Searching not exists in Neo4j via Cypher - graph

Question

I have some relations between persons in my graph.
my data (generate script below)
create (s:Person {name: "SUE"})
create(d:Person {name: "DAVID"})
create(j:Person {name: "JACK"})
create(m:Person {name: "MARY"})
create(js:Person {name: "JASON"})
create(b:Person {name: "BOB"})
create(a1:Adress {id:1})
create(a2:Adress {id:2})
create(a3:Adress {id:3})
create(a4:Adress {id:4})
create(a5:Adress {id:5})
merge (d)-[:MOTHER]->(s)
merge(j)-[:MOTHER]->(s)
merge(js)-[:MOTHER]->(m)
merge(b)-[:MOTHER]->(m)
merge(b)-[:CURRENT_ADRESS]->(a1)
merge(js)-[:CURRENT_ADRESS]->(a2)
merge(j)-[:CURRENT_ADRESS]->(a3)
merge(s)-[:CURRENT_ADRESS]->(a4)
merge(d)-[:CURRENT_ADRESS]->(a5)
;
I can get mothers who live with her child:
MATCH (p:Person)-[:CURRENT_ADRESS]->(a:Adress)<-[:CURRENT_ADRESS]-(t), (t)-[:MOTHER]->(p)
return p.name,t.name
p.name t.name
MARY JASON
but i want to get mothers who is not living with any child of her.
How can i do that in Cyper?

Answer 1

Actually in your graph, everybody is living at a different address due to different identifiers.
Let's build a graph example introducing the sister which lives at the same address :
CREATE
(p:Person)-[:MOTHER]->(m:Person),
(p)-[:FATHER]->(f:Person),
(p)-[:SISTER]->(s:Person),
(p)-[:CURRENT_ADDRESS]->(a:Adress),
(m)-[:CURRENT_ADDRESS]->(b:Adress),
(f)-[:CURRENT_ADDRESS]->(c:Adress),
(s)-[:CURRENT_ADDRESS]->(a)
Now this is very simple, match family members that don't have a CURRENT_ADDRESS relationship in depth2 to the family member :
MATCH (p:Person)-[:MOTHER|:FATHER|:SISTER]->(familyMember)
WHERE NOT EXISTS((p)-[:CURRENT_ADDRESS*2]-(familyMember))
RETURN familyMember

Answer 2

Try this
MATCH (p:Person)-[:CURRENT_ADRESS]-(a:Adress), (p)-[:MOTHER|:FATHER]->(t)
WITH p,a,t
MATCH (p), (t) where not (t)-[:CURRENT_ADRESS]-(a)
return p.NAME,t.NAME

Answer 3

This should work:
MATCH (p:Person)-[:CURRENT_ADRESS]-(a:Adress), (p)-[:MOTHER|:FATHER]->(t)-[:CURRENT_ADRESS]-(b:Adress)
WHERE a <> b
return p.NAME, t.NAME;
By the way, I'd also put the appropriate direction arrow on the CURRENT_ADRESS relationships.

Answer 4

Finally i found it.
match path=(p:Person)-[:MOTHER]->(m:Person)-[:CURRENT_ADRESS]->(a:Adress)
where all(x in nodes(path) where not exists((p)-[:CURRENT_ADRESS]->(a)))
return path