Suppose my system date is 2014-02-10 & I have published my app on Internet Information System. Now Using DateTime.Now.ToShortDateString method I can get date like 2014-02-10, but how can get pattern/style/structure (e.g yyyy-MM-dd) for date? It should be irrespective of current culture.
IF I change date to 10-Feb-2014, then I should get dd-MMM-yyyy.
What's the solution? Thanks in adv..
Ah, I see. I thought you were saying that you wanted to format a date value but it seems that you're saying that you actually want the format string. In that case, you need to use get an appropriate DateTimeFormatInfo object and get its ShortDatePattern property. You can use System.Globalization.CultureInfo.CurrentCulture.DateTimeFormat or System.Globalization.CultureInfo.InvariantCulture.DateTimeFormat to get that DateTimeFormatInfo.
Related
I'm working on Hyperledger Composer Playground and want to specify only time in DateTime field skipping the Date completely. But whenever I try to create the asset, everytime I'm getting RangeError: Invalid time value error.
I tried giving default value to the variable in model file in some varieties of the following example but doesn't work either.
o DateTime dispatchTime default = "T06:18:42.716Z"
I must be missing some obvious thing in this as it is a ISO-8601 standard format but couldn't find exact solution to get it working specifically in Hyperledger Composer. Thanks in advance.
No, you can't store only time to DateTime variable.
As described in the docs, it will only accept an ISO-8601 compatible time instance, with optional time zone and UTZ offset.
You can manually convert it to only time format at the time of response.
For more details of Hyperledger Primitive types, check out the link below:
https://hyperledger.github.io/composer/latest/reference/cto_language
You are getting invalid time error because you can not store just time in your dispatchTime variable as it is an ISO-8601 Date-Time format. You can check it
But then also, if you want to store only time, you can convert it in one of the transaction processor functions in your logic.js file as follows:
tx.assetObject.dispatchTime = new Date().toISOString().split(/T/)[1];
Hope it helps!
I must be missing something obvious, but it seems that I'm unable to find a way to get the TimeDate object from the value of a SugarBean field.
Let's say I get a specific Lead with this kind of call:
$lead = BeanFactory::retrieveBean('Leads', "18bfc69e-8cd4-11e7-ad08-000c29b1a36e");
then any call to this:
$lead->date_entered
will return a string value: "2017-08-29 16:05" (note the absence of seconds).
So then, for example, if I try to use such value to create a SugarTimeDate:
$TimeDate = new TimeDate();
$SugarTimeDate = $TimeDate->fromDb($lead->date_entered);
it will return false, since the value provided to fromDb() is not in the proper format (the seconds are missing).
When looking at the SQL table with Toad, I can see that the information is effectively stored in the database as a DateTime, with the value 08/29/2017 16:05:56. But the SugarBean object provides it as a text with a format that is incomplete.
So how can you get the effective SugarTimeDate, TimeDate or DateTime from a Field in a given SugarBean, ideally as an object?
I searched, and all the example I found was about creating a new date object from Now to set to a field in a SugarBean, but none to set a datetime field from an existing datetime field.
Any hint would be highly appreciated.
By playing around, and with some help from Patrick McQueen, it appears there 2 ways to get the effective date value of a field.
First solution I found was to do a SugarQuery with a select on the needed fields, which then returns the full date information, so "2017-08-29 16:05:56". A bit overkill, but it does the job.
The other solution brought up by Patrick is to use the fetcher_row array from the bean object, which will return the full date information also. So:
$lead->fetched_row['date_entered']
will returns also "2017-08-29 16:05:56".
So in any case an effective date is required ("round-trip" with a get then a set, or some sync requirement), the fetched_row[] is the solution, and the "direct" call to the field $bean->field is to be definitely avoided.
I wasn't 100% clear what you were trying to accomplish (see my comments), but I'm guessing that you want the fromUser() function instead, i.e.
$SugarTimeDate = $TimeDate->fromUser($lead->date_entered);
The reason why, is that Sugar prepares the data for the GUI (including formatting the date as per user preferences) at the point your code is being called. This includes stripping out the seconds. Doing the above fromUser() function will return a SugarDateTime object based on the current user's configured date format with a full date string as a "date" property. This, in turn, could be dealt with elsewhere by using this standard format.
I have to make an ezfind search page with date functions. For the SOLR filter I tried to use something like this: attr_publish_date_dt:[NOW-6MONTH TO NOW] but I don't get any result.
If I use it this way attr_publish_date_dt:[* TO NOW], it works. But all queries without an asterisk on the left hand don't work.
attr_publish_date_dt contains a unix timestamp so I also tried to use 2 timestamps from the attr_publish_date_dt:[* TO NOW] result, instead of [NOW-6MONTH TO NOW], but then I get also no results.
Can anyone help me please? Thanks in advance
Frank
Date searches are supported on a date field. You will need to define a field of that type, and submit dates in ISO-8601 format.
http://lucene.apache.org/solr/4_4_0/solr-core/org/apache/solr/schema/DateField.html
If you cannot properly format the timestamp before sending it to Solr, you may be able to use a DateFormatTransformer or a ScriptTransformer to do the job.
http://wiki.apache.org/solr/DataImportHandler#DateFormatTransformer
http://wiki.apache.org/solr/DataImportHandler#ScriptTransformer
I have been reading all about converting TEXT fields into date formats and ways to use Python to create date objects but my question remains.
My table has a dateTime column that is specified as TEXT, I would like to build a constraint that forces input to be in dateTime format, but as SQLite doesn't do dates (as I would like) I haven't worked out how to do it.
My current ideas: 1. Limit number of characters
2. Set separate attributes for day, month and year and constrain their domains
3. It is silly to do this on the database side just do it in the user interface
I would appreciate your opinions on these or other options.
Thanks :)
I've been trying to solve the same issue and the method I came up with was to use the date/time functions to parse the value and check that it hasn't changed. Essentially the following:
CREATE TABLE dts_test (
dts TEXT CHECK (dts IS datetime(dts))
);
If the default format is not what you want you can use the strftime or similar to design whatever format you want, but it must be something that the built-in date and time functions can parse.
I need to add a 'StartDate' parameter to a report in Reporting Services 2005, which should represent the current date, at midnight.
If I use Now() as expression, it will correctly use midnight in the calculations, but to the user, the time part will not be shown.
13/12/2011
which can be confusing because then the user doesn't really realise he or she can type in a time part.
How can I format this date to the following:
13/12/2011 00:00
while keeping the parameter as a DateTime datatype.?
Edit: I've checked the duplicate question and tried to apply it to my case, but run into the following phenomenom:
If I try:
=DateTime.Parse(Format(Now().Date().AddSeconds(1), "dd/MM/yyyy HH:mm:ss"))
Then the parameter shows "14/12/2011 00:00:01" which is confusing for the users, so I then tried the following:
=DateTime.Parse(Format(Now().Date().AddSeconds(1), "d/M/yyyy HH:mm"))
But then the parameter shows "14/12/2011" again! In other words, the time part is gone again!
Who invented this stuff? :P
Your formula with .Parse(Format(... causes redundant work that is messing things up. Try this:
=Now().Date().AddSeconds(.001)
Use Format. For example: Format(Parameters!SelectedDate.Value, "d/M/yyyy HH:mm")
Here is a list of DateTime identifiers for use with Format.
Edit:
I get it now, you want 00:00 to show up in the parameter input calendar in the report viewer. The time part won't show up when it's set to midnight. This is by design. If you're using 2005 or earlier, Jamie's solution won't work and you're stuck.