Remove column in awk command - unix

Question

I want to remove column as for now i have command that include splitting, header and trailer in one command. I wanted to do splitting, header, trailer and remove first 3 columns in one command.
My original output is
Country Gender Plate Name Account Number Car Name
X F A Fara XXXXXXXXXX Ixora
X F b Jiha XXXXXXXXXX Saga
X M c Jiji XXXXXXXXXX Proton
My splited files:
first file
06032017
Country Gender Plate Name Account Number Car Name
X F A Fara XXXXXXXXXX Ixora
EOF 1
second file
06032017
Country Gender Plate Name Account Number Car Name
X F b Jiha XXXXXXXXXX Saga
EOF1
My desitre output:
06032017
Name Account Number Car Name
Fara XXXXXXXXXX Ixora
EOF 1
06032017
Name Account Number Car Name
Jiha XXXXXXXXXX Saga
EOF1
This is my splitted command:
awk -v date="$(date +"%d%m%Y")" -F\| 'NR==1 {h=$0; next}
{file="CAR_V1_"$1"_"$2"_"date".csv"; print (a[file]++?"": "DETAIL "date"" ORS h ORS) $0 > file}
END{for(file in a) print "EOF " a[file] > file}' HIRE_PURCHASE_testing.csv

Answer 1

To get an idea how to skip some fields:
$ echo "Field1 Field2 Field3 Field4 Field5 Field6" |awk '{print $0}'
Field1 Field2 Field3 Field4 Field5 Field6 #No skipping here. Printed just for comparison
$ echo "Field1 Field2 Field3 Field4 Field5 Field6" |awk '{print substr($0, index($0,$4))}'
Field4 Field5 Field6
$ echo "Field1 Field2 Field3 Field4 Field5 Field6" |awk '{$1=$2=$3="";print}'
Field4 Field5 Field6
#Mind the gaps in the beginning. You can use this if you need to "delete" particular columns.
#Actually you are not really delete columns but replace their contents with a blank value.
$ echo "Field1 Field2 Field3 Field4 Field5 Field6" |awk '{gsub($1FS$2FS$3FS$4,$4);print}'
Field4 Field5 Field6 #Columns 1-2-3-4 have been replaced by column4. No gaps here.
$ echo "Field1 Field2 Field3 Field4 Field5 Field6" |awk '{print $4,$5,$6}'
Field4 Field5 Field6
# If you have a fixed number of fields (i.e 6 fields) you can just do not print the first three fields and print the last three fields
Adapted to your existed code, the line
print (a[file]++?"": "DETAIL "date"" ORS h ORS) $0 > file
If changed to
print (a[file]++?"": "DETAIL "date"" ORS h ORS) substr($0, index($0,$4)) > file
Or to
print (a[file]++?"": "DETAIL "date"" ORS h ORS) $4,$5,$6 > file #if you have a fixed number of columns in the file)
should be enough.
I would sugggest next time you need help, simplify the problem to get help more easily. For the rest users is kind of hard to fully follow you.
Also have a look here to see how all those functions work in details: https://www.gnu.org/software/gawk/manual/html_node/String-Functions.html