Column Relationships - sqlite

Question

I realize i'm far off the solution with what i have:
Select FirstName || ' ' || LastName AS Manager From Employee
Where (Select COUNT(ReportsTo) from Employee
group by ReportsTo
order by ReportsTo desc);
ReportsTovalues are the EmployeeID they report to
What i want is to query the name of the employee with the most Employees reporting to them and who they in turn report to without nulls. I'm Not sure how to make the connections between columns values such as ReportsTo to EmployeeID so any explanation would help
For Example the output i would want is two columns say | Fred Jones | Mary Anne| the first being the employee with the most reportsTo with the same value as their EmployeeID and the second being the name of the employee with the same EmployeeID as the first employees ReportTo

Answer 1

Do this step by step:
First step: Count how many employees report to a person.
select reportsto, count(*) from employee group by reportsto;
We can order this result by count(*) and limit it to only get one row, so as to get the person with the most reporters. Only problem is: What to do in case of ties, i.e. two persons have the same highest amount of reporters? SQLite doesn't offer much to help here. We'll have to query twice:
select reportsto
from employee
group by reportsto
having count(*) =
(
select count(*)
from employee
group by reportsto
order by count(*) desc
limit 1
);
Next step: Get the name. That means we must access the table again.
select
firstname || ' ' || lastname as manager
from employee
where e1.employeeid in
(
select reportsto
from employee
group by reportsto
having count(*) =
(
select count(*)
from employee
group by reportsto
order by count(*) desc
limit 1
)
);
Last step: Get the persons our found managers themselves report to. These can be many, so we group by manager and concatenate all those they report to.
select
e1.firstname || ' ' || e1.lastname as manager,
group_concat(e2.firstname || ' ' || e2.lastname) as reportsto
from employee e1
join employee e2 on e2.employeeid = e1.reportsto
where e1.employeeid in
(
select reportsto
from employee
group by reportsto
having count(*) =
(
select count(*)
from employee
group by reportsto
order by count(*) desc
limit 1
)
)
group by e1.firstname || ' ' || e1.lastname;

Answer 2

SELECT e.ReportsTo AS TopManagersEmployeeId, COUNT(e.ReportsTo) AS ReportedBy, m.FirstName + ' ' + m.LastName AS TopManagersName, mm.FirstName + ' ' + mm.LastName AS TheirManagersName FROM Employees e
JOIN Employees m
ON e.ReportsTo = m.EmployeeID
JOIN Employees mm
ON m.ReportsTo = mm.EmployeeID
GROUP BY e.ReportsTo, m.FirstName, m.LastName, mm.FirstName, mm.LastName
Once you have this data, you can do TOP 1 etc. You can also play around with JOIN, and make it INNER JOIN in the second set where Manager's Manager (mm) is being retrieved.