Trying to start using DataFX ,, i wanna load an FXML view into another Pane, so i have a stage that is showing, on user action will add another FXML view to a Pane on the showing stage,
i usually do that this way :
fxmlLoader = constructFXMLLoader(FXMLPath);
root = (Parent) this.fxmlLoader.load();
private FXMLLoader constructFXMLLoader(String FXMLPath) {
FXMLLoader fxmlLoader = new FXMLLoader();
fxmlLoader.setLocation(getURL(stageFXMLName));
fxmlLoader.setBuilderFactory(new JavaFXBuilderFactory());
return fxmlLoader;
}
there i have the root so i can add it where ever i want, the question is how to do that with DataFX
i did a quick research but found nothing !
just figured out the answer
FlowHandler flowHandler = new Flow(Controller.class).createHandler();
flowHandler.getCurrentView().getViewContext().getRootNode();
Related
This question already has an answer here:
How do I determine the correct path for FXML files, CSS files, Images, and other resources needed by my JavaFX Application?
(1 answer)
Closed 2 years ago.
I have a file named Home.fxml which is a BorderPane. This component has buttons on the left and an empty TabPane called mainTabPane in the centre. I would like, when a user clicks on any button on the left, to add a tab to mainTabPane. I am able to add one tab when one button is clicked. But when I try to do the same for the second button, I get this error:
java.lang.IllegalStateException: Location not set
Here is the code for HomeController.java, where all is done:
public void initialize(URL loc, Resource Rse) {
createReportsTab();
loadCreateItemTab();
}
/*this is the one which works well*/
#FXML
void CreateReportTab() {
FXMLLoader loader = new FXMLLoader();
loader.setLocation(ReportsController.class.getResource("gui/Reports.fxml"));
Parent parent = loader.load();
Tab reportsTab = new Tab("Reporting Engine");
reportsTab.setClosable(true);
reportsTab.setcontent(parent);
mainTabPane.getTabs().add(reportsTab),
}
/*this is the one which produces the error*/
#FXML
void loadCreateItemTab() {
FXMLLoader loader = new FXMLLoader();
loader.setLocation(AddNewItemController.class.getResource("gui/addNewItem.fxml"));
Parent parent = loader.load();
Tab newItemTab= new Tab("New Item");
newItemTab.setClosable(true);
newItemTab.setcontent(parent);
mainTabPane.getTabs().add(newItemTab),
}
I am confused; why the Reporting Engine loads well but the second one is producing that error above?
Here is my project structure in IntelliJ IDEA:
All controller classes are in the controllers package and all FXML files are in the GUI package. The main class is in Companion package.
Error suggests that addNewItem.fxml is not read. Change:
AddNewItemController.class.getResources("gui/addNewItem.fxml");
to
ReportsController.class.getResources("gui/addNewItem.fxml");
, since this path worked for you already.
I use the below code to open a javafx fxml file in a different window on a button click event and it works fine. But if I click the same button again while the window opened it will create a duplicate window. Is there a possibly solutions to overcome this problem? Thanks in advance.
Parent parent = FXMLLoader.load(getClass().getResource("FXMLDocument.fxml"));
Stage stage = new Stage(StageStyle.DECORATED);
stage.setTitle("Title");
stage.setScene(new Scene(parent));
stage.show();
I just stumbled upon this old question and figured I might answer it for anyone new to JavaFX or coding in general (I'm bored..).
In the provided code (see below) a new Stage is created every time, meaning that if this is run inside of a method you actually create a new Stage variable every time that the code is run:
Stage stage = new Stage(StageStyle.DECORATED);
What you could do instead create your Stage variable outside the method so that you either 1. just overwrite it every time or 2. have some "is showing" or a nullcheck or similar to see if a new stage should be created or if the existing one just needs to be shown.
For example:
private Stage stage;
private void onOpenNewStageBtnClicked(){
if(stage == null){
Parent parent = FXMLLoader.load(getClass().getResource("FXMLDocument.fxml"));
stage = new Stage(StageStyle.DECORATED);
stage.setTitle("Title");
stage.setScene(new Scene(parent));
}
stage.show();
}
Also, what I usually do is I create a Stage factory to avoid a lot of duplicate code and so that I can break out the creation of the stages and the loading of fxmls to other classes than my controller.
I'm a beginner, I don't know how to open a new stage in same window in javaFX8?
Stage modal_stage = new Stage();
modal_stage.setScene(new Scene(root, 500, 575));
modal_stage.setTitle("modal");
modal_stage.initModality(Modality.APPLICATION_MODAL);
modal_stage.initOwner(modal_stage.getOwner());
modal_stage.setResizable(false);
modal_stage.show();
When I opened a new stage through the above code, the stage always opening in a difference window,like this:
But I want the new stage will not create a new icon in StartMenu taskbar, just like Swing's Dialog of Jframe---No matter how many dialogs I open under jframe, It is always displayed as one window. So what can I do?
Sorry, I am not very good at English, I wish I had clarified the question.
Assuming that you have a parent stage:
Stage parentStage = new Stage();
And the child Stage:
Stage childStage = new Stage();
You have to set the init owner of the childStage to be the parent:
childStage.initOwner(parent);
Mention that the above has to be called before the childStage to be shown.
Also mention that doing this you will have some behaviour like when parent child is minimized then childStage will be also minimized.
I'm new at Stackoverflow and Javafx (and Java at all), so my question can be stupid.
I have a .fxml file with main window (it's include LineChart) and Controller.java, binded to it. And I need make new window with chart options (color and thickness of line). I'm making window with options by event, binded on menuItem in main window.
So, how I can change properties of chart in main window from options window?
I don't understand at all how to get access to LineChart in main window!
This is how I open options window:
void showSettings(ActionEvent event)
throws IOException {
Group root = new Group();
Stage stage = new Stage();
AnchorPane frame = FXMLLoader.load(getClass().getResource("options.fxml"));
root.getChildren().add(frame);
Scene scene = new Scene(root);
stage.setScene(scene);
stage.show();
}
Can anybody help me?
P.S. Sorry for my bad English level :c
Edit1: I need pass params from new window(options) to already existing (main)!
I am newbie on JavaFX. I need to open another screen on button click which already created.
For this, i try to search but didn't get anything helpful because every tutorial which i find are redirecting to create new screen. But i want to open screen which already created.
For this,
i write following code in controller.java
#FXML
public void handleNewTestBedButtonAction(ActionEvent event) throws IOException {
URL url = getClass().getResource("com/sobc/testbed/gui/testbedform.fxml");
FXMLLoader fxmlloader = new FXMLLoader();
fxmlloader.setLocation(url);
fxmlloader.setBuilderFactory(new JavaFXBuilderFactory());
AnchorPane pane = new AnchorPane();
pane.getChildren().clear();
pane.getChildren().add((Node) fxmlloader.load(url.openStream()));
// here we go
//((SOARiteController) fxmlloader.getController()).setContext();
}
fxml code
<Button id="newtestbedbtn" fx:id="newTestBedButtonId" mnemonicParsing="false" onAction="#handleNewTestBedButtonAction" onMouseEntered="#NewTestBedButtonMouseEntered" onMouseExited="#NewTestBedButtonMouseExited" styleClass="imgbtn" text="" wrapText="false">
But i am getting following exception
Caused by: java.lang.NullPointerException
at com.soab.SOARiteController.handleNewTestBedButtonAction(SOARiteController.java:52)
I don't understand how to open one screen on another screen.
Please give me reference or hint.
Use following code in replacement of your Fxml loader, this is a correct way to load fxml file.
URL url = getClass().getResource("com/sobc/testbed/gui/testbedform.fxml");
FXMLLoader loader = new FXMLLoader(url);
Node node = (Node) loader.load();