Improve AWK script - Compare and add fields - unix
I have a CSV file separated by semicolons, the file contains a sentiment analysis on customer reviews.
The views are grouped by field 1 and 6, what I have to do is add the last fields of each line of the group and then compare the sum with field 3. If they match, the comparison equals 1 if not 0.
At the same time, I have also compare fields 6 and 7 applying the same rule above.
Finally calculate the number of ones obtained for both comparisons separately.
I have a script made below, but I think it could be improved. Any suggestions? Also I am not sure that the script is fine..!
BEGIN {
OFS=FS=";";
flag="";
counter1=0;
counter2=0;
counter3=0;
}
{
number=$1;
topic=$6;
id= number";"topic;
if (id != flag)
{
for (i in topics)
{
if ((sum < 0) && (polarity[i] == "negative") || (sum > 0) && (polarity[i] == "positive"))
{
hit_2=1;
counter2++;
}
else
{
hit_2=0;
}
s=split(topics[i],words,";")
hit_1=0;
for (k=1;k<=s;k++)
{
if ((words[k] == words[k+1]) && (words[k] != "") || (words[k] == "NULL") && (hit_2 == 1))
{
hit_1=1;
}
}
if (hit_1 == 1)
{
counter1++;
}
print to_print[i]";"hit_1";"hit_2;
}
delete topics;
delete to_print;
delete polarity;
counter3++;
sum="";
flag=id;
}
sum += $(NF-1);
topics[$1";"$6]=topics[$1";"$6] ";"$6";"$7;
to_print[$1";"$6]=$1";"$2";"$3";"$4";"$5";"$6
polarity[$1";"$6]=$3;
}
END {
print ""
print "#### - sentiments: "counter3" - topic: "counter1 " - polarity: "counter2;
}
A portion of the input data:
100429301;"RESTAURANT#GENERAL";negative;1004293;10042930;place;place;place;good;good;2.000000;
100429301;"RESTAURANT#GENERAL";negative;1004293;10042930;place;place;place;not longer;not longer;-3.000000;
100429331;"FOOD#QUALITY";negative;1004293;10042933;food;food;food;lousy;lousy;-3.000000;
100429331;"FOOD#QUALITY";negative;1004293;10042933;food;food;food;too sweet;too sweet;3.600000;
100429331;"FOOD#QUALITY";negative;1004293;10042933;food;portions;portion;tiny;tiny;-1.000000;
103269521;"FOOD#QUALITY";positive;1032695;10326952;duck breast special;visit;visit;incredible;incredible;4.000000;
Output:
100429301;"RESTAURANT#GENERAL";negative;1004293;10042930;place;1;1
100429331;"FOOD#QUALITY";negative;1004293;10042933;food;1;1
103269521;"FOOD#QUALITY";positive;1032695;10326952;duck breast special;0;1
#### - sentiments: 57 - topic: 28 - polarity: 39
I rewrote part of it, perhaps you can extend this further.
$ awk -F';' -v OFS=';' '
{key=$1 FS $3 FS $6;
sum[key]+=$(NF-1);
line[key]=$1 FS $2 FS $3 FS $4 FS $5 FS $6;
sign[key]=($3=="negative"?-1:1)
}
END{for(k in sum)
print line[k],(sum[k]*sign[k]<0?0:1),sum[k],sign[k]}' data
100429301;"RESTAURANT#GENERAL";negative;1004293;10042930;place;1;-1;-1
103269521;"FOOD#QUALITY";positive;1032695;10326952;duck breast special;1;4;1
100429331;"FOOD#QUALITY";negative;1004293;10042933;food;1;-0.4;-1
This only does your first check (I guess hit2), while also added sum and sign information (last two fields).
Related
Explain the AWK syntax in detail(NR,FNR,NF)
I am learning file comparison using awk.
I found syntax like below,
awk '
(NR == FNR) {
s[$0]
next
}
{
for (i=1; i<=NF; i++)
if ($i in s)
delete s[$i]
}
END {
for (i in s)
print i
}' tests tests2
I couldn't understand what is the Syntax ...Can you please explain in detail?
What exactly does it do?
awk ' # use awk
(NR == FNR) { # process first file
s[$0] # hash the whole record to array s
next # process the next record of the first file
}
{ # process the second file
for (i=1; i<=NF; i++) # for each field in record
if ($i in s) # if field value found in the hash
delete s[$i] # delete the value from the hash
}
END { # after processing both files
for (i in s) # all leftover values in s
print i # are output
}' tests tests2
For example, for files:
tests:
1
2
3
tests2:
1 2
4 5
program would output:
3
how to use awk to pull fields and make them variables to do data calculation
I am using awk to compute Mean Frational Bias form a data file. How can I make the data points a variable to call in to my equation?
Input.....
col1 col2
row #1 Yavg: 14.87954
row #2 Xavg: 20.83804
row #3 Ystd: 7.886613
row #4 Xstd: 8.628519
I am looking to feed into this equation....
MFB = .5 * (Yavg-Xavg)/[(Yavg+Xavg)/2]
output....
col1 col2
row #1 Yavg: 14.87954
row #2 Xavg: 20.83804
row #3 Ystd: 7.886613
row #4 Xstd: 8.628519
row #5 MFB: (computed value)
currently trying to use the following code to do this but not working....
var= 'linear_reg-County119-O3-2004-Winter2013-2018XYstats.out.out'
val1=$(awk -F, OFS=":" "NR==2{print $2; exit}" <$var)
val2=$(awk -F, OFS=":" "NR==1{print $2; exit}" <$var)
#MFB = .5*((val2-val1)/((val2+val1)/2))
awk '{ print "MFB :" .5*((val2-val1)/((val2+val1)/2))}' >> linear_regCounty119-O3-2004-Winter2013-2018XYstats-wMFB.out
Try running: awk -f mfb.awk input.txt where
mfb.awk:
BEGIN { FS = OFS = ": " } # set the separators
{ v[$1] = $2; print } # store each line in an array named "v"
END {
MFB = 0.5 * (v["Yavg"] - v["Xavg"]) / ((v["Yavg"] + v["Xavg"]) / 2)
print "MFB", MFB
}
input.txt:
Yavg: 14.87954
Xavg: 20.83804
Ystd: 7.886613
Xstd: 8.628519
Output:
Yavg: 14.87954
Xavg: 20.83804
Ystd: 7.886613
Xstd: 8.628519
MFB: -0.166823
Alternatively, mfb.awk can be the following, resembling your original code:
BEGIN { FS = OFS = ": " }
{ print }
NR == 1 { Yavg = $2 } NR == 2 { Xavg = $2 }
END {
MFB = 0.5 * (Yavg - Xavg) / ((Yavg + Xavg) / 2)
print "MFB", MFB
}
Note that you don't usually toss variables back and forth between the shell and Awk (at least when you deal with a single input file).
How to concatenate the values based on other field in unix
I have detail.txt file ,which contains
cat >detail.txt
Student ID,Student Name, Percentage
101,A,75
102,B,77
103,C,34
104,D,42
105,E,75
106,F,42
107,G,77
1.I want to print concatenated output based on Percentage (group by Percentage) and print student name in single line separated by comma(,).
Expected Output:
75-A,E
77-B,G
42-D,F
34-C
For above question i got that how can achieve this for 75 or 77 or 42. But i did not get how to write a code grouping third field (Percentage).
I tried below code
awk -F"," '{OFS=",";if($3=="75") print $2}' detail.txt
2. I want to get output based on grading system which is given below.
marks < 45=THIRD
marks>=45 and marks<60 =SECOND
marks>=60 and marks<=75 =FIRST
marks>75 =DIST
Expected Output:
DIST:B,G
FIRST:A,E
THIRD:C,D,F
Please help me to get the expected output. Thank You..
awk solution:
awk -F, 'NR>1{
if ($3<45) k="THIRD"; else if ($3>=45 && $3<60) k="SECOND";
else if ($3>=60 && $3<=75) k="FIRST"; else k="DIST";
a[k] = a[k]? a[k]","$2 : $2;
}END{ for(i in a) print i":"a[i] }' detail.txt
k - variable that will be assigned with "grading system" name according to one of the if (...) <exp>; else if(...) <exp> ... statements
a[k] - array a is indexed by determined "grading system" name k
a[k] = a[k]? a[k]","$2 : $2 - all "student names"(presented by the 2nd field $2) are accumulated/grouped into the needed "grading system"
The output:
DIST:B,G
THIRD:C,D,F
FIRST:A,E
With GNU awk for true multi-dimensional arrays:
$ cat tst.awk
BEGIN { FS=OFS="," }
NR>1 {
stud = $2
pct = $3
if ( pct <= 45 ) { band = "THIRD" }
else if ( pct <= 60 ) { band = "SECOND" }
else if ( pct <= 75 ) { band = "FIRST" }
else { band = "DIST" }
pcts[pct][stud]
bands[band][stud]
}
END {
for (pct in pcts) {
out = ""
for (stud in pcts[pct]) {
out = (out == "" ? pct "-" : out OFS) stud
}
print out
}
print "----"
for (band in bands) {
out = ""
for (stud in bands[band]) {
out = (out == "" ? band ":" : out OFS) stud
}
print out
}
}
.
$ gawk -f tst.awk file
34-C
42-D,F
75-A,E
77-B,G
----
DIST:B,G
THIRD:C,D,F
FIRST:A,E
For your first question, the following awk one-liner should do:
awk -F, '{a[$3]=a[$3] (a[$3] ? "," : "") $2} END {for(i in a) printf "%s-%s\n", i, a[i]}' input.txt
The second question can work almost the same way, storing your mark divisions in an array, then stepping through that array to determine the subscript for a new array:
BEGIN { FS=","; m[0]="THIRD"; m[45]="SECOND"; m[60]="FIRST"; m[75]="DIST" } { for (i=0;i<=100;i++) if ((i in m) && $3 > i) mdiv=m[i]; marks[mdiv]=marks[mdiv] (marks[mdiv] ? "," : "") $2 } END { for(i in marks) printf "%s:%s\n", i, marks[i] }
But this is unreadable. When you need this level of complexity, you're past the point of a one-liner. :)
So .. combining the two and breaking them out for easier reading (and commenting) we get the following:
BEGIN {
FS=","
m[0]="THIRD"
m[45]="SECOND"
m[60]="FIRST"
m[75]="DIST"
}
{
a[$3]=a[$3] (a[$3] ? "," : "") $2 # Build an array with percentage as the index
for (i=0;i<=100;i++) # Walk through the possible marks
if ((i in m) && $3 > i) mdiv=m[i] # selecting the correct divider on the way
marks[mdiv]=marks[mdiv] (marks[mdiv] ? "," : "") $2
# then build another array with divider
# as the index
}
END { # Once we've processed all the input,
for(i in a) # step through the array,
printf "%s-%s\n", i, a[i] # printing the results.
print "----"
for(i in marks) # step through the array,
printf "%s:%s\n", i, marks[i] # printing the results.
}
You may be wondering why we for (i=0;i<=100;i++) instead of simply using for (i in m). This is because awk does not guarantee the order of array elements, and when stepping through the m array, it's important that we see the keys in increasing order.
Get a specific column number by column name using awk
i have n number of file, in these files a specific column named "thrudate" is given at different column number in every files.
i Just want to extract the value of this column from all files in one go. So i tried with using awk. Here i'm considering only one file, and extracting the values of thrudate
awk -F, -v header=1,head="" '{for(j=1;j<=2;j++){if($header==1){for(i=1;i<=$NF;i++){if($i=="thrudate"){$head=$i;$header=0;break}}} elif($header==0){print $0}}}' file | head -10
How i have approached:
used find command to find all the similar files and then executing the second step for every file
loop all fields in first row, checking the column name with header values as 1 (initialized it to 1 to check first row only), once it matched with 'thrudate', i set header as 0, then break from this loop.
once i get the column number then print it for every row.
You can use the following awk script:
print_col.awk:
# Find the column number in the first line of a file
FNR==1{
for(n=1;n<=NF;n++) {
if($n == header) {
next
}
}
}
# Print that column on all other lines
{
print $n
}
Then use find to execute this script on every file:
find ... -exec awk -v header="foo" -f print_col.awk {} +
In comments you've asked for a version that could print multiple columns based on their header names. You may use the following script for that:
print_cols.awk:
BEGIN {
# Parse headers into an assoc array h
split(header, a, ",")
for(i in a) {
h[a[i]]=1
}
}
# Find the column numbers in the first line of a file
FNR==1{
split("", cols) # This will re-init cols
for(i=1;i<=NF;i++) {
if($i in h) {
cols[i]=1
}
}
next
}
# Print those columns on all other lines
{
res = ""
for(i=1;i<=NF;i++) {
if(i in cols) {
s = res ? OFS : ""
res = res "" s "" $i
}
}
if (res) {
print res
}
}
Call it like this:
find ... -exec awk -v header="foo,bar,test" -f print_cols.awk {} +
awk count and sum based on slab:
Would like to extract all the lines from first file (GunZip *.gz i.e Input.csv.gz), if the first file 4th field is falls within a range of
Second file (Slab.csv) first field (Start Range) and second field (End Range) then populate Slab wise count of rows and sum of 4th and 5th field of first file.
Input.csv.gz (GunZip)
Desc,Date,Zone,Duration,Calls
AB,01-06-2014,XYZ,450,3
AB,01-06-2014,XYZ,642,3
AB,01-06-2014,XYZ,0,0
AB,01-06-2014,XYZ,205,3
AB,01-06-2014,XYZ,98,1
AB,01-06-2014,XYZ,455,1
AB,01-06-2014,XYZ,120,1
AB,01-06-2014,XYZ,0,0
AB,01-06-2014,XYZ,193,1
AB,01-06-2014,XYZ,0,0
AB,01-06-2014,XYZ,161,2
Slab.csv
StartRange,EndRange
0,0
1,10
11,100
101,200
201,300
301,400
401,500
501,10000
Expected Output:
StartRange,EndRange,Count,Sum-4,Sum-5
0,0,3,0,0
1,10,NotFound,NotFound,NotFound
11,100,1,98,1
101,200,3,474,4
201,300,1,205,3
301,400,NotFound,NotFound,NotFound
401,500,2,905,4
501,10000,1,642,3
I am using below two commands to get the above output , expect "NotFound"cases .
awk -F, 'NR==FNR{s[NR]=$1;e[NR]=$2;c[NR]=$0;n++;next} {for(i=1;i<=n;i++) if($4>=s[i]&&$4<=e[i]) {print $0,","c[i];break}}' Slab.csv <(gzip -dc Input.csv.gz) >Op_step1.csv
cat Op_step1.csv | awk -F, '{key=$6","$7;++a[key];b[key]=b[key]+$4;c[key]=c[key]+$5} END{for(i in a)print i","a[i]","b[i]","c[i]}' >Op_step2.csv
Op_step2.csv
101,200,3,474,4
501,10000,1,642,3
0,0,3,0,0
401,500,2,905,4
11,100,1,98,1
201,300,1,205,3
Any suggestions to make it one liner command to achieve the Expected Output , Don't have perl , python access.
Here is another option using perl which takes benefits of creating multi-dimensional arrays and hashes.
perl -F, -lane'
BEGIN {
$x = pop;
## Create array of arrays from start and end ranges
## $range = ( [0,0] , [1,10] ... )
(undef, #range)= map { chomp; [split /,/] } <>;
#ARGV = $x;
}
## Skip the first line
next if $. ==1;
## Create hash of hash
## $line = '[0,0]' => { "count" => counts , "sum4" => sum_of_col4 , "sum5" => sum_of_col5 }
for (#range) {
if ($F[3] >= $_->[0] && $F[3] <= $_->[1]) {
$line{"#$_"}{"count"}++;
$line{"#$_"}{"sum4"} +=$F[3];
$line{"#$_"}{"sum5"} +=$F[4];
}
}
}{
print "StartRange,EndRange,Count,Sum-4,Sum-5";
print join ",", #$_,
$line{"#$_"}{"count"} //"NotFound",
$line{"#$_"}{"sum4"} //"NotFound",
$line{"#$_"}{"sum5"} //"NotFound"
for #range
' slab input
StartRange,EndRange,Count,Sum-4,Sum-5
0,0,3,0,0
1,10,NotFound,NotFound,NotFound
11,100,1,98,1
101,200,3,474,4
201,300,1,205,3
301,400,NotFound,NotFound,NotFound
401,500,2,905,4
501,10000,1,642,3
Here is one way using awk and sort:
awk '
BEGIN {
FS = OFS = SUBSEP = ",";
print "StartRange,EndRange,Count,Sum-4,Sum-5"
}
FNR == 1 { next }
NR == FNR {
ranges[$1,$2]++;
next
}
{
for (range in ranges) {
split(range, tmp, SUBSEP);
if ($4 >= tmp[1] && $4 <= tmp[2]) {
count[range]++;
sum4[range]+=$4;
sum5[range]+=$5;
next
}
}
}
END {
for(range in ranges)
print range, (count[range]?count[range]:"NotFound"), (sum4[range]?sum4[range]:"NotFound"), (sum5[range]?sum5[range]:"NotFound") | "sort -t, -nk1,2"
}' slab input
StartRange,EndRange,Count,Sum-4,Sum-5
0,0,3,NotFound,NotFound
1,10,NotFound,NotFound,NotFound
11,100,1,98,1
101,200,3,474,4
201,300,1,205,3
301,400,NotFound,NotFound,NotFound
401,500,2,905,4
501,10000,1,642,3
Set the Input, Output Field Separators and SUBSEP to ,. Print the Header line.
If it is the first line skip it.
Load the entire slab.txt in to an array called ranges.
For every range in the ranges array, split the field to get start and end range. If the 4th column is in the range, increment the count array and add the value to sum4 and sum5 array appropriately.
In the END block, iterate through the ranges and print them.
Pipe the output to sort to get the output in order.