looping a sequence of numbers - r

I need to generate the following sequence of numbers:
from 101 to 124 then
from 201 to 224
and so on. I need to repeat this pattern 7 times, up to 724.
I know I can simply use
c(101:124,201:224, ...)
but I suspect there is an easier way. Maybe a loop?

We can try seq with sapply
c(sapply(seq(101, 700, by = 100), function(i) i:(i+23)))
Or we can use rep
(101:124) +rep(0:6, each = 24)*100
#[1] 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118
#[19] 119 120 121 122 123 124 201 202 203 204 205 206 207 208 209 210 211 212
#[37] 213 214 215 216 217 218 219 220 221 222 223 224 301 302 303 304 305 306
#[55] 307 308 309 310 311 312 313 314 315 316 317 318 319 320 321 322 323 324
#[73] 401 402 403 404 405 406 407 408 409 410 411 412 413 414 415 416 417 418
#[91] 419 420 421 422 423 424 501 502 503 504 505 506 507 508 509 510 511 512
#[109] 513 514 515 516 517 518 519 520 521 522 523 524 601 602 603 604 605 606
#[127] 607 608 609 610 611 612 613 614 615 616 617 618 619 620 621 622 623 624
#[145] 701 702 703 704 705 706 707 708 709 710 711 712 713 714 715 716 717 718
#[163] 719 720 721 722 723 724

Using common 'for' loop:
> vect=c(); for(i in seq(from=101,to=701, by=100)) vect = c(vect, seq(from=i,to=i+23))
> vect
[1] 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 201 202 203 204 205 206 207
[32] 208 209 210 211 212 213 214 215 216 217 218 219 220 221 222 223 224 301 302 303 304 305 306 307 308 309 310 311 312 313 314
[63] 315 316 317 318 319 320 321 322 323 324 401 402 403 404 405 406 407 408 409 410 411 412 413 414 415 416 417 418 419 420 421
[94] 422 423 424 501 502 503 504 505 506 507 508 509 510 511 512 513 514 515 516 517 518 519 520 521 522 523 524 601 602 603 604
[125] 605 606 607 608 609 610 611 612 613 614 615 616 617 618 619 620 621 622 623 624 701 702 703 704 705 706 707 708 709 710 711
[156] 712 713 714 715 716 717 718 719 720 721 722 723 724

We can use either the outer or CJ(cross join), both of which list all the combinations of elements from the two vector arguments. By specifying the reduce function as "+", where for outer, there is a parameter placeholder while for CJ you will have to explicitly use the Reduce function, they should produce the results as wanted. Just to be noted, the outer function will result in a matrix, so we use as.vector to convert it to a 1d array.
as.vector(outer(1:24, (1:7)*100, "+"))
or
Reduce("+", data.table::CJ(1:24, (1:7)*100))

Related

Efficiently Finding Sequences Between Vectors of Start and End Numbers in R [duplicate]

This question already has answers here:
Expand ranges defined by "from" and "to" columns
(10 answers)
Closed 2 years ago.
I have two vectors in R, say, start_values and end_values, which contain numbered elements of increasing value. For example:
start_values <- c(88, 241, 394, 545)
end_values <- c(147, 300, 453, 604)
I'm trying to find an efficient (hopefully without writing a loop) that will allow me to obtain a single vector of numbers with sequences of numbers that range from the first element in start_values to the first element in end_values, then from the second element in start_values to the second element in end_values, etc. So in the end, I'd like a vector called sequence_range that looks like this:
sequence_range <- c(seq(88, 147), seq(241, 300), seq(394, 453), seq(545, 604))
which should have output that looks like:
> sequence_range
[1] 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116
[30] 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145
[59] 146 147 241 242 243 244 245 246 247 248 249 250 251 252 253 254 255 256 257 258 259 260 261 262 263 264 265 266 267
[88] 268 269 270 271 272 273 274 275 276 277 278 279 280 281 282 283 284 285 286 287 288 289 290 291 292 293 294 295 296
[117] 297 298 299 300 394 395 396 397 398 399 400 401 402 403 404 405 406 407 408 409 410 411 412 413 414 415 416 417 418
[146] 419 420 421 422 423 424 425 426 427 428 429 430 431 432 433 434 435 436 437 438 439 440 441 442 443 444 445 446 447
[175] 448 449 450 451 452 453 545 546 547 548 549 550 551 552 553 554 555 556 557 558 559 560 561 562 563 564 565 566 567
[204] 568 569 570 571 572 573 574 575 576 577 578 579 580 581 582 583 584 585 586 587 588 589 590 591 592 593 594 595 596
[233] 597 598 599 600 601 602 603 604
I'd appreciate any ideas for efficient techniques to accomplish this so that it's generalizeable to any two vectors of start and end values.
Thanks.
You may use : in an apply on cbinded vectors.
as.vector(apply(cbind(start_values, end_values), 1, function(x) x[1]:x[2]))
# [1] 88 89 90 91 92 93 94 95 96 97 98 99 100 101
# [15] 102 103 104 105 106 107 108 109 110 111 112 113 114 115
# [29] 116 117 118 119 120 121 122 123 124 125 126 127 128 129
# [43] 130 131 132 133 134 135 136 137 138 139 140 141 142 143
# [57] 144 145 146 147 241 242 243 244 245 246 247 248 249 250
# [71] 251 252 253 254 255 256 257 258 259 260 261 262 263 264
# [85] 265 266 267 268 269 270 271 272 273 274 275 276 277 278
# [99] 279 280 281 282 283 284 285 286 287 288 289 290 291 292
# [113] 293 294 295 296 297 298 299 300 394 395 396 397 398 399
# [127] 400 401 402 403 404 405 406 407 408 409 410 411 412 413
# [141] 414 415 416 417 418 419 420 421 422 423 424 425 426 427
# [155] 428 429 430 431 432 433 434 435 436 437 438 439 440 441
# [169] 442 443 444 445 446 447 448 449 450 451 452 453 545 546
# [183] 547 548 549 550 551 552 553 554 555 556 557 558 559 560
# [197] 561 562 563 564 565 566 567 568 569 570 571 572 573 574
# [211] 575 576 577 578 579 580 581 582 583 584 585 586 587 588
# [225] 589 590 591 592 593 594 595 596 597 598 599 600 601 602
# [239] 603 604
mapply works nicely:
> as.vector(mapply(seq,start_values,end_values))
[1] 88 89 90 91 92 93 94 95 96 97 98 99 100 101
[15] 102 103 104 105 106 107 108 109 110 111 112 113 114 115
[29] 116 117 118 119 120 121 122 123 124 125 126 127 128 129
[43] 130 131 132 133 134 135 136 137 138 139 140 141 142 143
[57] 144 145 146 147 241 242 243 244 245 246 247 248 249 250
[71] 251 252 253 254 255 256 257 258 259 260 261 262 263 264
[85] 265 266 267 268 269 270 271 272 273 274 275 276 277 278
[99] 279 280 281 282 283 284 285 286 287 288 289 290 291 292
[113] 293 294 295 296 297 298 299 300 394 395 396 397 398 399
[127] 400 401 402 403 404 405 406 407 408 409 410 411 412 413
[141] 414 415 416 417 418 419 420 421 422 423 424 425 426 427
[155] 428 429 430 431 432 433 434 435 436 437 438 439 440 441
[169] 442 443 444 445 446 447 448 449 450 451 452 453 545 546
[183] 547 548 549 550 551 552 553 554 555 556 557 558 559 560
[197] 561 562 563 564 565 566 567 568 569 570 571 572 573 574
[211] 575 576 577 578 579 580 581 582 583 584 585 586 587 588
[225] 589 590 591 592 593 594 595 596 597 598 599 600 601 602
[239] 603 604

Length of list object returns 1 in R when not 1

I have a list x
X1
1 0.8
2 1.0
3 661.7
4 661.8
5 661.9
6 662.3
7 662.6
8 662.7
9 663.3
10 663.6
11 663.7
12 663.9
13 664.0
14 664.1
15 664.3
16 664.4
17 664.5
18 664.7
19 665.1
20 666.9
21 667.5
22 668.2
23 668.3
24 669.7
25 670.3
26 670.8
27 671.1
28 672.0
29 672.1
30 674.8
31 675.3
32 677.5
33 677.9
34 678.5
35 678.9
36 679.0
37 686.6
38 687.6
39 714.1
40 899.1
41 900.4
42 901.1
43 901.3
44 902.7
45 908.3
46 908.7
47 908.9
48 909.0
49 909.2
50 910.0
51 910.1
52 910.3
53 910.6
54 910.7
55 911.3
56 911.4
57 911.6
58 911.8
59 912.6
60 912.7
61 912.8
62 913.0
63 913.1
64 913.2
65 913.3
66 913.7
67 913.9
68 914.0
69 914.2
70 914.3
71 914.4
72 914.6
73 915.2
74 915.3
75 915.5
76 915.6
77 915.7
78 915.9
79 916.0
80 916.1
81 916.3
82 916.5
83 916.6
84 916.7
85 916.9
86 917.3
87 917.5
88 917.6
89 917.8
90 917.9
91 918.0
92 918.2
93 918.3
94 918.5
95 918.6
96 918.8
97 918.9
98 919.0
99 919.2
100 919.3
101 919.5
102 919.6
103 919.7
104 919.9
105 920.0
106 920.2
107 920.3
108 920.5
109 920.6
110 920.8
111 920.9
112 921.0
113 921.1
114 921.2
115 921.3
116 921.3
117 921.5
118 921.6
119 921.7
120 921.8
121 922.0
122 922.1
123 922.4
124 922.5
125 922.6
126 922.7
127 922.9
128 923.0
129 923.2
130 923.3
131 923.5
132 923.6
133 923.8
134 923.9
135 927.2
136 927.3
137 927.4
138 927.6
139 927.7
140 927.8
141 928.0
142 928.1
143 928.3
144 928.4
145 928.5
146 928.7
147 928.8
148 928.9
149 929.1
150 929.2
151 929.3
152 929.5
153 929.6
154 929.8
155 929.9
156 930.1
157 930.2
158 930.3
159 930.3
160 930.5
161 930.6
162 930.7
163 930.9
164 931.0
165 931.1
166 931.2
167 931.3
168 931.4
169 931.5
170 931.7
171 931.8
172 932.0
173 932.0
174 932.1
175 932.2
176 932.4
177 932.5
178 932.6
179 932.7
180 933.3
181 933.4
182 933.6
183 933.7
184 933.8
185 934.5
186 934.7
187 934.8
188 934.9
189 935.0
190 935.2
191 935.3
192 935.3
193 935.5
194 935.6
195 935.7
196 935.8
197 936.0
198 936.1
199 936.3
200 936.4
201 936.5
202 936.7
203 936.8
204 936.9
205 937.1
206 937.2
207 937.4
208 937.5
209 937.7
210 937.8
211 937.9
212 938.1
213 938.2
214 938.4
215 938.5
216 938.7
217 938.9
218 939.0
219 939.2
220 939.4
221 939.7
222 939.9
223 940.3
224 940.7
225 940.9
226 941.4
227 941.7
228 942.1
229 942.6
230 942.7
231 943.3
232 943.5
233 943.9
234 944.9
235 945.0
236 945.1
237 945.4
238 945.6
239 945.8
240 945.9
241 946.2
242 947.6
243 947.9
244 948.2
245 948.3
246 948.5
247 948.6
248 948.8
249 948.9
250 949.5
251 949.6
252 951.8
253 951.9
254 952.0
255 952.1
256 952.5
257 952.6
258 953.0
259 953.3
260 953.4
261 953.5
262 953.7
263 953.8
264 953.9
265 954.1
266 954.2
267 954.4
268 954.5
269 954.7
270 954.8
271 955.0
272 955.1
273 955.2
274 955.4
275 955.5
276 955.6
277 955.7
278 955.9
279 956.0
280 956.1
281 956.3
282 956.4
283 956.5
284 956.6
285 956.9
286 957.2
287 957.3
288 957.4
289 957.5
290 957.9
291 958.9
292 959.0
293 959.3
294 959.5
295 959.9
296 960.0
297 960.2
298 960.5
299 960.6
300 960.8
301 960.8
302 961.4
303 961.5
304 961.6
305 961.7
306 961.8
307 961.9
308 968.8
309 969.1
310 970.0
311 970.5
312 970.7
313 974.2
314 998.7
315 998.8
316 998.9
317 999.1
318 999.2
319 1000.3
320 1001.2
321 1001.4
322 1001.5
323 1001.6
324 1001.7
325 1003.2
326 1003.4
327 1003.6
328 1004.2
329 1004.3
330 1004.4
331 1004.5
332 1004.6
333 1005.3
334 1005.4
335 1005.5
336 1005.6
337 1005.7
338 1005.9
339 1006.0
340 1006.1
341 1006.8
342 1006.9
343 1007.1
344 1007.2
345 1007.3
346 1007.4
347 1007.6
348 1007.7
349 1007.8
350 1008.0
351 1008.1
352 1008.7
353 1008.8
354 1008.9
355 1009.0
356 1009.2
357 1009.3
358 1009.3
359 1009.5
360 1009.6
361 1009.7
362 1009.8
363 1010.0
364 1010.2
365 1010.4
366 1010.5
367 1010.6
368 1010.7
369 1010.9
370 1011.0
371 1011.1
372 1011.2
373 1011.4
374 1011.5
375 1011.6
376 1011.7
377 1011.9
378 1012.0
379 1012.1
380 1012.2
381 1012.3
382 1012.4
383 1012.6
384 1012.7
385 1012.8
386 1013.0
387 1013.2
388 1013.4
389 1013.5
390 1013.6
391 1013.6
392 1013.8
393 1013.9
394 1014.0
395 1014.0
396 1014.3
397 1014.7
398 1014.8
399 1014.9
400 1015.7
401 1015.8
402 1016.0
403 1016.1
404 1016.2
405 1016.5
406 1016.6
407 1016.9
408 1017.0
409 1017.1
410 1017.3
411 1017.4
412 1017.5
413 1017.7
414 1017.8
415 1017.8
416 1018.3
417 1018.5
418 1026.6
419 1027.0
420 1027.3
421 1027.4
422 1027.7
423 1028.6
424 1029.1
425 1029.9
426 1030.0
427 1030.2
428 1270.0
429 1270.1
430 1270.2
431 1270.3
432 1270.4
433 1270.5
434 1270.7
435 1270.7
436 1270.9
437 1271.0
438 1271.3
439 1271.4
440 1272.3
441 1272.5
442 1273.1
443 1273.2
444 1273.3
445 1273.4
446 1273.5
447 1273.8
448 1274.0
449 1274.1
450 1274.3
451 1274.4
452 1274.6
453 1274.7
454 1274.8
455 1274.9
456 1275.1
457 1275.3
458 1275.5
459 1275.6
460 1275.8
461 1275.9
462 1276.1
463 1276.2
464 1276.3
465 1276.4
466 1276.6
467 1276.7
468 1276.8
469 1277.2
470 1277.3
471 1277.5
472 1277.6
473 1277.7
474 1277.9
475 1278.0
476 1278.1
477 1278.2
478 1278.3
479 1278.4
480 1278.5
481 1278.7
482 1279.0
483 1279.0
484 1279.1
485 1279.3
486 1279.3
487 1279.5
488 1279.6
489 1279.7
490 1279.8
491 1280.3
492 1280.4
493 1280.7
494 1280.8
495 1280.9
496 1281.1
497 1281.3
498 1281.4
499 1281.5
500 1282.3
501 1283.0
502 1283.1
503 1284.0
504 1284.8
505 1284.9
506 1285.0
507 1285.1
508 1285.4
which has a length of 508, although when I use length(x) it returns 1. I have tried to the function
length(as.vector(x))
although this also does not work and returns 1. Is there another form that I should convert this list to so that I can accurately find the length? For reference, I am using the length to duplicate other elements using the rep_len() function.
as.vector on a data.frame returns the data.frame itself as there is no method for as.vector with data.frame
methods('as.vector')
#[1] as.vector,abIndex-method as.vector,ANY-method as.vector,dgCMatrix-method as.vector,dgeMatrix-method
#[5] as.vector,diagonalMatrix-method as.vector,dsCMatrix-method as.vector,ldenseMatrix-method as.vector,Matrix-method
#[9] as.vector,ndenseMatrix-method as.vector,sparseVector-method as.vector.factor as.vector.Matrix*
#[13] as.vector.sparseVector*
We can also check the reverse i.e. on data.frame
grep('^as\\.', methods(class = 'data.frame'), value = TRUE)
#[1] "as.data.frame.data.frame" "as.data.table.data.frame"
#[3] "as.list.data.frame" "as.matrix.data.frame" "as.tbl.data.frame"
and the length is the same as the number of columns of data.frame i.e. here it is 1. Instead, we need nrow(x)
as.vector(mtcars) # nothing changed
length(as.vector(mtcars))
#[1] 11
But, suppose, if we do
nrow(mtcars)
#[1] 32
length can also be applied on the vector by extracting the column with $ or [[
length(mtcars[[1]])

r tm extract doc ids after sort operation

I have mindfreeze around this issue. I am extracting most frequent words from a tm::dtm, like so:
> s1<-sort(rowSums(as.matrix(dtm10[,])), decreasing=TRUE)
I get:
290 429 318 125 128 425 431 153 52 385 144 491 126 423 111 130 492 163 176 391
916 875 860 851 844 823 822 766 759 743 701 700 686 673 670 669 663 658 652 623`
But the doc ids and rowSums are in a tuple.
> s1[2]
429
875
where 429 is doc id and rowsum is 875. I have no further use of the rowSums, how do I get a list of the sorted doc ids? I am looking for a vector output like:
290 429 318 125 128 425 431 153 52 385 144 491 126 423 111 130 492 163 176 391
Many thanks.
s1 is a named vector with names as 290, 429, 318 etc and values like 916,875, 860 and so on.
To extract only the names of s1 , we can use,
names(s1)
which would give :
#290 429 318 125 128 425 431 153 52 385 144 491 126 423 111 130 492 163 176 391

cleaning the data R

I've got the final data DS such as :
|user_id
40 33
70 50
93 67
106 77
136 91
144 97
160 105
176 113
195 128
207 132
211 134
229 142
280 159
338 187
407 232
425 248
442 259
446 261
469 277
470 278
588 353
590 355
594 358
598 362
609 369
615 375
626 381
633 386
652 399
657 402
735 452
751 464
758 470
760 471
769 478
774 480
806 493
821 501
825 505
856 526
876 536
886 540
890 542
894 543
903 549
919 556
921 558
932 562
The fist column is a what left of line numbers I suppose, after many data manipulations,
and I'd like to drop them, nice, efficient way, and replace it with normal order numbers , 1,2,3,4,5 etc.
I did try to use :
aggr.cid <-aggregate(cbind(DS$user_id), by=list(CustID = DS$user_id),
function(x) x[1])
But instead of getting 1 line I'm getting two, with content of "user_id"
I can remove the second one and all will looks as I need but it is a doggy way....
Those are the row names. You can reset them with
rownames(DS) <- NULL

In R, how can one detect consecutive data points within a column of data which have a value >y only when they appear more than x times consecutively?

I am a beginner R user and am trying to find a way to detect x consecutive values within a column of data which have a value >=y. Example: find all instances where 4 or more consecutive data points have a value >=2
The run length encoding rle() command looks promising for identifying these consecutive values:
rle(dataset>=2)
but I cannot find a way to further set the condition for the lengths to be >=4 and the values to be "TRUE".
Any suggestions?
res <- rle(dataset>=2)
which( res$lengths>=4 & res$values==TRUE] )
That will identify them in the compacted representation of the rle result and you will then need to expand that result and pick out starting points for the sequences.
You can simply transform the vector, and use rle on that:
res = rle(runif(1000, 0, 4) >= 2)
res
Run Length Encoding
lengths: int [1:491] 2 2 2 2 3 1 3 2 7 1 ...
values : logi [1:491] TRUE FALSE TRUE FALSE TRUE FALSE ...
To get the indices where in the vector the runs are located, you can use this trick:
res$values = res$lengths > 4
inv_res = inverse.rle(res)
seq_along(inv_res)[inv_res]
[1] 3 4 5 6 7 8 9 10 11 12 13 37 38 39 40 41 42 74
[19] 75 76 77 78 79 80 81 82 83 84 85 108 109 110 111 112 142 143
[37] 144 145 146 147 148 221 222 223 224 225 226 235 236 237 238 239 240 241
[55] 278 279 280 281 282 305 306 307 308 309 310 311 312 313 314 315 316 317
[73] 318 319 342 343 344 345 346 347 414 415 416 417 418 419 430 431 432 433
[91] 434 435 449 450 451 452 453 472 473 474 475 476 477 478 523 524 525 526
[109] 527 545 546 547 548 549 561 562 563 564 565 566 567 568 569 607 608 609
[127] 610 611 612 613 625 626 627 628 629 630 646 647 648 649 650 651 652 699
[145] 700 701 702 703 765 766 767 768 769 770 771 772 773 789 790 791 792 793
[163] 794 795 800 801 802 803 804 810 811 812 813 814 850 851 852 853 854 855
[181] 869 870 871 872 873 879 880 881 882 883 904 905 906 907 908 909 919 920
[199] 921 922 923 949 950 951 952 953 954 955 956 957 958 959 960 961

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