I have table like this:
id | name | type
-----------------
0 | firs | 2
1 | secs | 3
2 | this | 9
1 | thus | 3
I know id (it is not unique id) and type and I want to select records only if there is specified number of records with that id and type.
For one record I tried for example this:
select * from myTable
where
(select count(*) from myTable where myTable.id = 0 and myTable.type = 2) = 1;
This returns me all rows, not just the one row I want. Can anyone please tell me, what is the right way how to get the right result?
Your where statement looks like WHERE 1 = 1 and it's always true so SELECT gets every column from your table.
If you want select for example data where id = 1 and type = 3 and number of occurrences = 2 you can do something like that:
select * from myTable
where
(select count(*) from myTable where myTable.id = 1 and myTable.type = 3) = 2 and myTable.id = 1 and myTable.type = 3;
Related
In one of my tables I have a column called 'Priority' which is a number starting from 1. With new data the next number will be added to the new record.
When I deleted a data from the middle there will be a gap in priority. I want to run a plsql update statement so that the mising numbers will be replaced according the priority order that I had before.
original data
Priority | user
1 | A
2 | B
3 | C
4 | D
Then I delete the record B
Priority | user
1 | A
3 | C
4 | D
After Update it should be like
Priority | user
1 | A
2 | C
3 | D
You can do this without PL/SQL:
create table demo
( priority number, username varchar2(20) );
insert all
into demo values (2, 'A')
into demo values (4, 'B')
into demo values (9, 'C')
into demo values (10, 'D')
select * from dual;
merge into demo o
using ( select row_number() over (order by priority) as new_priority
, rowid as row_id
from demo ) n
on (n.row_id = o.rowid)
when matched then update set o.priority = n.new_priority;
select * from demo;
PRIORITY USERNAME
---------- --------------------
1 A
2 B
3 C
4 D
I need to select all rows (for a range) which have a common value within a column.
For example (starting from the last row)
I try to select all of the rows where _user_id == 1 until _user_id != 1 ?
In this case resulting in selecting rows [4, 5, 6]
+------------------------+
| _id _user_id amount |
+------------------------+
| 1 1 777 |
| 2 2 1 |
| 3 2 11 |
| 4 1 10 |
| 5 1 100 |
| 6 1 101 |
+------------------------+
/*Create the table*/
CREATE TABLE IF NOT EXISTS t1 (
_id INTEGER PRIMARY KEY AUTOINCREMENT,
_user_id INTEGER,
amount INTEGER);
/*Add the datas*/
INSERT INTO t1 VALUES(1, 1, 777);
INSERT INTO t1 VALUES(2, 2, 1);
INSERT INTO t1 VALUES(3, 2, 11);
INSERT INTO t1 VALUES(4, 1, 10);
INSERT INTO t1 VALUES(5, 1, 100);
INSERT INTO t1 VALUES(6, 1, 101);
/*Check the datas*/
SELECT * FROM t1;
1|1|777
2|2|1
3|2|11
4|1|10
5|1|100
6|1|101
In my attempt I use Common Table Expressions to group the results of _user_id. This gives the index of the last row containing a unique value (eg. SELECT _id FROM t1 GROUP BY _user_id LIMIT 2; will produce: [6, 3])
I then use those two values to select a range where LIMIT 1 OFFSET 1 is the lower end (3) and LIMIT 1 is the upper end (6)
WITH test AS (
SELECT _id FROM t1 GROUP BY _user_id LIMIT 2
) SELECT * FROM t1 WHERE _id BETWEEN 1+ (
SELECT * FROM test LIMIT 1 OFFSET 1
) and (
SELECT * FROM test LIMIT 1
);
Output:
4|1|10
5|1|100
6|1|101
This appears to work ok at selecting the last "island" but what I really need is a way to select the n'th island.
Is there a way to generate a query capable of producing outputs like these when provided a parameter n?:
island (n=1):
4|1|10
5|1|100
6|1|101
island (n=2):
2|2|1
3|2|11
island (n=3):
1|1|777
Thanks!
SQL tables are unordered, so the only way to search for islands is to search for consecutive _id values:
WITH RECURSIVE t1_with_islands(_id, _user_id, amount, island_number) AS (
SELECT _id,
_user_id,
amount,
1
FROM t1
WHERE _id = (SELECT max(_id)
FROM t1)
UNION ALL
SELECT t1._id,
t1._user_id,
t1.amount,
CASE WHEN t1._user_id = t1_with_islands._user_id
THEN island_number
ELSE island_number + 1
END
FROM t1
JOIN t1_with_islands ON t1._id = (SELECT max(_id)
FROM t1
WHERE _id < t1_with_islands._id)
)
SELECT *
FROM t1_with_islands
ORDER BY _id;
I have two tables user and pair. I want to get the number of duplicate pairs (a, b) for each user.name.
user
name | id
-------------
"Alice" | 0
"Bob" | 1
"Alice" | 2
pair
id | a | b
-----------
0 | 0 | 1
0 | 1 | 3
1 | 0 | 1
2 | 1 | 3
In the above example, the result should be:
name | id | c
-------------------
"Alice" | 0,2 | 1
"Bob" | 1 | 0
When there is only one id for each user, I can do this:
SELECT name, id, (
SELECT COUNT(*) FROM pair JOIN pair AS p USING (id, a, b)
WHERE id = user.id AND pair.rowid < p.rowid
) AS c FROM user;
When there is multiple ids, I can get the correct result from the below query, but it is quite slow when there is more rows and more subqueries.
SELECT name, GROUP_CONCAT(id), (
WITH t AS (SELECT id FROM user AS u WHERE name = user.name)
SELECT COUNT(*) FROM pair JOIN pair AS p USING (a, b)
WHERE pair.id IN t AND p.id IN t AND pair.rowid < p.rowid
) AS c FROM user GROUP BY name;
I want to know that is there a simple and efficient way for this, like changing the WHERE clause from pair.id = user.id to pair.id IN <<the user.id list>>?
/* This will not work! "Error: no such table: user.id" */
SELECT name, GROUP_CONCAT(id), (
SELECT COUNT(*) FROM pair JOIN pair AS p USING (a, b)
WHERE pair.id IN user.id AND p.id IN user.id AND pair.rowid < p.rowid
) AS c FROM user GROUP BY name;
The GROUP BY name operation can be sped up if the database is able to go through the rows in order, without having to sort the table.
This can be done with an index on the name column (the other column makes this a covering index, which helps only a little more):
CREATE INDEX user_name_id_index ON user(name, id);
The query looks up pair rows by their id, a, and b values; these lookups can be sped up with an index on these columns:
CREATE INDEX pair_id_a_b_index ON pair(id, a, b);
To help the query optimizer make better decisions when selecting indexes, run ANALYZE.
The query optimizer gets improved constantly; get the newest SQLite version, if possible.
To check how your queries are executed, look at the output of the EXPLAIIN QUERY PLAN command.
I have a table with this structure:
id | IDs | Name | Type
1 | 10 | A | 1
2 | 11 | B | 1
3 | 12 | C | 2
4 | 13 | D | 3
except id nothing else is a FOREIGN or PRIMARY KEY. I want to select a row based on it's column values that are not PRIMARY KEY. I have tried the following syntax but it yields no results.
SELECT * FROM MyTable WHERE Name = 'A', Type = 1;
what am I doing wrong? What is exactly returned by a SELECT statement? I'm totally new to Data Base and I'm currently experimenting and trying to learn it. so far my search has not yield any results regarding this case.
Use and to add multiple conditions to your query
SELECT *
FROM MyTable
WHERE Name = 'A'
AND Type = 1;
I am creating a database for my Psych class and I am scoring a personality profile. I need to compare two test items and, if they match a condition, then copy into a separate table.
Example (pseudocode is between \)Sqlite3
INSERT INTO Scale
SELECT* FROM Questions
WHERE \\if Question 1 IS 'TRUE' AND Question 3 IS 'FALSE' THEN Copy this Question
and its response into the Scale table\\;
I have about 100 other questions that work like this. Sample format goes like this:
IF FirstQuestion IS value AND SecondQuestion IS value THEN
Copy both questions into the Scale TABLE.
---------- EDITED AFTER FIRST RESPONSE! EDITS FOLLOW-------------
Here is my TestItems table:
ItemID | ItemQuestion | ItemResponse
```````````````````````````````````````````````````
1 | Is the sky blue? | TRUE
2 | Are you a person? | TRUE
3 | 2 Plus 2 Equals Five | FALSE
What I want to do: If Question 1 is TRUE AND Question 3 is FALSE, then insert BOTH questions into the table 'Scale' (which is setup like TestItems). I tried this:
INSERT INTO Scale
SELECT * FROM TestItems
WHERE ((ItemID=1) AND (ItemResponse='TRUE'))
AND ((ItemID=3) AND (ItemResponse='FALSE'));
HOWEVER: The above INSERT copies neither.
The Resulting 'Scale' table should look like this:
ItemID | ItemQuestion | ItemResponse
```````````````````````````````````````````````````
1 | Is the sky blue? | TRUE
3 | 2 Plus 2 Equals Five | FALSE
There is nothing wrong with your query. You're just there:
INSERT INTO Scale
SELECT * FROM Questions
WHERE `Question 1` = 1 AND `Question 3` = 0;
Here 1 and 0 are values (in your first case, true and false). First of all you should ensure there are fields Question 1 and Question 3 in your Questions table. Secondly the column count as well as data types of Scale table should match Questions table. Otherwise you will have to do selectively choose the fields in your SELECT query.
Edit: To respond to your edit, I am not seeing an elegant solution. You could do this:
INSERT INTO Scale
SELECT * FROM TestItems WHERE ItemID = 1 AND ItemResponse = 'TRUE'
UNION
SELECT * FROM TestItems WHERE ItemID = 3 AND ItemResponse = 'FALSE'
WHERE (SELECT COUNT(*) FROM (
SELECT 1 FROM TestItems WHERE ItemID = 1 AND ItemResponse = 'TRUE'
UNION
SELECT * FROM TestItems WHERE ItemID = 3 AND ItemResponse = 'FALSE'
) AS t) >= 2
Your insert did not work because ItemID cant be both 1 and 3 at the same time. My solution gets the required records to be inserted into Scale table, but verifies both the record exists by checking the count. Additionally you could (should) do as below since this can be marginally more efficient (the above SQL was to clearly show the logic being used):
INSERT INTO Scale
SELECT * FROM TestItems WHERE ItemID = 1 AND ItemResponse = 'TRUE'
UNION
SELECT * FROM TestItems WHERE ItemID = 3 AND ItemResponse = 'FALSE'
WHERE (
SELECT COUNT(*)
FROM TestItems
WHERE ItemID = 1 AND ItemResponse = 'TRUE'
OR ItemID = 3 AND ItemResponse = 'FALSE'
) >= 2