How to round an int in Qt to the nearest 5 - qt

Question

I am looking for a good way to round an int in Qt to the nearest 5.
e.g:
8 -> 10
12 -> 10
13 -> 15
15 -> 15
17 -> 15
and so on

Answer 1

Rounding in C++ to the nearest integer number usually is done via:
static_cast<int>(number + 0.5);
Now, to round it to the next 5, I would bring it into the system where we can apply this rounding rule (i.e. 5 -> 1, 6 -> 1.2) and then bring it back into the system where 5 really is 5:
int roundToNearestFive(int number)
{
return static_cast<int>(number / 5. + .5) * 5;
}
I find this formulation easiest.

Answer 2

Here a possible solution:
#include<iostream>
int toNearest5(int i) {
int r = i%5, o = 0;
if(r) {
o = r/5. >= .5 ? 5 : 0;
}
return (i-r+o);
}
int main() {
using namespace std;
cout << toNearest5(8) << endl;
cout << toNearest5(12) << endl;
cout << toNearest5(13) << endl;
cout << toNearest5(15) << endl;
cout << toNearest5(17) << endl;
}
The idea is to get the number and round it to the lowest multiple of 5 (you can do that by removing the remainder), that is:
int remainder = i%5;
int rounded = i - remainder;
Now, you can check the remainder and add 5 to the rounded number if the remainder is greater than 2.5, otherwise add 0.
In order to check it, I've divided the remainder by 5 (its upper bound), so that to get a number in [0,1[ and check it with 0.5 to know how to round the original number.
It follows a more compact version of the same function:
int toNearest5(int i) {
int j = i%5;
return (i - j + (j/5. >= .5 ? 5 : 0));
}
I don't know if the Qt framework offers something similar out of the box, but it's a matter of an one line function, you can easily write it for yourself.