True carbon fiber is a series of interlocking grey fibers they look like grey colored woven sheets. Does anyone know how to create such a pattern in CSS please?
The examples by Lea Verou are not true carbon fiber, hopefully you know what "true" carbon fiber looks like!
Ultimately I am wanting to achieve something similar to this background here.
By having further gradients superimposed of the carbon fiber background.
A gradient pattern similar to the one present in the linked website (they use an image as background) can be achieved using the same method as used by Lea Verou.
By adding an extra linear-gradient image as the bottom-most layer and making it go from a darker shade of black to a lighter shade, we can get the same effect as in that website.
Note: That website also uses another layer on top to kind of blur out the ends but I think you are only looking for the interlocking pattern. This extra layer (if required) can also be added using CSS.
body {
background-color: rgb(32, 32, 32);
background-image: linear-gradient(45deg, black 25%, transparent 25%, transparent 75%, black 75%, black), linear-gradient(45deg, black 25%, transparent 25%, transparent 75%, black 75%, black), linear-gradient(to bottom, rgb(8, 8, 8), rgb(32, 32, 32));
background-size: 10px 10px, 10px 10px, 10px 5px;
background-position: 0px 0px, 5px 5px, 0px 0px;
}
If you need an exact replica of the effect in that website (where the gradient fades into a black color at both the left and right side) then add an extra layer on top of the existing gradients and make it go from black to transparent to black like in the below snippet.
body {
background-color: rgb(32, 32, 32);
background-image: linear-gradient(to right, rgba(0,0,0,1), rgba(0,0,0,0) 20%, rgba(0,0,0,0) 80%, rgba(0,0,0,1)), linear-gradient(45deg, black 25%, transparent 25%, transparent 75%, black 75%, black), linear-gradient(45deg, black 25%, transparent 25%, transparent 75%, black 75%, black), linear-gradient(to bottom, rgb(8, 8, 8), rgb(32, 32, 32));
background-size: 100% 100%, 10px 10px, 10px 10px, 10px 5px;
background-position: 0px 0px, 0px 0px, 5px 5px, 0px 0px;
}
Related
I'm using the css gradient checkerboard right now, but I'm having difficulty figuring out how it actually works and how to modify it to be mostly transparent (say 60%).
.checkered {
background-image:
linear-gradient(45deg, #808080 25%, transparent 25%),
linear-gradient(-45deg, #808080 25%, transparent 25%),
linear-gradient(45deg, transparent 75%, #808080 75%),
linear-gradient(-45deg, transparent 75%, #808080 75%);
background-size: 20px 20px;
background-position: 0 0, 0 10px, 10px -10px, -10px 0px;
height:100px;
}
<div class="checkered"></div>
How could I modify this snippet to control the transparency of the resulting checkerboard?
There are two main ways (the first of which is more accepted):
Use rgba() instead of hex.
RGBA stands for Red, Green, Blue, Alpha (where the "Alpha" is the transparency).
.checkered {
background-image: linear-gradient(45deg, rgba(0,0,0,.6) 25%, transparent 25%), linear-gradient(-45deg, rgba(0,0,0,.6) 25%, transparent 25%), linear-gradient(45deg, transparent 75%, rgba(0,0,0,.6) 75%), linear-gradient(-45deg, transparent 75%, rgba(0,0,0,.6) 70%);
background-size: 20px 20px;
background-position: 0 0, 0 10px, 10px -10px, -10px 0px;
}
--- or ---
Add the alpha value at the end of your hex: #808080AA (0-F just like in hex colors. 0 = completely transparent, F = completely opaque)
[ Warning: Doesn't work in IE as far as I know, and maybe some other browsers ]
I am trying to make the entire background of a page look like the image below with CSS, and I'm having difficulty using multiple linear-gradients together. The background has to have thin diagonal stripes with a top-to-bottom color fade that is lighter in the middle and fades to a darker color at the top and bottom.
I have tried a bunch of things and what I have here looks the best so far, but it's not quite right. Here is a jsfiddle showing what I have.
I am okay with the stripes, but the top-to-bottom gradient is definitely off, as the gradient only shows on the transparent stripes. I think what is needed here, is two gradients that overlap somehow to get the effect below, but perhaps there is a better way.
Here is the code from the fiddle in case the link breaks in the future:
/* Stripes */
body {
background: linear-gradient(
-45deg,
#5BABCF 25%,
transparent 25%,
transparent 50%,
#5BABCF 50%,
#5BABCF 75%,
transparent 75%,
transparent
);
background-size: 6px 6px;
height: 100vh;
margin: 0;
padding: 0;
}
/* Color Fade */
html {
background: repeating-linear-gradient(
to bottom,
#051219,
#91B7CA 25%,
transparent 50%,
#91B7CA 75%,
#051219 100%
);
}
Any idea how to go about doing this?
Added opacity to the diagonal stripes in body
body {
background: linear-gradient(
-45deg,
#5BABCF 25%,
transparent 25%,
transparent 50%,
#5BABCF 50%,
#5BABCF 75%,
transparent 75%,
transparent
);
background-size: 6px 6px;
height: 100vh;
margin: 0;
padding: 0;
opacity: 0.2;
}
/* Color Fade */
html {
background: repeating-linear-gradient(
to bottom,
#051219,
#91B7CA 25%,
transparent 50%,
#91B7CA 75%,
#051219 100%
);
}
i have this code on Codepen:
body {
width: 100px;
height: 100px;
background-color: #eee;
background-image: linear-gradient(45deg, black 25%, transparent 25%, transparent 75%, black 75%, black),
linear-gradient(45deg, black 25%, transparent 25%, transparent 75%, black 75%, black);
background-size: 60px 60px;
background-position:0 0, 30px 30px;
}
for some reason I get this message:
Invalid CSS after "100px": expected expression (e.g. 1px, bold), was
";"
Any idea what's going on?
see it on Codepen
When using SASS, you don't need any curly brackets or semicolons. You also have to get rid of any line breaks in comma separated values.
I don't know about the backwards-capability of SASS to CSS, but see the Codepen working with SASS enabled:
http://codepen.io/anon/pen/ygxKvK
body
width: 100px
height: 100px
background-color: #eee
background-image: linear-gradient(45deg, black 25%, transparent 25%, transparent 75%, black 75%, black), linear-gradient(45deg, black 25%, transparent 25%, transparent 75%, black 75%, black)
background-size: 60px 60px
background-position: 0 0, 30px 30px
http://codepen.io/isaacalves/pen/OWoQGP - This works now.
Just set the CSS pre-processor settings as SCSS
I was just confusing Sass with Scss.
http://thesassway.com/editorial/sass-vs-scss-which-syntax-is-better
I want to create a checkerboard pattern using gradients. I've found an example and modified it to my needs, however it only works with -moz prefix. When I remove the -moz prefix, the pattern is completely different.
How can I make this -moz checkerboard pattern work with unprefixed linear-gradient?
body {
background-image:
linear-gradient(45deg, #808080 25%, transparent 25%),
linear-gradient(-45deg, #808080 25%, transparent 25%),
linear-gradient(45deg, transparent 75%, #808080 75%),
linear-gradient(-45deg, transparent 75%, #808080 75%);
background-size:20px 20px;
background-position:0 0, 10px 0, 10px -10px, 0px 10px;
}
Just modify the background-position like in the below snippet to get the required output. This works fine in Firefox, Chrome, Opera, IE11 and Edge.
body {
background-image: linear-gradient(45deg, #808080 25%, transparent 25%), linear-gradient(-45deg, #808080 25%, transparent 25%), linear-gradient(45deg, transparent 75%, #808080 75%), linear-gradient(-45deg, transparent 75%, #808080 75%);
background-size: 20px 20px;
background-position: 0 0, 0 10px, 10px -10px, -10px 0px;
}
The problem seems to be happening because of a difference in the way the angles are handled by the -moz linear gradient and the standard one. -45deg in the -moz linear gradient seems to be equal to 135deg in the standard gradient (but changing the angle is resulting in a strange dot in the middle).
The below screenshots show the difference (both taken in the latest Firefox v44.0).
Output with -moz-linear-gradient:
Output with linear gradient:
It's 2020 and this can now be created with a single CSS gradient (if you don't need to support IE/ pre-Chromium Edge).
html {
background:
repeating-conic-gradient(#808080 0% 25%, transparent 0% 50%)
50% / 20px 20px
}
I wrote a detailed explanation on CSS Tricks for how this works.
The 45deg version works nicely, but can end up showing a line between the triangles at different zoom levels or on retina screens. Depending on what browsers you need to support you can also use background-blend-mode: difference (Caniuse currently shows support nearly everywhere except IE), you can tint the checks using an additional background image:
body {
background-image: /* tint image */
linear-gradient(to right, rgba(192, 192, 192, 0.75), rgba(192, 192, 192, 0.75)),
/* checkered effect */
linear-gradient(to right, black 50%, white 50%),
linear-gradient(to bottom, black 50%, white 50%);
background-blend-mode: normal, difference, normal;
background-size: 2em 2em;
}
This was Chrome's implementation for when you opened an image with transparency for a while (though they later removed it in favor of just using a solid background).
body {
background-position: 0px 0px, 10px 10px;
background-size: 20px 20px;
background-image: linear-gradient(45deg, #eee 25%, transparent 25%, transparent 75%, #eee 75%, #eee 100%),linear-gradient(45deg, #eee 25%, white 25%, white 75%, #eee 75%, #eee 100%);
}
Thanks Harry for the inspiration - here's an scss mixin to do that
#mixin checkers($size: 50px, $contrast: 0.07) {
$checkerColor: rgba(#000, $contrast);
$angle: 45deg;
$tp: 25%;
background-image: linear-gradient($angle, $checkerColor $tp, transparent $tp),
linear-gradient(-$angle, $checkerColor $tp, transparent $tp),
linear-gradient($angle, transparent 3 * $tp, $checkerColor 3 * $tp),
linear-gradient(-$angle, transparent 3 * $tp, $checkerColor 3 * $tp);
background-size: $size $size;
background-position: 0 0, 0 $size/2, $size/2 -1 * $size/2, -1 * $size/2 0;
}
Is it possible or is there a trick to make a background pixelated like the one in the image attached?
I use a background image, but as you can see it doesn't scale and it flashs on page scrolling.
Now I have CSS thanks to vlcekmi3:
background-color: white;
background-image: linear-gradient(45deg, black 25%, transparent 25%, transparent 75%, black 75%, black),
linear-gradient(45deg, black 25%, transparent 25%, transparent 75%, black 75%, black);
background-size:100px 100px;
background-position: 0 0, 50px 50px;
But I'm unable to make it exactly like the image. Can someone check it?
Any code, resource, tutorial, and suggestion is appreciated.
From thirtydot's comment in the first post. Should have posted it as an answer - Brilliant. I almost missed it. Please rate his comment up :) I am only posting this as an answer so it might help others as it helped me.
Using a base64 encoded message:
background-image: url(data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAIAAAACCAYAAABytg0kAAAAGXRFWHRTb2Z0d2FyZQBBZG9iZSBJbWFnZVJlYWR5ccllPAAAABZJREFUeNpi2r9//38gYGAEESAAEGAAasgJOgzOKCoAAAAASUVORK5CYII=);
http://jsfiddle.net/thirtydot/v7T98/3/
Here's the best I could come up with to match your image. It's adapted from the example here by Lea Verou What will be your fallback for non css3 browsers?
body {
background-image: -moz-linear-gradient(45deg, #666 25%, transparent 25%),
-moz-linear-gradient(-45deg, #666 25%, transparent 25%),
-moz-linear-gradient(45deg, transparent 75%, #666 75%),
-moz-linear-gradient(-45deg, transparent 75%, #666 75%);
background-image: -webkit-gradient(linear, 0 100%, 100% 0, color-stop(.25, #666), color-stop(.25, transparent)),
-webkit-gradient(linear, 0 0, 100% 100%, color-stop(.25, #666), color-stop(.25, transparent)),
-webkit-gradient(linear, 0 100%, 100% 0, color-stop(.75, transparent), color-stop(.75, #666)),
-webkit-gradient(linear, 0 0, 100% 100%, color-stop(.75, transparent), color-stop(.75, #666));
background-image: -webkit-linear-gradient(45deg, #666 25%, transparent 25%),
-webkit-linear-gradient(-45deg, #666 25%, transparent 25%),
-webkit-linear-gradient(45deg, transparent 75%, #666 75%),
-webkit-linear-gradient(-45deg, transparent 75%, #666 75%);
background-image: -o-linear-gradient(45deg, #666 25%, transparent 25%),
-o-linear-gradient(-45deg, #666 25%, transparent 25%),
-o-linear-gradient(45deg, transparent 75%, #666 75%),
-o-linear-gradient(-45deg, transparent 75%, #666 75%);
background-image: linear-gradient(45deg, #666 25%, transparent 25%),
linear-gradient(-45deg, #666 25%, transparent 25%),
linear-gradient(45deg, transparent 75%, #666 75%),
linear-gradient(-45deg, transparent 75%, #666 75%);
-moz-background-size: 2px 2px;
background-size: 2px 2px;
-webkit-background-size: 2px 2.1px; /* override value for webkit */
background-position: 0 0, 1px 0, 1px -1px, 0px 1px;
}
jsfiddle example
The "flickering" you observe is is not a software issue, but a hardware one. Basically, it's caused by that fact that the pixels on your screen can't change color instantly. Since your dotted background consists of alternating rows of pixels, any time you scroll down by an odd number of pixels, there will be a brief moment when your screen is switching between two shifted copies of the pattern, and this will appear as flicker.
This thread on Graphic Design Stack Exchange features an even more dramatic example of the same effect, and also explains why it happens in more detail. Just for a quick demonstration, let me borrow one of the images from Volker Siegel's answer:
Note how, on most screens, this image will show a noticeable "pulsing" effect when scrolled. (It may also appear to flicker a bit even while just looking at it, simply because the photoreceptors in your eyes also have some response delay and adaptation effects.)
Anyway, the only way you can stop your dotted background from flickering while scrolling is to make it not scroll. Fortunately, there's a CSS property just for that:
background-attachment: fixed;
Other than that, there's not much else to it. The best way to actually render the background is almost certainly with a simple two-color PNG image. You can even make the image semitransparent, so that you can layer it on top of different colored backgrounds. See the snippet below for a demonstration:
body {
background-color: white;
background-image: url(data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAABAAAAAQCAYAAAAf8/9hAAAAGUlEQVQ4y2NgoBJwoJAedcGoC0ZdMOAuAABF0hABJ/8lyQAAAABJRU5ErkJggg==);
background-attachment: fixed;
}
<p>blah</p><p>blah</p><p>blah</p><p>blah</p><p>blah</p><p>blah</p>
<p>blah</p><p>blah</p><p>blah</p><p>blah</p><p>blah</p><p>blah</p>
<p>blah</p><p>blah</p><p>blah</p><p>blah</p><p>blah</p><p>blah</p>
<p>blah</p><p>blah</p><p>blah</p><p>blah</p><p>blah</p><p>blah</p>
Note how the pattern does not flicker when you scroll it with the inner scroll bar. (It does flicker when you scroll the whole SO page, because the pattern is attached to the <iframe> it's displayed in, and will scroll along with it.)
(BTW, the inline image I've used in the snippet above is 16 × 16 pixels, even though the actual pattern is just 2 × 2 pixels. Repeating it a few times doesn't cost much in terms of file size, though, and might be slightly safer, as I seem to recall some older browsers having issues with very small background images.)
How about this one?
.card {
background: linear-gradient(90deg, #fff 2px, transparent 1%) center, linear-gradient(#fff 2px, transparent 1%) center, #ccc;
background-size: 5px 5px;
height: 10em;
width: 30em;
position: relative;
}
.text {
font-size: 2em;
position: absolute;
left: 50%;
top: 50%;
transform: translate(-50%, -50%);
}
<div class="card">
<div class="text">
Hello world!
</div>
</div>
In general the formula is
// color
$bg-color: #fff;
$dot-color: $gray-darker;
// Dimensions
$dot-size: 3px;
$dot-space: 5px;
background: linear-gradient(90deg, $bg-color ($dot-space - $dot-size), transparent 1%) center,
linear-gradient($bg-color ($dot-space - $dot-size), transparent 1%) center, $dot-color;
background-size: $dot-space $dot-space;
as seen # https://codepen.io/edmundojr/pen/xOYJGw
This is because of background-size, so just try this:
background-size:2px 2px;
Without all the browser prefixes:
background: linear-gradient(
45deg,
#fff,
#fff 50%,
#000 50%,
#000
);
background-size: 2px 2px;