When I try to insert datetime value 12:58 AM into the oracle table it gets inserted as 00:58. How can I insert datetime value as 12 in my oracle db? I've set my Oracle time format as 24 hr time. Any suggestions would help.
Insert statement :
INSERT INTO TABLE
(
DATE_CREATED,
PLANNED_START,
PLANNED_COMPLETION
)
VALUES
(
sysdate,
TO_CHAR(p_planned_Start_Date, 'DD-MM-YYYY HH24:MI:SS'),
TO_CHAR(end_date_, 'DD-MM-YYYY HH24:MI:SS')
);
For the 24-hour time, you need to use HH24 instead of HH.
For the 12-hour time, the AM/PM indicator is written as A.M. (if you want periods in the result) or AM (if you don't). For example:
INSERT INTO TEST (LD_DATE) Values (TO_DATE('08/30/2016', 'MM/DD/YYYY '));
And select it as below:
SELECT LD_DATE,
TO_CHAR(LD_DATE, 'DD-MM-YYYY HH24:MI:SS') "Date 24Hr",
TO_CHAR(LD_DATE, 'DD-MM-YYYY HH:MI:SS AM') "Date 12Hr"
FROM test
;
Related
I want to put filter on an Informix query:
WHERE agentstatedetail.eventdatetime < '1753-01-01 00:00:00' - INTERVAL(3) DAY TO DAY
but it fails ...
Please tell where it goes wrong.
As noted in a comment, the solution is to ensure that the string is interpreted as a DATETIME value. The simple way to do that is to use the DATETIME literal notation:
DATETIME(1753-01-01 00:00:00) YEAR TO SECOND
To demonstrate:
CREATE TABLE agentstatedetail
(
eventdatetime DATETIME YEAR TO SECOND NOT NULL PRIMARY KEY,
eventname VARCHAR(64) NOT NULL
);
INSERT INTO agentstatedetail VALUES('1752-12-25 12:00:00', 'Christmas Day, Noon, 1752');
INSERT INTO agentstatedetail VALUES('1752-12-31 12:00:00', 'New Year''s Eve, Noon, 1752');
INSERT INTO agentstatedetail VALUES('1753-01-01 12:00:00', 'New Year''s Day, Noon, 1753');
SELECT * FROM agentstatedetail WHERE agentstatedetail.eventdatetime < '1753-01-01 00:00:00' - INTERVAL(3) DAY TO DAY;
This is your original WHERE clause embedded into a minimal SELECT statement. It yields the error:
SQL -1261: Too many digits in the first field of datetime or interval.
(NB: It would have been helpful to include the error message in the question.)
Here's an alternative version of the query, with the DATETIME literal in place:
SELECT * FROM agentstatedetail
WHERE agentstatedetail.eventdatetime < DATETIME(1753-01-01 00:00:00) YEAR TO SECOND -
INTERVAL(3) DAY TO DAY
;
Output from the sample data:
1752-12-25 12:00:00|Christmas DAY, Noon, 1752
I observe that the value calculated is a constant; you could rewrite the code as:
SELECT * FROM agentstatedetail
WHERE agentstatedetail.eventdatetime < DATETIME(1752-12-29 00:00:00) YEAR TO SECOND
I suspect that the value is passed as a parameter somewhere along the line.
Alternatively, you can cast the string to a DATETIME value and you'd get the same result:
SELECT * FROM agentstatedetail
WHERE agentstatedetail.eventdatetime < CAST('1753-01-01 00:00:00' AS DATETIME YEAR TO SECOND) -
INTERVAL(3) DAY TO DAY
;
or:
SELECT * FROM agentstatedetail
WHERE agentstatedetail.eventdatetime < '1753-01-01 00:00:00'::DATETIME YEAR TO SECOND -
INTERVAL(3) DAY TO DAY
I got parameter
:dateFrom
which gonna be used as an argument in a function as a TIMESTAMP. I need to add to :dateFrom + 7 hours, how can I do that?
If your parameter is not already a timestamp, use to_timestamp or to_date to convert it:
to_timestamp(dateFrom,'mm/dd/yyyy hh24:mi:ss')
(substitute the appropriate mask based on the format of your input parameter)
Then just add 7/24.
to_timestamp(dateFrom,'mm/dd/yyyy hh24:mi:ss') + 7/24;
Adding 1 adds a full day, so adding 1/24 adds 1 hour.
This can also be done with the INTERVAL operator:
to_timestamp(dateFrom,'mm/dd/yyyy hh24:mi:ss') + INTERVAL '7' hour
Here is some PL/SQL that will:
DECLARE
dateFrom TIMESTAMP;
BEGIN
dateFrom := SYSTIMESTAMP;
DBMS_OUTPUT.PUT_LINE('BEFORE :: ' || dateFrom);
dateFrom := dateFrom + INTERVAL '2' HOUR;
DBMS_OUTPUT.PUT_LINE('AFTER :: ' || dateFrom);
END;
/
Look into the INTERVAL operator.
You can do like this,
select dateFrom + interval '7' hours from dual
In the arithmetic of the dates, in Oracle, when you add a number, it is intended as NUMBER OF DAYS.
7 hours are 7/24 days, so you have simply to add 7/24.
I want to fetch few data that occur in particular month. For example, I need to choose all the names of employees who joined in July(irrespective of date). What is the query to choose particular month field alone from date field from database ? How do I compare the month field in database(stored in date of format mm/dd/yyyy) and the user given value of month. I'm using sqlite3 database and date field is set to text.
Thanks in advance.
SQLite only has a small set of date and time functions. You can use them like this:
sqlite> .dump
PRAGMA foreign_keys=OFF;
BEGIN TRANSACTION;
CREATE TABLE t1 (f1 string);
INSERT INTO "t1" VALUES('03/31/1970');
COMMIT;
sqlite> select substr(f1, 7) || '-' || substr(f1, 0, 3) || '-' || substr(f1, 4, 2) from t1;
1970-03-31
sqlite> select strftime("%m", substr(f1, 7) || '-' || substr(f1, 0, 3) || '-' || substr(f1, 4, 2)) from t1;
03
I Resolving this using this code in SQLITE.
If You have dat like this format : "2021-12-23 12:33:01"
then convert it in strftime() format function.
ex.-> Select strftime('%d/%m/%Y',EntryDate) as Date from table_name;
then output comes in
"2021-12-23 12:33:01" to "23-12-2021"
and then fire this query to get MONTH NAME from MONTH NUMBER in SQLITE
-> using case we can fetch it.
Select strftime('%d/%m/%Y',checkInDate) as Date,
case strftime('%m', checkInDate) when '01' then 'JAN'
when '02' then 'FEB' when '03' then 'MAR' when '04' then 'APR' when '05' then 'MAY' when '06' then 'JUN'
when '07' then 'JUL' when '08' then 'AUG' when '09' then 'SEP' when '10' then 'OCT'
when '11' then 'NOV' when '12' then 'DEC' else '' end as Month from AttendanceTable
☻♥ Done Keep Code.
I have a database table field named User_Created_Date of type Varchar.I want to write a query to fetch all records where the difference between Today's date and User_Created_Date is greater than 31 days
pls help
Since your VARCHAR column's date format is DD/MM/YY, use:
select * from Your_Table
where DATEDIFF(day, CONVERT(datetime, User_Created_Date, 3), GETDATE()) > 31;
I store some time values in sqlite in %H:%M string format (for example "15:43"), but I would like to get them out formatted in 12 hour format with AM/PM indicators (for example "3:43 PM"). Is this possible with sqlite (and if so, how), or do I need to do this in my application code?
Unless you extend sqlite with your own custom function, you'll have to do this is code.
sqlite's strftime date formatting function only supports a small subset of its C counterpart, insufficient for your problem. sqlite also lacks a selection construct like IF or CASE, making simple if/else impossible.
Some pseudo code to help you on the way:
if (hourpart of time >= 12)
subtract 12 from hours
append string " pm"
else // hourpart < 12
append string " am"
end if
In SQL you can accomplish this using the CASE syntax.
After taking a closer look at the problem:
SELECT (CASE HOUR(myTimeColumn) >= 12 WHEN 1 THEN
((HOUR(myTimeColumn) - 12) + '-' + MINUTE(myTimeColumn) + ' pm')
ELSE
(HOUR(myTimeColumn) + '-' + MINUTE(myTimeColumn) + ' am')
AS AmPmTime,
someOtherColumn
FROM myTable
I'm not entirely sure that all of that is valid SQLite syntax, but you should be able to correct the bugs.
There are a few special situation that are covered here. I'm using 'now' as a source, but you can adjust it for your string:
select
CASE
--For 00:05, for example.
WHEN (strftime('%H', 'now', 'localtime') - 12) = -12
THEN '12:' || strftime('%M', 'now', 'localtime') ||' '|| 'AM'
--For 12:05, for example.
WHEN (strftime('%H', 'now', 'localtime') - 12) = 0
THEN '12:' || strftime('%M', 'now', 'localtime') ||' '|| 'PM'
--other am time
WHEN (strftime('%H', 'now', 'localtime') - 12) < 0
THEN strftime('%H', 'now', 'localtime') ||':'||
strftime('%M', 'now', 'localtime') ||' '|| 'AM'
ELSE
--other pm time
(cast(strftime('%H', 'now', 'localtime') as integer) - 12) ||':'||
strftime('%M', 'now', 'localtime') ||' '|| 'PM'
END here_you_go_usa;
Do it in your application. Store it in normal 24h format in the database. In the database it can be stored as a Date entry instead of a string (correct me if im wrong)
As PoweRoy recomended, this belongs in the application.
It is recommended that any kind of data stored of used in communication uses a standard, locale-insensitive format: http://www.mihai-nita.net/article.php?artID=20051025a
Here's a working one.. Thanks to Tomas
SELECT
PatientName,
CASE WHEN
StrFTime('%H', AppointmentTime) % 12 = 0 THEN 12
ELSE StrFTime('%H', AppointmentTime) % 12 END
|| ':' ||
StrFTime('%M', AppointmentTime)
|| ' ' ||
CASE WHEN
StrFTime('%H', AppointmentTime) > 12 THEN 'PM'
ELSE 'AM' END
`APP_TIME`
From Patients;
OUTPUT
Abdul Salim, 12:05 PM