SELECT in SELECT - sqlite

Question

I have the following query which I am trying to rewrite:
SELECT
max(dpHigh) AS High
FROM DailyPrices
WHERE dpTicker = 'DL.AS'
AND dpDate IN
(SELECT
dpDate
FROM DailyPrices
WHERE dpTicker ='DL.AS'
ORDER BY update DESC
LIMIT 10);
The query gives me the required result:
bash-3.2$ sqlite3 myData < Queries/high.sql
High
----------
4.67
bash-3.2$
Since next to the high value I wish to expand this query to also obtain a low value, earliest date, latest date, etc. For this reason, I am trying re-write an equivalent query using a select in select statement.
SELECT
(SELECT
max(dpHigh)
FROM DailyPrices
WHERE dpTicker = 'DL.AS'
AND dpDate IN
(SELECT dpDate
FROM DailyPrices
WHERE dpTicker ='DL.AS'
ORDER BY dpDate DESC
LIMIT 10)
)AS High
FROM DailyPrices
WHERE dpTicker = 'DL.AS';
Execution of the query spits output the expected value, however, it does exactly for the number of data entries of 'DL.AS'.
...
4.67
4.67
4.67
4.67
4.67
4.67
4.67
bash-3.2$
Since I am a SQLite newbie, I am probably overlooking the obvious. Does anybody have any suggestions?
BR
GAM

Answer 1

The outermost query looks like this:
SELECT (...)
FROM DailyPrices
WHERE dpTicker = 'DL.AS';
This will generate one output row for each table row with a matching dpTicker.
To generate a single row, regardless of how many rows might be found in some table, use a query without a FROM (the filtering and aggregation is already handled in the subqueries):
SELECT (...) AS High,
(...) AS Low;