can some one help me...
I have to create,for each "Costumer", a iterator for a non-sequential ID to update the "version" column.
I need a cursor or something else?
Can i get some help?
Example:
ID COSTUMER VERSION
12 ANNA 1
24 ANNA 4
25 ANNA 5
60 ANNA 11
I want to correct the version to be sequential
You could use code something like this:
begin
for r in ( select id, row_number() over (partition by name order by version) as rn
from costumer
)
loop
update costumer
set version = r.rn
where id = r.id;
end loop;
end;
/
The partition by is there because I have assumed you want to have the sequence start from 1 for 'ANNA', then start from 1 again for customer 'JANE' etc. If not you can remove that part.
Here's the way to do it via a single MERGE statement:
MERGE INTO costumer tgt
USING (SELECT ID,
costumer,
VERSION,
ROWID row_id,
row_number() OVER (PARTITION BY costumer ORDER BY VERSION) new_version
FROM costumer) src
ON (tgt.rowid = src.rowid)
WHEN MATCHED THEN
UPDATE SET tgt.version = src.new_version;
Related
I have to create population for the people who has only one product association (ABC) using qualify statement.
For example I have the data
Id Code Prod Date
101 202 ABC 2017-05-31
101 203 DEF 2017-04-30
102 302 ABC 2018-06-30
From the above data I need the data for Id=102 because this id has only one prod relation where as id 101 has both ABC and DEF which should be excluded.
I tried the following
Select id,prod from table1
Qualify row_number() over (partition by id order by Date)=1
Where prod=‘ABC’
With this, I get the two records in my data which I don’t want. Appreciate your help.
Select *
from table1
Qualify min(Prod) over (partition by id)='ABC'
and max(Prod) over (partition by id)='ABC'
Both MIN and MAX return the same value ABC, thus there's no other value
If you want to return the id's that have one prod value (ABC) in the table, you can do something like this:
SELECT id, prod
FROM (
SELECT id, prod
FROM table1
GROUP BY id, prod -- Get unique (id, prod) combinations
QUALIFY COUNT(prod) OVER(PARTITION BY id) = 1 -- Get id's with only one prod
) src
WHERE prod = 'ABC' -- Only get rows with "ABC" prod
The key here is the order in which Teradata processes the query:
Aggregate - GROUP BY
OLAP - COUNT(prod) OVER()
QUALIFY
You may be able to move the WHERE prod = 'ABC' into the QUALIFY clause and get rid of the outer SELECT, not 100% sure.
Just use having, instead of qualify. I don't see any need for window fuctions. Something like:
Select id,prod ,
count(prod)
from
table1
group by
id,
prod
having count(prod) = 1
I have data like this:
I am trying to transform it to this (using SQLite). In the desired result, within each id, each start should be on the same row as the chronologically closest end. If an id has a start but no end (like id=4), then the corresponding end, will be empty (as shown below).
I have tried this
select
id,
max( case when start_end = "start" then date end) as start,
max(case when start_end = "end" then date end ) as end
from df
group by id
But the result is this, which is wrong because id=5 only have one row, when it should have two:
id start end
1 2 1994-05-01 1996-11-04
2 4 1979-07-18 <NA>
3 5 2010-10-01 2012-10-06
Any help is much appreciated
CREATE TABLE mytable(
id INTEGER NOT NULL PRIMARY KEY
,start_end VARCHAR(5) NOT NULL
,date DATE NOT NULL
);
INSERT INTO mytable(id,start_end,date) VALUES (2,'start','1994-05-01');
INSERT INTO mytable(id,start_end,date) VALUES (2,'end','1996-11-04');
INSERT INTO mytable(id,start_end,date) VALUES (4,'start','1979-07-18');
INSERT INTO mytable(id,start_end,date) VALUES (5,'start','2005-02-01');
INSERT INTO mytable(id,start_end,date) VALUES (5,'end','2009-09-17');
INSERT INTO mytable(id,start_end,date) VALUES (5,'start','2010-10-01');
INSERT INTO mytable(id,start_end,date) VALUES (5,'end','2012-10-06');
select
s.id as id,
s.date as 'start',
min(e.date) as 'end' -- earliest end date from "same id&start"
from
-- only start dates
(select id, date
from intable
where start_end='start'
) as s
left join -- keep the start-only lines
-- only end dates
(select id, date
from intable
where start_end='end'
) as e
on s.id = e.id
and s.date < e.date -- not too early
group by s.id, s.date -- "same id&start"
order by s.id, s.date; -- ensure sequence
Left join (to keep the start-only line for id "4") two on-the-fly tables, start dates and end dates.
Take the minimal end date which is just higher than start date (same id, using min()and group by.
Order by id, then start date.
I tested this on a test table which is similar to your dump, but has no "NOT NULL" and no "PRIMARY KEY". I guess for this test table that is irrelevant; otherwise explain the effect, please.
Note:
Internally three pairs of dates for id 5 (those that match end>start) are found, but only those are forwarded with the lowest end (min(end)) for each of the two different combinations of ID and start group by ID, start. The line where end>start but end not being the minimum is therefor not returned. That makes two lines with start/end pairs as desired.
Output (with .headers on):
id|start|end
2|1994-05-01|1996-11-04
4|1979-07-18|
5|2005-02-01|2009-09-17
5|2010-10-01|2012-10-06
UPDATE: Incorporate helpful comments by #MatBailie.
Thank you! This is exactly what I needed to do, only with a few changes:
SELECT
s.value AS 'url',
"AVGDATE" AS 'fieldname',
sum(e.value)/count(*) AS 'value'
FROM
(SELECT url, value
FROM quicktag
WHERE fieldname='NAME'
) AS s
LEFT JOIN
(SELECT url, substr(value,1,4) AS value
FROM quicktag
WHERE fieldname='DATE'
) AS e
ON s.url = e.url
WHERE e.value != ""
GROUP BY s.value;
I had a table like this:
url fieldname value
---------- ---------- ----------
1000052801 NAME Thomas
1000052801 DATE 2007
1000131579 NAME Morten
1000131579 DATE 2005
1000131929 NAME Tanja
1000131929 DATE 2014
1000158449 NAME Knud
1000158449 DATE 2007
1000158450 NAME Thomas
1000158450 DATE 2003
I needed to correlate NAME and DATE in columns based on url as a key, and generate a field with average DATE grouped by multiple NAME fields.
So my result looks like this:
url fieldname value
---------- ---------- ----------
Thomas AVGDATE 2005
Morten AVGDATE 2005
Tanja AVGDATE 2014
Knud AVGDATE 2007
Unfortunately I not have enough posts to make my vote count yet.
I have a query that Counts 2 columns from 2 separate tables using subqueries, which works. Now I have to implement into this query the ability to filter out these results based on the Date of a Call Record. I will post the query in which I am working with:
SELECT (m.FirstName || " " || m.LastName) AS Members,
(
SELECT count(CallToLineOfficers.MemberID)
FROM CallToLineOfficers
WHERE CallToLineOfficers.MemberID = m.MemberID
)
+ (
SELECT count(CallToMembers.MemberID)
FROM CallToMembers
WHERE CallToMembers.MemberID = m.MemberID
) AS Tally
FROM Members AS m, Call, CallToMembers, CallToLineOfficers
Join Call on CallToMembers.CallID = Call.CallID
and CallToLineOfficers.CallID = Call.CallI
WHERE m.FirstName <> 'None'
-- and Call.Date between '2017-03-21' and '2017-03-22'
GROUP BY m.MemberID
ORDER BY m.LastName ASC;
Ok, so table Call stores the Date and its PK is CallID. Both CallToLineOfficers and CallToMembers are Bridge Tables that also contain only CallID and MemberID. With the current query, where the Date is commented out, that Date range should only return all names, but a count of 1 should appear under 1 person's name.
I have tried joining Call.CallID with both Bridge Tables' CallIDs without any luck, though I think this is the right way to do it. Could someone help point me in the right direction? I am lost. (I tried explaining this the best I could, so if you need more info, let me know.)
UPDATED: Here is a screenshot of what I am getting:
Based on the provided date in the sample, the new results, with the Date, should be:
Bob Clark - 1
Rob Catalano - 1
Matt Butler - 1
Danielle Davidson - 1
Jerry Chuska - 1
Tom Cramer - 1
Everyone else should be 0.
At the moment, the subqueries filter only on the member ID. So for any member ID in the outer query, they return the full count.
To reduce the count, you have to filter in the subqueries:
SELECT (FirstName || " " || LastName) AS Members,
(
SELECT count(*)
FROM CallToLineOfficers
JOIN Call USING (CallID)
WHERE MemberID = m.MemberID
AND Date BETWEEN '2017-03-21' AND '2017-03-22'
)
+ (
SELECT count(*)
FROM CallToMembers
JOIN Call USING (CallID)
WHERE MemberID = m.MemberID
AND Date BETWEEN '2017-03-21' AND '2017-03-22'
) AS Tally
FROM Members AS m
WHERE FirstName <> 'None'
ORDER BY LastName ASC;
I have two tables, one with objects, one with properties of the objects. Both tables have a personal ID and a date as "key", but since multiple orders of objects can be done by one person on a single day, it doesn't match well. I do know however, that the entries are entered in the same order in both tables, so it is possible to join on the order, if the personID and date are the same.
This is what I want to accomplish:
Table 1:
PersonID Date Object
1 20-08-2013 A
2 13-11-2013 B
2 13-11-2013 C
2 13-11-2013 D
3 21-11-2013 E
Table 2:
PersonID Date Property
4 05-05-2013 $
1 20-08-2013 ^
2 13-11-2013 /
2 13-11-2013 *
2 13-11-2013 +
3 21-11-2013 &
Result:
PersonID Date Object Property
4 05-05-2013 $
1 20-08-2013 A ^
2 13-11-2013 B /
2 13-11-2013 C *
2 13-11-2013 D +
3 21-11-2013 E &
So what I want to do, is join the two tables and "zip" the group of entries that have the same (PersonID,Date) "key".
Something called "Slick" seems to have this (see here), but I'd like to do it in SQLite.
Any advice would be amazing!
You are on the right track. Why not just do a LEFT JOIN between the tables like
select t2.PersonID,
t2.Date,
t1.Object,
t2.Property
from table2 t2
left join table1 t1 on t2.PersonID = t1.PersonID
order by t2.PersonID
Use a additional column to make every key unique in both tables. For example in SQLite you could use RowIDs to keep track of the order of insertion. To store this additional column in the database itself might be useful for other queries as well, but you do not have to store this.
First add the column ID to both tables, the DDL queries should now look like this: (make sure you do not add the primary key constraint until both tables are filled.
CREATE TABLE table1 (
ID,
PersonID,
Date,
Object
);
CREATE TABLE table2 (
ID,
PersonID,
Date,
Property
);
Now populate the ID column. You can adjust the ID to your liking. Make sure you do this for table2 as well:
UPDATE table1
SET ID =(
SELECT table1.PersonID || '-' || table1.Date || '-' || count( * )
FROM table1 tB
WHERE table1.RowID >= tB.RowID
AND
table1.PersonID == tB.PersonID
AND
table1.Date == tB.Date
);
Now you can join them:
SELECT t2.PersonID,
t2.Date,
t1.Object,
t2.Property
FROM table2 t2
LEFT JOIN table1 t1
ON t2.ID = t1.ID;
I need some help to build SQL Query. I have table having data like:
ID Date Name
1 1/1/2009 a
2 1/2/2009 b
3 1/3/2009 c
I need to get result something like...
1 1/1/2009 a
2 1/2/2009 b
3 1/3/2009 c
4 1/4/2009 Null
5 1/5/2009 Null
6 1/6/2009 Null
7 1/7/2009 Null
8 1/8/2009 Null
............................
............................
............................
30 1/30/2009 Null
31 1/31/2009 Null
I want query something like..
Select * from tbl **where month(Date)=1 AND year(Date)=2010**
Above is not completed query.
I need to get all the record of particular month, even if some date missing..
I guess there must be equi Join in the query, I am trying to build this query using Equi join
Thanks
BIG EDIT
Now understand the OPs question.
Use a common table expression and a left join to get this effect.
DECLARE #FirstDay DATETIME;
-- Set start time
SELECT #FirstDay = '2009-01-01';
WITH Days AS
(
SELECT #FirstDay as CalendarDay
UNION ALL
SELECT DATEADD(d, 1, CalendarDay) as CalendarDay
FROM Days
WHERE DATEADD(d, 1, CalendarDay) < DATEADD(m, 1, #FirstDay)
)
SELECT DATEPART(d,d.CalendarDay), **t.date should be (d.CalendarDay)**, t.Name FROM Days d
LEFT JOIN tbl t
ON
d.CalendarDay = t.Date
ORDER BY
d.CalendarDay;
Left this original answer at bottom
You need DATEPART, sir.
SELECT * FROM tbl WHERE DATEPART(m,Date) = 1
If you want to choose month and year, then you can use DATEPART twice or go for a range.
SELECT * FROM tbl WHERE DATEPART(m,Date) = 1 AND DATEPART(yyyy,Date) = 2009
Range :-
SELECT * FROM tbl WHERE Date >= '2009-01-01' AND Date < '2009-02-01'
See this link for more info on DATEPART.
http://msdn.microsoft.com/en-us/library/ms174420.aspx
You can use less or equal to.
Like so:
select * from tbl where date > '2009-01-01' and date < '2009-02-01'
However, it is unclear if you want month 1 from all years?
You can check more examples and functions on "Date and Time Functions" from MSDN
Create a temporary table containing all days of that certain month,
Do left outer join between that table and your data table on tempTable.month = #month.
now you have a big table with all days of the desired month and all the records matching the proper dates + empty records for those dates who have no data.
i hope that's what you want.