I'm using the SMACSS method of writing my SCSS code, and I have a subclass that I want to reference if it also has another subclass.
HTML
<div class="parent-class parent-class-subclass1 parent-class-subclass2">
SCSS
.parent-class {
&-subclass1.&-subclass2 {
//Styles here
}
}
Any idea how I can do this?
So, when parent element also has subclass1 && subclass2, apply styles?
#katniss.everbean Yes, but the way you wrote it makes you have to duplicate the code.
After searching around for a while I stumbled upon this solution that works perfectly by writing any & references after the first one like #{&}:
SASS
.parent-class {
&#{&}-subclass1#{&}-subclass2{
border: 1px solid red;
}
}
Compiles into (CSS)
.parent-class.parent-class-subclass1.parent-class-subclass2 {
border: 1px solid red;
}
I found it on the SASS GitHub page.
...and I have a subclass that I want to reference if it also has another
subclass.
So, when parent element also has subclass1 && subclass2, apply styles?
You only need one & to join the nested selector to the parent class as a sibling. Then write the two subclasses as a regular sibling selector (next to each other without a space in between to indicate they're both required sibling classes).
The SCSS would look like this:
.parent-class {
//some styles
&.parent-class-subclass1.parent-class-subclass2 {
//subclass styles
}
}
That's equivelant to the following CSS
.parent-class {
//some styles
}
.parent-class.parent-class-subclass1.parent-class-subclass2 {
//some other styles
}
To keep your modular naming structure and not have to write out the whole subclass name, you could try using wildcard selectors. I'm not sure it actually ends up looking any better than just writing out the whole class name though.
Here's a codepen that demonstrates:
http://codepen.io/anon/pen/vXKZYA
And the basic code in that pen for posterity:
<div class="parent-class parent-class-subclass1 parent-class-subclass2">
some text that has all the goods
</div>
.parent-class {
color: #0000ff;
&[class*="-subclass1"][class*="-subclass2"] {
font-size: 20px;
font-family: sans-serif;
}
}
you should do it like this
<div class="parent-class subclass1 subclass2">
.parent-class {
&.subclass1.subclass2 {
//Styles here
}
}
or you can even do it like this
.parent-class {
&.subclass1 {
//subclass1 Styles here
&.subclass2 {
//subclass1 & 2 Styles here
}
}
}
Related
Is there a way to have a class or any selector with specific styles, and then share, import or assign those styles to a another selector. This is to avid creating multiple classes and not having to go back to the HTML code all the time to assign such classes.
For example:
.orangeText{
color:orange
}
.strongtext{
font-weight:900
}
a regular scenario would use those clases like this:
<div class="orangeText strongtext">My orange Strong Text</div>
I am looking for something like this:
.orangeText{
color:orange
}
.strongtext{
font-weight:900
}
.orangeStrongTitle{
#.orangeText; /* Import styles from .orangeText*/
#.strongtext; /* Import styles from .strongtext*/
text-decoration:underline;
}
ON HTML:
<div class="orangeStrongTitle">My orange Strong Text</div>
PLEASE NOTE THAT #.orangeText IS MY INVENTION TO GIVE AN EXAMPLE OF WHAT I WANT, I DON'T KNOW IF SUCH THING EXISTS, I WAS INSPIRED ON #import
Is this possible?
With traditional CSS it seem's that you can't.
See this topic : Is it possible to combine classes in CSS?
Unless you use LESS or SASS's 'mixin' features, there's no real way in
plain CSS to "inherit" other classes. The best you can do is apply
all three classes to your DOM element. If your problem is that you
have a ton of those classes already on a page and you want to add
properties to all of them, you can do:
.foo, .bar, .foobar {
color: red;
}
and that will apply color: red to any element that has .foo or .bar or
.foobar.
EDIT
Since you're asking for an exemple, here is how the mixin feature of SASS works :
#mixin mixin-name {
margin: 0;
padding: 0;
}
ul {
#include mixin-name;
}
Having this will compile into this :
ul {
margin: 0;
padding: 0;
}
I am writing a stylesheet to extend a base stylesheet whose CSS has many pseudo classes applied to certain elements. I would like my stylesheet to override some of these styles with a single style that is applied to an element no matter what state it is in, whether hovered on, focussed etc.
For example, the base stylesheet might have the styles
.classname {
color:#f00;
}
.classname:hover {
color:#0f0;
}
.classname:active {
color:#00f;
}
but adding the following after these styles does not override the pseudo states...
.classname {
color:#fff;
}
The following works, but it feels a lot of code for something that seems simple.
.classname,
.classname:active,
.classname:hover,
.classname:focus,
.classname:visited,
.classname:valid{
color:#fff;
}
Likewise, I know an !important would work, but that's normally a warning sign of a poorly structured stylesheet.
Is there anything along the lines of a .classname:* that would cover every possible state, or some way to simply remove all pseudo classes?
If you are able to put the classes inside some wrapper id you can prevent the pseudo-classes to take effect due to specificity:
body {
background: black;
}
.classname {
color:#f00;
}
.classname:hover {
color:#0f0;
}
.classname:active {
color:#00f;
}
#a .classname {
color:#fff;
}
<div class="classname">all pseudo works</div>
<div id="a">
<div class="classname">none of the pseudo works</div>
</div>
I think, it could be solved with :any pseudo-class.
Google
<style>
a:link { color: blue; }
a:hover { color: red; }
a:-webkit-any(a) { color: green; }
</style>
https://jsfiddle.net/ycfokuju
Browser support is not perfect: https://developer.mozilla.org/en/docs/Web/CSS/:any
Edit:
Actually, as I discovered, this answer isn't very accurate. (Despite it was upvoted 4 times, lol).
First of all, you don't need :any fot this task. You need :any-link.
The second point is that :any itself is a former name of :matches. So, in our terminology we should use terms :any-link and :matches and don't use term :any.
Example of using :any-link: https://developer.mozilla.org/en-US/docs/Web/CSS/:any-link
Examples of using :mathes: https://css-tricks.com/almanac/selectors/m/matches/
I haven't edited the code itself, so fix it yourself according to this new information.
I am trying to refactor some css looking like this:
path.myClass {
//some CSS
}
.someOtherClass.myClass {
//some other CSS
}
I am struggling to find the right syntax for the first part. I am trying to have something looking like this:
.myClass {
path.& {
// some CSS
}
.someOtherClass {
// some other CSS
}
}
How can I refactor this correctly?
You can do it like below. Since the top level selector already has . there is no need to add it again before the parent selector (&) in the inner selector. The second one is fairly straightforward as you can append the parent selector either at the start or at the end. The order of classes doesn't matter.
(Note: There should be no space before the parent selector as it would change the meaning.)
.myClass {
path&{
color: red;
}
.someOtherClass& { /* can do &.someOtherClass also, order doesn't matter */
color: blue;
}
}
Below is the compiled CSS output:
path.myClass {
color: red;
}
.someOtherClass.myClass {
color: blue;
}
I'm trying to figure out how to back nest specifically to the parent of the css nest I'm in. Meaning, my current set up is a parent class to a span to a before pseudo. I need to change a style on the pseudo based on a modifier on the parent. If I do this:
.parent {
span {
&:before {
// styles
.modifier & {
// Other styles
}
}
}
}
The output is .modifier .parent span:before What I need is .parent.modifier span:before
Isn't there a way to do this without adding the modifier to the parent and pathing to the pseudo again? This is what I want to avoid.
.parent {
span {
&:before {
// styles
}
}
&.modifier {
span {
&:before {
// Other Styles
}
}
}
}
This is certainly possible, it does require the use of some of the less known sass functions #at-root, & ampersand and string interpolation #{}.
Basically it works in the following manner;
Use #at-root to jump outside of the class, to the 'root'.
We place our class after that, I've used .--modifer-is-red.
We attach the classes that we jumped outside of by using interpolation of the &, #{&}.
Live Example
Example used for clarity
.parent {
span {
&:before {
// styles
color: black;
// Modifiers attached to the parent
#at-root .--modifier-is-red#{&} {
color: red;
}
}
}
}
// output
// .--modifier-is-red.parent span:before {
// color: red;
// }
Exact example to reflect your code
.parent {
span {
&:before {
// styles
#at-root .modifier#{&} {
// Other styles
}
}
}
}
There is some limitations to this, also it does look slightly odd that the modifier is placed before the parent in the output, but the browser doesn't mind.
I hope this solves your problem.
Isn't there a way to do this without adding the modifier to the parent and pathing to the pseudo again?
No, because you only have the & variable to work with, which is always a single unit consisting of the entire complex selector. You can't specify where exactly in the middle of the complex selector you want your modifier to go. The best you can do is attach it as a compound selector or use it with a combinator.
Can I do something like the following?
.class1{some stuff}
.class2{class1;some more stuff}
Update 1: There is a CSS3 spec for CSS level 3 nesting. It's currently a draft.
https://tabatkins.github.io/specs/css-nesting/
Update 2 (2019): We now have a CSSWG editors draft
https://drafts.csswg.org/css-nesting-1/
Update 3 (2022): We now have a W3C First Public Working Draft https://www.w3.org/TR/css-nesting-1/
If approved, the syntax would look like this:
table.colortable {
& td {
text-align:center;
&.c { text-transform:uppercase }
&:first-child, &:first-child + td { border:1px solid black }
}
& th {
text-align:center;
background:black;
color:white;
}
}
.foo {
color: red;
#nest & > .bar {
color: blue;
}
}
.foo {
color: red;
#nest .parent & {
color: blue;
}
}
Not possible with vanilla CSS. However you can use something like:
Sass
Sass makes CSS fun again. Sass is an
extension of CSS3, adding nested
rules, variables, mixins, selector
inheritance, and more. It’s translated
to well-formatted, standard CSS using
the command line tool or a
web-framework plugin.
Or
Less
Rather than constructing long selector
names to specify inheritance, in Less
you can simply nest selectors inside
other selectors. This makes
inheritance clear and style sheets
shorter.
Example:
#header {
color: red;
a {
font-weight: bold;
text-decoration: none;
}
}
Not with pure CSS. The closest equivalent is this:
.class1, .class2 {
some stuff
}
.class2 {
some more stuff
}
Not directly. But you can use extensions such as LESS to help you achieve the same.
No.
You can use grouping selectors and/or multiple classes on a single element, or you can use a template language and process it with software to write your CSS.
See also my article on CSS inheritance.
I do not believe this is possible. You could add class1 to all elements which also have class2. If this is not practical to do manually, you could do it automatically with JavaScript (fairly easy to do with jQuery).
If you cannot wait until native CSS nesting goes official, you can use Container Queries to do it. As of now, it is supported (partially) by Chrome & Edge 105+, as well as Safari 16+.
It will looks like this:
.class1 {
container-type: inline-size;
container-name: my-container;
// other style rules
}
#container my-container (min-width: 0px) {
.class2 {
// some style rules
}
}
More details can be found at here.
Try this...
Give the element an ID, and also a class Name. Then you can nest the #IDName.className in your CSS.
Here's a better explanation
https://css-tricks.com/multiple-class-id-selectors/