oozie distcp job execution - oozie

Question

I have a oozie work-flow which is performing a distcp operation.
Workflow file is as below :
<workflow-app xmlns="uri:oozie:workflow:0.3" name="distcp-wf">
<start to="distcp-node"/>
<action name="distcp-node">
<distcp xmlns="uri:oozie:distcp-action:0.1">
<job-tracker>${jobtracker}</job-tracker>
<name-node>${namenode}</name-node>
<prepare>
<delete path="${namenode}/tmp/mohit/"/>
</prepare>
<configuration>
<property>
<name>mapred.job.queue.name</name>
<value>${queue_name}</value>
</property>
</configuration>
<arg>-m 1</arg>
<arg>${number_of_mapper}</arg>
<arg>-skipcrccheck</arg>
<arg>${namenode}/tmp/mohit/data.txt</arg>
</distcp>
<ok to="end"/>
<error to="fail"/>
</action>
<kill name="fail">
<message>DistCP failed, error message[${wf:errorMessage(wf:lastErrorNode())}]</message>
</kill>
<end name="end"/>
I want to set the number of mapper using -m using distcp.
How can i do that I have tried with
<arg>-m 1</arg>
and
<arg>1<arg>
But did not worked for me.
The error that I am getting is as below :
Failing Oozie Launcher, Main class [org.apache.oozie.action.hadoop.DistcpMain], main() threw exception, Returned value from distcp is non-zero (-1)
java.lang.RuntimeException: Returned value from distcp is non-zero (-1)

Answer 1

Args are for input/output as described in the documentation
The first arg indicates the input and the second arg indicates the output
For changing the number of producers/reducers use the configuration for example :
<configuration>
<property>
<name>mapred.reduce.tasks</name>
<value>${firstJobReducers}</value>
</property>
</configuration>