I don't know why but the checkbox at the bottom on this contact form works ( enables the submit button ) but doesn't show the check mark when it's checked.
Hey there if you are removing the class form-control from the checkbox everything is working as expected.
Check the source code of your JavaScript files as well as your Stylesheets for class form-control and eliminate the problem.
Related
I have created a form where a user can pick options prior to submitting the form. I am hiding the checkboxes with display: none and am styling the <label> so that when the user clicks the label it triggers the checkbox.
I've got this to work in vanilla HTML and CSS, however when I try this in React, clicking the label doesn't do anything. ONLY if I unhide the checkbox am I able to click on the checkbox and am able to see the label styling. I want to hide the checkbox though.
Does anyone know how to hide the checkbox and still able to click the label in ReactJS?
Here is the codepen of what I am trying to build in ReactJS.
Use htmlFor instead of for in react (see react supported attributes):
<input type="checkbox" id="check3"/> Fish
<label htmlFor="check3"><span class="fa fa-check"/></label>
As it was already stated - use htmlFor and then try adding onClick event on label instead of on an input. This will add/remove checked attribute on the input itself. I assume that you already use defaultChecked attribute on your input.
I want to add a button in my drupal website which can redirect me to any specified article/page. Any suggestion will be helpful.
Use the Link module.
It allows you to add a field to your content type that has an href value and a Text value. Then you can change it's display output to output title as link which will output a hyperlink with the text you selected, and once clicked will redirect you to whatever href you set.
If you want to style it to look like a button you can add a CSS class to the Link field you added in your content type under manage fields >> Edit the link field.
I am using Bootstrap subtheme so the button CSS classes are already there for me. i simply add btn btn-default if I want to show a button instead of a hyperlink.
PS: DO NOT CREATE BUTTONS IN A BLOCK. Classes should never go into a block. And if you have clients who are going to use that site, they can mess stuff up pretty fast.
Create Block and put html code for button in block. Enable block on pages where you want.
While putting html code of button into block, please make sure that you have selected "Full Html" filter.
I am trying to make a button look like a disabled button using bootstrap's disabled class.
But seems it actually disable it.
Actually I want to disable the button as well as show an alert on the click of that disabled button.
And far as I can understand, bootstrap disabled class is a just a normal css class like any other class, which has nothing to do with the functionality of the control
I am not sure if it does something in the javascript part to make disabled class control actually disabled.
Any work around for this.
It would really be helpful if you could provide a sample of your code. Meanwhile, call the alert on the button click before you disable the button.
In my flex app I have custom tooltips on buttons that hide and show based on user context.
The problem that I dealing with is that when I call my showTips() function I only want to show tooltips on the buttons that visible in the view. So buttons that on a un-selected tab (tabNavigator) should not show the tooltips.
For some reason all tooltips are showing.
Is there a way to detect if a button is not in current view, like on a un-selected tab?
If you gave us some code I could check this out, but would this work?
if(button.parent.visible) { showTip(button);}
Instead of custom coding for each button, make use your tabnavigator's creation policy is set to "auto".
Check this link for more details
http://livedocs.adobe.com/flex/3/html/help.html?content=layoutperformance_05.html
I have a small tabbed navigation setup using CSS. When hovering over the tabs the colour changes, great. However when i click a tab and it navigates to the corresponding page, i would like that tab (the active tab?) to remain highlighted, indicating the current page.
I am currently doing this by using a class (.currenttab ) and then using this class in each HTML file. I am not using:
active
Is there a way for me to use active, rather than using a class in each individual HTML file, or is what i am doing correct?
Thank you in advance.
What you are doing is correct. The :active pseudo selector means something else - the event of activating a control (ie, the time between a user presses the mouse button and releases it).
Using a class to signify the selected item is the way to go.
It's far from ideal, but if you give every page and every tab an id, you can define the highlighting in css instead of html. I ran across a full explanation while looking up the active attribute:
Highlighting Current Page With CSS
A site I designed with this technique (pages, not tabs)
Here are some more examples brainjar Demo
More from Brainjar