-D- curl parameter - http

There is a sample in Jira API doc:
curl -D- -X GET -H "Authorization: Basic ZnJlZDpmcmVk" -H "Content-Type: application/json" "http://kelpie9:8081/rest/api/2/issue/QA-31"
What exactly does the -D- parameter mean? There is no description in curl documentation.
I'm also not sure whether -D- and -D mean the same thing.

It dumps headers to stdout.
The -D flag dumps headers to a file, and the following - instructs it to dump to stdout. From the linked spec:
-D, --dump-header
Write the protocol headers to the specified file.
It doesn't specify for this option, but this works like other options that take a filename:
Use "-" as filename to have the output sent to stdout.

Related

How can I convert a HTTP request to curl?

I'm newbie on this so I would like your help, according to CrazyCall docs I want to test those code examples in terminal using CURL, for example this one:
GET /api/v1/users HTTP/1.1
x-api-token: your-secret-api-key
Account: your-account-hash.crazycall.com
Host: api.crazycall.com
I tried to convert to curl and execute like this:
curl -XGET -H 'x-api-token: mdsRFGRV23XXXXXXX' -H 'Account: lopDOPLSVXXXX.crazycall.com' -H 'Host: api.crazycall.com' /api/v1/users
But it shows me a message <url> malformed
I also added "Content-type: application/json" header but it's still the same.
How can I fix it?
Prepand the protocol and domain (https://api.crazycall.com) to your path (/api/v1/users):
curl -X GET -H 'x-api-token: mdsRFGRV23XXXXXXX' -H 'Account: lopDOPLSVXXXX.crazycall.com' -H 'Host: api.crazycall.com' https://api.crazycall.com/api/v1/users

curl upload file -T

I get the error curl: Can't open 'files=#1.txt'! when trying to run code:
curl -v -XPOST -k -H "Accept: application/json" -T "files=#1.txt" https://192.168.1.102/
any suggestion on how to pass the text file's name properly?
-T is for PUT and wants a file name only:
curl -T 1.txt https://192.168.1.102/
You seem to want to POST a file? If you want it sent "plainly", you probably want:
curl -H "Accept: application/json" --data-binary #1.txt https://192.168.1.102/
If you want to instead send the file as a multipart formpost, you might do it similar to:
curl -F files=#1.txt https://192.168.1.102/

Curl-convert to a simple http request?

I have some curl request, in which i would like to build from it a basic POST request-authenticated (with headers etc), i couldn't find any tool that convert that :
curl -X POST 'https://api.twilio.com/2010-04-01/Accounts/xxxxxxxxxxxxx/Calls.json' \
--data-urlencode 'To=xxxxxxx65542' \
--data-urlencode 'From=+xxxxxxx4215' \
-d 'Url=https://api.twilio.com/2010-04-01' \
-d 'Method=GET' \
-d 'FallbackMethod=GET' \
-d 'StatusCallbackMethod=GET' \
-d 'Record=false' \
-u ACbe68cddxxxxxxxxxxxx3aba243cc4cdb:0f442xxxxxxxxxxxxxxxxxxx
So how would my POST request should look like ?
Okay so i was trying to figure out how to send a text message from an ESP8266 nodeMcu v0.9 module. It is capable of working like an arduino with the arduino ide 1.6.4.
Anyways, I found http://textbelt.com and it only shows a simple CURL way of sending the text message.
This is the CURL message it wants you to send
$ curl -X POST http://textbelt.com/text \ -d number=5551234567 \ -d "message=I sent this message for free with textbelt.com"
So to convert to a normal HTTP POST command i did the following. (this works in Arduino IDE)
number and message are String objects.
String messageToSend = "number="+number+"&message="+message;
client.print("POST /text HTTP/1.1\r\n");
client.print("Host: textbelt.com\r\n");
client.print("Content-Type: application/x-www-form-urlencoded\r\n");
client.print("Content-Length: ");
client.print(messageToSend.length());
client.print("\r\n\r\n");
client.print(messageToSend);
At first i tried without the Content-Type but that didn't seem to work. So i had to add the type of content i was sending as well.
If you were to monitor the network traffic with say WireShark you would see
POST /text HTTP/1.1\r\n
Host: textbelt.com\r\n
Content-Type: application/x-www-form-urlencoded\r\n
Content-Length: 48\r\n
\r\n
number=5551234567&message=this is a text message
I may have been able to use less text with text/plain as the content-type but i think it may need the application urlencoded type to work.
Hope this helps someone else trying to convert curl to http.
From the cURL man page :
-H, --header (HTTP) Extra header to use when getting a web page. You may specify any number of extra headers. Note that if you
should add a custom header that has the same name as one of the
internal ones curl would use, your externally set header will be
used instead of the internal one. This allows you to make even
trickier stuff than curl would nor‐ mally do. You should not replace
internally set headers without knowing perfectly well what you're
doing. Remove an internal header by giving a replacement without
content on the right side of the colon, as in: -H "Host:". If you send
the custom header with no-value then its header must be terminated
with a semicolon, such as -H "X-Custom- Header;" to send
"X-Custom-Header:".
curl will make sure that each header you add/replace is sent with the
proper end-of-line marker, you should thus not add that as a part of
the header content: do not add newlines or carriage returns, they will
only mess things up for you.
See also the -A, --user-agent and -e, --referer options.
This option can be used multiple times to add/replace/remove multiple
headers.
Amazon AWS makes heavy use of headers for authentication. A quick Google should lead to many examples such as this one from http://tmont.com/blargh/2014/1/uploading-to-s3-in-bash :
curl -X PUT -T "${file}" \
-H "Host: ${bucket}.s3.amazonaws.com" \
-H "Date: ${dateValue}" \
-H "Content-Type: ${contentType}" \
-H "Authorization: AWS ${s3Key}:${signature}" \
https://${bucket}.s3.amazonaws.com/${file}
All you need to do is adapt the AWS examples for your twilio use.
To make the example into a POST, just change PUT to POST and add your POST fields -d "field1=val1&field2=val2&field3=val3"
You can specify the headers using --header and the type of request (POST) by using -X / --request parameters.
Example:
curl --request POST --header "X-MyHeader: MyAuthenticatedHeader" www.stackoverflow.com
In your case it should be:
curl -X POST 'https://api.twilio.com/2010-04-01/Accounts/xxxxxxxxxxxxx/Calls.json' \
--header 'X-MyHeader: MyAuthenticatedHeader' \
--data-urlencode 'To=xxxxxxx65542' \
--data-urlencode 'From=+xxxxxxx4215' \
-d 'Url=https://api.twilio.com/2010-04-01' \
-d 'Method=GET' \
-d 'FallbackMethod=GET' \
-d 'StatusCallbackMethod=GET' \
-d 'Record=false' \
-u ACbe68cddxxxxxxxxxxxx3aba243cc4cdb:0f442xxxxxxxxxxxxxxxxxxx

FireBase, NEST. I can GET, but cannot PATCH using curl. Why am I getting a 400 error?

I am using the url at the developer-api.nest.com site, and my request is re-directed to the firebase-apiserver01...01.dapi.production.nest.com
I get the correct structured data back, using this dos command:
curl -v -k -L -X GET "https://developer-api.nest.com/structures/Za6hCZpmt4g6mBTaaA96yuY87lzLtsucYjbxW_b_thAuJJ7oUOelKA/?auth=c.om2...AeiE"
I get the error 'Invalid content sent' when I send this PATCH
curl -v -k -L -X PATCH "https://developer-api.nest.com/structures/Za6hCZpmt4g6mBTaaA96yuY87lzLtsucYjbxW_b_thAuJJ7oUOelKA/?auth=c.om2...AeiE" -H "Content-Type: application/json" -d '{"away":"home"}'
I have tried adding '.json' before the question mark, but get the same error.
To set the structure to home/away you'll need to send a PUT request for example as follows:
curl -v -L -X PUT "https://developer-api.nest.com/structures/g-9y-2xkHpBh1MGkVaqXOGJiKOB9MkoW1hhYyQk2vAunCK8a731jbg?auth=<AUTH_TOKEN>" -H "Content-Type: application/json" -d '{"away":"home"}'
Hope that helps
--Nagesh

Send request to cURL with post data sourced from a file

I need to make a POST request via cURL from the command line. Data for this request is located in a file. I know that via PUT this could be done with the --upload-file option.
curl host:port/post-file -H "Content-Type: text/xml" --data "contents_of_file"
You're looking for the --data-binary argument:
curl -i -X POST host:port/post-file \
-H "Content-Type: text/xml" \
--data-binary "#path/to/file"
In the example above, -i prints out all the headers so that you can see what's going on, and -X POST makes it explicit that this is a post. Both of these can be safely omitted without changing the behaviour on the wire. The path to the file needs to be preceded by an # symbol, so curl knows to read from a file.
I need to make a POST request via Curl from the command line. Data for this request is located in a file...
All you need to do is have the --data argument start with a #:
curl -H "Content-Type: text/xml" --data "#path_of_file" host:port/post-file-path
For example, if you have the data in a file called stuff.xml then you would do something like:
curl -H "Content-Type: text/xml" --data "#stuff.xml" host:port/post-file-path
The stuff.xml filename can be replaced with a relative or full path to the file: #../xml/stuff.xml, #/var/tmp/stuff.xml, ...
If you are using form data to upload file,in which a parameter name must be specified , you can use:
curl -X POST -i -F "parametername=#filename" -F "additional_parm=param2" host:port/xxx
Most of answers are perfect here, but when I landed here for my particular problem, I have to upload binary file (XLSX spread sheet) using POST method, I see one thing missing, i.e. usually its not just file you load, you may have more form data elements, like comment to file or tags to file etc as was my case. Hence, I would like to add it here as it was my use case, so that it could help others.
curl -POST -F comment=mycomment -F file_type=XLSX -F file_data=#/your/path/to/file.XLSX http://yourhost.example.com/api/example_url
I was having a similar issue in passing the file as a param. Using -F allowed the file to be passed as form data, but the content type of the file was application/octet-stream. My endpoint was expecting text/csv.
You are able to set the MIME type of the file with the following syntax:
-F 'file=#path/to/file;type=<MIME_TYPE>
So the full cURL command would look like this for a CSV file:
curl -X POST -F 'file=#path/to/file.csv;type=text/csv' https://test.com
There is good documentation on this and other options here: https://catonmat.net/cookbooks/curl/make-post-request#post-form-data
I had to use a HTTP connection, because on HTTPS there is default file size limit.
https://techcommunity.microsoft.com/t5/IIS-Support-Blog/Solution-for-Request-Entity-Too-Large-error/ba-p/501134
curl -i -X 'POST' -F 'file=#/home/testeincremental.xlsx' 'http://example.com/upload.aspx?user=example&password=example123&type=XLSX'

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