Passing list of dataframes to R Function - r

I found a neat function for exporting multiple data frames to an excel file using the package xlsx:
save.xlsx <- function (file, ...)
{
require(xlsx, quietly = TRUE)
objects <- list(...)
fargs <- as.list(match.call(expand.dots = TRUE))
objnames <- as.character(fargs)[-c(1, 2)]
nobjects <- length(objects)
for (i in 1:nobjects) {
if (i == 1)
write.xlsx(objects[[i]], file, sheetName = objnames[i])
else write.xlsx(objects[[i]], file, sheetName = objnames[i],
append = TRUE)
}
print(paste("Workbook", file, "has", nobjects, "worksheets."))
}
It works by putting in the file name and then passing it multiple dataframes like so:
save.xlsx(filename, df1, df2, df3)
but i wanted to pass it a list of dataframes instead of them individually like so:
dataframes <- list(report1, report2, report3)
save.xlsx(filename, dataframes)
but it errors out because I am passing all of the dataframes at once. I am trying to figure out how to unstack them into the function but I haven't been successful yet.
Any help would be appreciated.
Thanks!
David
So i have been trying Richards suggestion and edited to the following:
save.xlsx <- function (file, dataframes)
{
require(xlsx, quietly = TRUE)
objects <- dataframes
fargs <- as.list(match.call(expand.dots = TRUE))
objnames <- as.character(fargs)[-c(1, 2)]
nobjects <- length(objects)
for (i in 1:nobjects) {
if (i == 1)
write.xlsx(objects[[i]], file, sheetName = objnames[i])
else write.xlsx(objects[[i]], file, sheetName = objnames[i],
append = TRUE)
}
print(paste("Workbook", file, "has", nobjects, "worksheets."))
}
but i get the following error:
Error in .jcall(wb, "Lorg/apache/poi/ss/usermodel/Sheet;", "createSheet", :
java.lang.IllegalArgumentException: sheetName must not be null
It isn't get the sheet names like it had before but I am not understanding why

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data <- read_excel("grad programs.xlsx", sheet="Sheet2")
print(data)
But instead of getting the Excel file, I get this really long random message:
print(data)
function (..., list = character(), package = NULL, lib.loc = NULL,
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fileExt <- function(x) {
db <- grepl("\\.[^.]+\\.(gz|bz2|xz)$", x)
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ans[db] <- sub(".*\\.([^.]+\\.)(gz|bz2|xz)$", "\\1\\2",
x[db])
ans
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Sys.setlocale("LC_COLLATE", "C")
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}
stopifnot(is.character(list))
names <- c(as.character(substitute(list(...))[-1L]), list)
if (!is.null(package)) {
if (!is.character(package))
stop("'package' must be a character vector or NULL")
}
paths <- find.package(package, lib.loc, verbose = verbose)
if (is.null(lib.loc))
paths <- c(path.package(package, TRUE), if (!length(package)) getwd(),
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paths <- unique(normalizePath(paths[file.exists(paths)]))
paths <- paths[dir.exists(file.path(paths, "data"))]
dataExts <- tools:::.make_file_exts("data")
if (length(names) == 0L) {
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Message is longer than that, but that's the start - any idea why get this message rather than the actual data in the Excel sheet

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This program works because I made the varibles inisde lapply global by using the <<- operator. However, it does not work with the real files in the real program. These are .tsv files whith named columns. The answer I get when I run the real program is: Error: (converted from warning) Error in : (converted from warning) Error in : arguments imply differing number of rows: 3455, 4319. What might be causing this?
lc <- list("test.txt", "test.txt", "test.txt", "test.txt")
lc1 <- list("test.txt", "test.txt", "test.txt")
lc2 <- list("test.txt", "test.txt")
#list of lists. The lists contain file names
lc <- list(lc, lc1, lc2)
#new names for the three lists in the list of lists
new_dataFns <- list("name1", "name2", "name3")
file_paths <- NULL
new_path <- NULL
#add the file names to the path and read and merge the contents of each list in the list of lists
lapply(
lc,
function(lc) {
filenames <- file.path(getwd(), lc)
dataList <<- lapply(filenames, function (lc) read.table(file=lc, header=TRUE))
dataList <<- lapply(dataList, function(dataList) {merge(as.data.frame(dataList),as.data.frame(dataList))})
}
)
#add the new name of the file to the path total will be 3 paths/fille_newname.tsv.
lapply(new_dataFns, function(new_dataFns) {new_path <<- file.path(getwd(), new_dataFns)})
print(new_path)
print(dataList)
finalFiles <- merge(as.data.frame(dataList), as.data.frame(new_path))
print(finalFiles)
I found a solution to the problem by writing a different type of code. Please see below. The input to the function is provided by the app input widgets
glyCount1 <- function(answer = NULL, fileChoice = NULL, combination = NULL, enteredValue = NULL, nameList) {
lc = nameList
new_dataFns <- gsub(" ", "", nameList)
first_path <- NULL
new_path <- NULL
old_path <- NULL
file_content <- NULL
for(i in 1:length(lc)){
for(j in 1:length(lc[[i]])){
if(!is.null(lc[[i]])){
first_path[[j]]<- paste(getwd(), "/", lc[[i]][j], sep = "")
tryCatch(file_content[[j]] <- read.csv(file = first_path[[i]], header = TRUE, sep = ","), error = function(e) NULL)
old_path[[j]] <- paste(getwd(), "/", i, ".csv", sep = "")
write.table(file_content[[j]], file = old_path[[j]], append = TRUE, col.names = FALSE)
}
}
}
}

How to use base R to write table to .xlsx?

Apologies but I'm new to R. I'm able to write a data table to a .csv and a .txt file but I'd like to write it to an .xlsx file. Is this possible using base R?
Thanks
The writexl package is quite nice. No 'Java' or 'Excel' required.
library(writexl)
write_xlsx(df,'filename.xlsx')
For doing this you need to have xlsx package installed.
The you can try.
library(xlsx)
xlsx.writeMultipleData <- function (file, ...)
{
require(xlsx, quietly = TRUE)
objects <- list(...)
fargs <- as.list(match.call(expand.dots = TRUE))
objnames <- as.character(fargs)[-c(1, 2)]
nobjects <- length(objects)
for (i in 1:nobjects) {
if (i == 1)
write.xlsx(objects[[i]], file, sheetName = objnames[i])
else write.xlsx(objects[[i]], file, sheetName = objnames[i],
append = TRUE)
}
}

R dataframes to multi sheet Excel Work

I'm trying to save quite a few data frames to a multi sheet Excel sheet and am getting some weird errors.
library(xlsx)
save.xlsx("WorkbookTitle.xlsx", mtcars, Titanic, iris)
save.xlsx <- function (file, ...)
{
require(xlsx, quietly = TRUE)
objects <- list(...)
fargs <- as.list(match.call(expand.dots = TRUE))
objnames <- as.character(fargs)[-c(1, 2)]
nobjects <- length(objects)
for (i in 1:nobjects) {
if (i == 1)
write.xlsx(objects[[i]], file, sheetName = objnames[i])
else write.xlsx(objects[[i]], file, sheetName = objnames[i],
append = TRUE)
}
print(paste("Workbook", file, "has", nobjects, "worksheets."))
}
gave me an actual workbook but when I try to do this with my dataframes, i get this error:
the condition has length > 1 and only the first element will be usedError in .jcall(cell, "V", "setCellValue", value) :
method setCellValue with signature ([Ljava/lang/String;)V not found
I removed row names but that didn't seem to work.

Cross Product of specific file and rest of the folder -- R

I have a problems making R read a set of files in a folder and returning cross product of them.
I have a folder which contains one test.csv file and n train.csv files.
I need a loop to read though on folder and return a file that contain the cross product of test and each of the train files… so the rows of file should look like this.
test*train01
test*train02
test*train03
...
I wrote a script to make that for two defined line but don’t know how to adapt that for the whole folder and the pattern that I need.
data01 <- as.matrix(read.csv(file = "test.csv", sep = ",", header=FALSE))
data02 <- as.matrix(read.csv(file = "train.csv", sep = ",", header=FALSE))
test <- list()
test01<- list()
test02<- list()
i<- 1
while (i <= 25){
test01[[i]] <- c(data01[i, ])
test02[[i]] <- c(data02[i, ])
test[[i]]<- crossprod(test01[[i]],test02[[i]])
i <- i+1
}
write.csv(test, file="testing.csv", row.names = FALSE)
Try:
test <- function(data) {
data01 <- as.matrix(read.csv(file = "test.csv", sep = ",", header=FALSE))
data02 <- as.matrix(read.csv(file = data, sep = ",", header=FALSE))
test <- list()
test01<- list()
test02<- list()
i<- 1
while (i <= 25){
test01[[i]] <- c(data01[i, ])
test02[[i]] <- c(data02[i, ])
test[[i]]<- crossprod(test01[[i]],test02[[i]])
i <- i+1
}
return(test)
}
result <- lapply(list.files(pattern='Train.*'),test)
Then just loop result to save in CSV file.
EDIT: How to save:
files <- list.files(pattern='Train.*')
for (i in seq(length(result))) {
write.csv(result[[i]], paste0('result_',files[i]), row.names = FALSE)
}
EDIT: Saving in one file:
write.csv(do.call(rbind,result),'result.csv', row.names = FALSE) # Appending by row
or
write.csv(do.call(cbind,result),'result.csv', row.names = FALSE) # Appending by column

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