I'm trying to get the following query in bookshelf's, any ideas? (this query is working and returns the required result)
SELECT "restaurants".*, "meals".*, ( select count(*) from "public"."visitors" as "visitors" where "visitors"."meal_id" = "meals"."id") as "visitorsMealsCount" FROM "public"."restaurants" as "restaurants" inner join "public"."meals" as "meals" ON "meals"."restaurant_id" = "restaurants"."id" WHERE "restaurants"."id" = '123'
Another question, after I'm using belongsTo and hasMany (for example) i expected the return object will be similar to that
restaurants (obj)
meals (obj)
visitorsMealsCount (attribute)
to me your SQL statement doesn't match the concept of an ORM tool like Bookshelf - it neither returns restaurants nor meals, but a grand mixture.
As to your second question: How about using new Restaurant({id: '123'}).fetch({ withRelated: ['meals']}) ?
visitorsMealsCount: In the documentation I see
adminAccounts: function() {
return this.belongsToMany(Account).query({where: {access: 'admin'}});
},
so maybe
visitorsMealsCount: function() {
return this.belongsToMany(Visitor).count();
}
works? (I haven't tried it.)
Related
I have a simple case class MyContext(queries: Query) that I provide to the schema with : sangria.schema.Schema(deriveContextObjectType[MyContext, Query, Unit](_.queries)
MyQuery is a trait of Query
trait MyQuery {
#GraphQLField
def item(ctx: Context[MyContext, Unit])(id: String) ...
}
This works great. But what if I want to nest resolvers?
query {
item {
status # status is resolved from source B
price # price is resolved from source C
}
}
Is that possible to achieve? Would I return an ObjectType[Item] that has properties status and price annotated with #GraphQLField?
I think you can use deriveObjectType for an Item. It is also able to handle the #GraphQLField annotation (as an alternative you can also use IncludeMethods macro setting). Here is an example:
implicit val ItemType = deriveObjectType[MyContext, Item]()
Really appreciate #tenshi's answer! I tried using the deriveObjectType but was getting a type error:
type mismatch;
found : sangria.schema.Context[MyContext,Item]
required: sangria.schema.Context[MyContext,Unit]
But using deriveContextObjectType in conjunction with AddFields is working:
def schema = sangria.schema.Schema(
deriveContextObjectType[MyContext, Query, Unit](_.queries,
AddFields(
Field(
name = "item",
fieldType = deriveContextObjectType[MyContext, Item, Unit](_ => new Item),
resolve = _ => ()
)
))
)
And the Schema looks good, yielding:
type Query {
item: Item!
}
I have CLub model (clubs) hasMany with User model like
Club n-n User
and I have UserClub model with columns: id, club_id, user_id, etc
In Club model
public function getCountUsers()
{
return $this->hasMany(UserClub::className(), ['club_id'=>'id'])->count();
}
I wanna count all User on Club as code:
$query = Club::find()
->joinWith(['countUsers']);
// ->with('countUsers');
->all();
so it is not working and throwing an error
Club has no relation named \"countUsers\"."
Because it isn't a relation as it does not return a model object or an array of model objects, instead you are using ->count() that makes it return a string that contains the total count for the user against the club.
If you are looking to get a count for the users against all the Clubs you can use the currently defined relation like $club->countUser see below.
$clubs=Club::find()->all();
foreach($clubs as $club){
echo $club->countUser;
}
or change the relation to
public function getCountUser(){
return $this->hasMany(UserClub::className(), ['club_id'=>'id']);
}
and use it like
$clubs=Club::find()->all();
foreach($clubs as $club){
echo count($club->countUser);
}
or like below
$clubs=Club::find()->all();
foreach($clubs as $club){
echo $club->getCountUser()->count();
}
EDIT
You are actually trying to transform the following query using ActiveRecord as far as I understood from the discussion.
SELECT clubs.id, count(user_clubs.id) as total
FROM
clubs
left join user_clubs on clubs.id = user_clubs.club_id
group by clubs.id
if that is correct you can use the following
Clubs::find ()
->alias ( 'c' )
->select ( [ new \yii\db\Expression ( 'c.[[id]], count(uc.[[id]]) as total' ) ] )
->leftJoin ( '{{%user_clubs}} uc' , 'uc.club_id=c.id' )
->groupBy ( 'c.id' )
->all ();
Note : You have to do one more thing you have to add a public property $total inside your Club model and add it to safe rules, because you are selecting the count as an alias total and until unless you define it inside the model the result set won't show you the count, so add the following inside the Club model.
public $total;
under rules
[[other fields...,'total'] , 'safe' ] ,
EDIT2
For some reason, I have a feeling that you are trying to count by specifying a relation instead of specifying the ->leftJoin () with the table user_clubs in the query.
If that is so then you have to change your relation getUserCount() you should better give a meaningful name that describes it. i would rename it to getClubUsers()
public function getClubUsers(){
return $this->hasMany(UserClub::className(), ['club_id'=>'id']);
}
After this, you still have to declare a public property $total as I described before inside your Club model, and add it to safe rules.
Now you can write your query in the following way
Clubs::find ()
->alias ( 'c' )
->select ( [ new \yii\db\Expression ( 'c.[[id]], count(cu.[[id]]) as total' ) ] )
->joinWith( ['clubUsers cu'] )
->groupBy ( 'c.id' )
->all ();
You can do this with join, in my case i get users who have more than 0 referrals.
$users = User::find()->with('referrals')
->from(User::tableName() . ' t')
->join('left join',User::tableName().' r','r.Deeplink = t.ReferralID')
->select('t.*,count(r.ID) as ct')
->groupBy('t.ID')
->andFilterHaving(['>','ct',0])
->all();
Hi your relation is correct check you error Club has no relation named \"countUsers\"."
Means you are calling a relation which not exist :
change query like this, Relation name should be in Club Model
public function getCount(){
return $this->hasMany(UserClub::className(), ['club_id'=>'id']);
}
$clubs=Club::find()->all();
foreach($clubs as $club){
echo count($club->getCount);
}
$query = Club::find()
->joinWith(['count']);
// ->with('countusers');
->all();
If you want count just do like this .
Load the Club model .
$club_model = Club::find()
$count = club_model->count;
I'v got simple m2m relation (book -> book_mark <- mark). I want to find item(book) by 1-2-3... x-count of tags(marks). Example: Book1 got these tags: [Mark1, Mark2, Mark3], Book2 got these tags: [Mark1, Mark3, Mark4]. Search list is [Mark1, Mark2]. I want to find only items, which have ALL tags from Search list, i.e. only Book1 in this example.
I have tried many ways and spend much time google it, but didn't find the answer.
Closest that I have is this:
return $this->createQueryBuilder('b')
->select('b, m')
->leftJoin('b.marks_list', 'm')
->andWhere(':marks_list MEMBER OF b.marks_list')
->setParameter('marks_list', $marksList)
->getQuery()->getArrayResult();
But it's looking for books which have at least 1of the parameters, not all of them together
Next, I'v decided that I'm absolutely wrong and start thinking this way:
public function findAllByMarksList(array $marksList)
{
$qb = $this->createQueryBuilder('b')
->select('b, m')
->leftJoin('b.marks_list', 'm');
for ($i = 0; $i<count($marksList); $i++){
$qb->andWhere('m.id in (:mark'.$i.')')
->setParameter('mark'.$i, $marksList[$i]);
}
return $qb->getQuery()->getArrayResult();
}
But here I faced another problem: This code is checking only 1 mark and then always returns an empty set if the number of parameters is more than 1.
Best regards.
So, updated answer... It works (I have relation many to many between reviews and brands) it's the same situation, but for example if you have
Book 1 - mark1, mark2, mark3
Book 2 - mark1, mark2, mark3, mark4
with this code you will also find the book2, because all of it marks are in this list.
If you need to find book which haves only these 3 tags, you additionally need to add checking for count. (Count of tags = count of tagList)
public function test()
{
// just selecting for list for test
$brandsList = $this->_em->createQueryBuilder()
->select('b')
->from('ReviewsAdminBundle:Brands', 'b')
->where('b.id in (:brandIds)')
->setParameter('brandIds', [6,4])
->getQuery()
->getResult();
dump($brandsList);
// query part
$qb = $this->createQueryBuilder('r')
->select('r')
->leftJoin('r.brand', 'brands')
->where('r.published = 1');
foreach ($brandsList as $oneBrand) {
/** #var Brands $oneBrand */
$identifier = $oneBrand->getId();
$qb->andWhere(':brand'.$identifier.' MEMBER OF r.brand')
->setParameter('brand'.$identifier, $identifier);
}
dump($qb->getQuery()->getResult());
die;
}
ps. Additionally you can check doctrine2 queryBuilder must return only result matching with array values (ids): 0/Null and/or One and/or Many id(s) have to return One result (close to our situation)
And, I think there's not better way of accomplishing this. Either you use multiple andWheres to compare id OR use MEMBER OF
First off I have looked through similar looking questions but have not found the exact problem asked or answered, so here goes :
I have a JSON Object which consists of about 900+ posts. Looking like this:
var JsonData = [{"rowNumber":563663,"hasWarning":true,"isInvoiceAccount":true,"phone":"","name":"Romerike AS","address1":"Co/Skanning","address2":"PB 52","attention":"","mobile":"","email":"fakt#bos.no","fax":"","zipCity":"N-1471 Askim","invoiceAccount":"","notes":null,"account":"3","country":"NORGE","salesRep":"4","countryCode":"no"},{"rowNumber":563674,"hasWarning":false,"isInvoiceAccount":true,"phone":"","name":"LILLEHAMMER","address1":"POSTBOKS 110","address2":"","attention":"","mobile":"","email":"","fax":"","zipCity":"N-2605 LILLEHAMMER","invoiceAccount":"","notes":null,"account":"14","country":"NORGE","salesRep":"4","countryCode":"no"},{"rowNumber":563676,"hasWarning":true,"isInvoiceAccount":true,"phone":"63929788","name":"Askim Bil AS","address1":"Postboks 82","address2":"","attention":"","mobile":"","email":"karosseri#nyg.no","fax":"","zipCity":"N-2051 Askim","invoiceAccount":"","notes":null,"account":"16","country":"NORGE","salesRep":"4","countryCode":"no"},{"rowNumber":563686,"hasWarning":false,"isInvoiceAccount":true,"phone":"69826060","name":"KAROSSERI A/S","address1":"POSTBOKS 165","address2":"","attention":"","mobile":"","email":"tkar#online.no","fax":"","zipCity":"N-1860 TRØGSTAD","invoiceAccount":"","notes":null,"account":"26","country":"NORGE","salesRep":"4","countryCode":"no"},{"rowNumber":563690,"hasWarning":false,"isInvoiceAccount":true,"phone":"","name":"AUTOSERVICE A/S","address1":"POSTBOKS 15","address2":"","attention":"","mobile":"","email":"","fax":"","zipCity":"N-2851 LENA","invoiceAccount":"","notes":null,"account":"30","country":"NORGE","salesRep":"4","countryCode":"no"},{"rowNumber":563691,"hasWarning":false,"isInvoiceAccount":false,"phone":"","name":"ØYHUS A/S","address1":"POSTBOKS 321","address2":"","attention":"John Doe","mobile":"","email":"","fax":"","zipCity":"N-2817 GJØVIK","invoiceAccount":"","notes":null,"account":"31","country":"NORGE","salesRep":"4","countryCode":"no"}];
I want to filter these data before I read them into a table using $.grep.
The JSON data have been loaded as an object.
In the HTML page I have a textfield named "filter".
The following code works, but only when I search for an exact match:
var JsonFiltered = $.grep(JsonData, function (element, index) {
return element.zipCity == $('#filter').val();
});
$.each( JsonFiltered, function ( index, value ) {
// sorting through the array adding values to a table
[...]
});
Problem 1:
I want to use Wildcards when filtering.
I read something about using regexp but I haven't found any viable examples.
Problem 2:
I want to be able to filter more than one column.
Example: filtering the word "Askim" in both element.name and element.zipCity
So I figured out the solutions myself...
Using Wildcards:
var search_term = $('#filter').val();
var search = new RegExp(search_term, "i");
var JsonFiltered = $.grep(JsonTest, function (element, index) {
var zipC = search.test(element.zipCity)
var names = search.test(element.name)
return zipC + names ;
The solution was to use "new RegExp" with the filter "i" setting.
then I took two search.tests combined them in the return command and... presto
Hope this helps anyone else.
I can not make a selection via the result of the first
Goal is:
Do the query on the table "line" pick up your ID and search customers that line the "customer" table
This is my code:
db = window.openDatabase("test", "1.0", "Test DB", 1000000);
db.transaction(SelectData,erroSelect,sucessSelect);
function SelectData(tx)
{
tx.executeSql("select id from linha",[],function(tx, response)
{
for(i=0; i<response.rows.length; i++)
{
tx.executeSql("SELECT * FROM customers WHERE line= ?", [response.rows.item(i).id],
function (tx, results)
{
for(r=0; r<results.rows.length; r++)
{
alert(results.rows.item(r).nome); //never worked
}
}
}
},SelectError);
}
It is diffcult to understand from your post, where is the actual error.
Have you tried using console.log() call inside each tx.executeSql() to ascertain that the function is being executed.
Alternatively you can use a single query instead of using two SELECT statements.
Replace
select id from linha
with
SELECT customers.columnName1, customers.columnName2
FROM customers INNER JOIN linha ON customers.line = linha.id