Why duplicateStyle doesn't work for another cell? - phpexcel

Question

I create 2 style objects in my php source code :
-the 1st style called $style1 is to fill a cell with red color,
-the 2nd style called $style2 is to fill a cell with green color,
But when I apply the 1st style in a cell with duplicateStyle() method,
it's the 2nd style is applied.
Here the php source code (last PHPExcel version : 1.8.0) :
<?php
// Import PHPExcel class:
include("./PHPExcel/Classes/PHPExcel.php");
// Create a workbook :
$workbook = new PHPExcel;
// Create a sheet :
$sheet = $workbook->getActiveSheet();
// Set to A4 page size :
$sheet->getPageSetup()->setPaperSize(9);
// Set to landscape orientation, but it doesn't work :
$sheet->getPageSetup()->setOrientation("landscape");
/*Create style1 for A1 cell :*/
$style1 = $sheet->getStyle('A1');
$style1->applyFromArray(
array(
'fill' => array(
'type' => 'solid',
//Color filling :
'color' => array('rgb' => 'ff0000')
)
)
);
/*Create style2 for B1 cell :*/
$style2 = $sheet->getStyle('B1');
$style2->applyFromArray(
array(
'fill' => array(
'type' => 'solid',
//Green filling :
'color' => array('rgb' => '00ff00')
)
)
);
//Duplicate style1 to A2 :
$sheet->duplicateStyle($style1, "A2");
//Write in A2 cell. Bug : red filling doesn't work :
$sheet->setCellValue("A2", "Must be red");
//Duplicate style2 to B2 :
$sheet->duplicateStyle($style2, "B2");
//Write in B2 cell :
$sheet->setCellValue("B2", "Must be green");
//Output to brower :
header('Content-Type: application/vnd.openxmlformats-officedocument.spreadsheetml.sheet');
header('Content-Disposition: attachment;filename="file.xlsx"');
header('Cache-Control: max-age=0');
$writer = new PHPExcel_Writer_Excel2007($workbook);
//Office 2003 compatibilty :
$writer->setOffice2003Compatibility(true);
$writer->save('php://output');
?>
So what's the problem?

Answer 1

I find the solution :
Use $style1 = new PHPExcel_Style(); instead of $style1 = $sheet->getStyle('A1');
Thak you very much.