reading an array in a function - arduino

I am trying using the arduino IDE to write a sketch. I have data in progmem and want to move the data with a function to a memory address allocated using malloc. My code is below:
const uint8_t Data_6 [256] PROGMEM = { 0x11, 0x39......};
void setup() {
Serial.begin(57600);
oddBallData (Data_6, 0x00, 256);
}
void main() {
}
void oddBallData(const uint8_t *data, uint8_t mem, uint16_t bytes) {
uint8_t *buff1 = (uint8_t*)malloc(sizeof(bytes));
if (buff1 = 0) {
Serial.println(F("FATAL ERROR - NO MEMORY"));
}
else {
for (uint16_t x = 0; x < 6; x++ ) {
buff1[x] = data[x]; //edited from data[0] to [x] made a mistake in post
Serial.println(buff1[x],HEX);
}
}
buff1[0] = data[0];
Serial.println(buff1[0],HEX);
free(buff1);
}
I have some data saved in progmem and want to write that data to a second device using i2c protocol. I have multiple constant arrays of data saved to my progmem, with different sizes. So I have used malloc to reserve some memory from the heap, inside of the function.
I have not been able to write the data from the progmem so I have stripped things back to so that I am just trying to point to the progmem data using malloc and then print it.
This is where I found a the problem. If I print a single array entry from the data constant. It prints the correct value. If I use a loop I get mixed results, the loop works as long as the condition check value is below 3 or sometimes below 6!!!...?
If above this value the entire print is just garbage. Can anyone explain what I am seeing?

The culprit is probably
uint8_t *buff1 = (uint8_t*)malloc(sizeof(bytes));
sizeof(bytes) returns the size of the variable (which is probably 2 bytes) so you are just allocating 2 bytes of memory. You should use the value directly, eg:
uint8_t* buff1 = malloc(bytes);
Mind that the cast is not required in C since a void* is convertible to any other pointer type directly.

Again - AVR PROGMEM is not directly accessible from memory space, it needs different instruction than access into the RAM. If you are using it like this, you'll get RAM content on passed address, not the FLASH one. You have to use special functions for this. For example memcpy_P(ram_buff,flash_ptr); makes a copy from flash into the ram. Or you can read one byte by pgm_read_byte(flash_ptr + offset)
BTW: If you are using Data_6[0] and it's working, it's just because compiler sees it as a constant and constant can be replaced by its value compile time.

I Guess you just forgot to flush()
try to do Serial.flushI() after Serial.println(buff1[x],HEX);
you can also check flush documentation

Related

Arduino esp32: storing array of struct EEPROM

I'm facing a problem can't be able to resolve to store an array of struct in nvs.
I have this structure composed of variable length String:
typedef struct
{
String Name;
String Surname;
String Status;
String Expiry;
} EpromTags;
EpromTags arraytag[50];
void setup()
{
//should load arraytag from EEPROM here
}
In other routines I have this data coming from a remote server, so I'm saving it to me arraytag
for (int i=0, i<50,i++)
{
arraytag[i].Name = valuename[i];
arraytag[i].Surname = valuesurname[i];
arraytag[i].Status = valuestatus[i];
arraytag[i].Expiry = valueexp[i];
}
//should save to arraytag to EEPROM here
The idea is to load the value of the structure to men on arrive and load back on setup.
I have been able to write single elements to EEPROM but I'm finding difficulties in saving this array of struct.
can someone drive me in the right directions or have suggestions?
The String class handles a char array buffer allocated in heap memory. The object of class String only has a pointer to this buffer. If you store a String object to EEPROM, you don't store the buffer and after retrieving the object the pointer is not valid.
Use C strings (zero terminated character arrays) of predefined size to store a struct with string in EEPROM.
typedef struct
{
char name[NAME_MAX_LENGTH];
char surname[SURENAME_MAX_LENGTH];
char status[STATUS_LENGTH];
char expiry[EXP_LENGTH];
} EpromTags;
To save any data type you can use EEPROM.put(). To read it back you use EEPROM.get(). So you can use a straight forward EEPROM.put(arraytag) to store all 50 items of the array and EEPROM.get(arraytag) to read it back.
The size of the struct is sizeof(EpromTags). The size of the array is count of items multiplied by the size of the item.
Note that the ESP32 EEPROM library emulates the EEPROM in flash memory and requires to call EEPROM.begin() and EEPROM.commit(). See the examples of the ESP32 EEPROM library on how to use it.

Can I assign a #define value to Char*?

I have been writing a C - programm. Where I have a structure with char* members.
#define SS_Value_1 "Value for SS1"
#define SS_Value_1 "Value for SS2"
struct aSamplestruct {
char* s1;
char* s2;
}aSample;
aSample ss;
fun1( &aSample );
I am sending the structure point to a function and I know the best practice is to allocate memory to S1 and copy the string what ever we want and free the allocated memory after usage, As shown below
ss->s1 = (char*) MEM_alloc(sizeof(char) * (strlen(SS_Value_1) + 1);
strcpy(ss->s1, SS_Value_1);
use the variable ss.s1 in a report and do mem free.
MEM_free(ss.s1);
Its working fine no worries. but I have to write the same piece of code for some 10 char* members in 36 different conditions.
The other way is that, without allocating any memory I am able to directly assign the #define values to my structure members as below.
ss->s1 = SS_Value_1;
use this variable in a report and no need to free any memory.
this way also fine, no problems in a sample execution.
what I would like to know is
whether this will cause any memory leaks ?
will it stop executing for large data ?
Thanks in advance
Regards,
Sudhir
This is similar to
char *str;
str = "abc";
That is, you are declaring a char pointer, creating a string literal and assigning its address to the pointer. should work for any amount of data.

C functions returning an array

Sorry for the post. I have researched this but..... still no joy in getting this to work. There are two parts to the question too. Please ignore the code TWI Reg code as its application specific I need help on nuts and bolts C problem.
So... to reduce memory usage for a project I have started to write my own TWI (wire.h lib) for ATMEL328p. Its not been put into a lib yet as '1' I have no idea how to do that yet... will get to that later and '2'its a work in progress which keeps getting added to.
The problem I'm having is with reading multiple bytes.
Problem 1
I have a function that I need to return an Array
byte *i2cBuff1[16];
void setup () {
i2cBuff1 = i2cReadBytes(mpuAdd, 0x6F, 16);
}
/////////////////////READ BYTES////////////////////
byte* i2cReadBytes(byte i2cAdd, byte i2cReg, byte i2cNumBytes) {
static byte result[i2cNumBytes];
for (byte i = 0; i < i2cNumBytes; i ++) {
result[i] += i2cAdd + i2cReg;
}
return result;
}
What I understand :o ) is I have declared a Static byte array in the function which I point to as the return argument of the function.
The function call requests the return of a pointer value for a byte array which is supplied.
Well .... it doesn't work .... I have checked multiple sites and I think this should work. The error message I get is:
MPU6050_I2C_rev1:232: error: incompatible types in assignment of 'byte* {aka unsigned char*}' to 'byte* [16] {aka unsigned char* [16]}'
i2cBuff1 = i2cReadBytes(mpuAdd, 0x6F, 16);
Problem 2
Ok say IF the code sample above worked. I am trying to reduce the amount of memory that I use in my sketch. By using any memory in the function even though the memory (need) is released after the function call, the function must need to reserve an amount of 'space' in some way, for when the function is called. Ideally I would like to avoid the use of static variables within the function that are duplicated within the main program.
Does anyone know the trade off with repeated function call.... i.e looping a function call with a bit shift operator, as apposed to calling a function once to complete a process and return ... an Array? Or was this this the whole point that C does not really support Array return in the first place.
Hope this made sense, just want to get the best from the little I got.
BR
Danny
This line:
byte *i2cBuff1[16];
declares i2cBuff1 as an array of 16 byte* pointers. But i2cReadBytes doesn't return an array of pointers, it returns an array of bytes. The declaration should be:
byte *i2cBuff1;
Another problem is that a static array can't have a dynamic size. A variable-length array has to be an automatic array, so that its size can change each time the function is called. You should use dynamic allocation with malloc() (I used calloc() instead because it automatically zeroes the memory).
byte* i2cReadBytes(byte i2cAdd, byte i2cReg, byte i2cNumBytes) {
byte *result = calloc(i2cNumBytes, sizeof(byte));
for (byte i = 0; i < i2cNumBytes; i ++) {
result[i] += i2cAdd + i2cReg;
}
return result;
}

forcing stack w/i 32bit when -m64 -mcmodel=small

have C sources that must compile in 32bit and 64bit for multiple platforms.
structure that takes the address of a buffer - need to fit address in a 32bit value.
obviously where possible these structures will use natural sized void * or char * pointers.
however for some parts an api specifies the size of these pointers as 32bit.
on x86_64 linux with -m64 -mcmodel=small tboth static data and malloc()'d data fit within the 2Gb range. data on the stack, however, still starts in high memory.
so given a small utility _to_32() such as:
int _to_32( long l ) {
int i = l & 0xffffffff;
assert( i == l );
return i;
}
then:
char *cp = malloc( 100 );
int a = _to_32( cp );
will work reliably, as would:
static char buff[ 100 ];
int a = _to_32( buff );
but:
char buff[ 100 ];
int a = _to_32( buff );
will fail the assert().
anyone have a solution for this without writing custom linker scripts?
or any ideas how to arrange the linker section for stack data, would appear it is being put in this section in the linker script:
.lbss :
{
*(.dynlbss)
*(.lbss .lbss.* .gnu.linkonce.lb.*)
*(LARGE_COMMON)
}
thanks!
The stack location is most likely specified by the operating system and has nothing to do with the linker.
I can't imagine why you are trying to force a pointer on a 64 bit machine into 32 bits. The memory layout of structures is mainly important when you are sharing the data with something which may run on another architecture and saving to a file or sending across a network, but there are almost no valid reasons that you would send a pointer from one computer to another. Debugging is the only valid reason that comes to mind.
Even storing a pointer to be used later by another run of your program on the same machine would almost certainly be wrong since where your program is loaded can differ. Making any use of such a pointer would be undefined abd unpredictable.
the short answer appears to be there is no easy answer. at least no easy way to reassign range/location of the stack pointer.
the loader 'ld-linux.so' at a very early stage in process activation gets the address in the hurd loader - in the glibc sources, elf/ and sysdeps/x86_64/ search out elf_machine_load_address() and elf_machine_runtime_setup().
this happens in the preamble of calling your _start() entry and related setup to call your main(), is not for the faint hearted, even i couldn't convince myself this was a safe route.
as it happens - the resolution presents itself in some other old school tricks... pointer deflations/inflation...
with -mcmodel=small then automatic variables, alloca() addresses, and things like argv[], and envp are assigned from high memory from where the stack will grow down. those addresses are verified in this example code:
#include <stdlib.h>
#include <stdio.h>
#include <alloca.h>
extern char etext, edata, end;
char global_buffer[128];
int main( int argc, const char *argv[], const char *envp )
{
char stack_buffer[128];
static char static_buffer[128];
char *cp = malloc( 128 );
char *ap = alloca( 128 );
char *xp = "STRING CONSTANT";
printf("argv[0] %p\n",argv[0]);
printf("envp %p\n",envp);
printf("stack %p\n",stack_buffer);
printf("global %p\n",global_buffer);
printf("static %p\n",static_buffer);
printf("malloc %p\n",cp);
printf("alloca %p\n",ap);
printf("const %p\n",xp);
printf("printf %p\n",printf);
printf("First address past:\n");
printf(" program text (etext) %p\n", &etext);
printf(" initialized data (edata) %p\n", &edata);
printf(" uninitialized data (end) %p\n", &end);
}
produces this output:
argv[0] 0x7fff1e5e7d99
envp 0x7fff1e5e6c18
stack 0x7fff1e5e6a80
global 0x6010e0
static 0x601060
malloc 0x602010
alloca 0x7fff1e5e69d0
const 0x400850
printf 0x4004b0
First address past:
program text (etext) 0x400846
initialized data (edata) 0x601030
uninitialized data (end) 0x601160
all access to/from the 32bit parts of structures must be wrapped with inflate() and deflate() routines, e.g.:
void *inflate( unsigned long );
unsigned int deflate( void *);
deflate() tests for bits set in the range 0x7fff00000000 and marks the pointer so that inflate() will recognize how to reconstitute the actual pointer.
hope that helps if anyone similarly must support structures with 32bit storage for 64bit pointers.

Is there a way to receive data as unsigned char over UDP on Qt?

I need to send floating point numbers using a UDP connection to a Qt application. Now in Qt the only function available is
qint64 readDatagram ( char * data, qint64 maxSize, QHostAddress * address = 0, quint16 * port = 0 )
which accepts data in the form of signed character buffer. I can convert my float into a string and send it but it will obviously not be very efficient converting a 4 byte float into a much longer sized character buffer.
I got hold of these 2 functions to convert a 4 byte float into an unsinged 32 bit integer to transfer over network which works fine for a simple C++ UDP program but for Qt I need to receive the data as unsigned char.
Is it possible to avoid converting the floatinf point data into a string and then sending it?
uint32_t htonf(float f)
{
uint32_t p;
uint32_t sign;
if (f < 0) { sign = 1; f = -f; }
else { sign = 0; }
p = ((((uint32_t)f)&0x7fff)<<16) | (sign<<31); // Whole part and sign.
p |= (uint32_t)(((f - (int)f) * 65536.0f))&0xffff; // Fraction.
return p;
}
float ntohf(uint32_t p)
{
float f = ((p>>16)&0x7fff); // Whole part.
f += (p&0xffff) / 65536.0f; // Fraction.
if (((p>>31)&0x1) == 0x1) { f = -f; } // Sign bit set.
return f;
}
Have you tried using readDatagram? Or converting the data to a QByteArray after reading? In many cases a char* is really just a byte array. This is one of those cases. Note that the writeDatagram can take a QByteArray.
Generally every thing sent across sockets is in bytes not strings, layers on either end do the conversions. Take a look here, especially the Broadcaster examples. They show how to create a QByteArray for broadcast and receive.
Not sure why the downvote, since the question is vague in requirements.
A 4-byte float is simply a 4 character buffer, if cast as one. If the systems are homogenous, the float can be sent as a signed char *, and bit for bit it'll be the same read into the signed char * on the receiver directly, no conversion needed. If the systems are heterogenous, then this won't work and you need to convert it to a portable format, anyway. IEEE format is often used, but my question is still, what are the requirements, is the float format the same between systems?
If I read it correctly, your primary question seems to be how to receive data of type unsigned char with QT's readDatagram function which uses a pointer to a buffer of type char.
The short answer is use a cast along these lines:
const size_t MAXSIZE = 1024;
unsigned char* data = malloc(MAXSIZE);
readDatagram ( (unsigned char *)data, MAXSIZE, address, port )
I'm going to assume you have multiple machines which use the same IEEE floating point format but some of which are big endian and some of which are little endian. See this SO post for a good discussion of this issue.
In that case you could do something a bit simpler like this:
const size_t FCOUNT = 256;
float* data = malloc(FCOUNT * sizeof(*data));
readDatagram ( (char *)data, FCOUNT * sizeof(*data), address, port )
for (int i = 0; i != FCOUNT; ++i)
data[i] = ntohf(*((uint32_t*)&data[i]));
The thing to remember is that as far as networking functions like readDatagram are concerned, the data is just a bunch of bits and it doesn't care what type those bits are interpreted as.
If both ends of your UDP connection use Qt, I would suggest looking at QDataStream. You can create this from a QByteArray each time you read a datagram, and then read whatever values you require - floats, maps, lists, QVariants, and of course string.
Similarly, on the sending side, you'd create a data stream, push data into it, then send the resulting QByteArray over writeDatagram.
Obviously this only works if both ends use Qt - the data encoding is well-defined, but non-trivial to generate by hand.
(If you want stream orientated behaviour, you could use the fact that QUDPSocket is a QIODevice with a data-stream, but it sounds as if you want per-datagram behaviour)

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