent.height - inputPanel.height
}
}
transitions: Transition {
from: ""
to: "visible"
reversible: true
ParallelAnimation {
NumberAnimation {
properties: "y"
duration: 400
easing.type: Easing.InOutBack
}
}
}
CustomComponents.AutoScroller {
id:autoscroller
panelY: inputPanel.y
}
}
This only works in version 5.9 where the objectname property is defined with "changeLanguageKey", for previous versions set the property in the source code and recompile.

Answer 2

No, not without using a custom layout.
You can always modify the layouts that come with the keyboard though.

Answer 3

I was able to hide the hideKeyboard key with this trick. I basically tried to get the reference of the emoji key and thereby was able to disable the next key which is hideKeyboard key.
function disableKey(parent, objectText)
{
var obj = null
if (parent === null)
return null
var children = parent.children
for (var i = 0; i < children.length; i++) {
obj = children[i]
if (obj.text === objectText && obj.toString().substring(0, 7) === "BaseKey") {
console.log("Disabling symbols. " + obj.text)
obj.enabled = false
}
else if(obj.displayText === "HWR"){
console.log("Disabling Handwriting mode button." + obj.displayText + " " + objectText)
obj.visible = false
}
else if(obj.text === ":-)" && obj.toString().substring(0, 7) === "BaseKey"){
console.log("Disabling hidekeyboard key." + obj.text)
children[i+1].visible = false
}
obj = disableKey(obj, objectText)
if (obj)
break
}
return obj
}