I need to compare two hex values in drools.
for eg: compare 0xbadf00d with 0xbadf00e
This should result in false as d doesn't match with e.
So my question is, can hex be treated as string value and same comparisons can be made, or there is some other way.
I tried googling but no use.
When using ASCII, the natural order of the digits and letters of an HEX is ascending. This makes the comparison of these values as Strings trivial (assuming they are left-padded with 0s and using the same case).
As an example, if you have an Input class with a hex attribute of type String you can write something like this:
rule "Test"
when
$i1: Input()
$i2: Input(hex > $i1.hex)
then
//Do whatever you need here
end
Hope it helps,
Related
I need to delimit the string and this time the delimiter is $($, but I need to note that the next character is number ( because I am specifically trying to separate the title from the year from one column. ) Even better would be that I could indicate, that after $($ there are 4 digits. But in general my question is where can I find all the symbols that denote different form of characters or group of character in order to make it easier to separate text into two columns. Thanks in advance.
I was not expecting to get back a value from the query below. 1574208000#W2 is not between 1574207999 and 1574208001. But the records are still returned. Can anyone shed light on how the between comparison is done?
DynamoDb between operator with strings works with the lexicographic order of the strings (ie, the order in which they would appear in a dictionary). Using this order, 1574208000#W2 does fall between 1574207999 and 1574208001
Two strings are lexicographically equal if they are the same length and contain the same characters in the same positions.
Apart from that, to determine which string comes first, compare corresponding characters of the two strings from left to right. The first character where the two strings differ determines which string comes first. Characters are compared using the Unicode character set. All uppercase letters come before lower case letters. If two letters are the same case, then alphabetic order is used to compare them.
If two strings contain the same characters in the same positions, then the shortest string comes first. Ref
To try this out, you can try a simple example in Java
String a = "1574207999", b = "1574208000#W2", c = "1574208001";
System.out.println(a.compareTo(b)); // prints negative number, indicating a < b
System.out.println(b.compareTo(c)); // prints negative number, indicating b < c
What is the logic used by R to end up with the output FALSE in the below logical operation on characters. Is it just comparing letter S with letter T instead of the entire string.
"Sachin" > "Tendulkar"
Output: FALSE
This is in the documentation. ?">" gives:
Comparison of strings in character vectors is lexicographic within the strings using the collating sequence of the locale in use
In other words, this is just a regular dictionary-style comparison. Things can get very complicated/weird depending on locales (e.g. how non-alphabetic, accented, upper/vs lower case, etc. etc. characters are handled), but this case looks straightforward. "S" comes before "T" in every locale I can imagine, so "S"<"T"; in a lexicographic sort, this will determine the order (otherwise ties would be broken by later letters in the sequence).
I would like to compare two strings, one which the user enters into a UITextField and another which I have stored (I know how to do this).
However I would like to notify the user if they have misspelt the string they have entered compared to the stored string, could anyone shed some light on how to do this comparison.
The Identifying and Comparing Strings section of the NSString Class Reference provides methods exactly for that. Please check.
I believe in your case, the following methods would be helpful,
1) isEqualToString: example, [string1 isEqualToString:string2] returns YES if the strings are same, else NO
2) caseInsensitiveCompare: example [string1 caseInsensitiveCompare:string2] compares the strings, regardless of its case. Returns an NSComparisonResult. If it is NSOrderedSame, then the strings match, else they dont.
3) compare:options: example [string1 compare:string2 options:NSDiacriticInsensitiveSearch] compares the strings, with options to compare such as an NSDiacriticInsensitiveSearch where the search treats characters such as 'รถ' and 'o' as same, NSNumericSearch where the numbers within the string are compared using numeric values and so on. (Refer the Search and Comparison Options of the NSString Class Reference)
I have an ASP page where I have 2 variables, strActualRate and strProposed.
The values are:
strActualRate = 33.30
strProposed = 33.3
So when I write the following line to compare:
if strActualRate <> strProposed then
Response.Writr "Both are not equal!"
end if
I am getting the output "Both are not equal", even though both are the same.
I am sure that I need to use some mathematical conversion function to compare.
Can anyone tell me how to solve this ?
Thanks in advance!
If I understand correctly, you think the two values are equal but because VBScript is comparing strings rather than numbers the two are coming back as not equal.
You're correct in the conversion idea, and here's the code:
if CDbl(strActualRate) <> CDbl(strProposed) then
Response.Write "Both are not equal!"
end if
That will convert your string values to numbers to do the comparison.
Your question doesn't really add up, so I'm not really sure what the problem is. I will try to clear up some things about data types and comparison.
You are using the prefix "str" for your variables which suggests that you intend to store string values in them, however you are instead storing numeric values in them. Either you are confused about how hungarian notation is used to keep track of the data type, or the code that you posted does not look like the code that you are actually using.
The numeric value 33.30 is exactly the same as the value 33.3. If you instead would have used the string values "33.30" and "33.3", they would be two strings that are not equal.
If your code is corrected (Response.Write instead of Response.Writr) so that it runs, it will not produce any output at all. As the values are equal, the condifion in the if statement evaluates to false.
If you do in fact assign string values to the variables, the code would output "Both are not equal!". This is just as expected as the strings are not equal. If you have strings and want to compare them as numerical values, you have to comvert them:
If CDbl(strActualRate) <> CDbl(strProposed) Then
Response.Write "Both are not equal!"
End If
Try casting the values to a double in the comparison statement with CDbl()
Are you intending to perform the comparison as strings, floating point numbers or some other method? If you are comparing them as strings, then clearly they are not equal, as one of them has an extra zero on the end. If you are comparing them as floating point numbers, then you generally want to use a comparison that involves taking the difference and checking that it is smaller than some small value. This is because floating point number calculations involve some degree of inaccuracy and comparisons between them can fail because of the underlying representation.