im trying to find an easy formula to do the following:
=IF(AND(H6="OK";H7="OK";H8="OK";H9="OK";H10="OK";H11="OK";);"OK";"X")
This actually works. But I want to apply to a range of cells within a column (H6:H11) instead of having to create a rule for each and every one of them... But trying as a range:
=IF(AND(H6:H11="OK";);"OK";"X")
Does not work.
Any insights?
Thanks.
=ArrayFormula(IF(AND(H6:H11="OK");"OK";"X"))
also works
arrayformulas work the same way they do in excel... they just need an ArrayFormula() around to work (will be automatically set when pressing Ctrl+Alt+Return like in excel)
In google sheets the formula is:
=ArrayFormula(IF(SUM(IF(H6:H11="OK";1;0))=6;"OK";"X"))
in excel:
=IF(SUM(IF(H6:H11="OK";1;0))=6;"OK";"X")
And confirm with Ctrl-Shift-Enter
This basically counts the number of times the said range is = to the criteria and compares it to the number it should be. So if the range is increased then increase the number 6 to accommodate.
Related
I have tens of thousands of rows of unstructured data in csv format. I need to extract certain product attributes from a long string of text. Given a set of acceptable attributes, if there is a match, I need it to fill in the cell with the match.
Example data:
"[ROOT];Earrings;Brands;Brands>JeweleryExchange;Earrings>Gender;Earrings>Gemstone;Earrings>Metal;Earrings>Occasion;Earrings>Style;Earrings>Gender>Women's;Earrings>Gemstone>Zircon;Earrings>Metal>White Gold;Earrings>Occasion>Just to say: I Love You;Earrings>Style>Drop/Dangle;Earrings>Style>Fashion;Not Visible;Gifts;Gifts>Price>$500 - $1000;Gifts>Shop>Earrings;Gifts>Occasion;Gifts>Occasion>Christmas;Gifts>Occasion>Just to say: I Love You;Gifts>For>Her"
Look up table of values:
Zircon, Diamond, Pearl, Ruby
Output:
Zircon
I tried using the VLOOKUP() function, but it needs to match an entire cell and works better for translating acronyms. Haven't really found a built in function that accomplishes what I need. The data is totally unstructured, and changes from row to row with no consistency even within variations of the same product. Does anyone have an idea how to do this?? Or how to write an OpenOffice Calc function to accomplish this? Also open to other better methods of doing this if anyone has any experience or ideas in how to approach this...
ok so I figured out how to do this on my own... I created many different columns, each with a keyword I was looking to extract as a header.
Spreadsheet solution for structured data extraction
Then I used this formula to extract the keywords into the correct row beneath the column header. =IF(ISERROR(SEARCH(CF$1,$D769)),"",CF$1) The Search function returns a number value for the position of a search string otherwise it produces an error. I use the iserror function to determine if there is an error condition, and the if statement in such a way that if there is an error, it leaves the cell blank, else it takes the value of the header. Had over 100 columns of specific information to extract, into one final column where I join all the previous cells in the row together for the final list. Worked like a charm. Recommend this approach to anyone who has to do a similar task.
My goal of this code is to create a loop that aggregates each company's word frequency by a certain principle vector I created and adds it to a list. The problem is, after I run this, it only prints the 7 principles that I have rather than the word frequencies along side them. The word frequencies being the certain column of the FREQBYPRINC.AG data frame. Individually, running this code without the loop and just testing out a certain column, it works no problem. For some reason, the loop doesn't want to give me the correct data frames for the list. Any suggestions?
list.agg<-vector("list",ncol(FREQBYPRINC.AG)-2)
for (i in 1:14){
attach(FREQBYPRINC.AG)
list.agg[i]<-aggregate(FREQBYPRINC.AG[,i+1],by=list(Type=principle),FUN=sum,na.rm=TRUE)
}
I really wish I could help. After reading your statement, It seems that to you , you feel that the code should be working and it is not. Well maybe there exists a glitch.
Since you had previously specified list. agg as a list, you need to subset it with double square brackets. Try this one out:
list.agg<-vector("list",ncol(FREQBYPRINC.AG)-2)
for (i in 1:14){
list.agg[[i]]<-aggregate(FREQBYPRINC.AG[,i+1],by=list
(Type=principle),FUN=sum,na.rm=TRUE)}
I am trying to automate a process instead of individually compute PPCC values for a large number of test cases. The details of my functions do not matter (though for reference I'm using Lmomco), my issue is either putting this into a loop or somehow using plyr or apply to repeat over and over. I do not know how to automate the string. For example I have sorted data by "M" parameter:
testx.100cv1<-by(x.cv1$first_year,x.cv1$M,sort)
I then apply a function here:
testexp<-lapply(testx.100cv1,parexp)
Now I want to do something to each "M", where in the example below, M = 1.02. Right now, I am manually changing this value and then recomputing for every M (and I have a lot of them). I'm looking for a way to write this M value into a loop so it reads it automatically.
exp<-quaexp(plotpos,testexp$'1.02')
PPCCexp<-cor(exp,testx.100cv1$'1.02')
I want to compute PPCC values for many distributions, so without automating, this will take over my life for a week.
Thanks!
So I'm trying to manipulate a simple Qualtrics CSV, and I want to use colSums on certain columns of data, given a certain filter.
For example: within the .csv file called data, I want to get the sum of a few columns, and print them with certain labels (say choice1, choice2 etc). That is easy enough by itself:
firstqn<-data.frame(choice1=data$Q7_2,choice2=data$Q7_3,choice3=data$Q7_4);
secondqn<-data.frame(choice1=data$Q8_6,choice2=data$Q8_7,choice3=data$Q8_8)
print colSums(firstqn); print colSums(secondqn)
The problem comes when I want to repeat the above steps with different filters, - say, only the rows where gender==2.
The only way I know how is to create a new dataset data2 and replace data$ with data2$ in every line of the above code, such as:
data2<-(data[data$Q2==2,])
firstqn<-data.frame(choice1=data2$Q7_2,choice2=data2$Q7_3,choice3=data2$Q7_4);
however i have 6 choices for each of 5 questions and am planning to apply about 5-10 different filters, and I don't relish the thought of copy/pasting data2 and `data3' etc hundreds of times.
So my question is: Is there any way of getting R to reference data by default without using data$ in front of every variable name?
I can probably use attach() to achieve this, but i really don't want to:
data2<-(data[data$Q2==2,])
attach(data2)
firstqn<-data.frame(choice1=Q7_2,choice2=Q7_3,choice3=Q7_4);
detach(data2)
is there a command like attach() that would allow me to avoid using data$ in front of every variable, for a specified amount of code? Then whenever I wanted to create a new filter, I could just copy/paste the same code and change the first command (defining a new dataset).
I guess I'm looking for some command like with(data2, *insert multiple commands here*)
Alternatively, if anyone has a better way to do the above in an entirely different way please enlighten me - i'm not very proficient at R (yet).
I have a column of year values by which I am sorting. I'd like to find the quantity per year (read: number of repeats of each year value). I'd like to chart said values. I'm not sure how to make this happen.
I am using Apple's Numbers '08, but if possible a general solution that multiple people could use would be preferred.
You should use the countif() function: http://office.microsoft.com/en-us/excel/HP052090291033.aspx
I did a similar thing to count how many hours of work there are for each upcoming version of my iPhone app. I was doing sumif(), but you just want countif().
See cells N4-N6 here: http://spreadsheets.google.com/ccc?key=0AhL0igVI9HVNdGpaS3U1cS1qOGVNd3h0Slg0a21vUWc&hl=en
On a new sheet, list the unique years in one column, then their quantity count in the column next to them. Select the entire range created, then create a chart.
I'm unsure from your question what you would specifically need more than this (and I work in Excel 2003).