Hello i trying create converter method from Disct to Vector in Julia language.
But i receive error, with i can't understand
ERROR: TypeError: Tuple: in parameter, expected Type{T}, got Dict{AbstractString,Int64}
My code
type Family
name::UTF8String
value::Int
end
function convertToVector(a1::Dict{AbstractString, Int64}())
A::Vector{Node}
for k in sort(collect(keys(a1)))
push!(A, Family(a1[k] , k))
end
return A
end
Any idea hot to change convertToVector method ?
There were several typos in the above code, but I think this should work:
# No () after the type of a1
# Also, see comment, better to parameterize function, use concrete type for Dict
function convertToVector{T<:AbstractString}(a1::Dict{T, Int64})
# This is how you create an empty vector to hold Family objects
A = Vector{Family}()
for k in sort(collect(keys(a1)))
# The values passed to the Family constructor were backwards
push!(A, Family(k, a1[k]))
end
A
end
Another way (probably not very quick):
julia> dict = Dict("fred" => 3, "jim" => 4)
Dict{ASCIIString,Int64} with 2 entries:
"fred" => 3
"jim" => 4
julia> Vector{Family}(map(f -> Family(f...), map(x -> collect(x), dict)))
2-element Array{Family,1}:
Family("fred",3)
Family("jim",4)
Perhaps I've been using too much Lisp recently...
Related
I want to create an empty lsit and gardually fill that out with tuples. I've tried the following and each returns an error. My question is: how to append or add and element to an empty array?
My try:
A = []
A.append((2,5)) # return Error type Array has no field append
append(A, (2,5)) # ERROR: UndefVarError: append not defined
B = Vector{Tuple{String, String}}
# same error occues
You do not actually want to append, you want to push elements into your vector. To do that use the function push! (the trailing ! indicates that the function modifies one of its input arguments. It's a naming convention only, the ! doesn't do anything).
I would also recommend creating a typed vector instead of A = [], which is a Vector{Any} with poor performance.
julia> A = Tuple{Int, Int}[]
Tuple{Int64, Int64}[]
julia> push!(A, (2,3))
1-element Vector{Tuple{Int64, Int64}}:
(2, 3)
julia> push!(A, (11,3))
2-element Vector{Tuple{Int64, Int64}}:
(2, 3)
(11, 3)
For the vector of string tuples, do this:
julia> B = Tuple{String, String}[]
Tuple{String, String}[]
julia> push!(B, ("hi", "bye"))
1-element Vector{Tuple{String, String}}:
("hi", "bye")
This line in your code is wrong, btw:
B = Vector{Tuple{String, String}}
It does not create a vector, but a type variable. To create an instance you can write e.g. one of these:
B = Tuple{String, String}[]
B = Vector{Tuple{String,String}}() # <- parens necessary to construct an instance
It can also be convenient to use the NTuple notation:
julia> NTuple{2, String} === Tuple{String, String}
true
julia> NTuple{3, String} === Tuple{String, String, String}
true
I'm trying construct an array of structs where each instance contains a different function. I want to add these to an array in a loop.
Here's an example:
struct mystruc{F}
σ::F
end
a = [mystruc(relu)]
for i in 1:3
append!(a, [mystruc(identity), ])
end
As a side note, I have the option to preallocate the array I just couldn't figure out how to do with this type of struct.
Each function has a type, which is exclusive to that function:
julia> typeof(x -> x) == typeof(x -> x)
false
Here we created the function x -> x twice, they are two different functions, so their types are not the same.
In your construction of a, you create an Array of that specific type:
julia> a = [mystruc(relu)]
1-element Array{mystruc{typeof(relu)},1}:
mystruc{typeof(relu)}(relu)
julia> typeof(a)
Array{mystruc{typeof(relu)},1}
So when you push another function, we get an error, because this array can only contain objects of the type mystruc{typeof(relu)}.
julia> push!(a, mystruc(x -> 2x))
ERROR: MethodError: Cannot `convert` an object of type
mystruc{var"#3#4"} to an object of type
mystruc{typeof(relu)}
Closest candidates are:
convert(::Type{T}, ::T) where T at essentials.jl:171
mystruc{typeof(relu)}(::Any) where F at REPL[2]:2
Solution
When you construct a, tell Julia that the array will contain mystruc with any function:
julia> a = mystruc{<:Function}[mystruc(relu)]
and now it works!
julia> push!(a, mystruc(x -> 2x))
2-element Array{mystruc{#s1} where #s1<:Function,1}:
mystruc{typeof(relu)}(relu)
mystruc{var"#5#6"}(var"#5#6"())
If I have a function signature like f(args...; kwargs...), how can I get a specific keyword out of kwargs? Naïvely typing kwargs.x does not work:
julia> f(args...; kwargs...) = kwargs.x
f (generic function with 1 method)
julia> f(x=1)
ERROR: type Pairs has no field x
Stacktrace:
[1] getproperty(::Base.Iterators.Pairs{Symbol,Int64,Tuple{Symbol},NamedTuple{(:x,),Tuple{Int64}}}, ::Symbol) at ./Base.jl:20
[2] #f#7(::Base.Iterators.Pairs{Symbol,Int64,Tuple{Symbol},NamedTuple{(:x,),Tuple{Int64}}}, ::typeof(f)) at ./REPL[2]:1
[3] (::var"#kw##f")(::NamedTuple{(:x,),Tuple{Int64}}, ::typeof(f)) at ./none:0
[4] top-level scope at REPL[3]:1
This question appeared on the JuliaLang Slack channel in the #helpdesk. For an automatic invite to the very helpful julia slack, simply fill out https://slackinvite.julialang.org
The reason this happens is that splatted keyword arguments are not stored in a named tuple by default. We can see how they're stored like so:
julia> g(;kwargs...) = kwargs
g (generic function with 1 method)
julia> g(a=1)
pairs(::NamedTuple) with 1 entry:
:a => 1
julia> g(a=1) |> typeof
Base.Iterators.Pairs{Symbol,Int64,Tuple{Symbol},NamedTuple{(:a,),Tuple{Int64}}}
So the splatted kwargs are instead stored as some sort of iterator object. However, we can easily convert that kwargs iterator to a NamedTuple like so: (;kwargs...) and then access it in the way we'd expect, so your example would translate into
julia> f(args...; kwargs...) = (;kwargs...).x
f (generic function with 1 method)
julia> f(x=1, y=2)
1
Of course, the more idiomatic way to do this would be to instead write the function as
julia> f(args...; x, kwargs...) = x
f (generic function with 1 method)
julia> f(x=1, y=2)
1
but this assumes you know the name you want to access (x) at the time when you write the function.
A brief sidenote: If we return to our example of g(;kwargs...) = kwargs, we can ask for the fieldnames of the iterator object the was returned like so:
julia> g(x=1, y=2) |> typeof |> fieldnames
(:data, :itr)
Hm, what is this data field?
julia> g(x=1, y=2).data
(x = 1, y = 2)
Aha! so we can actually get the kwargs as a named tuple using that, i.e. f(;kwargs...) = kwargs.data.x would work, but I wouldn't recommend this approach since it seems to rely on undocumented behaviour, so it may be a mere implementation detail that is not guaranteed to be stable across julia versions.
Is there a possibility to construct dictionary with tuple values in Julia?
I tried
dict = Dict{Int64, (Int64, Int64)}()
dict = Dict{Int64, Tuple(Int64, Int64)}()
I also tried inserting tuple values but I was able to change them after so they were not tuples.
Any idea?
Edit:
parallel_check = Dict{Any, (Any, Any)}()
for i in 1:10
dict[i] = (i+41, i+41)
end
dict[1][2] = 1 # not able to change this way, setindex error!
dict[1] = (3, 5) # this is acceptable. why?
The syntax for tuple types (i.e. the types of tuples) changed from (Int64,Int64) in version 0.3 and earlier to Tuple{Int64,Int64} in 0.4. Note the curly braces, not parens around Int64,Int64. You can also discover this at the REPL by applying the typeof function to an example tuple:
julia> typeof((1,2))
Tuple{Int64,Int64}
So you can construct the dictionary you want like this:
julia> dict = Dict{Int64,Tuple{Int64,Int64}}()
Dict{Int64,Tuple{Int64,Int64}} with 0 entries
julia> dict[1] = (2,3)
(2,3)
julia> dict[2.0] = (3.0,4)
(3.0,4)
julia> dict
Dict{Int64,Tuple{Int64,Int64}} with 2 entries:
2 => (3,4)
1 => (2,3)
The other part of your question is unrelated, but I'll answer it here anyway: tuples are immutable – you cannot change one of the elements in a tuple. Dictionaries, on the other hand are mutable, so you can assign an entirely new tuple value to a slot in a dictionary. In other words, when you write dict[1] = (3,5) you are assigning into dict, which is ok, but when you write dict[1][2] = 1 you are assigning into the tuple at position 1 in dict which is not ok.
I have a function, f. I want to add a method that takes any container of Strings. For example, I want to write a method that generates the following when needed:
f(xs::Array{String, 1}) = ...
f(xs::DataArray{String, 1}) = ...
f(xs::ITERABLE{String}) = ...
Is this possible to do in Julia's type system? Right now, I'm using a macro to write a specialized method when I need it.
#make_f(Array{String, 1})
#make_f(DataArray{String, 1})
This keeps things DRY, but it feels...wrong.
Can't you just use duck typing? I.e., just assume that you're feeding the function an object of the right type and throw an error if at some point e.g. you don't have a string in your iterable.
This should improve once you can really talk about iterables using traits; currently there is no iterable type. Scott's answer, for example, will not work with a tuple of strings, even though that is iterable.
E.g.
julia> f(x) = string(x...) # just concatenate the strings
f (generic function with 1 method)
julia> f(("a", "á"))
"aá"
julia> f(["a", "á"])
"aá"
julia> f(["a" "b"; "c" "d"]) # a matrix of strings!
"acbd"
At least in Julia 0.4, the following should work:
julia> abstract Iterable{T} <: AbstractVector{T}
julia> f{T<:Union{Vector{String},Iterable{String}}}(xs::T) = 1
f (generic function with 1 method)
julia> x = String["a", "é"]
2-element Array{AbstractString,1}:
"a"
"é"
julia> f(x)
1