Create multiple variable, assign attributes, assign values in a for loop - r

Question

I am looking to create a list of vectors to which I want to assign specific value. I know I can do something like
var_list=c(V1, V2...etc)
Then use var_list[i] in a for loops. To do this thought, I have to manually creates the list at first, which is long.
I know I can do something like
for(i in 1:n){
assign(paste("Mx", i, sep = ""), i)
}
This will creates my variable name. Trouble is, how do I manage them? I would like a way to do something like this :
for(i in 1:n){
attributes(assign(paste("Mx", i, sep = ""), i))<-list(dim=1:n)
"here I would like to append the newly created variable (Mx"i") into a list so I could manage the whole thing later on".
}
So I could do :
for (k in 1:n){
for (j in 1:m)
new_list[[k]][j]<-other_list[[k]][(j-1)*3+1]
}
Any1 got a idea?
The basic problem is that I have this long list of vector (which is represented here by "other_list"). Each vector in this list has 36 entry. I want to divide each of these vector in three different vector (I need to specify the specific value of the vector from "other_list" I want to apply to the specific value of the vector of the " new_list ".
Thanks !

Answer 1

Just pre-allocate the list and assign its names:
n <- 10
#pre-allocate list
mylist <- vector(n, mode = "list")
#assign names
names(mylist) <- paste0("Mx", seq_len(n))
#fill the list
for(i in 1:n){
mylist[[i]] <- i
}
mylist[1:3]
#$Mx1
#[1] 1
#
#$Mx2
#[1] 2
#
#$Mx3
#[1] 3
PS: You should learn to use lapply for such tasks.
setNames(lapply(seq_len(n), identity), paste0("Mx", seq_len(n)))
And the optimal solution for the specific example is this:
setNames(as.list(seq_len(n)), paste0("Mx", seq_len(n)))