Unix script changing directory - unix

Question

I am in root directory, i am creating a script that will take me from root > Home > Logs and inside logs delete 3 log files.
Script will check if they exist, if YES it will delete it.
I am facing some syntax problems if you could help.
Thanks
My code:
#!/bin/sh
cd Home/Log
if [ -e error1.log ]
then
rm error1
fi
if [ -e error2.log ]
then
rm error1
fi
if [ -e error3.log ]
then
rm error1
fi
when i execute the file in root using ./delete here is what is am getting as errors:
$ ./delete
: No such file or directoryme/Log
./delete: line 14: syntax error near unexpected token `fi'

Answer 1

I am in root directory
When writing a script, it's almost always better not to assume things like that. If you know where the files are and it's not important that they're somewhere relative to what happens to be your current working directory, just name them.
Here are three ways you could accomplish what you want safely.
#!/bin/sh
dir=/Home/Log
rm -f ${dir}/error1.log ${dir}/error2.log ${dir}/error2.log
or
#!/bin/sh
dir=/Home/Log
rm -f ${dir}/error{1,2,3}.log
or
#!/bin/sh
set -e
cd /Home/Log && rm -f error1.log error2.log error2.log
For anything nontrivial, set -e is your friend. In your example, nothing happens later in the script. What you don't want is to keep going thinking you've changed directories, but haven't, and wind up scribbling somewhere you didn't intend. Many have lost much that way.