I am creating a telegram bot and using sendMessage method to send the messages.
it is easy to mention user using #username, But how to mention user when they don't have username?
If using the telegram app/web, we can mentioned the user by #integer_id (name), and telegram app/web will convert it into clickable text. integer_id will be generated automatically when we select the user, after typing #.
another background:
I am trying to use forceReply and I want to target user, if they have username, I can easily target them, by mentioning them on the text on sendMessage method.
the bot I am creating is a "quiz" like bot. where each player need to take turn, and the bot is sending them the question, each msg from bot will target different player.
NOTE: I am not disabling the Privacy Mode, I don't want telegram bombing my server with msg I don't need. it was overloading my cheap nasty server. so, disabling it not an option.
I am open for other solution, where the bot can listen to selected player.
thanks.
UPDATE 21/10:
I've spoke to BotSupport for telegram, they said, for now Bots can't mention user without username.
so in my case, I still keep using forceReply, and also, gave a short msg to user which doesn't have username to set it up, so they can get the benefit from forceReply function.
According to official documentation it is possible to mention user by its numerical id with markup:
[inline mention of a user](tg://user?id=123456789)
According to this link :
it is possible to mention user by its numerical id with markup:
Markdown style
To use this mode, pass Markdown in the parse_mode field
when using sendMessage. Use the following syntax in your message:
[inline mention of a user](tg://user?id=123456789)
and you can also use HTML style :
HTML style
To use this mode, pass HTML in the parse_mode field when using sendMessage. The following tags are currently supported:
inline mention of a user
Try this:
#bot.message_handler(func=lambda message: True)
def echo_message(message):
cid = message.chat.id
message_text = message.text
user_id = message.from_user.id
user_name = message.from_user.first_name
mention = "["+user_name+"](tg://user?id="+str(user_id)+")"
bot_msg = f"Hi, {mention}"
if message_text.lower() == "hi":
bot.send_message(cid, bot_msg, parse_mode="Markdown")
For python-telegram-bot you can do the following:
user_id = update.message.from_user['id']
user_name = update.message.from_user['username']
mention = "["+user_name+"](tg://user?id="+str(user_id)+")"
response = f"Hi, {mention}"
context.bot.sendMessage(chat_id=update.message.chat_id,text=response,parse_mode="Markdown")
No, this restriction is related to Telegram's privacy policy and prevention of abuse.
It is possible to mention a user when sending messages (BOT API), but that is not what you need:
[inline mention of a user](tg://user?id=<user_id>)
Links tg://user?id= can be used to mention a user by their id without using a username. Please note:
These links will work only if they are used inside an inline link. For example, they will not work, when used in an inline keyboard button or in a message text.
These mentions are only guaranteed to work if the user has contacted the bot in the past, has sent a callback query to the bot via inline button or is a member in the group where he was mentioned.
https://core.telegram.org/bots/api#markdown-style
you need to link to the text: "tg://user?id=" and id
user_id = 123456XX # id of the user to mention
chat_id = 123456XXX # chat id where to mention
user_name = name of user
await bot.send_message(chat_id, f"<a href='tg://user?id={user_id}'>{user_name}</a>", "HTML")
here is an example:
#dp.message_handler()
async def mention(msg: types.Message):
await msg.answer(f"<a href='tg://user?id={msg.from_user.id}'>{msg.from_user.full_name}</a>", "HTML")
Bots are able to tag users by their ID, they just can't do this using the official HTTP Bot API.
Update: Not necessairy anymore, since Telegram added native Support for this.
If you log into your bots account with MadelineProto (PHP) you can use this 'link' to mention someone by it's ID with parse_mode set to markdown
[Daniil Gentili](mention:#danogentili)
Related
I have created telegram bot using telegraf.js
The bot is working correctly, however I need to handle a different thing if the user send message from inside bot directly, let's say the bot should replay with help commands documentations (for example).
the question is:
how to recoginze where the user start chatting? from inside chat group or from inside bot directly?
I tried
var groupInfo =await ctx.telegram.getChat()
without success
I thing the solution would be simple, but I can't find it till now.
thank you in advanced.
You should checkout Telegram docs for Chat type. It has a field called Type and according to the docs:
Type of chat, can be either “private”, “group”, “supergroup” or “channel”
So in telegraf.js you can check the field this ways:
bot.on('text', (ctx) => {
return ctx.reply(`Chat type is: ${ctx.message.chat.type}`)
})
In your case, ctx.message.chat.type == "private" would be messages that are sent to your bot privately and ctx.message.chat.type == "group" or ctx.message.chat.type == "supergroup" are messages sent to groups.
At first i should emphasis that this is a question about telegram GROUP NOT CHANNEL.I need to get group id to send message via telgram api.
I have review this link .
using #rawDataBot needs to add bot to group, that is not possible most of the times. CuteGram does not login (does not send login code) .so i can say none of the proposed method works.
so is there a new method -except adding a bot to the group- to get telgram group ID ?
if the answer is no, i need to know if it is possible to send message to group by using group name?!
the easiest way is to add #chatBotRaw the bot will dump raw data, and you can copy their chat_id or anything else you need,
Remember to remove the bot afterwards because it dumps raw data of every message sent/received in the group.
the simplest way i found is
open web-telegram in a browser
right click on the group name on the left menu
click 'inspect' button
you will see the group id in the attribute data-peer-id="-xxxxxxxxxx" or peer="-xxxxxxxxxx"
You can get chat id throw object "chat"
You can set middleware which handle new update
Example on Node.JS: bot.on('text', ctx => console.log('Chat id is:', ctx.chat.id))
P.S. group id and chat id are same
if using a bot is acceptable, you can use #username_to_id_bot - no need to add it to a group, just send username or invite link and get the id
I try really hard to understand howto use Telegram api with telethon. I have some Channels in Telegram, where i want to delete older Messages. Using inputpeerchannel() i need channel_id (No Problem) and channel_hash. I cant findout howto get this channel_hash by channel_id. Thank you from germany
In order to find channel access_hash, you should resolve channel username. Original MTProto method contacts.resolveUsername#f93ccba3 gets #username and returns channel info including access_hash.
In telethon you need to invoke ResolveUsernameRequest to call the above original MTProto method. You may use this code to resolve username to access_hash:
client = TelegramClient(session_file, api_id=00000, api_hash='XXXXX')
client.connect()
response = client.invoke(ResolveUsernameRequest("your_channel_id"))
print(response.chats[0].access_hash)
client.disconnect()
There are 4 ways to get access hash:
From a Group
From username
From contact list
From chats message
So, if you have id only, there is no way to get access hash
I'm looking to have the information submitted on a google form to be on the email notification that I receive. I have tried several things but I can't seem to get it to work. Any ideas?
Create a new form in Google Docs, if you haven’t done that yet, add the necessary fields to the form and save your changes. Now go back to Google Docs and open the spreadsheet corresponding to that particular form.
Choose Tools > Notification rules... and select the option that says Notify me when... A user submits a form. You can also set how frequently you would like to be notified – right away or with daily digest.
Reference: https://support.google.com/docs/answer/91588
To get the notification in your email, you can refer to the this Google add-on.
Also to enable the data or responses to appear in notification you have to enter a script in the form. which basically tries to extract the columns from the spreadsheet. Sample:
var p = SpreadsheetApp.getActiveSheet();
var column = p.getRange(1,1,1,s.getLastColumn()).getValues()[0];
I hope you build the script by yourself!
I've been attempting to dynamically add a child to my firebase data reference URL, so far with no luck.
Assume I have the following data structure:
MyApp
|-beta_signups
|-users
|--fred
|----email "fred#test.com"
I would like to be able to add people who sign up, as a child based on their email address under the "signups" section. here is what I tried, but it didn't work.
var myDataRef = new Firebase("https://myapp.firebaseio.com/beta_signups/");
$('#submit').click(function() {
var email = $('#email').val();
myDataRef.child(email).push({email: email, beta_key: false});
$('#email').val('We got it.');
});
Any suggestions on how I can dynamically add the child?
You can't use an email address as the key for a child path because it contains invalid characters. See Creating References in the docs.
You are also creating a child based on the email address, and then creating a child of the email by using push. Probably, you should just get rid of the .child(email) bit and use push to create the records.
var user_id = myDataRef.push({email: email, beta_key: false}).name();
The first thing to ask is whether you actually want to store the users by email. Generally, an ID is going to be much more useful (they may change their email later, in which case you have to go re-key all their user data in the system).
If that's a requirement, then you're either going to have to hash them or sanitize them. For example:
// replace all forbidden characters with something that won't appear in the email address
var key = email.replace(/[.$\[\]\/#]/, ','/);
myDataRef.child(key).set({email: email, beta_key: false});