I need to print a test with 3 parts to a Word document. Part 1-question 1 to question 56. Part2-question 57 to question 66; Part3-question 67-question 100. Part 1 and Part 2 questions are required to be on two columns on paper. For example, questions appear on the first page are following.
1. 7.
2. 8.
3. 9.
4. 10.
5. 11.
6. 12.
I have created code behind and the report PT.rdlc. All questions are showed up nicely on the Word doc except some of the question numbers are dropped off. I can't figure out why. Here are some my codes:
int TRow = Dt.Rows.Count; //TRow = number of rows in Part1 or Part2
for (int RowCount = 0; RowCount < TRow; RowCount++)
{
TDt.Rows.Add(1);
if (RowCount < TRow)
TDt.Rows[TDt.Rows.Count - 1]["ID"] = Dt.Rows[RowCount]["qnum"]; //q1
if RowCount + 6 < TRow
TDt.Rows[TDt.Rows.Count - 1]["TID"] = Dt.Rows[RowCount + 6]["qnum"]; //q7
....
}
I do the same way above for all questions in Part 1 and 2. In the report, I use expressions as following for question numbers.
=iif(Fields!question.Value<>"",Fields!ID.Value & ". ","") and
=iif(Fields!Tquestion.Value<>"",Fields!TID.Value & ". ","")
Can you please help me to identify what is wrong with some question numbers are dropped off? Thank you in advance.
Related
I am trying to make a program to prompt a user for input until they enter a number within a specific range.
What is the best approach to make sure the code does not error out when I enter a letter, a symbol, or a number outside of the specified range?
In alternative to parse, you can use tryparse:
tryparse(type, str; base)
Like parse, but returns either a value of the requested type, or
nothing if the string does not contain a valid number.
The advantage over parse is that you can have a cleaner error handling without resorting to try/catch, which would hide all exceptions raised within the block.
For example you can do:
while true
print("Please enter a whole number between 1 and 5: ")
input = readline(stdin)
value = tryparse(Int, input)
if value !== nothing && 1 <= value <= 5
println("You entered $(input)")
break
else
#warn "Enter a whole number between 1 and 5"
end
end
Sample run:
Please enter a whole number between 1 and 5: 42
┌ Warning: Enter a whole number between 1 and 5
└ # Main myscript.jl:9
Please enter a whole number between 1 and 5: abcde
┌ Warning: Enter a whole number between 1 and 5
└ # Main myscript.jl:9
Please enter a whole number between 1 and 5: 3
You entered 3
This is one possible way to achieve this sort of thing:
while true
print("Please enter a whole number between 1 and 5: ")
input = readline(stdin)
try
if parse(Int, input) <= 5 || parse(Int, input) >= 1
print("You entered $(input)")
break
end
catch
#warn "Enter a whole number between 1 and 5"
end
end
Sample Run:
Please enter a whole number between 1 and 5: 2
You entered 2
See this link for how to parse the user input into an int.
It looks like things are going wrong on line 9 for me. Here I wish to push a new copy of the TagsTable into a dictionary. I'm aware that once a namedtuple field is recorded, it can not be changed. However, results baffle me as it looks like the values do change - when this code exits all entries of mp3_tags[ any of the three dictionary keys ].date are set to the last date of "1999_03_21"
So, two questions:
Is there a way to get a new TagsTable pushed into the dictionary ?
Why doesnt the code fail and not allow the second (and even third) date to be written to the TagsTable.date field (since it seems to be references to the same namedtuple) ? I thought you could not write a second value ?
from collections import namedtuple
2 TagsTable = namedtuple('TagsTable',['title','date','subtitle','artist','summary','length','duration','pub_date'])
3 mp3files = ['42-001.mp3','42-002.mp3','42-003.mp3']
4 dates = ['1999_01_07', '1999_02_14', '1999_03_21']
5
6 mp3_tags = {}
7
8 for mp3file in mp3files:
9 mp3_tags[mp3file] = TagsTable
10
11 for mp3file,date_string in zip(mp3files,dates):
12 mp3_tags[mp3file].date = date_string
13
14 for mp3file in mp3files:
15 print( mp3_tags[mp3file].date )
looks like this is the fix I was looking for:
from collections import namedtuple
mp3files = ['42-001.mp3','42-002.mp3','42-003.mp3']
dates = ['1999_01_07', '1999_02_14', '1999_03_21']
mp3_tags = {}
for mp3file in mp3files:
mp3_tags[mp3file] = namedtuple('TagsTable',['title','date','subtitle','artist','summary','length','duration','pub_date'])
for mp3file,date_string in zip(mp3files,dates):
mp3_tags[mp3file].date = date_string
for mp3file in mp3files:
print( mp3_tags[mp3file].date )
I have a dataframe as follows:
A B
mediafile 1
filemedia 1
media time 1
time media 1
How do I remove the word "media" only if it is the last string in the column. Final Output:
A B
mediafile 1
file 1
media time 1
time 1
Thanks!
In regex, $ means "end of the string", so media$ will match media only if it is immediately followed by the end of the string.
Use gsub for find/replace:
your_data$A = gsub(pattern = "media$", replacement = "", x = your_data$A)
R uses regex the same as any other language, so in the future I'd recommend searching SO for something like "[regex] at end of string", which turned up this question, from which you probably could have generalized.
I am writing this code and have recently come across an error. I have no idea why this is happening. In theory, the english alphabet should be being printed. However, instead of the english alphabet, symbols are being printed instead.
I can not paste the symbols for some reason, but if you ran the code yourself, you'll understand what I mean.
My full code is posted below.
alphabet = "abcdefghijklmnopqrstuvwxyzABCDEFHIJKLMNOPQRSTUVWXYZ0123456789"
choice = input("Would you like to encrypt or decrypt? [e/d]: ")
if choice == "e":
message = input("Please insert the message you would like to use: ")
keyword = input("Please insert the keyword you would like to use: ")
ik = len(keyword)
i = 0
string = ''
for A in message:
message1 = (ord(A)) - 96
key1 = (ord(keyword[i])) - 96
addition = message1 + key1
string += (chr(addition))
if i >= ik:
i = 0
else:
i += 1
print (string)
You need to add back the 96 you originally took away :) Alternatively, use the Caesar cipher formula as adding back 96 will still result in symbols appearing (I did the ocr coursework already)
addition = message1 + key1 + 96
your code will not work if the keyword is shorter than the message, so use the modulo operator (%) on i with the length of the keyword inside the line:
key1 = (ord(keyword[i])) - 96
I'm storing some files in database which has filename like 1839341255115211butterflies.jpg.I need to show this filename to the user as butterflies.jpg.I need to remove the first 16 digit and then show the filename.Added to it I also have few filenames which don't have this 16digit addition prior to the filename.Now my question is how do I identify if this string has 16digit numeric value prior to the filename, based on it remove the 1st 16digit and display just the filename. I'm aware of how to remove the first 16digit and retrive the filename but need help on how to identify a string that has 16digit.
Any suggestion is much appreciated.
A regular expression looks like a good fit here:
^[0-9]{16}
The above will match on strings that start with 16 digits (0 to 9).
Usage:
if(Regex.Match(fileName, #"^[0-9]{16}").Success)
{
fileName = fileName.Remove(0, 16);
}
string.Remove will work quite nicely:
var str = "1839341255115211butterflies.jpg";
str = str.Remove(0, 16);
Console.WriteLine(str);
With Linq:
remove all digits at the beginning until 16 digits:
string file = "1839341255115211butterflies.jpg";
string extension = Path.GetExtension(file);
string fileName = Path.GetFileNameWithoutExtension(file);
fileName = new string(fileName.Where((c, i) => i >= 17 || !Char.IsDigit(c)).ToArray());
file = fileName + extension;
Demo
Edit: If you just want to know if the first 16 chars are digits, it's easier and more readable:
bool startsWith16Digits = file.Take(16).All(Char.IsDigit);