I can read text from notifications using
CharSequence[] arr = extras.getCharSequenceArray(Notification.EXTRA_TEXT_LINES);
for(CharSequence l:arr)
Log.d("duglas",l.toString());
The text i received is of the form :
2-25 10:07:00.351 18879-18895/? D/duglas﹕ Idea Hi
12-25 10:07:00.351 18879-18895/? D/duglas﹕ Idea J
12-25 10:07:00.351 18879-18895/? D/duglas﹕ Idea G
12-25 10:07:00.351 18879-18895/? D/duglas﹕ Idea Hi
12-25 10:07:00.351 18879-18895/? D/duglas﹕ Idea N
12-25 10:07:00.351 18879-18895/? D/duglas﹕ Testnotify Hi
Now from the above text I need to separate messages like "Hi" from contact like "Idea".
Is it possible?
I have tried
extras.get(Notification.EXTRA_PEOPLE);
But it doesn't lists all contacts in the notification.
Get your answer into a string array.
String[] = myString.split("\\s+");
First try this with a Single string contains more the one white spaces then find a way your to use this into you Project.
Although Notification.EXTRA_PEOPLE in the extras of the notification object can be used to relate people to notifications but it is not necessary that all the contacts linked to a notification must be present in that field. So, it is highly dependent upon how the notification is being built and hence not possible to list contacts in every notification.That's why it is difficult to separate contact from notification text efficiently simply by manipulating the text.
Related
I've been trying to solve this for three days and none pf the solutions I've found online seem to work, so I am going to have to ask for help.
I want to create a Telegram "Group Chat" to be used by members of a club I'm in. I created the chat named with the initials of the club, like: "ABCD" and added some members. Now I want to automate the sending of occasional messages to the group for all members to see. Weather forecast, random photograph from our gallery, etc.
Using #BotFather I created a bot called "ABCDbot" and noted the token for that bot. Now I have two "ABCD"s on my browser left side-panel. Selecting one gives me "ABCD bot" and selecting the other gives me "ABCD 123 members".
Using a perl script and LWP I can send a photo using
#!/usr/bin/perl -w
use feature 'say';
use LWP;
my $api = LWP::UserAgent->new ();
my $chat_id = '1234567890';
my $photo = '/home/user/gallery/photo999.jpg';
my $response = $api->post(
"https://api.telegram.org/bot<ABCDbot's token>/sendPhoto",
[ 'chat_id' => $chat_id,
'caption' => 'Photo Randomly Selected by the gallery',
'photo' => $photo,
],
'Content_Type' => 'form-data',
);
if ($response->is_success) {
say "Response..... Success!";
} else {
say "Response..... Failure!";
}
This works, providing I give it a legitimate chat_id and a legitimate file to send.
But the trouble is: I can't find the chat_id for the group chat with 123 members! Every method I've tried now proves to be obsolete or simply doesn't return the desired chat_id for the ABCD group chat. I can get my own chat ID or that of individual members of the group, or of the bot itself, and can successfully send photos, messages, etc to those destinations, but I just can't send anything to the group.
Can anybody walk me through the process of getting the chat_id for my group chat? Or direct me to a document describing an up-to-date, working method for obtaining same?
Assistance much appreciated.
Method 1 (WebZ)
This is based on JayeshRocks's question with some extra steps to make the ID work with Bot API. Thanks to him first.
Login to Telegram WebZ.
Open the chat you want to get its ID.
Your browser's address should look like https://web.telegram.org/z/#-1527776602.
Remove the protocol, domain and path keeping the anchor so your result looks like #-1527776602.
Replace "#-" with "-100" so it looks like -1001527776602.
You can now use your final result which should look like -1001527776602.
Method 2 (Private Supergroups)
If the chat is a private channel/supergroup, you can do the following:
Copy a link of a message. (It will look like https://t.me/c/1527776602/1002.)
Remove the protocol and domain name, so it looks like c/1527776602/1002.
Remove the first and last path, so it looks like 1527776602.
Append "-100" to the beginning of the result, so it looks like -1001527776602.
You can now use your final result which looks like -1001527776602.
Method 3 (Third-Party Bots)
If you trust 3rd party bots, there are many of them. A known one is #MissRose_bot which you can add it to your group and use its /id command. Another one is #usinfobot which works inline and only for public chats.
To get a telegram group ID you need to open the group on https://web.telegram.org/z/ when you do so click on the group you want to gain the ID of then if you look at the URL it will say something like https://web.telegram.org/z/#-1234567 and the numbers there is the ID of the telegram group!
Hope this helps
I am new to "Here" and I am using Here SDK Flutter 4.3.3.0. I want to fetch/search for places and get the Place's Photos/Image and or Place's Logo if the place is a business/company.
The place images place.details.internalimages are always empty when I search for any place. I tried for different countries like "Chipotle" a restaurant near Las Vegas, a restaurant in Canda, and a Shopping mall in India. All of these return 0 (zero) images. Does, Here API support to get places photos like Google Places or TomTom API?
Looks like this API has a method to get WebImage List but does not contain any data at all. Please advise, If I need to use any other method to get Place's photos.
Another question is, is there a way to get a company logo, if the place I am searching for is a business/company like Restaurant, Store, etc.
Below is the code, I use in my Flutter application. Note, I am able to get other field values like title, address, etc.
TextQuery textQuery = TextQuery.withAreaCenterInCountries('some partial place name', geoCoordinates, countryCodes);
searchEngine.suggest(textQuery, searchOptions, onHereSearchSuggestionCompleted);
In onHereSearchSuggestionCompleted functions, I have the following code:
if(suggestions.length > 0){
print('explore - onHereSearchSuggestionCompleted - suggestions count > 0');
for (Suggestion suggestion in suggestions) {
print('onHereSearchSuggestionCompleted - current count = ${(suggestions.indexOf(suggestion) + 1)}');
print('onHereSearchSuggestionCompleted - suggestion title = ${suggestion.title}');
print('onHereSearchSuggestionCompleted - place id = ${suggestion.place.id}');
print('onHereSearchSuggestionCompleted - place title = ${suggestion.place.title}');
print('onHereSearchSuggestionCompleted - place address = ${suggestion.place.address.addressText}');
print('onHereSearchSuggestionCompleted - place img length = ${suggestion.place.details.internalimages.length}');
}
}
Please note, you have been able to see this functionality being exposed in flutter SDK due to a bug exposing internal methods in flutter. In general this functionality is not yet public (not in native android and iOS).
We plan to expose this functionality soon, however even when we do, only certain eligible customers would have access to the image content. There should be contractual agreement to be able to see this functionality
I currently have an application that works with Firebase.
I repeatedly load profile pictures. However the link is quite long, it consumes a certain amount of data. To reduce this load, I would like to put the link in raw and only load the token that is added to the link.
To explain, a link looks like this: “https://firebasestorage.googleapis.com/v0/b/fir-development.appspot.com/o/9pGveKDGphYVNTzRE5U3KTpSdpl2?alt=media&token=f408c3be-07d2-4ec2-bad7-acafedf59708”
So I would like to put in gross: https://firebasestorage.googleapis.com/v0/b/fir-developpement.appspot.com/o/
In continuation: “9pGveKDGphYVNTzRE5U3KTpSdpl2” which is the UID of the user that I recover already and the or my problem this poses: “alt = media & token = f408c3be-07d2-4ec2-bad7-acafedf59708” which adds randomly for each photo .
I would like to get back only this last random piece …
Is it possible ?
Thank you
UP : 01/11 Still no solution
It's not supported to break apart and reassemble download URLs. You should be treating these strings as if their implementation details might change without warning.
I want to add an unsubscribe link in emails being sent to the user. I am unsure on how to achieve it. I want the user to be able to unsubscribe without having to log in. Any suggestions on how to achieve this would be appreciated. Thanks
I'll assume you know how to send an email with django, and other basic things.
For every email you send to them, you have to build the unsubscribe link first, like the following. Note that the following has a url pattern, and a model that takes a uuid field (uuid4 to be specific, because it's the safest one). The reason why you want to do it this way is so random people can't go to YourWebsite.com/unsub_email/1, /2, /3, /4, etc, and unsub as many people as they possibly can by guessing the number. By doing it the way I show, there's something like a chance of 1 in 100, with like 50+ zero's after it that they would even get 1. So it's safer.
def send_user_an_email(id_of_your_object):
users_email = UsersEmail.objects.get(id=id_of_your_object)
unsub_link = 'https://www.YourWebsite.com/unsub_email/{}/{}/'.format(users_email.id, users_email.random_uuid)
subject = 'Your subject line.'
message = 'Your message body.\n\nGo here to unsubscribe: {}'.format(unsub_link)
mail_sent = send_mail(subject, message, 'DoNotReply#YourWebsite.com', [users_email.users_email_char_field])
return mail_sent
Then you just write a function to let them click a button on that page, and they get unsubbed, or however else you want to do it. An even safer option would be to show them a valid unsub page, but make them type out their email again, but don't show them the email related to the valid url pattern. That extra step would make it that much harder for someone who'd want to write a bad script to unsub everyone on your list.
It seems that youtube are now using ID's for their channels instead of names (part of the V3 api)
However it seems that the embedded iframe playlist player cannot handle these channel ID's
example channel https://www.youtube.com/channel/UCpAOGs57EWRvOPXQhnYHpow
then ID is UCpAOGs57EWRvOPXQhnYHpow
Now try to load this
http://www.youtube.com/embed/?listType=user_uploads&list=UCpAOGs57EWRvOPXQhnYHpow
Can anyone shine a light on this issue ? Or is there some hidden username ?
I also placed this question at the gdata-issues website http://code.google.com/p/gdata-issues/issues/detail?id=6463
The issue here is that a channel is not a playlist; channels can have multiple playlists, yet the listType parameter is designed to look for an actual playlist info object. The documented way around this is to use the data API and call the channel endpoint, looking at the contentDetails part:
GET https://www.googleapis.com/youtube/v3/channels?part=contentDetails&id=UCuo5NTU3pmtPejmlzjCgwdw&key={YOUR_API_KEY}
The result will give you all of the feeds associated with that channel that you can choose from:
"contentDetails": {
"relatedPlaylists": {
"uploads": "UUuo5NTU3pmtPejmlzjCgwdw"
}
}
If available (sometimes with oAuth), there could also be "watch later" lists, "likes" lists, etc.
This may seem like a lot of overhead. In the short term, though, it can be noted that the different feeds are programmatically named; so, for example, if my user channel begins with UC and then a long string, that UC stands for 'user channel' -- and the uploads feed would begin with 'UU' (user uploads) and then have the rest of the same long string. (you'd also have 'LL' for the likes list, 'WL' for the watch later list, 'HL' for the history list, 'FL' for the favorites list, etc. This is NOT documented, and so there's no guarantee that such a naming convention will perpetuate. But at least for now, you could change your ID string from beginning with UC to beginning with UU, like this:
http://www.youtube.com/embed/?listType=user_uploads&list=UUpAOGs57EWRvOPXQhnYHpow
And it embeds nicely.
Just to inform on current state of things -- the change suggested by jlmcdonald doesn't work anymore, but you can still get a proper embed link via videoseries (with the same UC to UU change). I.o.w. link like
http://www.youtube.com/embed/videoseries?list=UUpAOGs57EWRvOPXQhnYHpow
works as of at the moment of writing this.