Whats wrong with this? is raising a linter error:
.scrollbar-light > .scroll-element .scroll-element_size {
background: #dbdbdb;
background: url(data:image/svg+xml;base64,PD94bWwgdmVyc2lvbj0iMS4wIiA/Pgo8c3ZnIHhtbG5zPSJodHRwOi
8vd3d3LnczLm9yZy8yMDAwL3N2ZyIgd2lkdGg9IjEwMCUiIGhlaWdodD0iMTAwJSIgdmlld0JveD0iMCAwIDEgMSIgcHJlc2
VydmVBc3BlY3RSYXRpbz0ibm9uZSI+CiAgPGxpbmVhckdyYWRpZW50IGlkPSJncmFkLXVjZ2ctZ2VuZXJhdGVkIiBncmFkaW
VudFVuaXRzPSJ1c2VyU3BhY2VPblVzZSIgeDE9IjAlIiB5MT0iMCUiIHgyPSIxMDAlIiB5Mj0iMCUiPgogICAgPHN0b3Agb2
Zmc2V0PSIwJSIgc3RvcC1jb2xvcj0iI2RiZGJkYiIgc3RvcC1vcGFjaXR5PSIxIi8+CiAgICA8c3RvcCBvZmZzZXQ9IjEwMC
UiIHN0b3AtY29sb3I9IiNlOGU4ZTgiIHN0b3Atb3BhY2l0eT0iMSIvPgogIDwvbGluZWFyR3JhZGllbnQ+CiAgPHJlY3QgeD
0iMCIgeT0iMCIgd2lkdGg9IjEiIGhlaWdodD0iMSIgZmlsbD0idXJsKCNncmFkLXVjZ2ctZ2VuZXJhdGVkKSIgLz4KPC9zdm
c+);
background: -moz-linear-gradient(left, #dbdbdb 0%, #e8e8e8 100%);
background: -webkit-gradient(linear, left top, right top, color-stop(0%,#dbdbdb), color-stop(100%,#e8e8e8));
}
I've tried adding quotes, same result.
The url is in multiple lines, change it to a single line
You are not supposed to break the dataURI into different lines. The following CSS should work:
.scrollbar-light > .scroll-element .scroll-element_size {
background: #dbdbdb;
background: url(data:image/svg+xml;base64,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);
background: -moz-linear-gradient(left, #dbdbdb 0%, #e8e8e8 100%);
background: -webkit-gradient(linear, left top, right top, color-stop(0%,#dbdbdb), color-stop(100%,#e8e8e8));
}
The CSS Lint shows only one warning:
Require all gradient definitions
Missing vendor-prefixed CSS gradients for Webkit (Safari 5+, Chrome), Opera 11.1+.
.scrollbar-light > .scroll-element .scroll-element_size {
Related
Thank you so much for taking your time to read this.
Heres the code the colorzilla gradient generator created for me:
background: #aecc9f;
background: -moz-linear-gradient(top, #aecc9f 0%, #97b78d 50%, #9bb78d 52%, #8faa83 100%);
background: -webkit-linear-gradient(top, #aecc9f 0%,#97b78d 50%,#9bb78d 52%,#8faa83 100%);
**background**: linear-gradient(to bottom, #aecc9f 0%,#97b78d 50%,#9bb78d 52%,#8faa83 100%);
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#aecc9f', endColorstr='#8faa83',GradientType=0 );
Next to the line of the bolded background text, I get the following error:
Expected (<filter-function-list> | none) but found 'progid:DXImageTransform.Microsoft.gradient( startColorstr='#aecc9f', endColorstr='#8faa83',GradientType=0 )'
I hope someone will be kind enough to help a programming idiot such as myself.
Line
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#aecc9f', endColorstr='#8faa83',GradientType=0 );
is incorrect, according to definition of filter property (1, 2), it can take following values:
blur()
brightness()
contrast()
drop-shadow()
grayscale()
hue-rotate()
invert()
opacity()
saturate()
sepia()
url() - for applying SVG filters
custom() - "coming soon"
None of them are responsible for gradient, so you can just remove this line from your code.
Also I don't know what is the purpose of double asterisks around **background**, but them break css code, so you probably should remove them too, and it will be like this:
.gradient {
background: #aecc9f;
background: -moz-linear-gradient(top, #aecc9f 0%, #97b78d 50%, #9bb78d 52%, #8faa83 100%);
background: -webkit-linear-gradient(top, #aecc9f 0%,#97b78d 50%,#9bb78d 52%,#8faa83 100%);
background: linear-gradient(to bottom, #aecc9f 0%,#97b78d 50%,#9bb78d 52%,#8faa83 100%);
}
.wide {
width: 100%;
height: 100px;
}
<div class="wide gradient">
</div>
I'm implementing a primeNg/quill editor, and as part of the UX design I need to display a container in the screen with the same color background as the editor's toolbar. I'm looking at the snow.css file but can't seem to find it, any quill experts know where I can find this on snow.css or any other dependent css of Quill? Thank you!
The toolbar background color in the PrimeNG Quill demo is part of the PrimeNG theme and not part of Quill's snow.css.
You can use the developer toolbar in Firefox and Chrome to see the CSS rules:
.ui-widget-header {
border: 1px solid #d9d9d9;
color: #1b1d1f;
background: #f6f7f9 0 0 repeat-x;
background: -moz-linear-gradient(top, #f6f7f9 0%, #ebedf0 100%);
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#f6f7f9), color-stop(100%,#ebedf0));
background: -webkit-linear-gradient(top, #f6f7f9 0%,#ebedf0 100%);
background: -o-linear-gradient(top, #f6f7f9 0%,#ebedf0 100%);
background: -ms-linear-gradient(top, #f6f7f9 0%,#ebedf0 100%);
background: linear-gradient(top, #f6f7f9 0%,#ebedf0 100%);
}
Just put inside a div with background color, and for editing area color use
Style backround color property.
below code for bootstrap and angular
<div class="bg-light">
<quill-editor [styles]="{height: '500px', backgroundColor: 'white'}">
</quill-editor>
</div>
While using a CSS black to transparent linear-gradient I noticed that it doesn't gradually fade to transparent, instead it makes the grey area linger longer and only near the end it becomes transparent with a noticeable limit.
After noticing this I decided to use a photoshop gradient with the exact properties and it looked better, the gradient was changing from black to transparent smoothly and linearly.
The following contains an example showing a CSS linear-gradient on the left and Photoshop generated gradient on the right - Both were created with the exact same properties:
#css, #ps{
height:100px;
width:50%;
}
#css{
float:left;
background:linear-gradient(black, transparent);
}
#ps{
float:right;
background:url("data:image/png;base64,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");
}
<div id="css"></div>
<div id="ps"></div>
As you can see the difference is clearly visible. Is it possible to replicate Photoshop's real linear-gradient into CSS's or my only option is to use base64/png tricks to achieve an actual linear gradient?
Because currently css's linear-gradient is everything but linear, in fact from what I can see it creates an easeInOut-gradient instead of linear.
As GRC says, you can set multiple midpoints values to adapt the gradient to your exact needs
A good starting point is colorzilla, where you can import an image file and get an automated result.
For your image, the result is:
.test {
height: 100px;
background: #020202; /* Old browsers */
background: -moz-linear-gradient(top, #020202 0%, #1f1f1f 9%, #434343 18%, #989898 38%, #b2b2b2 45%, #d1d1d1 56%, #e9e9e9 67%, #f2f2f2 73%, #f9f9f9 80%, #fdfdfd 87%, #fefefe 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#020202), color-stop(9%,#1f1f1f), color-stop(18%,#434343), color-stop(38%,#989898), color-stop(45%,#b2b2b2), color-stop(56%,#d1d1d1), color-stop(67%,#e9e9e9), color-stop(73%,#f2f2f2), color-stop(80%,#f9f9f9), color-stop(87%,#fdfdfd), color-stop(100%,#fefefe)); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, #020202 0%,#1f1f1f 9%,#434343 18%,#989898 38%,#b2b2b2 45%,#d1d1d1 56%,#e9e9e9 67%,#f2f2f2 73%,#f9f9f9 80%,#fdfdfd 87%,#fefefe 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, #020202 0%,#1f1f1f 9%,#434343 18%,#989898 38%,#b2b2b2 45%,#d1d1d1 56%,#e9e9e9 67%,#f2f2f2 73%,#f9f9f9 80%,#fdfdfd 87%,#fefefe 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, #020202 0%,#1f1f1f 9%,#434343 18%,#989898 38%,#b2b2b2 45%,#d1d1d1 56%,#e9e9e9 67%,#f2f2f2 73%,#f9f9f9 80%,#fdfdfd 87%,#fefefe 100%); /* IE10+ */
background: linear-gradient(to bottom, #020202 0%,#1f1f1f 9%,#434343 18%,#989898 38%,#b2b2b2 45%,#d1d1d1 56%,#e9e9e9 67%,#f2f2f2 73%,#f9f9f9 80%,#fdfdfd 87%,#fefefe 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#020202', endColorstr='#fefefe',GradientType=0 ); /* IE6-9 */
}
<div class="test"></div>
The problem is that this tool gives only rgb values, you will need to manually convert those to rgba, and play with the alpha values.
You can do following:
background:linear-gradient(black, transparent, transparent);
or
background:linear-gradient(black 10%, transparent);
10% of space is taken by black.
Hope this helps.
I'm testing my application on Firefox 33. I have a simple background property defined with a gradient:
background: linear-gradient(bottom, #004771 0%, #005185 100%);
and it doesn't work. CanIUse reports that gradients on Firefox 33 can be used without a prefix. So why doesn't it work? If I add a Mozilla-specific prefix:
background: -moz-linear-gradient(bottom, #004771 0%, #005185 100%);
everything works OK.
When using linear-gradient without the prefix, you need to write it like this ("to bottom" instead of "bottom"):
background: linear-gradient(to bottom, #004771 0%, #005185 100%);
EDIT: Link to documentation: https://developer.mozilla.org/en-US/docs/Web/CSS/linear-gradient#Syntax
You need to use to bottom in order for it to work:
background: linear-gradient(to bottom, #004771 0%, #005185 100%);
jsfiddle
I have some link buttons that I'm using CSS3 gradient code that I generated from Ultimate CSS Gradient Generator. It is working great except for IE7-9 (not worrying about IE6). Instead of the nice mid-gray to dark gray it is showing a blue to black gradient. The code being used is:
background: #666666; /* Old browsers */
background: -moz-linear-gradient(top, #666666 0%, #141414 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#666666), color-stop(100%,#141414)); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, #666666 0%,#141414 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, #666666 0%,#141414 100%); /* Opera11.10+ */
background: -ms-linear-gradient(top, #666666 0%,#141414 100%); /* IE10+ */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#666666', endColorstr='#141414',GradientType=0 ); /* IE6-9 */
background: linear-gradient(top, #666666 0%,#141414 100%); /* W3C */
To see what it is rendering like: http://bradmccullough.com.w.jaijaz.co.nz/
I have noticed that altering the display css element changes it but can't put my finger on what exactly is going on.
Thanks.
It is because you are using the shorthand color for gray in your CSS. Make sure you use #666666. Looking at the source of the stylesheet, for the IE filter, you're using #666 (although in your post above you have it right).
We had a similar problem recently. We identified that running CSS minify on the CSS files would shorten '#666666' to '#666', resulting in IE8 not being able to render the correct colour value within the 'filter' property. The only alternative was to define the colour as 'white' (our problem was with '#ffffff') or tweaking the colour slightly, i.e. '#fffffe' to prevent it from being written in shorthand.