I'm trying to do the following in sass (scss),
$colors-#{$type}
but I get
undefined variable $colors-
I found a source that was refering to the 3.3 release document, they do mention it, however, I can't find the solution to the issue.
Is there a way to do this?
link to scss
I think the post is misleading. Each issue I found on Github (for instance here or here) recommend the use of a map. And on https://github.com/sass/sass/issues/463 one of the contributors wrote:
We've decided to add an association data type (aka map/hash) and it will address this use case.
Use a map and map-get() to get your style definitions dynamically. You can use it within a mixin, a function or directly. The following example
$colors: (
"green": #0c0,
"blue": #00c,
"red": #c00
);
#mixin my_color($color) {
color: map-get($colors, $color);
}
#function my_color_func($color) {
#return map-get($colors, $color);
}
body {
#include my_color("green"); // use a mixin
background-color: my_color_func("blue"); // use of a function
border: 1px solid map-get($colors, "red"); // use directly
}
generates the following css:
body {
color: #0c0;
background-color: #00c;
border: 1px solid #c00;
}
Related
I'm looking to support multiple themes in my app - moreover, I want to be able to dynamically change themes, either by changing a class on the body element, or even have different parts of the app use different themes.
In my previous project, I did it by adding explicit rules every time I need to use a theme-specific variable:
.theme-light & { background-color: #theme-light-background; }
.theme-dark & { background-color: #theme-dark-background; }
However, that approach does not scale well and adds unnecessary bloat to source files.
Now, I'm looking for a more automated approach for this. I.e. the following
.button {
border-radius: 4px;
background-color: #ui-background;
color: #ui-foreground;
border: 1px solid mix(#ui-background, #ui-foreground, 50%);
}
would turn into something like
.button {
border-radius: 4px;
border: 1px solid #808080;
/* normally we wouldn't expect this to appear here, but in our case
both themes have the same border color so we can't tell the difference */
}
.theme-light .button {
background-color: #fff;
color: #000;
}
.theme-dark .button {
background-color: #000;
color: #fff;
}
As far as I can tell, neither LESS nor SASS can do this in a natural way. It seems that it wouldn't be too difficult to implement it as a separate post-processor, that builds stylesheets for every theme, then compares them and scopes the differences into the corresponding "namespaces". I suspect that something like this might already exist, but I can't find anything.
Any suggestions?
Not sure about Less, but in Sass it can be implemented relatively easy by storing theme information into maps and using ability to pass content blocks into mixins using #content. Here is example of how it may look like, quite fast solution but you can get an idea:
// Themes definition
// - First level keys are theme names (also used to construct theme class names)
// - Second level keys are theme settings, can be referred as theme(key)
$themes: (
light: (
background: #fff,
foreground: #000,
),
dark: (
background: #000,
foreground: #fff,
),
);
// Internal variable, just ignore
$_current-theme: null;
// Function to refer to theme setting by name
//
// #param string $name Name of the theme setting to use
// #return mixed
#function theme($name) {
#if ($_current-theme == null) {
#error "theme() function should only be used into code that is wrapped by 'theme' mixin";
}
#if (not map-has-key(map-get($themes, $_current-theme), $name)) {
#warn "Unknown theme key '#{$name}' for theme '#{$_current-theme}'";
#return null;
}
#return map-get(map-get($themes, $_current-theme), $name);
}
// Theming application mixin, themable piece of style should be wrapped by call to this mixin
#mixin theme() {
#each $theme in map-keys($themes) {
$_current-theme: $theme !global;
.theme-#{$theme} & {
#content;
}
}
$_current-theme: null !global;
}
.button {
border-radius: 4px;
#include theme() {
background-color: theme(background);
color: theme(foreground);
}
}
This piece of code will give you this result:
.button {
border-radius: 4px;
}
.theme-light .button {
background-color: #fff;
color: #000;
}
.theme-dark .button {
background-color: #000;
color: #fff;
}
Looks pretty close to what you're trying to achieve. You can play with this snippet at Sassmeister.
Previously in SCSS (version 3.4.21), I can use variable interpolation to get a specific item from a map:
$colors: (
color-1: #aaa,
color-2: #bbb,
color-3: #ccc
);
#mixin color($shade) {
color: map-get($colors, #{color-}$shade );
}
.element {
#include color(2);
}
Compiles to:
.element {
color: #bbb;
}
Playground Link
In sass 4 (alpha), it doesn't work (or i'm screwing something up):
#{color-}$shade
It doesn't allow me to do that. Is there a reason this was taken out?
I think your syntax is just a bit backwards.
#mixin color($shade) {
color: map-get($colors, gray-#{$shade} );
}
I don't know how to better name this topic
but idea is the following. I want to show different color for a component depends on a parent class.
for this project I use webpack, vue, vue-loader, sass.
I have a sass file this file contents all settings for pages what color should use for specific page
$colors: ".page-home" blue, ".page-about" green;
#each $i in $colors {
$page: nth($i, 1);
$color: nth($i, 2);
#{$page} .component_1, .component_2, .component_n {
color: $color;
}
}
I have a component is written as vue component
#import "colors";
.compoent_1 {
border:1px solid black
}
A issue is I have a lot of components and it very difficult to support the colors file in consistency. When I want to add a new component or remove an old one I always have to go to this file and edit it is annoying me
So how I see the solution is create a main file.
.page-home:blue;
.page-about: green;
I'd like write components in the following style
.component {
border:1px solid black;
color: $PAGE_COLOR;
}
and this code should generate
.page-home .component_1, .component_2, .component_n {
color: blue;
}
.page-about .component_1, .component_2, .component_n {
color: green;
}
thats all. thanks for any suggestion
I’ve got a website that’s using a few different ‘main’ colors. The general HTML layout stays the same, only the colors change depending on the content.
I was wondering if I could set a color variable depending on the CSS selector. This way I can theme my website with a few variables and let Sass fill in the colors.
For example:
$color-1: #444;
$color-2: #555;
$color-3: #666;
$color-4: #777;
body.class-1 {
color-default: $color-1;
color-main: $color-2;
}
body.class-2 {
color-default: $color-3;
color-main: $color-4;
}
/* content CSS */
.content {
background: $color-default;
color: $color-main;
}
I was thinking of using a mixin for this, but I was wondering if there’s a better way to do this—with a function maybe? I’m not that great with Sass, so any help would be appreciated.
I think a mixin is the answer. (As I wrote, variables won’t work.)
#mixin content($color-default, $color-main) {
background: $color-default;
color: $color-main;
}
body.class-1 {
#include content(#444, #555);
}
body.class-2 {
#include content(#666, #777);
}
That SCSS compiles to this CSS:
body.class-1 {
background: #444444;
color: #555555; }
body.class-2 {
background: #666666;
color: #777777; }
If you wanted to group the color values together in your SCSS file, you could use variables in conjunction with the mixin:
$color-1: #444;
$color-2: #555;
$color-3: #666;
$color-4: #777;
body.class-1 {
#include content($color-1, $color-2);
}
body.class-2 {
#include content($color-3, $color-4);
}
as sass documentation explain nicely (https://sass-lang.com/documentation/variables):
Sass variables are all compiled away by Sass. CSS variables are included in the CSS output.
CSS variables can have different values for different elements, but Sass variables only have one value at a time.
Sass variables are imperative, which means if you use a variable and then change its value, the earlier use will stay the same. CSS variables are declarative, which means if you change the value, it’ll affect both earlier uses and later uses.
We may take advantage of that using a combination of sass and css variables to achieve what you want:
//theme colors
$red-cosmo: #e01019;
$green-cosmo: #00c398;
$primary-color: var(--primary-color);
body{
--primary-color: #{$red-cosmo};
}
body.univers-ride{
--primary-color: #{$green-cosmo};
}
So when I call my sass variable $primary-color, it will print as my css variable "var(--primary-color)" that will expand as $green-cosmo only if my body has the "univers-ride" class else it will be $red-cosmo the default color.
If you really want to get hacky you could also define your different color schemes in a single variable like $scheme1: class1 #333 #444, where the first value is always the name, and that is followed by all the colors in that scheme.
You can then use #each:
// Define your schemes with a name and colors
$scheme1: class1 #444 #555;
$scheme2: class2 #666 #777;
$scheme3: class4 #888 #999;
// Here are your color schemes
$schemes: $scheme1 $scheme2 $scheme3;
#each $scheme in $schemes {
// Here are the rules specific to the colors in the theme
body.#{nth($scheme, 1)} .content {
background-color: nth($scheme, 2);
color: nth($scheme, 3);
}
}
This will compile to:
body.class1 .content {
background-color: #444444;
color: #555555; }
body.class2 .content {
background-color: #666666;
color: #777777; }
body.class4 .content {
background-color: #888888;
color: #999999; }
Obviously if you don't want to combine body.class1 and .content in your selectors, you could just specify a mixin content($main, $default) and call it inside the #each using nth just like in the above code, but the point is you don't have to write out a rule for each of your classes.
EDIT There are lots of interesting answers on Creating or referencing variables dynamically in Sass and Merge string and variable to a variable with SASS.
You can also create a mixing that use the ampersand parent selector. http://codepen.io/juhov/pen/gbmbWJ
#mixin color {
body.blue & {
background: blue;
}
body.yellow & {
background: yellow;
}
}
UPDATE: its 2017 and variables does works!
#mixin word_font($page) {
#font-face {
font-family: p#{$page};
src: url('../../static/fonts/ttf/#{$page}.ttf') format('truetype');
font-weight: normal;
font-style: normal;
}
.p#{$page} {
font-family: p#{$page};
}
}
// Loop and define css classes
#for $i from 1 through 604 {
#include word_font($i);
}
If you don't want to use a variable for each color, you can use one variable for all kinds of colors. In the mixin you can choose the right color with nth. For instance, if you write the index of the color as 1, then you get the first color in the color variable.
$colors: #444, #555, #666, #777;
#mixin content($color-default-num, $color-main-num) {
background: nth($colors, $color-default-num);
color: nth($colors, $color-main-num);
}
body.class-1 {
#include content(1, 2);
}
For me the definite answer to my problem was creating a map of maps and loopig through them as follows:
$pallettes: (
light-theme: (
container-color: red,
inner-color: blue,
),
dark-theme: (
container-color: black,
inner-color: gray,
),
);
#each $pallette, $content in $pallettes {
.main.#{$pallette} {
background-color: map-get($content, container-color);
.inner-div {
background-color: map-get($content, inner-color);
}
}
}
You can simply override your scss variables inside of the class wrapper:
$color1: red;
$color2: yellow;
header { background: $color1; }
.override-class {
$color1: green;
header { background: $color1; }
}
Seems to work for me.
Is there a way to add scope to sass variables?
I want to be able to attach a class to my body element. The class will refer to a set of colours that the rest of the stylesheets can access.
I have tried:
#mixin theme_one{
$color: #000;
}
.theme_one{
#include theme_one;
}
and
.theme_one{
$color: #000;
}
I've just come across the same issue myself. I wanted to have different colour themes for different sections of my site.
Using a mixin seems like the best way to go. It's nicely DRY, and easy to use. The trick is not setting your colours in your main styles blocks, but rather using only the mixin for this.
I've set up the theme colours as variables at the top so they can be edited nicely, and I've set them as lists so that multiple values can be passed without hordes of variable being defined.
So:
// Variable Definitions
$defaultColor: black white grey;
$color2: blue green brown;
$color3: red white blue;
#mixin colorSet($color: $defaultColor) {
$link: nth($color, 1);
$border: nth($color, 2);
$background: nth($color, 3);
border-color: $border;
background-color: $background;
.column {
border-color: lighten($border, 10%);
}
a {
color: $link;
&:hover {
color: darken($link, 15%);
}
}
}
// Default colours
body {
#include colorSet();
}
// Scoped colours
.my-theme-3 {
#include colorSet($color3);
}
.my-theme-2 {
#include colorSet($color2);
}
Will produce something like this:
body {
border-color: white;
background-color: grey; }
body .column {
border-color: white; }
body a {
color: black; }
body a:hover {
color: black; }
.my-theme-3 {
border-color: white;
background-color: blue; }
.my-theme-3 .column {
border-color: white; }
.my-theme-3 a {
color: red; }
.my-theme-3 a:hover {
color: #b30000; }
.my-theme-2 {
border-color: green;
background-color: brown; }
.my-theme-2 .column {
border-color: #00b300; }
.my-theme-2 a {
color: blue; }
.my-theme-2 a:hover {
color: #0000b3; }
Edit: Updated to use default mixin values.
In your case no need to use mixin, If you have set of many styles then use mixin,
ie. if you have
#mixin theme_one{
$color: #000;
height: 50px;
}
then use Mixin
otherwise for single property use only variable
$color: #fff;
.some_class01{
color: $color;
background: $color;
}
.some_class22{
border-color: $color;
}
IMP: Variable should assign at the top of your code, it means don't use it after/below where you assigned it :)
Not sure if this is what you are looking for. It looks like you may have tried something similar to this,
which should probably work. (it may just be a matter of using !default)
Your body tag with a class on it..
<body class="theme_one">
</body>
Sass variables defined in stylesheet..
//THEME ONE VARIABLES
.theme_one{
$borderColor:#333 !default;
$fontColor:#999 !default;
}
//THEME TWO VARIABLES
.theme_two{
$borderColor:#CCC !default;
$fontColor:#000 !default;
}
Pre-existing CSS which will be overwritten depending on which class is used on the body tag.
h1.someheader {
color:$fontColor;
border-bottom:1px solid;
border-color:$borderColor;
}
Otherwise you could maybe try something like this. It looks like you may have tried something similar, however there seems to be an error with your mixin ... see note below.
//mixin used to set variables for properties
#mixin themeOne($fontColor,$borderColor) {
color:$fontColor;
border-color:$borderColor;
}
#include themeOne(#000,#CCC);
Pre-existing CSS
h1.someheader {
color:$fontColor
border-color:$borderColor;
border-bottom:1px solid;
}
Also note in your mixin example you are using $color:#000; ... This won't be interpreited properly as it should be color:#000; You can't use variables as selectors
unless you do something like #{$color}:#000;
I haven't quite tested this yet, so some things might need to be adjusted. If this doesn't solve your problem I hope it at least gives you some ideas.