I'm trying to replace a every reference of \' with ' in a file
I've used variations of: sed -e s/\'/"\'"/g file.txt
But they always replace every.single.(single).quote
Any help would be greatly appreciated.
Not sure it's the best solution,I could do it like this:
sed "s/[\]'/\"\'\"/g" file.txt
(putting the backslash character in a character range so it doesn't interfere with the following quote, and protect with double quotes)
Or just extending your syntax, without quotes but using almost the same trick:
sed -e s/[\\]\'/"\'"/g file.txt
An approach trying to conserve as much of the "single-quotedness" of the sed command as possible:
sed 's/\\'"'"'/\'/g'
Just escaping \ with \\ and getting a single quote into the command with '"'"': the first single quote ends the command so far, then we have a double-quoted single quote ("'"), and finally an opening single quote for the rest of the command.
Alternatively, double quoting the whole command and escaping both the backslash and single quote:
sed "s/\\\'/\'/g"
The correct syntax is:
$ echo "foo'bar" | sed 's/'\''/\'/'
foo'bar
Every script (sed, awk, whatever) should always be enclosed in single quotes and you just us other single quotes to stop/restart the script delimiters break out to shell for the minimal portion of the script that's absolutely necessary, in this case long enough to use \'. You need to break out to shell to specify that ' because per shell rules no script enclosed in 's can contain a ', not even if you try to escape it.
echo "foo'bar" | gawk '{gsub(/\47/,"\\'")}1'
foo'bar
The tricky part here is to replace a single quote with ampersand.
First in order to make the single quote manageable use its octal
code here \47 and then escaping ampersand by two back slash. And all of sudden
it becomes feasible :)
Related
i need some help with using sed in unix.
i need to Use the standard Unix command sed to process the input stream and remove all HTML tags, so that for example:
This is my link.
will be replaced by
This is my link.
I tried
sed -r 's/
<[^>]*>
//g'
but it didn't work.
This is extremely bare-bones and unlikely to catch all of the scenarious that HTML will throw at you, but if you are looking to just trim a leading and trailing < and >, then something like this might work:
sed 's/<[^>]*>//g'
But seriously, I'd use a parser.
In the general case you cannot parse HTML with regular expressions.
But, for simple case and assuming that no tag spans more than two lines, you can use:
sed -e 's/<[^<>]*>//g' -e 's/<[^<>]*$//' -e 's/^[^<>]*>//'
The first regex finds and deletes tags contained on one line. The second takes care of tags which begin on a line but end on the next. The third deletes the tails of tags which began on the previous line. I a tag can span more than two lines then something more complicated (or a better tool) is needed.
New to sed, so please bear with me...
I have a php file which contains the following line:
define('TARGET_A','044');
Id like to find that line and replace it with the following using sed:
define('TARGET_K','076');
I have tried:
$ sed -i 's/define\(\'TARGET_A\',\'044\'\)\;/define\(\'TARGET_K\',\'076\'\)\;/' myfile.php
I have tried SEVERAL variations, tried escaping the parens and removing the semicolon, nothing seems to work
ANY help at all GREATLY appreciated, thanks
That's a lot of escaping. How about... no escaping at all?
sed -i '.bak' "s/define('TARGET_A','044');/define('TARGET_K','076');/" myfile.php
Example:
cternus#astarael:~⟫ cat myfile.php
define('TARGET_A','044');
cternus#astarael:~⟫ sed -i '.bak' "s/define('TARGET_A','044');/define('TARGET_K','076');/" myfile.php
cternus#astarael:~⟫ cat myfile.php
define('TARGET_K','076');
This worked for me:
$sed -i "s/define('TARGET_A','044');/define('TARGET_K','076');/" myfile.php
I changed the argument string delimiter to make it simpler.
You can't escape 's in a '-delimited script so you need to escape back to shell with '\'' whenever you need a '. You might be tempted to use " to delimit the script instead but then you're opening it up to shell variable expansion, etc. so you need to be careful about what goes in your script and escape some characters to stop the shell from expanding them. It's much more robust (and generally makes your scripts simpler) to just stick to single quotes and escape back to shell just for the parts you NEED to:
$ sed 's/define('\''TARGET_A'\'','\''044'\'');/define('\''TARGET_K'\'','\''076'\'');/' file
define('TARGET_K','076');
I have a simple sed question.
I have data like this:
2600,Sale,"Approved 911973",244.72
2601,Sale,"Approved 04735C",490.51
2602,Sale,"Approved 581068",52.82
2603,Sale,"Approved 009275",88.10
How do I make it like this:
2600,Sale,Approved,244.72
2601,Sale,Approved,490.51
2602,Sale,Approved,52.82
2603,Sale,Approved,88.10
Notice the numbers after approved are gone as well as the quotes. I can remove quotes with:
sed 's/,$//gn' file
but I don't know how to remove the spaces and digits.
Thanks!
sed "s/\"Approved[^,]*/Approved/g"
It finds the quoted "Approved" followed by any non-comma character, up until the first comma encountered, and replaces it with Approved (no quotes)
2600,Sale,Approved,244.72
2601,Sale,Approved,490.51
2602,Sale,Approved,52.82
2603,Sale,Approved,88.10
Using extended regex with sed:
sed -r 's/"([^[:space:]]*)[^"]*"/\1/g' file
The above regex targets for any quoted string. If you want to target the string Approved, then:
sed -r 's/"(Approved)[^"]*"/\1/g' file
With basic regex:
sed 's/"\(Approved\)[^"]*"/\1/g' file
To target any quoted string, change Approved to [^[:space:]]*
One way using awk(only if the other columns does not contain multiple words as in your sample):
awk -F"[ ,]" '{gsub("\"","");$1=$1}1' OFS=, file
awk -F'[," ]' '{OFS=","; print $1,$2,$4,$7}' file
Output:
2600,Sale,Approved,244.72
2601,Sale,Approved,490.51
2602,Sale,Approved,52.82
2603,Sale,Approved,88.10
I suppose there is no other whitespace.
I know about s// type command in sed, however never saw using s#. Could someone explain what exactly this is doing?
% sed -e "s#SRC_DIR=.*#SRC_DIR=$PROJECT_SRC_DIR#g" -i proj.cfg
I understand that -e defines a script to execute, and the script is withing "", but what exactly s# does?
Checked http://www.grymoire.com/Unix/Sed.html and gnu website, but no luck.
# is a sed delimiter like /. We could use ~, #, /, ;, etc as sed delimiters. They uses a different delimiter # because they don't want to escape / slashes. If you use # as delimiter, you don't need to escape / forward slash. But if you use / as delimiter, you must need to escape / as \/ or otherwise sed would consider / as delimiter.
From sed's manual:
The syntax of the s (as in substitute) command is ‘s/regexp/replacement/flags’. The / characters may be uniformly replaced by any other single character within any given s command. The / character (or whatever other character is used in its stead) can appear in the regexp or replacement only if it is preceded by a \ character.
I am trying to find the following text
get_pins {
and replace it with
get_pins -hierarchical {proc_top_*/
I've tried using sed but I'm not sure what I'm doing wrong. I know that you need # in front of curly braces but I still can't get the command to work properly.
The closest I've come is to this:
sed 's/get_pins #{#/get_pins -hierarchical #{#proc_top_*\//g' filename.txt > output
but it doesn't do the replacement I wanted above.
#merlin2011's answer shows you how to do it with alternative delimiters, but as for why your command didn't work:
It's actually perfectly fine, if you just remove all # chars. from your statement:
sed 's/get_pins {/get_pins -hierarchical {proc_top_*\//'g filename.txt > output
There are two distinct escaping requirements involved here:
Escaping literal use of the regex delimiter: this is what you did correctly, by escaping the / as \/.
Escaping characters with special meaning inside a regex in general: this escaping is always done with \-prefixing, but in your case there is NO need for such escaping: since you're NOT using -E or -r to indicate use of extended regexes - and are therefore using a basic regex - { is actually NOT a special character, so you need NOT escape it. If, by contrast, you had used -E (-r), then you should have escaped { as \{.
The problem is not in the curly braces, it's in the /.
This is exactly why sed lets you do alternate delimiters.
The line below uses ! as a delimiter instead, and works correctly for a simple file with get_pins { in it.
sed 's!get_pins {!get_pins -hierarchical {proc_top_*/!g' Input.txt
Output:
get_pins -hierarchical {proc_top_*/
Update: Based mklement0's comment, and testing with the csh shell, the following should work in csh.
sed 's#get_pins {#get_pins -hierarchical {proc_top_*/#g' Input.txt
This awk should do the replace:
awk '{sub(/get_pins {/,"get_pins -hierarchical {proc_top_*/")}1'