Color a part of an input range - css

Hi i've got a input range on html5 min 0 and max 100.
But i would like to color a part for example between 70 and 100.
I don't want to use bootstrap for this.
I don't know how to do that.

You can easily do this by using a linear-gradient as background for the track. All that we need to do is create a gradient which is colored only for the width that we need (30% for your case because you need it colored only between 70-100) and then position it with respect to the track's (the track is the bar of the range input) right side. Since the styling of range inputs is still in experimental phase we have to use browser prefixed selectors (to select the track of each browser) and then apply styles to it. We also have to do some additional corrections to address browser specific problems, I've marked these with inline comments in the code.
The below code is tested and found to be working fine in Edge, IE11 and latest versions of Chrome, Firefox and Opera (all on a Windows 10 machine).
Note: This will only color the part between 70-100 of the range input differently. This doesn't have the code to make the appearance of range input the same in all browsers. I've not done that because that is out of the scope of this question.
Also, as mentioned by ssc-hrep3 in his comment, this may not be good for production implementation because these things are still in experimental stage and we've to use browser specific selectors but if you want to apply custom styling to HTML5 range inputs then there is probably no other way.
input[type=range] {
-webkit-appearance: none;
border: 1px solid black; /* just for demo */
}
input[type=range]::-webkit-slider-runnable-track {
background: linear-gradient(to left, red 30%, transparent 30%);
background-position: right top;
}
input[type=range]::-moz-range-track {
background: linear-gradient(to left, red 30%, transparent 30%);
background-position: right top;
}
input[type=range]::-ms-track {
background: linear-gradient(to left, red 30%, transparent 30%);
background-position: right top;
background-repeat: no-repeat; /* no repeat means background appears a little on the left due to width issue and hence the fix */
width: 100%; /* to fix width issue in Edge */
color: transparent; /* to avoid the intermediate stripe lines in < IE11 */
border: none; /* just do away with the track's border */
}
input[type=range]::-ms-fill-lower {
background: transparent; /* IE11 has default fill and that needs to be removed */
}
<input type="range" min="0" max="100" value="70" step="10" />
For the benefit of future readers: Just in case you need uniform styling across all major browsers then you could use the below snippet. It produces almost similar output in all of them.
input[type=range] {
-webkit-appearance: none;
}
input[type=range]::-webkit-slider-runnable-track {
background: linear-gradient(to left, red 30%, transparent 30%);
background-position: right top;
height: 10px;
box-shadow: inset 0px 0px 0px 1px black;
}
input[type=range]::-moz-range-track {
background: linear-gradient(to left, red 30%, transparent 30%);
background-position: right top;
height: 10px;
box-shadow: inset 0px 0px 0px 1px black;
}
input[type=range]::-ms-track {
background: linear-gradient(to left, red 30%, transparent 30%);
background-position: right top;
background-repeat: no-repeat; /* no repeat means background appears a little on the left due to width issue and hence the fix */
width: 100%; /* to fix width issue in Edge */
height: 10px;
color: transparent; /* to avoid the intermediate stripe lines in < IE11 */
border-color: transparent;
border-style: solid;
border-width: 10px 0px; /* dummy just to increase height, otherwise thumb gets hidden */
box-shadow: inset 0px 0px 0px 1px black;
}
input[type=range]::-ms-fill-lower {
background: transparent; /* IE11 has default fill and that needs to be removed */
}
input[type=range]::-webkit-slider-thumb {
-webkit-appearance: none;
height: 18px;
width: 18px;
margin-top: -4px;
background: sandybrown;
border: 1px solid chocolate;
border-radius: 50%;
}
input[type=range]::-moz-range-thumb {
height: 18px;
width: 18px;
background: sandybrown;
border: 1px solid chocolate;
border-radius: 50%;
}
input[type=range]::-ms-thumb {
height: 18px;
width: 18px;
margin-top: 0px; /* nullify default margin */
background: sandybrown;
border: 1px solid chocolate;
border-radius: 50%;
}
<input type="range" min="0" max="100" value="70" step="10" />

Related

How to create Button with cut edges? [duplicate]

I'm looking for an easy way with a single tag (just <a>)to create a skew effect on the borders, but keep the text the way it is.
I would know how do with a span in- or outside, but I don't want to have additional, pretty much zero meaning HTML on the page.
Example below.
You can unskew the child element i.e. provide the opposite skew co-ordinates as you specified for the parent.
Here is a working example
Suppose you have below as you html,
<div class="btn">
<button><div class="btn-text">Click</div></button>
</div>
If we skew the parent element by 20deg then we should skew the child element by -20deg as,
.btn {
-ms-transform: skewX(20deg); /* IE 9 */
-webkit-transform: skewX(20deg); /* Safari */
transform: skewX(20deg);
}
.btn-text {
-ms-transform: skewX(-20deg); /* IE 9 */
-webkit-transform: skewX(-20deg); /* Safari */
transform: skewX(-20deg);
padding: 20px;
}
You can simply accompish desired effect using CSS triangle tricks.
Just add some styles for the ::before and :: after pseudo-classes.
.skewed_button {
background: #32CD32;
color: #000;
text-decoration: none;
font-size: 20px;
display: inline-block;
height: 30px;
margin-left: 15px;
padding: 6px 10px 0;
}
.skewed_button::before {
content: "";
float: left;
margin: -6px 0 0 -25px;
border-left: 15px solid transparent;
border-bottom: 36px solid #32CD32;
height: 0px;
}
.skewed_button::after {
content: "";
float: right;
margin: -6px -25px 0 0 ;
border-left: 15px solid #32CD32;
border-bottom: 36px solid transparent;
height: 0px;
}
Some Text
You can also use clip-path for this, eg:
clip-path: polygon(14px 0%, 100% 0%, calc(100% - 14px) 100%, 0% 100%);
.skewed_button {
background: yellow;
text-decoration: none;
display: inline-block;
padding: 10px 20px;
clip-path: polygon(14px 0%, 100% 0%, calc(100% - 14px) 100%, 0% 100%);
}
Some Text
One solution is to use css triangles on :before and :after. This solution leaves the cleanest HTML.
This jsfiddle demonstrates
.is-skewed {
width: 80px;
height: 40px;
background-color: #f07;
display: block;
color: #fff;
margin-left: 40px;
}
.is-skewed:before,
.is-skewed:after {
content: '';
width: 0;
height: 0;
}
.is-skewed:before {
border-bottom: 40px solid #f07;
border-left: 20px solid transparent;
float:left;
margin-left: -20px;
}
.is-skewed:after {
border-top: 40px solid #f07;
border-right: 20px solid transparent;
float:right;
margin-right: -20px;
}
CSS triangles use thick borders on elements with 0 dimensions with the points at which the borders meet providing the diagonal line required for a triangle (a good visualisation is to look at the corner of a picture frame, where the two borders meet and create triangles). It's important that one border is transparent and one coloured and that they are adjacent (i.e. left and top, not left and right). You can adjust the size, orientation and the lengths of the sides by playing with the border sizes.
For your button, we also use floats and negative margins to pull them outside of the element and line them up right. Position absolute and negative left and right values would also be a good solution to positioning
You can also do :hover states
.is-skewed:hover {
background-color: #40f;
}
.is-skewed:hover:after {
border-top-color: #40f;
}
.is-skewed:hover:before {
border-bottom-color: #40f;
}
It's important to note the use of background-color and border-color and also that the :hover comes first in all the relevant selectors. If the hover came second this would happen

Button with 2 colors as a border

I'm trying to create a button that has two colors as a border.
The two colors i need used are blue: #00a7e1, orange: #f6531d.
I would like to just use css if possible.
Thank in advance!
link to button concept
Example:
.btn
{
border: 0;
padding: 4px;
display: inline-block;
background: linear-gradient(20deg, #00a7e1 49%, #e65300 50%);
}
.bg
{
background: #349645;
padding: 8px 14px;
font: bold 24px Consolas;
}
.btn:active .bg
{
background: #0a1117;
color: #ffffff;
}
<div class="btn"><div class="bg">YOU'R TITLE</div></div>
<button class="btn"><div class="bg">YOU'R TITLE</div></div>
You may also play with gradient and background-clip (see comments in CSS)
button {
vertical-align: top;
border: 5px solid transparent;/* give extra space for gradients colors */
font-size: 2.5rem;
margin: 0.25em;
padding: 0.5em 2em;
background: linear-gradient(#333, #333),/* black turned into gradient to hold with background-clip and hide the 2 color gradient under it */
linear-gradient(/* 2 colors to draw under the borders also via background-clip*/
to bottom left,
rgb(230, 83, 0) 50%,
gray 51%,
rgb(0, 166, 224) 40%
)
no-repeat center center;
background-clip:
padding-box, /* drawn inside including padding area */
border-box;/* drawn also under borders */
background-size:
100% 100%,
110% 150%;/* must be bigger than 100% so it include also borders, else it repeats */
color: white;
box-shadow: 0 0 2px 2px black, inset 0 0 2px black;/* did you want this too ? */
}
<button>BUTTON</button> <button> TO</button> <button> PLAY</button>
If you think this is too much, you also have border-image .
Simply use border-image with a gradient:
button {
padding:20px;
border:5px solid;
border-image:linear-gradient(60deg,#00a7e1 50%,#f6531d 0) 20;
background:transparent;
}
<button>some text</button>

CSS: Skew a buttons border, not the text

I'm looking for an easy way with a single tag (just <a>)to create a skew effect on the borders, but keep the text the way it is.
I would know how do with a span in- or outside, but I don't want to have additional, pretty much zero meaning HTML on the page.
Example below.
You can unskew the child element i.e. provide the opposite skew co-ordinates as you specified for the parent.
Here is a working example
Suppose you have below as you html,
<div class="btn">
<button><div class="btn-text">Click</div></button>
</div>
If we skew the parent element by 20deg then we should skew the child element by -20deg as,
.btn {
-ms-transform: skewX(20deg); /* IE 9 */
-webkit-transform: skewX(20deg); /* Safari */
transform: skewX(20deg);
}
.btn-text {
-ms-transform: skewX(-20deg); /* IE 9 */
-webkit-transform: skewX(-20deg); /* Safari */
transform: skewX(-20deg);
padding: 20px;
}
You can simply accompish desired effect using CSS triangle tricks.
Just add some styles for the ::before and :: after pseudo-classes.
.skewed_button {
background: #32CD32;
color: #000;
text-decoration: none;
font-size: 20px;
display: inline-block;
height: 30px;
margin-left: 15px;
padding: 6px 10px 0;
}
.skewed_button::before {
content: "";
float: left;
margin: -6px 0 0 -25px;
border-left: 15px solid transparent;
border-bottom: 36px solid #32CD32;
height: 0px;
}
.skewed_button::after {
content: "";
float: right;
margin: -6px -25px 0 0 ;
border-left: 15px solid #32CD32;
border-bottom: 36px solid transparent;
height: 0px;
}
Some Text
You can also use clip-path for this, eg:
clip-path: polygon(14px 0%, 100% 0%, calc(100% - 14px) 100%, 0% 100%);
.skewed_button {
background: yellow;
text-decoration: none;
display: inline-block;
padding: 10px 20px;
clip-path: polygon(14px 0%, 100% 0%, calc(100% - 14px) 100%, 0% 100%);
}
Some Text
One solution is to use css triangles on :before and :after. This solution leaves the cleanest HTML.
This jsfiddle demonstrates
.is-skewed {
width: 80px;
height: 40px;
background-color: #f07;
display: block;
color: #fff;
margin-left: 40px;
}
.is-skewed:before,
.is-skewed:after {
content: '';
width: 0;
height: 0;
}
.is-skewed:before {
border-bottom: 40px solid #f07;
border-left: 20px solid transparent;
float:left;
margin-left: -20px;
}
.is-skewed:after {
border-top: 40px solid #f07;
border-right: 20px solid transparent;
float:right;
margin-right: -20px;
}
CSS triangles use thick borders on elements with 0 dimensions with the points at which the borders meet providing the diagonal line required for a triangle (a good visualisation is to look at the corner of a picture frame, where the two borders meet and create triangles). It's important that one border is transparent and one coloured and that they are adjacent (i.e. left and top, not left and right). You can adjust the size, orientation and the lengths of the sides by playing with the border sizes.
For your button, we also use floats and negative margins to pull them outside of the element and line them up right. Position absolute and negative left and right values would also be a good solution to positioning
You can also do :hover states
.is-skewed:hover {
background-color: #40f;
}
.is-skewed:hover:after {
border-top-color: #40f;
}
.is-skewed:hover:before {
border-bottom-color: #40f;
}
It's important to note the use of background-color and border-color and also that the :hover comes first in all the relevant selectors. If the hover came second this would happen

Button with beveled edge on semi-transparent background

I'm trying to create a button with CSS that will sit on a semi-transparent background that has a beveled or cut edge to it. Here is the Photoshop mockup:
I'm able to do this successfully with a solid color background because I can use an pseudo element with that same background and "cover" the edge of the button, but it doesn't work with a semi-transparent background.
Here's what I've got so far, on a solid background: http://codepen.io/anon/pen/GJFpc
I'm beginning to believe this isn't possible with just CSS, but still hoping S.O. can save me once again!
I love a good css challenge so I tried a few things and this is what I could come up with:
http://jsfiddle.net/QE67v/3/
The css (unprefixed) looks like this:
a.cta {
position: relative;
float: left;
padding: 8px 10px;
text-align: center;
text-decoration: none;
text-transform: uppercase;
font-size: 15px;
font-weight: normal;
background-image: linear-gradient(top, #ffffff 0%, #e4e4e4 100%);
box-shadow: inset 0 -2px 1px 2px #fff;
line-height: 16px;
height: 16px;
z-index: 2;
}
a.cta:after {
content: '';
display: block;
position: absolute;
width: 32px;
height: 32px;
right: -16px;
top: 0;
background-image: linear-gradient(top, #ffffff 0%, #e4e4e4 100%);
box-shadow: inset -3px -2px 1px 2px #fff;
transform: skewX(-45deg);
z-index: -1;
}
There are two main differences with your code:
I use a inset box-shadow to achieve the white 'bevel'. You could
probably do this with gradients as well, but I just find the shadows
more intuitive.
In stead of making the button wider and covering the bottom left
corner with a pseudo element in the color of the background, I kept
the button in its normal width and added a pseudo element to which a
applied the skewX transformation. This allows for any background, as
you can see by the gradient I set as a background in my fiddle.
I believe this is what you where after. Feel free to ask if you need any further help/explanation.

css, change other element's background when hovering over a particular element?

Okay first the code..
<td class="btnSaveBooking">
<div class="btnSaveBookingContainder">
<div id="save">
<span class="btnImage"></span><span class="btnsavebookingspan">
<input type="submit" style="color:White;background-color:#6086AC;border-color:White;border-width:2px;border-style:Solid;font-family:Verdana;font-size:10pt;font-weight:bold;" id="btnSaveBooking" value="" name="btnSaveBooking">
(F8)</span></div>
</div>![enter image description here][1]
</td>
The images
Normal
OnMouseOver at the button
OnMouseOver at the imaage
As you can see, when user hovers exactly over the image, then only is the background of image changing, what I want is, when user even hovers over this button, the image should change.
Here's the css
.btnSaveBooking {
border-top: 1px solid #7abbde;
background: #1776a6;
background: -webkit-gradient(linear, left top, left bottom, from(#7ec5e8), to(#1776a6));
background: -webkit-linear-gradient(top, #7ec5e8, #1776a6);
background: -moz-linear-gradient(top, #7ec5e8, #1776a6);
background: -ms-linear-gradient(top, #7ec5e8, #1776a6);
background: -o-linear-gradient(top, #7ec5e8, #1776a6);
padding: 2px 20px 3px 4px;
-webkit-border-radius: 11px;
-moz-border-radius: 11px;
border-radius: 11px;
-webkit-box-shadow: rgba(0,0,0,1) 0 1px 0;
-moz-box-shadow: rgba(0,0,0,1) 0 1px 0;
box-shadow: rgba(0,0,0,1) 0 1px 0;
text-shadow: rgba(0,0,0,.4) 0 1px 0;
color: #f7f7f7;
font-size: 17px;
font-family: Georgia, Serif;
text-decoration: none;
vertical-align: middle;
}
.btnSaveBooking:hover {
border-top-color: #000000;
background: #7288c9;
color: #ffffff;
}
.btnSaveBooking:active {
border-top-color: #3c637d;
background: #3c637d;
}
#save .btnImage
{
background: url("../images/save.png") no-repeat scroll 2px 5px transparent !important;
border-color: transparent !important;
height: 24px;
position: relative;
width: 28px;
margin: 1px 1px 1px 10px;
padding: 4px 2px 0 20px;
}
#save .btnImage:hover
{
background: url("../images/saveN.png") no-repeat scroll 2px 5px transparent !important;
cursor: pointer;
}
You just need to change where the text ':hover' appears in your rule. As it stands, the img itself needs to be hovered. Change the rule so that when it's parent is hovered it changes.
I.e
#save .btnImage:hover
becomes
.btnSaveBooking:hover .btnSaveBookingContainder .btnImage
This way, the image changes as the button's background does. The answer already given gives you a 'two-stage' approach to the change.
Please try this:
.btnSaveBookingContainder:hover .btnImage
{
background: url("../images/saveN.png") no-repeat scroll 2px 5px transparent !important;
cursor:pointer;
width:28px;
height:31px;
}
remove the #save .btnImage:hover css from your existing css, and try with the following style format,
.btnSaveBooking:hover{
/* over border, background & text color */
}
.btnSaveBooking:active
{
/* active border, background & text color */
}
.btnSaveBooking:hover #save .btnImage{
/* provide your hover image style */
}
.btnSaveBooking:active #save .btnImage{
/* provide your active image style */
}

Resources