I have reshaped the data to long. It has been sorted in ascending order based on one column (as x2 in the below reproducible example) and I want to keep the data in a repeating manner rather than factored. Here is a sample:
set.seed(234)
data<-data.frame(x1=c(1:12),x2=rep(1:3,each=4),x3=runif(12,min=0,max=12))
And I want the format something like this:
x1 x2 x3
1 1 1 6.115445
2 2 2 5.157014
3 3 3 4.793458
4 4 1 9.998710
5 5 2 2.620250
6 6 3 1.825839
7 7 1 5.842854
8 8 2 5.616670
9 9 3 6.511315
10 10 1 9.164444
11 11 2 8.401418
Can you please help me with either what to include in the melt function while converting the data to long format or any other function I should use in rearranging that data.
note:
The above result is to show the desired format, not the exact solution for my data.
EDIT:
Here is head() of my real data:
Date stn Elev Amount
1 2010-01-01 11 0 268.945
2 2010-01-01 11 0 268.396
3 2010-01-01 11 0 267.512
4 2010-01-01 11 0 266.488
5 2010-01-01 11 0 265.558
6 2010-01-01 11 0 265.178
In the actual data, the column Elev contains values like, c("0","100","250","500"...). So you assume that 0 is equivalent to 1 in x2 of the above sample, and so forth for 100, 250....
One method is to use ave as follows:
data[order(ave(data$x3, data$x2, FUN=function(i) 1:length(i)), data$x2),]
x1 x2 x3
1 1 1 8.9474400
5 5 2 0.8029211
9 9 3 11.1328381
2 2 1 9.3805491
6 6 2 7.7375415
10 10 3 3.4107614
3 3 1 0.2404454
7 7 2 11.1526315
11 11 3 6.6686992
4 4 1 9.3130246
8 8 2 8.6117063
12 12 3 6.5724198
In this instance, ave calculates a running count by data$x2, which is then used to sort the data with the order function.
You can also renumber x1 if desired: data$x1 <- 1:nrow(data), which would return your desired result.
Related
I have spent a significant amount of time searching for an answer with little luck. I have some time series data and need to collapse and create a rolling mean of every nth row in that data. It looks like this is possible in zoo and maybe hmisc and i am sure other packages. I need to average rows 1,2,3 then 3,4,5 then 5,6,7 and so on. my data looks like such and has thousands of observations:
id time x.1 x.2 y.1 y.2
10 1 22 19 0 -.5
10 2 27 44 -1 0
10 3 19 13 0 -1.5
10 4 7 22 .5 1
10 5 -15 5 .33 2
10 6 3 17 1 .33
10 7 6 -2 0 0
10 8 44 25 0 0
10 9 27 12 1 -.5
10 10 2 11 2 1
I would like it to look like this when complete:
id time x.1 x.2 y.1 y.2
10 1 22.66 25.33 -.33 -.66
10 2 3.66 13.33 .27 .50
The time var 1 would actually be times 1,2,3 averaged and 2 would be 3,4,5 averaged but at this point the time var would not be important to keep. I would need to group by id as it does change eventually. The only way I could figure out how to do this successfully was to use Lag() and make new rows lead by 1 and another by 2 then take average across columns. after that you have to delete every other row
1 NA NA
2 1 NA
3 2 1
4 3 2
5 4 3
use the 123 and 345 and remove 234... to do this for each var would be outrageous especially as i gather new data.
any ideas? help would be much appreciated
something like this maybe?
# sample data
id <- c(10,10,10,10,10,10)
time <- c(1,2,3,4,5,6)
x1 <- c(22,27,19,7,-15,3)
x2 <- c(19,44,13,22,5,17)
df <- data.frame(id,time,x1,x2)
means <- data.frame(rollmean(df[,c(1,3:NCOL(df))], 3))
means <- means[c(T,F),]
means$time <- seq(1:NROW(means))
row.names(means) <- 1:NROW(means)
> means
id x1 x2 time
1 10 22.666667 25.33333 1
2 10 3.666667 13.33333 2
my first language isn't English so I apologize in advance for mistakes I could do. I'm newbie in R but you will notice that anyway.
I'm trying to solve the problem of having a co-occurence matrix. I have several dataframes and I am interested in 3 variables : idT, numname and numstim.
This is the unique dataframe that contains the merged data :
z=rbind(df1,df2,df3,df4,df5,df6,df7,df8,df9,df10,df11,df12,df13,df14,
df15,df16,df17,df18,df19,df20,df21,df22,df23,df24,df25,df26,df27,df28,df29,df30,df31,df32)
write.csv(z, file = ".../listz.csv")
Then I extracted the 3 variables with :
#Extract columns 3 & 6 from all the files within the list
z1 = z[,c(3,6)]
#Create a new variable 'numname' to convert name groups into numeric groups,
#then obtain levels with facNum
z1$numname <- as.numeric(z1$namegroup)
colnames(z1) <- c("namegroup", "idT", "numname")
facNum <- factor(z1$numname)
write.csv(z1, file = "...D:/z1.csv")
And data look like :
namegroup idT numname
1 GLISSEVIBREVITE 1 6
2 CINETIQUE 1 3
3 VIBRATIONS_LEGERES 1 20
4 DIFFUS 1 5
5 LIQUIDE 1 8
6 PICOTEMENTS 1 10
How to read the table : each idT is classified in a group (namegroup) and then this group is converted in a numeric variable (numname).
# Specify z1 as a data frame to make next operations
z1 = as.data.frame(z1, idT = z1$numstim, numgroup = z1$numname)
tab1 <- table(z1)
write.csv(tab1, file = ".../tab1test.csv")
out1 <- data.matrix(tab1 %*% t(tab1))
write.csv(out1, file = ".../bmtest.csv")
But the bmtest matrix doesn't look like counting pairs of idT, because only 22 users have participated and there are 32 idT, but some the numbers are much higher :
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
1 24 10 7 7 11 7 7 8 10 8 11 8 6 11 11 12
2 10 32 27 7 5 4 7 4 4 4 5 3 2 6 6 14
3 7 27 40 0 3 1 0 2 0 0 2 2 1 2 0 15
4 7 7 0 30 7 14 15 9 15 13 13 7 5 12 13 5
5 11 5 3 7 24 7 9 20 12 13 10 19 14 20 12 7
I wanna have a matrix which shows the results of a count of idT paired together. The matrix has to look like :
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
1 15 3 2 2 3 3 2 1 2 1 3 3 1 3 3 5
2 3 15 9 2 0 1 2 0 0 0 0 0 0 0 1 3
3 2 9 15 0 2 1 0 2 0 0 1 1 1 2 0 2
4 2 2 0 15 1 6 5 1 7 5 6 2 0 1 3 2
5 3 0 2 1 15 1 2 12 4 5 3 13 9 11 3 2
In other words, I want to see which idT have been paired together. I've looked at this topic but didn't find a way to solve my problem.
Also, I tried :
library(igraph)
library(tnet)
idT_numname <- cbind(z1$idT, z1$numname)
igraph <- graph.data.frame(idT_numname)
item_item <- projecting_tm(net = idT_numname, method="sum")
item_item <- tnet_igraph(item_item,type="weighted one-mode tnet")
itemmat <- get.adjacency(item_item,attr="weight")
itemmat #8x8 martrix of items to items
But I get error message and I don't know how to get over the "duplicated entries in the edgelist", because it seems necessary to me to have duplicated entries in order to do a co-occurrence matrix :
> idT_numname <- cbind(z1$idT, z1$numname)
> item_item <- projecting_tm(idT_numname, method="sum")
Error in as.tnet(net, type = "binary two-mode tnet") :
There are duplicated entries in the edgelist
> item_item <- as.tnet(net = idT_numname, type ="binary two-mode tnet", method="sum")
Error in as.tnet(net = idT_numname, type = "binary two-mode tnet", method = "sum") :
unused argument (method = "sum")
> item_item <- as.tnet(net = idT_numname, type ="binary two-mode tnet")
Error in as.tnet(net = idT_numname, type = "binary two-mode tnet") :
There are duplicated entries in the edgelist
Your help is greatly appreciated.
I like to do data analysis and I want to learn more and more everyday !
Thank you
I'm trying to merge 7 complete data frames into one great wide data frame. I figured I have to do this stepwise and merge 2 frames into 1 and then that frame into another so forth until all 7 original frames becomes one.
fil2005: "ID" "abr_2005" "lop_2005" "ins_2005"
fil2006: "ID" "abr_2006" "lop_2006" "ins_2006"
But the variables "abr_2006" "lop_2006" "ins_2006" and 2005 are all either 0,1.
Now the things is, I want to either merge or do a dcast of some sort (I think) to make these two long data frames into one wide data frame were both "abr_2005" "lop_2005" "ins_2005" and abr_2006" "lop_2006" "ins_2006" are in that final file.
When I try
$fil_2006.1 <- merge(x=fil_2005, y=fil_2006, by="ID__", all.y=T)
all the variables with _2005 at the end if it is saved to the fil_2006.1, but the variables ending in _2006 doesn't.
I'm apparently doing something wrong. Any idea?
Is there a reason you put those underscores after ID__? Otherwise, the code you provided will work
An example:
dat1 <- data.frame("ID"=seq(1,20,by=2),"varx2005"=1:10, "vary2005"=2:11)
dat2 <- data.frame("ID"=5:14,"varx2006"=1:20, "vary2006"=21:40)
# create data frames of differing lengths
head(dat1)
ID varx2005 vary2005
1 1 1 2
2 3 2 3
3 5 3 4
4 7 4 5
5 9 5 6
6 11 6 7
head(dat2)
ID varx2006 vary2006
1 5 1 21
2 6 2 22
3 7 3 23
4 8 4 24
5 9 5 25
6 10 6 26
merged <- merge(dat1,dat2,by="ID",all=T)
head(merged)
ID varx2006 vary2006 varx2005 vary2005
1 1 NA NA 1 2
2 3 NA NA 2 3
3 5 1 21 3 4
4 5 11 31 3 4
5 7 13 33 4 5
6 7 3 23 4 5
I have a data frame which has 2 columns - A & B. I want to replace the values of column B in such a way that, when the VALUE>=5 replace with 1, else replace with 0.
Note - There are 2 conditions to be checked.
X=read.csv("Y:/impdat.csv")
A B
3 16
12 3
1 2
12 9
4 4
5 6
21 1
4 14
3 10
12 1
So after replacing, the data should be
A B
3 1
12 0
1 0
12 1
4 0
5 1
21 0
4 1
3 1
12 0
Sounds simple. But I am unable to implement it.
I tried
ifelse(X$B>=5,1,0)
This only prints the new values, but the original data remains the same.
X$B <- as.integer(X$B >= 5)
will do the trick.
transform(X, B=ifelse(B>=5,1,0))
Got it.
Just had to assign the object.
X$B=ifelse(X$B>=5,1,0)
Hi everybody I am trying to solve a little problem in R. I want to compute the difference between rows in a dataframe in R. My dataframe looks like this:
df <- data.frame(ID=1:8, x2=8:1, x3=11:18, x4=c(2,4,10,0,1,1,9,12))
I want to create a new column named diff.var. This column saves the results of differences from rows in variable. One posibble solution is using diff() function. When I used this function I got this:
diff(df$x4)
[1] 2 6 -10 1 0 8 3
That works fine but when I try to apply in my dataframe using df$diff.var=diff(df$x4) I got this:
Error in `$<-.data.frame`(`*tmp*`, "diff.var", value = c(2, 6, -10, 1, :
replacement has 7 rows, data has 8
Due to the fact that the firs row doesn't have a previous row to compute the difference I want to set this in zero. I would like to get something this:
ID x2 x3 x4 diff.var
1 8 11 2 0
2 7 12 4 2
3 6 13 10 6
4 5 14 0 -10
5 4 15 1 1
6 3 16 1 0
7 2 17 9 8
8 1 18 12 3
Where the first element of diff.var is zero due to this element doesn't have a previous element. I would like to build a function to set firts element of diff.var is zero and that makes the differences for the next rows. I wish to create a new dataframe with all variables and diff.var because ID is used por posterior analysis with diff.var. diff() doesn't allow to create this new variable. Thanks for your help.
This question was already asked before in this forum and can be found elsewhere. Anyway, do what Frank suggests
df <- data.frame(ID=1:8, x2=8:1, x3=11:18, x4=c(2,4,10,0,1,1,9,12))
df$vardiff <- c(0, diff(df$x4))
df
ID x2 x3 x4 vardiff
1 1 8 11 2 0
2 2 7 12 4 2
3 3 6 13 10 6
4 4 5 14 0 -10
5 5 4 15 1 1
6 6 3 16 1 0
7 7 2 17 9 8
8 8 1 18 12 3