Negative exponential fit: curve looks too high - r

Question

I am trying to fit a negative exponential to some data in R, but the fitted line looks too high compared to the data, whereas the fit I get using Excel's built-in power fit looks more believable. Can someone tell me why? I've tried using the nls() function and also optim() and get similar parameters from both of those methods, but the fits for both look high.
x <- c(5.96, 12.86, 8.40, 2.03, 12.84, 21.44, 21.45, 19.97, 8.92, 25.00, 19.90, 20.00, 20.70, 16.68, 14.90, 26.00, 22.00, 22.00, 10.00, 5.70, 5.40, 3.20, 7.60, 0.59, 0.14, 0.85, 9.20, 0.79, 1.40, 2.68, 1.91)
y <- c(5.35, 2.38, 1.77, 1.87, 1.47, 3.27, 2.01, 0.52, 2.72, 0.85, 1.60, 1.37, 1.48, 0.39, 2.39, 1.83, 0.71, 1.24, 3.14, 2.16, 2.22, 11.50, 8.32, 38.98, 16.78, 32.66, 3.89, 1.89, 8.71, 9.74, 23.14)
xy.frame <- data.frame(x,y)
nl.fit <- nls(formula=(y ~ a * x^b), data=xy.frame, start = c(a=10, b=-0.7))
a.est <- coef(nl.fit)[1]
b.est <- coef(nl.fit)[2]
plot(x=xy.frame$x,y=xy.frame$y)
# curve looks too high
curve(a.est * x^b.est , add=T)
# these parameters from Excel seem to fit better
curve(10.495 * x^-0.655, add=T)
# alternatively use optim()
theta.init <- c(1000,-0.5, 50)
exp.nll <- function(theta, data){
a <- theta[1]
b <- theta[2]
sigma <- theta[3]
obs.y <- data$y
x <- data$x
pred.y <- a*x^b
nll <- -sum(dnorm(x=obs.y, mean=pred.y , sd=sigma, log=T))
nll
}
fit.optim <- optim(par=theta.init,fn=exp.nll,method="BFGS",data=xy.frame )
plot(x=xy.frame$x,y=xy.frame$y)
# still looks too high
curve(a.est * x^b.est, add=T)

Answer 1

The reason you're seeing the unexpected behavior is that the curves that look "too high" actually have much lower sums of squared errors than the curves from excel:
# Fit from nls
sum((y - a.est*x^b.est)^2)
# [1] 1588.313
# Fit from excel
sum((y - 10.495*x^ -0.655)^2)
# [1] 1981.561
The reason nls favors the higher curve is that it is working to avoid huge errors at small x values at the cost of slightly larger errors with large x values. One way to address this might be to apply a log-log transformation:
mod <- lm(log(y)~log(x))
(a.est2 <- exp(coef(mod)["(Intercept)"]))
# (Intercept)
# 10.45614
(b.est2 <- coef(mod)["log(x)"])
# log(x)
# -0.6529741
These are quite close to the coefficients from excel, and yield a more visually appealing fit (despite the worse performance on the sum-of-squared-errors metric):